Is there a way to change the properties of a file? I'm trying to run selenium tests in parallel, with Spring and Jetty, so I'm trying to configure the url of the database, the port of the jettyserver and the port of the selenium server. So that I'm able to initialize two or more servers where the tests can run on.
My server.properties file contains this:
jdbc.url=jdbc:hsqldb:hsql://localhost/bibliothouris_scenario
jetty.port=8081
seleniumServer.port=4444
I can read those properties with a PropertyPlaceholderConfigurer, and I need the database URL, jettyport and seleniumserver port to be flexible.
I have declared them like this:
In my applicationContext.xml:
<bean class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer">
<property name="location">
<value>classpath:server.properties</value>
</property>
</bean>
<bean id="dataSource" destroy-method="close" class="org.apache.commons.dbcp.BasicDataSource">
<property name="driverClassName" value="org.hsqldb.jdbcDriver" />
<property name="url" value="${jdbc.url}" />
<property name="username" value="sa" />
<property name="password" value="" />
</bean>
In the serverContext.xml file:
<bean class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer">
<property name="location">
<value>classpath:server.properties</value>
</property>
</bean>
<bean class="com.~companyName~.bibliothouris.jetty.JettyServer" init-method="start" destroy-method="stop">
<constructor-arg value="${jetty.port}" />
<constructor-arg ref="dataSource" />
</bean>
<bean class="org.openqa.selenium.server.SeleniumServer" init-method="start" destroy-method="stop">
<constructor-arg>
<bean class="org.openqa.selenium.server.RemoteControlConfiguration">
<property name="port" value="${seleniumServer.port}" />
<property name="singleWindow" value="true" />
<property name="timeoutInSeconds" value="10" />
</bean>
</constructor-arg>
</bean>
<bean class="com.thoughtworks.selenium.DefaultSelenium" init-method="start" destroy-method="stop" lazy-init="true">
<constructor-arg>
<bean class="com.thoughtworks.selenium.HttpCommandProcessor">
<constructor-arg value="localhost" />
<constructor-arg value="${seleniumServer.port}" />
<constructor-arg value="*firefox c:/~companyname~/firefox/firefox.exe" />
<constructor-arg value="http://localhost:${jetty.port}" />
</bean>
</constructor-arg>
</bean>
When I change the data in server.properties the selenium tests run on the right servers with the right ports, without failures.
So now I'm looking for a method to change the properties in the server.properties file.
Kind regards and thanks in advance
I solved this by having a flag in my build process (I'm using Maven) that chose which property file to include in the final war. This way you can include different artifacts (different property files) with different properties without having to mess with the low level property support of Spring.
If you do need to do this is Spring only, I would recommend going for a Java based configuration, where you can get and set the properties by in code not in XML.
Is there a way to change the
properties of a file?
No, but you could solve this in the following ways.
Split the properties into jdbc.properties (for applicationContext.xml) and test.properties (for serverContext.xml)
override server.properties via a src/test/resources resource
use system properties in addition to server.properties (use PropertyPlaceholderConfigurer.setSystemPropertiesMode for this)
Thanks for the help guys, without your info, I couldn't find my own solution. Here it is:
try {
Properties props = new Properties();
FileInputStream fileInputStream = new FileInputStream(
"C:\\~CompanyName~\\workspace\\bibliothouris\\infrastructure\\src\\main\\resources\\server.properties");
props.load(fileInputStream);
fileInputStream.close();
props.setProperty("seleniumServer.port", "4445");
FileOutputStream fileOutputStream = new FileOutputStream(
"C:\\~CompanyName~\\workspace\\bibliothouris\\infrastructure\\src\\main\\resources\\server.properties");
props.store(fileOutputStream, "");
fileOutputStream.close();
} catch (Exception e) {
e.printStackTrace();
}
I've wrote this piece of code in a testclass, now I have to create a method of it, which takes a few arguments (the URL, jettyport and seleniumport). And I have to change the path to a relative one.
Thanks for the help!
Related
My application has applicationContext.xml with entityManagerFactory bean defined as :
<bean id="entityManagerFactory"
class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
<property name="packagesToScan" value="org.xyz" />
**<property name="dataSource" ref="poolDVLDataSource" />**
<!--<property name="dataSource" ref="poolPRDDataSource" /> -->
<property name="jpaVendorAdapter">
<bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter">
<property name="databasePlatform"
value="org.hibernate.dialect.Oracle10gDialect" />
<property name="database" value="ORACLE" />
<property name="showSql" value="false" />
</bean>
</property>
</bean>
and data source references as
<bean id="poolPRDDataSource" class="org.apache.commons.dbcp.BasicDataSource">
<property name="driverClassName" value="oracle.jdbc.driver.OracleDriver"/>
....
