I want to store the output of text file into a variable, so I can pass the whole file as parameter.
I am using Windows 2003 Server.
The text files have multiple lines like:
10.20.210.100 fish
10.20.210.101 rock
I was using:
Set /P var=<file.txt
It reads only the first line of the file.
I tried with FOR loop also but it assigned only the last line to the variable.
There is no simple way to get the complete content of a file into one variable.
A variable has a limit of ~8100 length.
And it is complicated to get CR/LF into a variable
But with a FOR-loop you can get each single line.
Try a look at batch script read line by line
EDIT:
To get each line in a single variable you can use this
#echo off
SETLOCAL EnableDelayedExpansion
set n=0
for /f "delims=" %%a IN (example.txt) do (
set /a n+=1
set "line[!n!]=%%a"
echo line[!n!] is '%%a'
)
set line
or to get all in only one variable (without CR/LF)
#echo off
SETLOCAL EnableDelayedExpansion
set "line="
for /f "delims=" %%a IN (example.txt) do (
set "line=!line! %%a"
)
echo !line!
Jeb’s script is working perfect, But if you echo %line% it contains each line no of line in file times. And if you use echo !Line! ,it contain one !line! also with other line. I did a little modification in script and now I am getting expected result.
#echo off
SETLOCAL EnableDelayedExpansion
set "line="
for /f "delims=" %%a IN (example.txt) do (
set "line1=%%a"
set "line=!line1! and %%a"
)
echo !line!
or
echo %line%
Now you will get same result in bot cases.
Related
I used the following code, but set Content is blank in my case. Please help. Thanks.
set content=
for /f "delims=" %%i in (fileA.txt) do set content=%%i
for /f "delims=" %%i in (FileA.txt) do set content=%content% %%i
ECHO %content%> result.txt
FileA.txt
test
A
Testing
B
Expected Output:
test A
Testing B
You need a single for command to process all lines and this simple logic: if it is the first line read, store it; else show the stored first line and the second one AND delete the first line, so the same logic be used in all line pairs:
#echo off
setlocal EnableDelayedExpansion
set "firstLine="
(for /F "delims=" %%a in (FileA.txt) do (
if not defined firstLine (
set "firstLine=%%a"
) else (
echo !firstLine! %%a
set "firstLine="
)
)) > result.txt
Your two for work independently (the second starts when the first is finished).
Your first loop gets the last line of the file and then the second adds every line of the textfile to the variable (there is a limit for variable length and you will soon reach it with this method).
The empty variable at the end is due to lack of using delayed expansion.
Work with a single for and an alternating flag instead:
#echo off
setlocal enabledelayedexpansion
set flag=0
(for /f "delims=" %%i in (FileA.txt) do (
if !flag!==0 (
<nul set /p ".=%%i "
) else (
echo %%i
)
set /a "flag=(flag+1) %% 2"
))>result.txt
Note: due to batch/cmd limitations, this may have some problems (line length, special characters
We need '#echo off' statement to not to print code on every execution of the program and only echo statements, 'rem' is to mention the line is a comment. 'SETLOCAL EnableExtensions EnableDelayedExpansion' is need to enable ! statements to resolve the variables.
#echo off
rem this for loop reads the file FileA.txt line by line by specifying delims= (nothing)
rem then checks the condition if the line is even line or not, if odd then adding it to myVar variable
rem if even then printing both earlier odd with the current even line to the result.txt file.
set myVar=
set nummod2=0
set /a i=0
rem creating an empty file on everytime the program runs
copy /y nul result.txt
SETLOCAL EnableExtensions EnableDelayedExpansion
for /f "delims=" %%a in (FileA.txt) do (
set /a i=i+1
set /a nummod2=i%%2
if !nummod2!==0 (
echo !myVar! %%a
) else (
set myVar=%%a
)
) >> result.txt;
echo 'Done with program execution. Result saved to result.txt in the same folder of this batchfile'
rem pause
I'm new to batch script, I have a file with a string containing the word "media"(quotes included) and I need to insert another string right before it.
I messed around with findstr but couldn't make heads or tails of it.
Edit2:
here's what i did, doesn't seem to work:
#echo off
SETLOCAL=ENABLEDELAYEDEXPANSION
for /f "delims=," %%a in (f1.txt) do (
set foo=%%a
if !foo!=="media"
set var=!foo:"media"=aa"media"!
echo !foo! >> f2.txt)
You have two options to do this. You can read the file with a FOR /F command or if you are just editing a single line file then you can use the SET /P command.
Here are both of those examples in a single batch file.
#echo off
setlocal enabledelayedexpansion
for /F "delims=" %%G in (sotemp.txt) do (
set "line=%%G"
set "foo=!line:"media"=aa"media"!"
echo !foo!
