I have a group of files that are named as such (word can be any word or numbers):
Word word-word word word Floor B2342 Word Word-word.pdf
Word word-word word Floor: B-2342 Word Word-word.pdf
Word word- Floor C43 Word Word.pdf
Word word word- Floor- E2AD342 Word Word.pdf
I want to rename everything in the folder to only have the group that follows Floor... You can count on Floor always being in the file name and what I want to keep following floor.
B2342.pdf
B-2342.pdf
C43.pdf
E2AD342.pdf
Pass the path of the folder you want to process as the first argument to this script. You might have to tweak the regular expression for your input.
Set expr = New RegExp
Set fs = CreateObject("Scripting.FileSystemObject")
Set fpath = fs.GetFolder(WScript.Arguments(0))
expr.Pattern = "Floor\S*\s+([^\s.]*)"
For Each fspec In fpath.Files
Set matches = expr.Execute(fspec.Name)
If matches.Count = 0 Then
WScript.StdErr.WriteLine "Invalid file name " & fspec.Name
Else
fspec.Move fspec.ParentFolder & "\" & matches(0).Submatches(0) & ".pdf"
End If
Next
Related
In a text file, I want to remove all Carriage Returns (vbCrLf) except those vbCrLf that are preceded by a period (.)
Honestly, no regex is needed.
Open the text file, split the entire text contents on what you want to retain (to create an array), then loop through the array and replace want you don't want during the file rewrite, ensuring to append what you wanted to retain.
For example:
Dim retain : retain = "." & vbCrLf
Dim toss : toss = vbCrLf
With CreateObject("Scripting.FileSystemObject")
Dim txtFile
With .OpenTextFile("C:\TestFile.txt", 1, False)
txtFile = Split(.ReadAll(), retain)
.Close
End With
With .OpenTextFile("C:\NewTestFile.txt", 2, True)
Dim row
For Each row In txtFile
.Write Replace(row, toss, " ") & retain
Next
.Close
End With
End With
Truth be told, VBScript's RegExp Pattern syntax may not be robust enough -- due to lack of look-ahead patterns -- to handle your conditional criteria cleanly with a single pass.
I've been working on a VBScript that finds all files with a specific extension, .dat, searches for a specific pattern, "Date Due:\d{8}", and shifts the string around in a specific format.
I am having two problems with the below code:
It is not reading the first line. Whenever I run the script it seems to jump immediately to the second line.
It is only using the first pattern it finds and replaces the following patterns with the first pattern in the newly formatted manner.
I hope this makes sense, it's a very specific script, but I am hoping for some help understanding the problem here.
Below is my code:
Set fso = CreateObject("Scripting.FileSystemObject")
'newtext = vbLf & "Date Due:" & sub_month & sub_day & sub_year 'the text replacing Date Due:
'the purpose of this script is to format the date after Date Due:, which is currently formatted as YYYYMMDD, to MM/DD/YYYY
'example: Date Date:20180605 should be Date Due:06/05/2018
Set re = New RegExp
re.Pattern = "(\nDate Due:\d{8})" 'Looking for line, Date Due: followed by 8 digits
Dim sub_str 'substring of date due, returns the 8 digits aka the date 12345678
Dim sub_month
Dim sub_day
Dim sub_year
Dim concat_full
re.Global = False
re.IgnoreCase = True
For Each f In fso.GetFolder("C:\Users\tgl\Desktop\TestFolder\").Files
If LCase(fso.GetExtensionName(f.Name)) = "dat" Then
text = f.OpenAsTextStream.ReadAll
sub_str = Mid(text, 10, 8) 'substring of the full line, outputs the 8 digit date
sub_month = Mid(sub_str, 5, 2) 'substring of the date, outputs the 2 digit month
sub_day = Mid(sub_str, 7, 2) 'substring of the date, outputs the 2 digit day
sub_year = Mid(sub_str, 1, 4) 'substring of the date, outputs the four digit year
newtext = vbLf & "Date Due:" & sub_month & "/" & sub_day & "/" & sub_year 'replaces the text pattern defined above and concatenates the substrings with slashes
'concat_full = (sub_month & sub_day & sub_year)
f.OpenAsTextStream(2).Write re.Replace(text, newtext)
End If
Next
EDIT: When changing re.Global to True it replaces each line with the one found pattern. It should be using each found pattern as it's own and not the first one it finds.
Make your regular expression more specific and use capturing groups for extracting the relevant submatches:
re.Pattern = "(\nDate Due:)(\d{4})(\d{2})(\d{2})"
then replace the matches like this:
re.Replace(text, "$1$4/$3/$2")
$1 through $4 in the replacement string are backreferences to the capturing groups in the pattern (i.e. they're replaced with the respective captured substring).
I have a file "D:\test.log" that has either one of two styles. This will appear if the user is offline when the user received the message:
[02:19:47] Brother Aimbot (adama900): (Saved Thu Mar 31 05:15:09 2016)This is a test line
It will be like this if the user is online when the user received the message:
[02:19:47] Brother Aimbot (adama900): This is a test line
What I would like this to do is cut out the excess parts so it would look like this if it's either the first or second style:
Brother Aimbot (adama900) This is a test line
then place it into a message box.
