I have a file with Version resource that File vesrion/Product version fields are filled. I need to retrieve Product version via BAT file. Example, I have File with ProductVersion 1.0.1 in the output of bat file I wan't to have string "101" or "1.0.1"
You can use sigcheck tool which is part of Sysinternals Suite since filever is quiet old, e.g.
$ sigcheck.exe -q -n app.exe
5.0.0.1241
By specifying -q (quiet) and -n, it'll show you only the file version number.
How to use the Filever.exe tool to obtain specific information about a file in Windows
From what I gather about filever's output it's always in columns and you want the fifth column (version). So a simple for should suffice:
for /f "tokens=5 delims= " %%v in ('filever myFile.dll /b') do echo %%v
For dummy's like me there is one correction in the above statement to get the value of product version it would be like:
for /f "tokens=5 delims= " %%v in ('filever myFile.dll /b /v') do echo %%v
the /v parameter was missing and I am unable to get the correct value.
To read version from resource RC-file you can use:
for /F "tokens=3" %%a in ( 'findstr ProductVersion YourProgram.rc' ) do set VERSION=%%~a
Related
I'm trying to scan a text file, and wanted to get the version only
I've tried running this
>for /f "usebackq tokens=2 delims=, " %i in (`findstr /l "version" "C:\Test\myfiles\package.text"`) do echo %i
however it's returning an entry twice
echo "4.2.20"
"4.2.20"
The text file has this format
"version": "4.2.20",
how to use findstr to return only the exact version in this format 4.2.20
Thank you!
Q:is there a way to return on the following format 4.220 (remove the last decimal/period?)
A: there is. Split the version string (handle it like a filename, so the first part (%%~ni, "Filename") gets anything before the last dot and the second part (%%~xi, "extension" gets the last dot and everything after). Then simply remove the dot from the "extension" and merge the two substrings:
#echo off
setlocal
for /f "usebackq tokens=2 delims=, " %%i in (`findstr /l "version" "C:\Test\myfiles\package.text"`) do (
set "major=%%~ni"
set "minor=%%~xi"
)
set "version=%major%%minor:.=%"
echo method 1: %version%
set "version=%major%%minor:~1%"
echo method 2: %version%
It is possible to do it in a single command line, but as you need delayed expansion, this gets ugly, hard to read and maintain. Not worth the effort, except you have a special requirement for that, IMHO. So (because you also tagged batch-file) I stuck to that.
I have a deployment that installs a driver and I want to provide the ability to uninstall.
Im leveraging the PNPUTIL.exe tool.
I know the syntax to delete and uninstall the driver, ex:
pnputil.exe /delete-driver oem103.inf /uninstall /force
But my issue, is the oem*.inf number designation is random on each machine, so I can't hard code the .inf into the command and call it a day.
pnputil has /enum-driver switch that will give you details of all the drivers in the DriverStore. Among the line items is the original name of .inf (something I can work with) and the oem# associated with it.
So what I need help with is scripting something that will enumerate the drivers pipe the results to the command to be able the run /delete-drive and /uninstall switches
I tried messing with the Find and FindSTR commands, but it only returned the one line which was the name of the original .inf. I need the OEM# associated with original name of the .inf to be piped to the command.
In the output of pnputil, the desired oemXX.inf is one line above the Original Name.
So numerate the output, look for the original name and subtract one from the line number. This is the line number where you find the oemXX.inf.
Then find that line and extract the oemXX string. (the for %%b is to get rid of the leading spaces)
#echo off
setlocal
set "Orig=rt640x64.inf"
pnputil /enum-drivers |findstr /n "^" > pnputil.txt
for /f "delims=:" %%a in ('findstr /c:" %Orig%" pnputil.txt') do set /a line=%%a-1
for /f "tokens=3 delims=:" %%a in ('findstr /b "%line%:" pnputil.txt') do for %%b in (%%a) do set "oem=%%b"
echo "%oem%"
Note: the output of pnputil is language-dependent, but this code doesn't look for words (except the "Original name" of course) but for line numbers, so it should work on all languages.
