AdvancedDatagrid DataTipFunction - flex4

i have a grouped AdvancedDatagrid. It looks like...
dataProvider - GroupingCollection2 - Grouping - GroupingField - summaries - summaryRow - fields.
Sorry for the strage Codefragemt. I try everything to paste a litte bit mxml-Code. But i fail...
And a AdvancedDataGrid Column with a long long description. I want to show a DataTip. In the grouped headline, the DataTip shows [Object][Object]. In the expanded lines, the DataTip works fine.
I assume, what I need is a DataTipFunction to fix this. In this function, i will receive a object (AdvancedDataGridColumn). But how can i reference to the data of the highlighted line? And how can i find out, if this is a groupedLine or an expanded?
Thank you for reading it
Frank

In Adobe Document, it says that the DataTipFunction will look like this:
private function tipFunc(value:Object):String
{
if (value is AdvancedDataGridColumn)
return "Column Name";
// Use the 'name' property of the data provider element.
return "Name: " + value["name"];
}
show the object you received could be an AdvancedDataGridColumn when user's mouse is over the Column Header, and while moving the mouse over a row in datagrid, the function will receive an Object that is the data item in dataProvider.
when you use grouping, the value item you received will contain a sub-item called 'children', so you can depend on that to determind whether it's an expanded leaf node or grouped node.
so you function could be:
private function tipFunc(value:Object):String
{
if (value is AdvancedDataGridColumn)
// return dataTip you want to show for column header
return "Column Name";
if(value.hasOwnProperty('children'))
// return dataTip for grouped column item
return "Grouped Item";
// return data value in this column
return value["dataField name"];
}

Related

Add row name to cde table component

I have a table component in my Pentaho CDE dashboard and data source is sql. I want to make a table like this
enter image description here
I need to add a column as row names for this table and a row on the top of column header.
I found a method here:
Table Component SubColumns
to add header, but how can i add a column before other columns?
I think a clever way to do the extra column part would be by modifying the query result object after it's retrieved from the query, so that you add the columns and rows as needed. You can do this in the PostFetch callback function, which takes the query result object as first argument:
function yourTableComponentPostFetch(queryResult) {
// Let's say you have an array of row names
var rowNames = ['Title1', 'Title2', ... ];
// Add a "title" column for every row
queryResult.resultset.forEach(function (row, idx) {
// Push it at the beginning of the row array
row.unshift(rowNames[idx]);
});
// Change metadata description of columns to reflect this new structure
queryResult.metadata.unshift({
colName: 'Title',
colIndex: -1, // this makes sense when reindexing columns below ;)
colType: 'String'
});
// One last re-indexing of metadata column descriptions
queryResult.metadata.forEach(function (column, idx) {
// The title added column will be 0, and the rest will rearrange
column.colIndex++;
});
}
The only tricky part is the part about modifying the metadata since you are effectively changing the structure of the dataset, and making sure the queryResult object is updated in-place instead of just changing its reference (queryResult = myNewQueryResult would not work), but the code I proposed should do the trick.

Remove blank column in jqGrid - Pivot

I have created a jqGrid - Pivot table JSFiddle example: here.
In this It should not print the line if Component Type value is blank, I Used this empty column, to show all periods(months) in the year, which is mandatory.
Need help in removing that blank line. and also is it possible to remove the last sum column 2015 from grid, if so how?
You includes dummy data with ComponentType:"" group which you don't want to display. So the best solution which I see would be to include the data in the input pivot data only, but don't use the dummy data in the grid data. jqPivot uses datatype: "jsonstring" to prevent additional sorting of previously sorted data. The input data will be placed as the value of datastr option. So one can use the following onInitGrid to remove the dummy data before the data will be processed by jqGrid:
onInitGrid: function () {
var p = $(this).jqGrid("getGridParam"),
userdata = p.datastr.userdata;
p.datastr = $.grep(p.datastr, function (item) {
return item.ComponentType !== "";
});
p.datastr.userdata = userdata;
}
see the modified demo http://jsfiddle.net/OlegKi/b47ocLd7/11/.

