I have a basic checkbox click function that only allows the user to click only one checkbox within each fieldset (there are four fieldsets each containing numberous checkboxes:
$(document).ready(function(){
$('input[type=checkbox]').click(function(){
// get the fieldset class
var fieldset = $(this).parents('fieldset').attr('class');
// set the number of checked
var numChecked = $('.'+fieldset+' input:checked').size();
// if more than 1
if(numChecked > 1){
alert('Please select only one option per breakout session.')
$(this).attr('checked',false);
}
});
Then I have a submit function on the form that will confirm that at least one checkbox is selected before posting the form:
$('form[name=mainForm]').submit(function(){
var error = '';
// loop through each fieldset
$('fieldset',this).each(function(){
// set the number of checked for this fieldset
var numChecked = $('input:checked',this).size();
// if none are checked
if(!numChecked){
// set the error var
error = 'At least one of your time sessions has no checkbox selected!';
// add class to show user
$(this).addClass('errorSessions');
}
else{
$(this).removeClass('errorSessions');
}
});
// if any errors, show them and don't allow the form to be submitted
if(error.length){
alert(error);
return false;
}
$("#mainForm").validate();
The form validates perfectly and everything happens flawlessly the first time around. The problem is that if you submit the form, the validation occurs and it gives the error "At least one of your time sessions has no checkbox selected!" - at that point if you proceed to select multiple checkboxes within a given fieldset that was not initially checked, it will ignore the checkbox click function and allow you to select more than one checkbox in a fieldset.
Can someone please help with this?
Okay, I figured it out. The error has to do with the script adding the class 'errorsessions' to the fieldset which changes the unique classname of the fieldset. By adding a unique id to each fieldset and then changing the script to reference .attr('id'); instead of .attr('class'); the issue resolved and the on click alert function resumed after the class was added.
Do you consider using radio buttons as they are there for single selection? This way you don't have to check for multi selection as it isn't possible for select more than one radio button in given group.
Related
Here is my situation:
I have a very long multi-page survey built by webforms in drupal.
The questions are not required but we don't want the users to skip all the questions too easy by just clicking Next Page button.
So this is what we need:
When the user try to click on "Next Page" button with any empty fields on the page, error or warning messages will show up, "Are you sure you want to skip this question?", as well as a skip button next to it. When the user click on the skip button, the message disappears and they click on the next page button to proceed the survey.
Here are my thoughts on this:
I used webform validation module to create an Not Empty validation and apply it to the fields.
in webform_validation_validators.inc:
case 'skip_if_empty':
foreach ($items as $key => $val) {
if (count($val) == 0) {
drupal_set_message(t('This field is empty.'), 'warning');
// do something, not sure about it here
}
}
Another thought:
I used the Dismiss module to display an X button next to the error message.
Can I add some functions to the X button to bypass the validation when it is clicked?
And here is the script for the Dismiss module, :
(function ($) {
Drupal.behaviors.dismiss = {
attach: function (context) {
$('.messages').each(function () {
var flag = $(this).children().hasClass('dismiss');
if (!flag) {
$(this).prepend('' + Drupal.t('Close this message.') + '');
}
});
$('.dismiss').click(function () {
$(this).parent().hide('fast');
// some functions to bypass validation to the field?
});
}
}
})(jQuery);
I don't know what to do to after the //. Or is there any other ideas that will work?
AS per the you requirement mention
Take this example
You have created webform having field like
Firstname with required field
Lastname with required field
Then Next button button
When user click next button then error show because you have make the fields are required
When your showing "Dismiss button" next to each field.
Whenr user click "Dismiss button" that time you have to remove "required" attribute of field using jquery or drupal ajax
After that when user click next button then user not get any kind of required field validation error.
I have a form with 2 steps and with a continue button. At a time one step is visible. I have to validate only visible elements in each step. While using twitter bootstrap, when i go to next step the elements are getting highlighted as soon as the step is visible.
I was searching my own problem but I will try to help you.
I did steps with bootstrapWizard. If step isnt validated not goes and focus on error. My problem is I cant validate wysihtml5 because its hidden and validation ignores it, and hidden:not didnt work on my steps..
That is my on next validation if validated goes to next step.
onNext: function(tab, navigation, index) {
var $valid = $("#form").valid();
if(!$valid) {
$validator.focusInvalid();
return false;
}
my validator,
var $validator = $("#form").validate({
});
I have a form in an ASP.Net MVC project on which I am using qTip2 to display validation erros. On that form, I also have text fields that are activated/deacivated depending on choices made with radio buttons. When fields are not to be used, I set their disabled="disabled" properties. This ensures that client side validation (jQuery unobtrusive validation) for these fields is also deactivated. Now, I am wondering how to reset the qTip2 "bubbles" for fields that get disabled.
Let's say I have radio buttons 1 and 2 that enable text boxes A and B respectively. Let's also say that radio button 1 is selected by default, and that text boxes A and B are required fields when the corresponding radio button is selected. If I press on the Submit button without filling any text field, a qTip error bubble appears beside text box A. Now, if I press on radio button 2, I have to clear that bubble, disable text box A and its validation, and enable text box B and its validation. However, if I press submit at this point without filling text box B, no error bubble appears and the form is not getting submitted.