I'm trying to get a side-by-side file path and file name in a text file so I can make inserting into a database easier. I've taken a look at other examples around SO, but I haven't been able to understand what is going on. For instance, I saw this batch file to append file names to end of lines but figured that I shouldn't ask for clarification because it's 1.5 years old.
What I have is a text file of file paths. They look like this:
\\proe\igi_files\TIFFS\AD\1_SIZE_AD\1AD0019.tif
What I want it to look like is this:
1AD0019.tif \\proe\igi_files\TIFFS\AD\1_SIZE_AD\1AD0019.tif
so that I can insert it into a database. Is there an easy way to do this on Windows via Batch files?
No batch file required. From the command line:
>"outputFile.txt" (for /f "usebackq eol=: delims=" %F in ("inputFile.txt") do #echo %~nxF %~dpF)
But that output format is risky because file and folder names can contain spaces, so it may be difficult to determine where the file name ends and the path begins. Better to enclose the file and path within quotes.
>"outputFile.txt" (for /f "usebackq eol=: delims=" %F in ("inputFile.txt") do echo "%~nxF" "%~dpF")
if done within a batch file, then percents must be doubled.
#echo off
>"outputFile.txt" (
for /f "usebackq eol=: delims=" %%F in ("inputFile.txt") do echo "%%~nxF" "%%~dpF"
)
You should read the built in help for the FOR command. Type help for or for /? from a command prompt to get help. That strategy works for pretty much for all commands.
In powershell, this little script should do the trick. In the first line, just specify the name of the text file that contains all the file paths.
$filelist="c:\temp\filelist.txt"
foreach($L in Get-Content $filelist) {
$i = $L.length - $L.lastindexof('\') -1
$fname=$L.substring($L.length - $i, $i)
echo ($fname + ' ' + $L)
}
If you don't have powershell installed on your machine, check out http://technet.microsoft.com/en-us/library/hh847837.aspx.
#ECHO OFF
SETLOCAL
(
FOR /f "delims=" %%i IN (yourfile.txt) DO ECHO %%~nxi %%i
)>newfile.txt
GOTO :EOF
No big drama - all on one active line, but spaced for clarity
I'm trying to remove the first 10 characters from multiple lines inside a text file using a batch script, then output the results to a new file. I ran across this and it got me pointed in the right direction but the final output isn't working.
Here's what I've got so far:
setLocal EnableDelayedExpansion
CSCRIPT /nologo %windir%\System32\prnport.vbs -l > c:\IPPorts.txt
type c:\IPPorts.txt | findstr IP_ > c:\IPPorts2.txt
for /f "tokens=*" %%a in (c:\IPPorts2.txt) do (set line=%%a set chars=!line:~10! > c:\IPPorts3.txt)
for /f "delims=" %%x in (c:\IPPorts3.txt) do CSCRIPT /nologo %windir%\System32\prnport.vbs -d -r %%x
The 2nd line exports a list of printer ports to a file named IPPorts.txt. The 3rd finds the lines with "IP_" in them and exports to IPPorts2.txt. The 4th line is supposed to remove unneeded text (which it isn't doing) and export to IPPorts3.txt. And the last line will take the results from IPPorts3.txt and then delete those ports.
IPPorts.txt is as follows:
Server name
Port name IP_172.20.51.11
Host address 172.20.51.11
Protocol RAW
Port number 9100
SNMP Disabled
These lines are repeated for every port, of which there are several. Since I only need the line containing the port name, IPPorts2.txt looks like this:
Port name IP_172.20.51.11
Port name IP_172.20.52.58
Port name IP_172.20.53.16
Port name IP_172.20.54.19
Port name IP_172.20.55.15-1
Port name IP_172.20.55.15
Port name IP_172.20.55.11
Where I'm having trouble is removing the "Port name " portion of the lines (the first 10 characters). I want the output to read on each line as "IP_X.X.X.X". The problem is the 3rd file is always empty.
