Read Data from csv file using VB - vb6

Question

This is the code i wrote in order to First open a csv file as excel, then find the required three columns, n then read data from them n save the data into another variables showing them in textbox. As about the csv file, it contains many columns out of which my focus is on only 3 columns under title ID, L, Lg.
Problem is Excel doesnt actually open but Excel.exe process runs in task manager.
But by this point its not the compile error; Compile error comes at 'Next' Statement. It says Compile Error: Next without For!!!!
I am Confused with this one. Please help me with this one, Thanks in Advance.
Private Sub cmdFind_Click()
Dim xlApp As Excel.Application
Set xlApp = New Excel.Application
Dim X As Double, Y As Double, FleetID As String
Dim F As String, FCol As Integer, LCol As Integer, LgCol As Integer, Srno As Integer, I As Integer
Dim xlWbook As Workbook
Dim xlSht As Excel.Worksheet
Set xlWbook = xlApp.Workbooks.Open("C:\Users\saurabhvyas\Desktop\test VB2\testfile.csv")
xlApp.Visible = True
Set xlSht = xlWbook.Worksheets("sheet1")
For I = 1 To 8 Step 1
If xlSht.Cells(I, 1).Value = "ID" Then
FCol = I
Else
If xlSht.Cells(I, 1).Value = "L" Then
LCol = I
Else
If xlSht.Cells(I, 1).Value = "Lg" Then
LgCol = I
End If
Next I
Set Srno = 2
Do
If xlSht.Cells(FCol, Srno).Value = Str$(txtF.Text) Then
Set X = xlSht.Cells(LCol, Srno).Value
Set Y = xlSht.Cells(LgCol, Srno).Value
End If
Srno = Srno + 1
Loop While xlSht.Cells(FCol, Srno).Value = vbNullString
txtL.Text = Str$(X)
txtLg.Text = Str$(Y)
xlWbook.Close
xlApp.Quit
Excel.Application.Close
Set xlSht = Nothing
Set xlWbook = Nothing
Set xlApp = Nothing
End Sub

Answer 1

You can open CSV format text files and operate on them using ADO with the Jet Provider's Text IISAM. Much less clunky than automating Excel. Or you can read the lines as text and Split() them on commas.
What you're doing does open Excel, but you haven't asked Excel to be visible... though I have no idea why you'd want that.
What are you really trying to do?

Answer 2

As for your compile error, that's because you are missing some End Ifs.
Write it as:
For I = 1 To 8 Step 1
If xlSht.Cells(I, 1).Value = "ID" Then
FCol = I
Else
If xlSht.Cells(I, 1).Value = "L" Then
LCol = I
Else
If xlSht.Cells(I, 1).Value = "Lg" Then
LgCol = I
End If
End If
End If
Next I
Or as:
For I = 1 To 8 Step 1
If xlSht.Cells(I, 1).Value = "ID" Then
FCol = I
ElseIf xlSht.Cells(I, 1).Value = "L" Then
LCol = I
ElseIf xlSht.Cells(I, 1).Value = "Lg" Then
LgCol = I
End If
Next I