I tried various combinations of the following commands to accomplish this, but then the validation errors get completely disabled:
$('.qtip').remove();
$('.qtip').hide();
$("input.input-validation-error").removeClass("input-validation-error"); // watch out for the error message labels or they won't go away
$('form').data('validator').resetForm();
$("form").validate().form();
No matter what combinations of these commands I execute after a radio button got clicked and the proper text-boxes disabled/enabled, the qTip bubbles disappear, but they never reappear even if I click on the Submit button and other errors should appear on the form.
I am probably not using the right commands to reset qTip validation bubbles.
Ok, I found a solution right after posting the question. I used the solution proposed on this page http://johnculviner.com/?tag=/unobtrusive-validation-reset that I modified a bit. I added the following line: $form.find('input').qtip('destroy');
It gives this:
//Taken from: http://johnculviner.com/?tag=/unobtrusive-validation-reset
(function ($) {
$.fn.resetValidation = function () {
var $form = this.closest('form');
//Destroy qTip error bubbles (http://craigsworks.com/projects/forums/thread-using-qtip-with-jquery-validation-framework)
//$form.find('input:not(.errormessage)').qtip('destroy');
$form.find('input').qtip('destroy');
//reset jQuery Validate's internals
$form.validate().resetForm();
//reset unobtrusive validation summary, if it exists
$form.find("[data-valmsg-summary=true]")
.removeClass("validation-summary-errors")
.addClass("validation-summary-valid")
.find("ul").empty();
//reset unobtrusive field level, if it exists
$form.find("[data-valmsg-replace]")
.removeClass("field-validation-error")
.addClass("field-validation-valid")
.empty();
return $form;
};
//reset a form given a jQuery selected form or a child
//by default validation is also reset
$.fn.formReset = function (resetValidation) {
var $form = this.closest('form');
$form[0].reset();
if (resetValidation == undefined || resetValidation) {
$form.resetValidation();
}
return $form;
}
})(jQuery);
Then when a radio button is clicked, I call $("form").resetValidation(); after the proper fields have been enabled/disabled.
I have a web page that has a few text boxes, and a dual list control. All of these data elements are for a particular entity. The form is for creating a new instance of this entity and saving it to the database. The dual list shows available people to use, and the user can move options from the available list to the selected list. All of this works perfectly when posted. There is a button at the bottom of the page to post the form.
To make things easy, I also want to include a hidden "form" that lets the user add a new person to the dual list without leaving the page. They click an "Add New" link which shows a previously hidden div. In the div are two text boxes: "emailName" and "emailAddress", and a button to click called "Add".
When the user clicks the "Add" button I need to validate the emailName and emailAddress fields, and only those two fields. If they are valid then I will make my AJAX request and handle the return data by adding a new option to the dual list.
Here's the solution I am using.
First, I disable validation of my partial's form elements and never re-enable it. I do this by specifying a class selector in the validator options using a custom script that's referenced in the main page.
Then, on my parital's button click I call validator.element for each element. If they are all valid then I perform the AJAX request.
Calling .element will show the validation message for the field and return a boolean indicating if it's valid. You have to check these carefully to avoid boolean operator short-circuiting issues, to make sure all the error messages get shown. I used the bitwise & to accomplish this.
var validator = $("#EmailRecipient_Name").closest("form").validate();
//validator.settings.defaultIgnoreClass is defined in a custom script, and set to ".ignoreValidation"
$("#EmailRecipient_Name").addClass(validator.settings.defaultIgnoreClass);
$("#EmailRecipient_Email").addClass(validator.settings.defaultIgnoreClass);
$("#addNewRecipientLink").click(
function () {
$("#addNewRecipientBox").toggle()
return false;
}
);
$("#addNewRecipient").click(
function(){
var validator = $("#EmailRecipient_Name").closest("form").validate();
if ( validator.element( "#EmailRecipient_Name" ) & validator.element( "#EmailRecipient_Email" ) )
{
$.post(
"#Url.Action( "Create", "EmailRecipient" )",
{
Name: $("#EmailRecipient_Name").val(),
Email : $("#EmailRecipient_Email").val()
},
function( data ){
if ( data.ErrorMessage )
{
alert( data.ErrorMessage );
}
else
{
$("#SelectedEmailRecipients").append("<option value='" + data.EmailRecipientID + "'>" + data.Name + "</option>");
$("#EmailRecipient_Name").val("");
$("#EmailRecipient_Email").val("");
}
}
);
}
return false;
}
);
I have a page of products and for each of them, I want to have a form that uses AJAX to update the session. I've done this bit - just providing background.
I use the product's ID to create a different form class and name for each form, so each form is called something like this_form_name_567 and the next would be this_form_name_568 and so on.
There is a submit button per form. I'm having trouble figuring out
Which event is best to use so that the correct form will be identified when a submit button is clicked?
Once clicked, how to then make sure the correct value is taken from a hidden field (unique ID) within the submitted form so that I can populate a line of code such as:
$.post("compare_response.php", {compare_this: $("#compare_this").val()}, function(data){
}
You can use the .closest tree traversal method to get the form in which the button of interest is nested:
$("input[type=submit]").click(function() {
alert($(this).closest("form").attr("id"));
});
or even simpler, just get the element's form property :)
$("input[type=submit]").click(function() {
alert(this.form.id);
});
You can try it out here.
You can get the form you are submitting like this:
$('form').submit(function() {
var yourForm = $(this);
var hiddenValue = $(this).find('input[type=hidden]').val();
});
Of course you can get the hidden value differently, or if you have more than one hidden you'll have to give a little more information about it.