Where am I going wrong? Any help is greatly appreciated.
EDIT:
This is further down under Endoro's answer, but I thought it might be nice to post the answer here. Here's what I changed the 4th line to:
for /f "tokens=* delims=" %%c in ('type c:\IPPorts2.txt') do (
set LINE=%%c
>> c:\IPPorts3.txt echo !LINE:~10!
)
This has corrected my problems. Thanks everyone!
try this:
(for /f "tokens=3" %%i in (IPPorts2.txt) do #echo %%i)>IPPorts3.txt
Script to get directory name out of DIR command output :
...
20/09/2014 01:23 [DIR] some1
21/09/2014 02:34 [DIR] some2
22/09/2014 03:45 [DIR] some3
23/09/2014 11:22 [DIR] some4
...
We want it to be:
some1
some2
some3
some4
...
Code :
#FOR /f "tokens=4" %%D IN (i:\test.txt) DO #( echo %%D ) >> result.txt
In your case tokens=3, not perfect but does the job with few lines manually edited in the result.
(For /f "tokens=3delims= " %%i in (ipports2.txt) do echo %%i) >ipports3.txt
should do it for you.
The paretheses are important - ensure that the file is created anew. If omitted, will only generate the last line.
Simply uses the delimiter [space] to tokenise the string on each line into token1=Port, token2=Name and sets %%i to each token3 in turn.
The following isn't really a different solution but merely a suggestion to simplify your script by reducing the number of output files.
In fact, it is possible to exclude all of them from the script, unless you need to keep them for history.
Basically, the idea is first to apply FINDSTR directly to the output of prnport.vbs:
CSCRIPT /nologo %windir%\System32\prnport.vbs -l | FINDSTR "IP_"
then apply a loop directly to the output of FINDSTR (note the single quotation marks around the piped command line, as well as the escaped |):
FOR /F "tokens=3" %%A IN (
'CSCRIPT /nologo %windir%\System32\prnport.vbs -l ^| FINDSTR "IP_"'
) DO …
and call prnport.vbs with another set of arguments in that same loop:
FOR /F "tokens=3" %%A IN (
'CSCRIPT /nologo %windir%\System32\prnport.vbs -l ^| FINDSTR "IP_"'
) DO (
CSCRIPT /nologo %windir%\System32\prnport.vbs -d -r %%A
)
The tokens option of a FOR /F loop specifies which token (or field) to take based on a specific delimiter or set of delimiters. The default set of delimiters is a space, a comma, a tab. Your Port name IP_whatever lines conveniently consist of exactly three tokens and the third one is what you are after, hence "tokens=3" in the options.
So, as you can see, no output files, the necessary value is extracted and passed to the target command in the same iteration.
CMD Q: I want to remove the extension of a filename.
It is actually a complete path, like C:/Me/My/Path/filename.xxxx
i know that the extension has 4 chars, like shown in example above.
How can i get rid of the extension?
Thanks.
In terminal:
set file=C:/Me/My/Path/filename.1234
for /F "tokens=*" %A IN ("%file%") DO #echo variable ^%file^%: %~dpnA
In batch file:
#echo off
set file=C:/Me/My/Path/filename.1234
echo If called with path as batch parameter: %~dpn1
for /F "tokens=*" %%A IN ("%file%") DO echo variable %%file%%: %%~dpnA
This does the trick:
#echo off
set fullpath= C:/Me/My/Path/filename.xxxx
set withoutext=%fullpath:~0,-5%
echo %withoutext%
The result is:
c:\>test
C:/Me/My/Path/filename
In this example script the last 5 characters are removed from the variable %fullpath%.
The syntax is explained here: http://www.computerhope.com/forum/index.php?topic=78901.0
In cases where the length of the extension is unknown this would not work.
ren C:/Me/My/Path/filename.xxxx filename.
this should do it (the "." at the end is important)