kendo UI grid dataitem set method

grid.dataItem(selectedRow)
this is return the selected row which is a kendo.data.ObservableObject.
this object has all the columns for that grid's selected row. Is there a way to iterate thru all the columns and update.
or do i have to do it like this:
dataitem.set("Id", 1);
dataitem.set("name", Eric);
dataitem.set("age", 12);
As far as I understand what you are trying is to copy one JavaScript object into a Grid item, correct?
Let's assume that you have the new value in val:
var val = {
Id : 1,
name: "Eric",
age: 12
};
And you want to copy it in the selected row.
There are several ways of doing it:
What you just did.
Iterate through the different keys of val and copy the value.
Use jQuery extend.
Option 2.
for (var key in val) {
if (val.hasOwnProperty(key)) {
dataitem.set(key, val[key]);
}
}
Option 3.
$.extend(item, val);
item.set("uid", kendo.guid());
The first instruction performs a deep copy of val into item.
The second instruction makes the item dirty by just changing the UID.
NOTE: You don't need to update every single field using set, is enough changing one and all will get updated.

idPrefix usage in jqGrid

Given a jqGrid populated with local data and created with the option of idPrefix:"custTable" , all the generated rows get the prefix in the html id i.e. custTableRow_1 custTableRow_2 etc. Does this idPrefix'ed version of the id need to be passed in to the jqGrid methods, if so which ones?
for example to delete a row with deleteRowData does it need the prefixed id? how about setRowData or addRowData? when adding after row x it seems to need the prefixed for the srcrowid parameter. How about multiselect rows?
If I delete a row using the prefixed id of the row it disappears from the display but when I reload the grid the delete item shows up again in the grid, like it wasn't removed. This doesn't happen when idPrefix is not used.
thanks for any help.
The option idPrefix was introduced to hold ids on the HTML page unique even you have on the page the ids like the rowids loaded from the server. Typical example is two grids with the data loaded from the server. Let us you have two tables in the database where you use IDENTITY or AUTOINCREMENT in the definition of the PRIMARY KEY. In the case the primary key will be generated automatically in the table and will be unique inside the table, but there are not unique over the tables. So if you would use the primary keys as ids of the grids and place on one page two grids you can have id duplicates.
To solve the problem you can use idPrefix: "a" as additional option in the first grid and use idPrefix: "b" in the second grid. In the case locally jqGrid will uses everywhere ids with the prefix, but the prefix will be cut if the ids will be sent to the server.
So you will see locally in all callbacks (events) and in all methods (like setRowData, addRowData etc) the ids with the prefix, but on the server side the ids the prefixes will be removed immediately before sending to the server.
I recommend you additionally to read another answer about the restrictions in the ids which I posted today.
UPDATED: I looked through the code which you posed on jsfiddle and found some clear bugs in your code. You current code
1) use wrong algorithm to generate id of the new row. For example the following code
// generic way to create an animal
function newAnimal(collection, defaults) {
var next = collection.length + 1;
var newpet = {
id : next,
name: defaults.name + next,
breed: defaults.breed
};
return newpet;
}
use collection.length + 1 for the new id. It's wrong if you allows to delete the items. By adding of two items, deleting one from there and adding new item one more time follows to id duplicates. Instead of that it's more safe to use some variable which will be only incremented. You can use $.jgrid.randId() for example which code is very simple.
2) you call addRowData with adding a prefix manually (see dogsPrefix+newdog.id below). It's wrong because jqGrid adds the prefix one more time to the rows.
// add dog button actions
$('#dogAddAtEnd').click(function() {
var newdog = newAnimal(dogs, dogDefaults);
dogs.push(newdog);
dogAdded();
dogsTable.jqGrid('addRowData', dogsPrefix+newdog.id, newdog);
});
Probably there are more problems, but at least these problems can explain the problems which you described.
UPDATED 2: I examined new demo which you posted. It has still the lines
grid.jqGrid('addRowData', newanimal.id, newanimal,
"after", prefix+ followingId);
and
dogsTable.jqGrid('addRowData', dogsPrefix+newdog.id, newdog);
which must be fixed to
grid.jqGrid('addRowData', newanimal.id, newanimal,
"after", followingId);
and
dogsTable.jqGrid('addRowData', newdog.id, newdog);
Nevertheless I tested the demo after the changes and found bugs in code of addRowData, delRowData and setRowData. The problem are in the line of the delRowData and the same line of setRowData
var pos = $t.p._index[rowid];
can be fixed to the following
var id = $.jgrid.stripPref($t.p.idPrefix, rowid), pos = $t.p._index[id];
Inside of addRowData I suggest to include the line
var id = rowid; // pure id without prefix
before the line
rowid = t.p.idPrefix + rowid;
of addRowData. Another tow lines of addRowData
lcdata[t.p.localReader.id] = rowid;
t.p._index[rowid] = t.p.data.length;
should be changed to
lcdata[t.p.localReader.id] = id;
t.p._index[id] = t.p.data.length;
where unprefixed id will be used.
The modified code of you demo which uses the fixed version of jquery.jqGrid.src.js you can test here.
I will post my bug report to trirand later to inform the developer of the jqGrid. I hope that soon the bug fix will be included in the main code of jqGrid.
Additionally I recommend you to use $.jgrid.stripPref method to strip prefixes from the rowids. For example the function
//general delete selected
function deleteSelectedAnimal(list, grid, prefix)
{
var sel = grid.jqGrid('getGridParam', 'selrow');
if (sel.length)
{
var gridrow = sel;
//get the unprefixed model id
var modelid = gridrow;
if (prefix.length !== 0)
{
modelid = modelid.split(prefix)[1];
}
// make it a numeric
modelid = Number(modelid);
//delete the row in the collection
list = RemoveAnimal(list, modelid);
//delete the row in the grid
grid.jqGrid('delRowData', gridrow);
}
}
from your demo can be rewritten to the following
//general delete selected
function deleteSelectedAnimal(list, grid)
{
var sel = grid.jqGrid('getGridParam', 'selrow'),
gridPrefix = grid.jqGrid('getGridParam', 'idPrefix');
if (sel !== null)
{
//delete the row in the collection
// ??? the gogs list will be not modified in the way !!!
list = RemoveAnimal(list, $.jgrid.stripPref(gridPrefix, sel));
//delete the row in the grid
grid.jqGrid('delRowData', sel);
}
}
I am not sure that the line list = RemoveAnimal(list, $.jgrid.stripPref(gridPrefix, sel)); or the function RemoveAnimal do what you want, but it's not a problem which connected with jqGrid.
One more small remark about your code. You use already in the objects which you add to the grid the id property. It's the same name as defined in the localReader.id. In the case the data from the id property will be used as id attribute of the grid rows (<tr>). The local data parameter will save the id additionally to other properties which are build from the name property of the items of colModel. So I see no sense to define hidden column
{ key: true, name: 'id', align: 'left', hidden: true }
How you can see on the demo all stay works exactly as before if you remove id column from the grids which you use.
UPDATED 3: As promised before I posted the corresponding bug report here.

