HI I have a codeigniter controller called CIcontroller and I have a method say redirectmethod
in the redirectmethod i have some code and then i do this
$data['redirect_page'] = 'page_name';
$this->load->view('template_view',$data);
the template view basically loads header footer and the corresponding view as specified by the data parameter
Now everything works fine but my url has value http:\\blabla\CIcontroller\redirectmethod instead of http:\\blabla\page_name
could anyone help me fix this thing
You need to emit a Location header to tell the browser to load a different page. See redirect in the url helper.
Related
Currently my users must get the visit form given by Route::get then fill it in to get back a result view given by Route::post. I need to create a shareable link such as /account/search/vrm/{vrm} where {vrm} is the VRM that is usually filled in on the form page. This VRM then needs to redirected to Route::post as post data. This needs to be done by my controller. How can I do this in my controller?
Routes:
// Shows form view
Route::get('/account/search', 'User\AccountController#getSearch')->name('account.search');
// Shows result view
Route::post('/account/search', 'User\AccountController#runSearch');
// Redirect to /account/search as POST
Route::get('/account/search/vrm/{vrm}', function($vrm) { ???????? });
POSTs cannot be redirected.
Your best bet is to have them land on a page that contains a form with <input type="hidden"> fields and some JavaScript that immediately re-submits it to the desired destination.
You can redirect to a controller action or call the controller directly, see the answer here:
In summary, setting the request method in the controller, or calling a controller's action.
Ps: I don't want to repeat the same thing.
For those who comes later:
If you are using blade templating engine for the views, you can add '#csrf' blade directive after the form starting tag to prevent this. This is done by laravel to prevent cross site reference attacks. By adding this directive, you can get around this.
return redirect()->route('YOUR_ROUTE',['PARAM'=>'VARIABLE'])
I have a grant_requests controller and I want all all of the actions to show up as "sponsored_licences" in the url.
My routes file has the following:
resources :sponsored_licences, as: :grant_requests, controller: :grant_requests
Going to new_grant_request_path works as expected; it routes to the sponsored_licenses/new url when the form is valid it posts correctly to the database.
However, when there are form validation errors and I render new_grant_request_path in the controller I get the Missing template error.
Redirecting will not work (I want to save the form data, etc.) and I am at a loss on how to correctly render the form. Is there something else I have to add to my routes file?
Try render :new if you're in the GrantRequests controller, otherwise, render "grant_requests/new"
I have an extension which should give the users (logged in as an Admin in the magento backend) the ability to change some configs in the frontend area. I want to have a link in the frontend which loads the config area via ajax and gives the user the possibility to edit&save this config in the loaded div. I want to use the magento backend forms for this so i don't have to code the forms myself.
My current approach has the link on the pages and loads via ajax the correct backend page (e.g. System > Configuration > Design). For this approach I created a Controller which extends the Mage_Adminhtml_Controller_Action. This Controller get the params from the ajax request and uses an action (like the editAction of the class Mage_Adminhtml_System_ConfigController) to get the right config page in the backend.
My Problems are:
- showing only the correct Area (I just want the user to edit only the section "themes" under System > Configuration > Design) everything else should be not available... so how to remove all the information around this config section?
The form needs the JS-variable Form_Key. How to get the current Form_Key (in the frontend)?
After the ajax has loaded the content the form doesnt get initialized correctly. So if I'm trying to submit the form my firebug says "JS-Error: configForm is not defined". How to solve this form initialising ? Any ideas?
I really hope anybody here can give me a hint how to solve this problems to get the backend config work in the frontend.
This is untested, but it should be enough to get you on the right track:
Output only a specific block
In the frontend most blocks are instantiated via layout XML. In the adminhtml area this is different, so you need to work with PHP instantiation much more.
In your AJAX action I assume you are currently calling loadLayout() and renderLayout().