</bean>
and
<bean id="poolDVLDataSource" class="org.apache.commons.dbcp.BasicDataSource">
<property name="driverClassName" value="oracle.jdbc.driver.OracleDriver"/>
....
</bean>
I'm using gradle for build. Depending on the deploying environment, is there a way to replace the dataSource ref to either "poolDVLDataSource" or "poolPRDDataSource" dynamically?
ReplaceRegExp ant task should fix your issue. https://ant.apache.org/manual/Tasks/replaceregexp.html
Sample gradle code below:
ant.replaceregexp(match:'existingName', replace:'newName', byline:true) {
fileset(dir: 'WebContent/WEB-INF', includes: 'applicationContext.xml')
}
I wouldn't be solving this with gradle, you should solve this in spring
You can use spring's <import /> with a ${parameter} so that the actual file is decided at runtime. For instance you could split your service configuration into two files. The "internal" file could contain all the services implemented by your application and the "external" config file could contain external config including database connections, JMS connections, mail servers etc, etc.
Eg: applicationContext.xml
<context:property-placeholder/>
<import resource="classpath:internal-services.xml" />
<import resource="classpath:${environment}/external-services.xml" />
For production, you can pass environment=prod as a system property and load the prod/external-services.xml which contains the "real" services. For tests you could pass environment=mock and load mock/external-services.xml which contains mocks of all of your external services.
I’m using Spring 3.2.11.RELEASE. I currently have the following set up in my application context file for the purposes of loading a cron trigger based off a schedule defined in a properties file (the property = cron.schedule) …
<bean id="localPropertyConfigurer"
class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer">
<property name="location">
<value>classpath:application.properties</value>
</property>
</bean>
…
<bean id="updateResourcesJob" class="org.springframework.scheduling.quartz.MethodInvokingJobDetailFactoryBean">
<property name="targetObject" ref="myService" />
<property name="targetMethod" value="myMethod" />
<property name="concurrent" value="true" />
</bean>
<bean id="updateResourcesCronTrigger" class="org.springframework.scheduling.quartz.CronTriggerBean">
<property name="jobDetail" ref="myJob" />
<property name="cronExpression" value="${cron.schedule}" />
</bean>
My question is, I would like to create an XML configuration in my context file that allows me to edit my properties file and have everything automatically reloaded without having to restart my server or re-deploy my application. I have read several places about Apache Commons Configuration, but I can’t figure out how to take the above and rewrite an XML config that would utilize the configuration.
Thanks for any help, - Dave
I've got two properties files:
environment.properties:
- project.host.db3.database.name=oracle
application.properties:
- database.name=${project.host.db3.database.name}
The first one represents the environment variables and the second one the properties to be used in a spring project, in this configuration i try to set the environment.properties but of course it doesn't work:
<bean id="systemPropertiesLoader"
class="org.springframework.beans.factory.config.MethodInvokingFactoryBean">
<property name="targetObject" value="#{#systemProperties}" />
<property name="targetMethod" value="putAll" />
<property name="arguments">
<util:properties location="classpath:environment.properties" />
</property>
</bean>
<bean id="propertyPlaceholderConfigurer"
class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer"
depends-on="systemPropertiesLoader">
<property name="locations">
<list>
<value>classpath:application.properties</value>
</list>
</property>
<!-- bean using database.name -->
Is it doable?, and if not, how do people have agnostic properties in their projects (like database.name), and only one file (war, jar, etc.) to be deployed?
Well, it seems it's doable for beans xml defined as long as you define your properties it like this:
<bean id="propertyPlaceholderConfigurer"
class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer"
depends-on="systemPropertiesLoader">
But if you ever try to access the properties from a servlet:
this.getClass().getClassLoader().getResourceAsStream("application.properties");
chances are you get this:
bad port configuration: ${project.host.db3.database.port}
java.lang.NumberFormatException: For input string: "${project.host.db3.database.port}"
In answer to yorkw, now i can have the same war to be deployed in several environments and configure the host with -Denvironment=development, so i can deploy a properties file for development, production, etc. and simply use:
<bean id="systemPropertiesLoader"
class="org.springframework.beans.factory.config.MethodInvokingFactoryBean">
<property name="targetObject" value="#{#systemProperties}" />
<property name="targetMethod" value="putAll" />
<property name="arguments">
<util:properties location="classpath:**${environment}/**environment.properties" />
</property>
</bean>
Otherwise i should have the application.properties substituted before deployment for every environment. I'm sure there are better solutions than this.