Here is my code:
Sub main()
filename = "D:\Test.txt"
Set fso = CreateObject("Scripting.FileSystemObject")
Set f = fso.OpenTextFile(filename)
LNEVAL = f.ReadLine
LNENUM = 0
Do Until f.AtEndOfStream
For i = 1 To LNENUMs
f.ReadLine
Next
If InStr(LNEVAL, "(S") Then
LNEVAL = Left(LNEVAL, (Len("(S")+4))
MsgBox = LNEVAL
End If
Loop
f.Close
End Sub
This is what I have so far.
It's fairly simple to do what you want with a regular expression replacement. Basically what you want to do is remove three things from each line:
a substring between square brackets from the beginning of the string,
the colon separating the name from the message, and
an optional substring between parentheses after that colon.
A regular expression ^\[.*?\] matches an opening square bracket at the beginning of a string and the shortest number of characters up to a closing square bracket.
A regular expression \(Saved.*?\) matches an opening parenthesis followed by the word Saved and the shortest number of characters up to a closing parenthesis. However, since this part is optional you need to indicate that the expression can occur zero or one time by putting it in a non-capturing group and appending the ? modifier to it ((?:...)?).
Put the submatches that you do want to preserve in parentheses to create capturing groups
^\[.*?\] (.*?): (?:\(Saved.*?\))?(.*)
and replace each matching line with just the captured groups:
Set re = New RegExp
re.Pattern = ...
Set f = fso.OpenTextFile(filename)
Do Until f.AtEndOfStream
MsgBox re.Replace(f.ReadLine, "$1 $2")
Loop
f.Close
Some comments on your existing code:
For i = 1 To LNENUMs: this loop is always skipped over, because you set LNEUMs to 0. Since you only do f.ReadLine inside that For loop your outer Do loop becomes an infinite loop, since you never read the file to the end.
Len("(S")+4 always evaluates to 6, because the length of the string (S is not going to change, so you could just replace the expression with the numeric value.
MsgBox = LNEVAL: The MsgBox function doesn't work that way. Remove the = between function name and message.
I have 6400+ records which I am looping through. For each of these: I check that the address is valid by testing it against something similar to what the Post Office uses (find address). I need to double check that the postcode I have pulled back matches.
The only problem is that the postcode may have been inputted in a number of different formats for example:
OP6 6YH
OP66YH
OP6 6YH.
If Replace(strPostcode," ","") = Replace(xmlAddress.selectSingleNode("//postcode").text," ","") Then
I want to remove all spaces from the string. If I do the Replace above, it removes the space for the first example but leave one for the third.
I know that I can remove these using a loop statement, but believe this will make the script run really slow as it will have to loop through 6400+ records to remove the spaces.
Is there another way?
I didn't realise you had to add -1 to remove all spaces
Replace(strPostcode," ","",1,-1)
Personally I've just done a loop like this:
Dim sLast
Do
sLast = strPostcode
strPostcode = Replace(strPostcode, " ", "")
If sLast = strPostcode Then Exit Do
Loop
However you may want to use a regular expression replace instead:
Dim re : Set re = New RegExp
re.Global = True
re.Pattern = " +" ' Match one or more spaces
WScript.Echo re.Replace("OP6 6YH.", "")
WScript.Echo re.Replace("OP6 6YH.", "")
WScript.Echo re.Replace("O P 6 6 Y H.", "")
Set re = Nothing
The output of the latter is:
D:\Development>cscript replace.vbs
OP66YH.
OP66YH.
OP66YH.
D:\Development>
This is the syntax Replace(expression, find, replacewith[, start[, count[, compare]]])
it will default to -1 for count and 1 for start. May be some dll is corrupt changing the defaults of Replace function.
String.Join("", YourString.Split({" "}, StringSplitOptions.RemoveEmptyEntries))
Because you get all strings without spaces and you join them with separator "".
Hey all, i am trying to replace large spaces between text with just one. My output looks like this right now:
5964215">
This is just the first example of the spaces
5964478">
This would be the 2nd example of showing how many spaces this thing has in each sentence.
5964494">
That comes from a textbox that has multi-line to true. Here is what it looks like when it doesn't have multi-line to true.
http://www.june3rdsoftware.com/forums/vb6.jpg
I can not seem to get the spaces to go away! BTW, this text is from a webpage if that makes any difference.
David
According to the suggestion of MvanGeest, here is some VB code to replace blocks of white spaces:
Sub test()
Dim x As String, y As String
x = "abcd defg 1233"
Dim re As New RegExp
re.Pattern = "\s+"
re.Global = True
y = re.Replace(x, " ")
Debug.Print y
End Sub
To make this work, you will have to add a reference to "Microsoft VBScript Regular Expresssions" to your project.
Assuming no regex support, why not set up a simple state machine that will set the state=1 when a space is found and set state=0 once a non-space is encountered. You can move char by char when state=0 (thus copying over only 1 space per series of spaces).
Also assuming no regex, you could try something like
str = "long text with spaces "
i = LenB(str)
str = Replace(str, " ", " ")
Do While LenB(str) <> i
i = LenB(str)
str = Replace(str, " ", " ")
Loop
Of course this code could be optimized for long space sequences but it might be all you need as well