Programming DBA Jobs in Stored procs - oracle

Question

I am a little new to programming, so any help is appreciated.
Find below the code of my stored proc to delete a table and also create a DBA job which will run on a hourly basis.
CREATE OR REPLACE procedure DELETE_My_TABLE(myschema varchar2) as
BEGIN
BEGIN
execute immediate 'delete from '||myschema||'.mytable where clause;';
END;
BEGIN
DBMS_SCHEDULER.create_program (
program_name => 'DELETE_My_TABLE',
program_type => 'STORED_PROCEDURE',
program_action => 'execute DELETE_My_TABLE(myschema)',
number_of_arguments => 1,
enabled => FALSE,
comments => 'Program to delete table using a stored procedure.');
DBMS_SCHEDULER.define_program_argument (
program_name => 'DELETE_My_TABLE',
argument_name => 'myschema',
argument_position => 1,
argument_type => 'VARCHAR2',
default_value => 'myschema');
DBMS_SCHEDULER.enable (name => 'DELETE_My_TABLE');
END;
BEGIN
DBMS_SCHEDULER.create_schedule (
schedule_name => 'DELETE_My_TABLE',
start_date => SYSTIMESTAMP,
repeat_interval => 'freq=hourly; byminute=0',
end_date => NULL,
comments => 'Hourly Job to purge SEARCH_TEMP_TABLE');
END;
END;
/
Issues:
ERROR at line 1:
ORA-00920: invalid relational operator
ORA-06512: at "MYSCHEMA.DELETE_My_TABLE", line 4
ORA-06512: at line 1
Will the logic (and syntax) work?

Answer 1

One issue I can see is that you need to take the semi-colon out of the EXECUTE IMMEDIATE string:
execute immediate 'delete from '||myschema||'.mytable where clause';
^^
Removed from here
thought I suspect this won't solve your immediate problem, which looks like it's your BEGIN ...END blocks.

Answer 2

For the Oracle Scheduler you normally create a program, once. Next you create a job that has the program as action. You can give that job a schedule like you specified in your code but you have to choose. Either you create a schedule and have the job use it, or you give the job it's own repeat interval.
I happen to know about a book ( Mastering Oracle Scheduler ) that I wrote that could be very helpful.