I am really stuck on this one... Help! :)
I am using j2ee:jndi lookup for a property file. The following works fine:
<bean class="org.springframework.core.io.FileSystemResource">
<constructor-arg>
<jee:jndi-lookup id="myProps" jndi-name="myProps" resource-ref="true" />
</constructor-arg>
</bean>
However, I want to handle the case where the jndi lookup fails but will fall back on a default file located in WEB-INF/classes folder. If I use the default-value as below, the webapp throws an exception complaining that it cannot find the file "classpath:myprops.properties"
<bean class="org.springframework.core.io.FileSystemResource">
<constructor-arg>
<jee:jndi-lookup id="myProps" jndi-name="myProps" resource-ref="true"
default-value="classpath:myprops.properties" />
</constructor-arg>
</bean>
However, if I hard-code a specific path for default-value, then it works fine, but that is unacceptable as a final solution.
Thus, my issue is how to use "classpath:" so that it gets properly resolved?
This is the overall usage I'm employing:
<bean id="authServerProperties"
class="org.springframework.beans.factory.config.PropertiesFactoryBean">
<property name="ignoreResourceNotFound" value="true"/>
<property name="location">
<bean class="org.springframework.core.io.FileSystemResource">
<constructor-arg>
<jee:jndi-lookup id="myProps" jndi-name="myProps" resource-ref="true"
default-value="classpath:myprops.properties" />
</constructor-arg>
</bean>
</property>
.....
</bean>
Let Spring use its built-in PropertyEditor support to decide on the type of resource, rather than supplying an explicit FileSystemResource bean as this won't work with classpath resources (it needs to be configured with a path on the file system). Instead you should use something like
<bean id="authServerProperties"
class="org.springframework.beans.factory.config.PropertiesFactoryBean">
<property name="ignoreResourceNotFound" value="true"/>
<property name="location" ref="myProps" />
</bean>
<jee:jndi-lookup id="myProps" jndi-name="myProps" resource-ref="true"
default-value="classpath:myprops.properties"/>
Here we are setting the location to be a string value and allowing Spring to convert that to the appropriate resource type, so if you have
<env-entry>
<env-entry-name>myProps</env-entry-name>
<env-entry-type>java.lang.String</env-entry-type>
<env-entry-value>file:///Users/something/myProps.properties</env-entry-value>
</env-entry>
in your web.xml, it will use a UrlResource with the given file URL, otherwise it will create a ClasspathResource to look for the file myprops.properties.
I have created a JAR that I need to use in my WEB-APP. Both are created with spring framework. I would like to load a .properties file outside the JAR file, in the main context of the web-application. And I want to do it with the facilities that Spring offers us.
I've tried to do something like this in my spring.xml file inside the JAR:
<bean class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer">
<property name="location">
<value>/WEB-INF/classes/my.properties</value>
</property>
</bean>
<bean class="org.springframework.scheduling.quartz.SchedulerFactoryBean">
<property name="triggers">
<bean id="cronTrigger" class="org.springframework.scheduling.quartz.CronTriggerBean">
<property name="jobDetail" ref="myJob" />
<property name="cronExpression" value="${my.cronExpression}"/>
</bean>
</property>
</bean>
Trying to load my.cronExpression from my.properties file. But without any success.
I always get this error:
Could not resolve placeholder 'my.cronExpression'.
I've tried to change the location with many variants, using classpath:/WEB-INF/classes/my.properties etc...
But I'm not able to load the configuration file.
Thanks for your help.
Use classpath:my.properties - /WEB-INF/classes is root of your classpath.
Try declaring it as follows:
<bean class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer">
<property name="location">
<value>/WEB-INF/classes/my.properties</value>
</property>
<property name="ignoreUnresolvablePlaceholders">
<value>true</value>
</property>
</bean>
I have gone through your code and want you to try this code snippet
It works well for me :)
<bean id="placeholderProperties"
class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer">
<property name="location" value="file:/WEB-INF/classes/my.properties" />
<property name="systemPropertiesModeName" value="SYSTEM_PROPERTIES_MODE_OVERRIDE" />
<property name="ignoreUnresolvablePlaceholders" value="true" />
<property name="order" value="1" />
</bean>