jqgrid randId() produces duplicates after page reload

On my grid, after a user enters text on the bottom row, I am adding another row so they can fill out another row if needed. The grid will grow as needed by the user. This is working fine, however after a page reload and populating from db, the addrowdata() function does not honor existing row ids and creates duplicates, starting from 1 again, e.g. jqg1. It should look at existing row ids and create new unique ids. So if I have 5 rows already, it might start at jqg6. Here is the relevant code inside onCellSelect:
var records = jQuery("#table-1").jqGrid('getGridParam', 'records');
var lastRowId = jQuery("#table-1").jqGrid('getDataIDs')[records - 1];
if (lastRowId == id)
{
jQuery('#table-1').addRowData(undefined, {}, 'last');
}
I have also tried $.jgrid.randId() instead of undefined, same results as expected.
Thanks
Ryan
I think that the error is in the part where you fill grid with the data from the database. The data saved in the database has unique ids. The ids are not in the form jqg1, jqg2, ... So if should be no conflicts. You should just fill the id fields of the JSON with the ids from the database.
One more possibility is that you just specify the rowid parameter (the first parameter) of addRowData yourself. In the case you will have full control on the new ids of the rows added in the grid.
The code of $.jgrid.randId function is very easy. There are $.jgrid.uidPref initialized as 'jqg' and $.jgrid.guid initialized to 1. The $.jgrid.randId function do the following
$.jgrid.randId = function (prefix) {
return (prefix? prefix: $.jgrid.uidPref) + ($.jgrid.guid++);
}
If it is really required you can increase (but not decrease) the $.jgrid.guid value without any negative side effects.

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