)
set /p "line="<sotemp.txt
echo %line:"media"=aa"media"%
pause
I have a file "file.txt" which contains the output of "dir /s /b *.c"
I want to write this whole content of file.txt in a single variable .
Any ideas?
The usual way to treat questions like this one is to reply: "What do you want this for?". However, your question is pure and simple, so here is the answer. The Batch file below not just store the contents of file.txt in a single variable, but it also later process the variable value as individual lines.
EDIT: I added the method to extract individual lines from the variable value as substrings.
#echo off
setlocal EnableDelayedExpansion
rem Create variables with LF and CR values:
set LF=^
%empty line 1/2, don't remove%
%empty line 2/2, don't remove%
for /F %%a in ('copy /Z "%~F0" NUL') do set CR=%%a
rem Store the contents of file.txt in a single variable,
rem end each line with <CR><LF> bytes
set "variable="
for /F "delims=" %%a in (file.txt) do (
set "variable=!variable!%%a!CR!!LF!"
)
rem 1- Show the contents of the variable:
echo !variable!
rem 2- Process the contents of the variable line by line
echo/
set i=0
for /F "delims=" %%a in ("!variable!") do (
set /A i+=1
echo Line !i!- %%a
)
rem Get the starting position and length of each line inside the variable
set /A i=0, lastStart=0
for /F "delims=:" %%a in (
'(cmd /V:ON /C set /P "=^!variable^!" ^& echo/^) ^<NUL ^| findstr /O "^^"'
) do (
set /A len[!i!]=%%a-lastStart-2, i+=1
set /A start[!i!]=%%a, lastStart=%%a
)
set "len[0]="
set "start[%i%]="
set /A lastLine=i-1
rem 3- Extract individual lines from the variable contents as substrings
:getNumber
echo/
set "num="
set /P "num=Enter line number (nothing to end): "
if not defined num goto end
if %num% gtr %lastLine% echo Invalid number & goto getNumber
for /F "tokens=1,2" %%i in ("!start[%num%]! !len[%num%]!") do (
echo Line %num%- !variable:~%%i,%%j!
)
goto getNumber
:end
You must note that Batch variables can only store a maximum of 8K characters.
No. But you can go through the lines one by one.
for /f "delims=" %A in (file.txt) do echo %A
Maybe say what you are trying to achieve. Knowledge of C won't help you in batch because it's contary for historical reasons.
You can use set /p:
set /p foo=<file.txt
See also this question.
Batch-Script is a very limited tool with a primitive support for multi-line variables (with specific hacks that will not work as expected for this sceneario but if you are interested see this).
The only reasonable solution is to move to a capable language, which is every else less Batch-Script.
I need to remove a string that may occur inside a file. The string has many lines. Can I perform this action using a Batch script?
I've heard that you cant have variables with more than one line in Batch? The string will come from another file that I will read into a variable using Batch.
The following code seems to only store the 1st/last line of a file in the string?? Whats going wrong?
Rem Read file and store all contents in string
Set replace=
Set target=
Set OUTFILE=res.txt
for /f "delims=" %%i in (myFile.txt) do set target=%target% %%i
echo %target%
Rem When I print target I only have one line not many lines?? Whats going wrong
Rem Remove the target string from myOtherFile.txt: this code is from http://stackoverflow.com/questions/5273937/how-to-replace-substrings-in-windows-batch-file
for /f "tokens=1,* delims=¶" %%A in ( '"type myOtherFile.txt"') do (
SET string=%%A
SET modified=!string:%target%=%replace%!
echo !modified! >> %OUTFILE%
)
Try this:
#echo off &setlocal enabledelayedexpansion
for /f "delims=" %%i in (myFile.txt) do set "target=!target! %%i"
echo %target%
Inside a code block you need always delayed expansion for variables with variable values.
Try this, change last to:
echo !target!
I have a XML file and I need to replace a perticular line say 7th line with the my own line using DOS command. How to do this?
My proposal is based on the fact you identify the line by its number and not by its content
#echo OFF
REM Say LINE 7 to be removed
SETLOCAL ENABLEDELAYEDEXPANSION
SET LOWER=6
SET UPPER=8
SET INDEX=0
SET MYLINE="this is my new line"
SET OUTFILE=%~n1.new%~x1
>%OUTFILE% (
for /F "tokens=*" %%L in (%1) do (SET /A INDEX += 1
IF !INDEX! LEQ %LOWER% (echo %%L) ELSE break
)
echo %MYLINE%
more +%UPPER% %1
)
echo off needed since we do a massive redirect
ENABLEDELAYEDEXPANSION
needed for the counter in the loop
You just pass the xml file as an argument to the script.
HTH