Find latest available RVM version number - ruby

Question

I can't seem to find an easy way to identify the latest release of RVM from command line or rvm.beginrescueend.com!?!
I currently type rvm get latest every few days or so to update RVM. If version is same, RVM goes through the download & update process regardless. I'd like to be able to first 'see' if there's an update to get.
Anyone know how? I'm sure I'm missing the obvious...

Answer 1

you could use this one liner to check version:
$ curl -sS https://api.github.com/repos/wayneeseguin/rvm/git/refs/tags | awk -F": |\"" '$2=="ref"{sub(/.*\//,"",$5); print $5}' | sort -V | tail -n 1
1.15.8
or a pure ruby one liner:
$ ruby -ropen-uri -rjson -e 'open("https://api.github.com/repos/wayneeseguin/rvm/git/refs/tags"){|r| puts JSON.parse(r.read).map{|l| l["ref"].gsub(/.*\//,"").split(".").map(&:to_i)}.sort.last.join(".") }'
1.15.8
but the simplest thing to do is:
$ curl https://raw.github.com/wayneeseguin/rvm/stable/VERSION
1.15.8

Answer 2

Curl the rvm repository like this:
curl https://raw.githubusercontent.com/rvm/rvm/master/VERSION

Answer 3

Ok, magic :)
Place this into some .rb file :)
require 'open-uri'
require 'openssl'
regex = Regexp.new(/data-name="([0-9]+).([0-9]+).([0-9]+)"/)
f=open("https://github.com/wayneeseguin/rvm",:ssl_verify_mode => OpenSSL::SSL::VERIFY_NONE)
v = []
f.each_line do |l|
regex.match(l) {|m| v << {:full => m[0], :major => m[1].to_i, :minor => m[2].to_i, :inc => m[3].to_i} }
end
v.sort_by{|m| [m[:major],m[:minor],m[:inc]] }
v=v.first
puts "#{v[:major]}.#{v[:minor]}.#{v[:inc]}"
I have no idea why I just did that.

Answer 4

I used:
$ rvm get head && rvm reload
It ran fast and seemed to do the job. I had installed rvm the week before, rvm 1.15.5, and already there was a newer version, rvm 1.15.8.
This was recommended on:
The Ruby on Rails Tutorial by Michael Hartl
http://ruby.railstutorial.org/ruby-on-rails-tutorial-book#sec-install_ruby