problem in using awk - shell

Question

i couldn't solve this. when i execute this program i get the following error
" line 7: unexpected EOF while looking for matching `'' "
a=115292a1504606846976ULL
b=2
if [ "$b" = "2" ]; then
var1=`echo $a | awk -F"U" '\
{
var2=`echo $var1 | awk -F"a"
{print " "$2}'`
}\
fi
Update: from other, recently closed question
To be more specific, this is my project code
if [ "$FORMAT" = "java" ]; then
cat $INPUT_FILE | awk -F":" '\
/^$/ { print "" }\
/^\/\/.*/ { print " "$0}\
/:string:/ { print " public static final String "$1" = "$3";" }\
/:char:/ { print " public static final char "$1" = "$3";" }\
/:ullong:/ { print " public static final long "$1" = "$3";" }\
/:ulong:/ { print " public static final int "$1" = "$3";" }\
/:long:/ { print " public static final int "$1" = "$3";" }\
' >> $CONST_FILE
fi;
Now i need to truncate $3 (this value is actually read from another file) into two parts(only for ullong). lets say
$3=1256985361455ULL
i need to truncate into 1256985361455 and ULL. (only when it is ullong)
please help me out in this issue.
i tried using another awk inside the the following, but ended up in chaos.
/:ullong:/ { print " public static final long "$1" = "$3";" }\

Answer 1

If you expect the value of $3 for the ullong records to be something like "1256985361455ULL" then
/:ullong:/ {
sub(/ULL$/, "", $3)
print " public static final long "$1" = "$3";"
}

Answer 2

Your quoting problem is because once you start a back-quoted command, it continues until the next back-quote. This is your code as shown above, except I've removed the blank lines.
a=115292a1504606846976ULL
b=2
if [ "$b" = "2" ]; then
var1=`echo $a | awk -F"U" '\
{
var2=`echo $var1 | awk -F"a"
{print " "$2}'`
}\
fi
(Back-quotes '`' are hard to show in in-line Markdown.)
The line var1= line starts a back-quoted expression, which stops at the next unescaped back-quote, which is the one after var2=. It then reads the rest of that line, and on the following line, encounters a single quote. When it looks for the following single quote, there is none - so it reports an error. You can demonstrate this is what goes on in steps:
a=115292a1504606846976ULL
b=2
if [ "$b" = "2" ]; then
var1=`echo $a | awk -F"U" '\
{
var2=\`echo $var1 | awk -F"a"
{print " "$2}'`
}\
fi
The script above has an escape (backslash) before the back-quote after var2=, so now the command in back-quotes extends to the back-quote after the print line. This still isn't valid shell; the line with }\ combines with the fi to make a command name }fi, so you still get an unexpected EOF error - because the fi for the end of the if is missing. Modify the script again:
a=115292a1504606846976ULL
b=2
if [ "$b" = "2" ]; then
var1=`echo $a | awk -F"U" '\
{
var2=\`echo $var1 | awk -F"a"
{print " "$2}'`
#}\
fi
This comments out the close brace, and the shell script is now 'valid'; it is awk's turn to start complaining about the invalid script it is given.
++ awk -FU '{
var2=`echo $var1 | awk -F"a"
{print " "$2}'
awk: syntax error at source line 2
context is
>>> var2=` <<<
awk: illegal statement at source line 2
awk: illegal statement at source line 2
missing }
Other people have given you roughly what you need as an answer. I'd probably use Perl to do the splitting up (and I suspect I could lose the intermediate array #x if I spent enough time on it, producing a script of line noise):
a=115292a1504606846976ULL
b=2
if [ "$b" = "2" ]
then var1=$(echo $a | perl -ne '#x=split /[aU]/; print "$x[1]\n"')
fi
However, you can also do it in one line with awk, thus:
a=115292a1504606846976ULL
b=2
if [ "$b" = "2" ]
then var1=$(echo $a | awk -Fa '{sub("ULL","",$2); print $2}')
fi
This splits the input on the 'a' instead of the 'U'; it then removes the 'ULL' from the second field and prints it. If you want to split on 'U', then you use:
a=115292a1504606846976ULL
b=2
if [ "$b" = "2" ]
then var1=$(echo $a | awk -FU '{sub("[0-9]+a", "", $1); print $1}')
fi
The regular expression in the sub is marginally more complex this way.

Answer 3

Not sure exactly what you are trying to do, but this slight re-write printed out the middle part of a (which is I think what you wanted)
> cat moo.sh
a=115292a1504606846976ULL
b=2
if [ "$b" = "2" ]; then
var1=`echo $a | awk -F"U" '{print $1}'`
var2=`echo $var1 | awk -F"a" '{print " "$2}'`
echo $var2
fi
> sh moo.sh
1504606846976

Answer 4

You can't do shell commands inside awk except to make system calls. without you telling us what you are trying to achieve
#!/bin/bash
a=115292a1504606846976ULL
b=2
case "$b" in
2 )
a=${a%U*}
echo ${a#*a} # I assume you want to get 1504606846976
esac

Answer 5

a=115292a1504606846976ULL
b=2
if [ "$b" = "2" ]; then
var1=`echo $a | awk -F "U" '{print $1}' | awk -F "a" '{print $2}'`
fi