To only output a specific section use this instead:
public function yourAjaxAction()
{
// assuming the required config section is set in the AJAX request
$sectionCode = $this->getRequest()->getParam('section');
$sections = Mage::getSingleton('adminhtml/config')->getSections();
$blockName = (string)$sections->frontend_model;
if (empty($blockName)) {
$blockName = Mage_Adminhtml_Block_System_Config_Edit::DEFAULT_SECTION_BLOCK;
}
$block = $this->getLayout()->createBlock($blockName)->initForm();
// Set the AJAX response content
$this->getResponse()->setBody($block->toHtml());
}
The form key
The form key can be fetched via
Mage::getSingleton('core/session')->getFormKey()
It must be present in the form posted back to the server. You can use the following code to create a HTML hidden field with the formkey:
// If loadLayout() was called:
$formkeyHtml = Mage::app()->getLayout()->getBlock('formkey')->toHtml();
// If working without layout XML:
$formkeyHtml = Mage::app()->getLayout()->createBlock('core/template', 'formkey')
->setTemplate('formkey.phtml') // adminhtml theme formkey
//->setTemplate('core/formkey.phtml') // frontend theme formkey
->toHtml();
Add configForm JavaScript
The configForm variable is an JS varienForm object of the DOM element containing the config fields.
It is instantiated using:
// config_edit_form is the CSS id
configForm = new varienForm('config_edit_form');
The varienForm declaration is in the file js/varien/form.js.
There also is some additional javascript used by the system configuration. Magento always adds in these blocks to set up the system config JS environment:
Mage::app()->getLayout()->getBlock('js')->append(
$this->getLayout()->createBlock('adminhtml/template')
->setTemplate('system/shipping/ups.phtml')
);
Mage::app()->getLayout()->getBlock('js')->append(
$this->getLayout()->createBlock('adminhtml/template')
->setTemplate('system/config/js.phtml')
);
Mage::app()->getLayout()->getBlock('js')->append(
$this->getLayout()->createBlock('adminhtml/template')
->setTemplate('system/config/applicable_country.phtml')
);
I hope that gets you started.
I am trying to use CodeIgniter and jQuery-ui dialog to create a modal window with form to update user information.
The process should be like:
1. Press a button on a view page.
2. A modal window pops up.
3. Inside the window is a form that a user can fill.
4. If the user filled something before, the information should be shown in corresponding field
5. Click the update button on the modal window to save the changes to database.
Can anyone provide a good sample of this process?
I used ajax to pass the data but it didn't work when I was trying to update the data to the database. It would be nice if an example of how to pass data from ajax to php and how php handle that.
Thanks,
Milo
well the jquery bit for post(), get(), ajax() works the same in any measure you would normally use it.. key difference here is with CI you can't post directly to a file-name file-location due to how it handles the URI requests. That said your post URL would be the similar to how you would access a view file normally otherwise
ie: /viewName/functionName (how you've done it with controllers to view all along. post, get, ajax doesnt have to end in a extension. I wish I had a better example then this but I can't seem to find one at the moment..
url = '/home/specialFunction';
jQuery.get(url, function(data) {
jQuery("#div2display").html(data);
});
in the case of the above you notice despite it not being a great example that. you have the url with 2 parameters home and specialFunction
home in this case is the controller file for home in the control folder for the home file in views the specialFunction is a "public function" within the class that makes the home controller file. similar to that of index() but a separate function all together. Best way I have found to handle it is through .post() and a callback output expected in JSON cause you can form an array of data on the php side json_encode it and echo out that json_encode and then work with that like you would any JSON output. or if your just expecting a sinlge output and not multiples echoing it out is fine but enough of the end run output thats for you to decide with what your comfortable doing currently. Hopefully all around though this gives you some clairity and hopefully it works out for you.
After processing a jQuery Ajax Post from an HTML form successfully within a Go program, how do I load a new form? I first tried sending the form as the response and the Javascript displayed it, but it did not clear the old (existing) form. I then tried within the HTML Javascript to set the URL using "window.location = 'localhost:8088/MaintForm/'". That resulted in a warning from the browser but did not load the form and did not change the URL. I would like to ideally know both methods - via the Go program acting as a server, and via Javascript. If I manually change the URL, the form loads OK. What I am trying to do is receive a response in Javascript (jQuery Ajax), and then request the new form if the response is positive. I would prefer to do this without changing the URL. As I said above, this partially worked.
You would have to put your original form inside a tag, for example a div, and use your JQuery code to replace the contents of that tag with the new form. This way you are not changing the URL.
This is more of a javascript/JQuery question than a go-specific one.
In javascript:
location.href = '/MaintForm/';
In golang, you can use the http.Redirect function, like this:
http.Redirect(w, r, "/MaintForm/", http.StatusFound)
Please note: this appears to be solved by : I just need to do an "document.write(data);" in Javascript. "Data" contains the new HTML.