Renaming a file extension without specifying - bash

I am creating a bash shell script that will rename a file extension without having to specify the old file extension name. If I enter "change foo *" to the Terminal in Linux, it will change all file extension to foo.
So lets say I've got four files: "file1.txt", "file2.txt.txt", "file3.txt.txt.txt" and "file4."
When I run the command, the files should look like this: "file1.foo", "file2.txt.foo", "file3.txt.txt.foo" and "file4.foo"
Can someone look at my code and correct it. I would also appreciate it if someone can implement this for me.
#!/bin/bash
shift
ext=$1
for file in "$#"
do
cut=`echo $FILE |sed -n '/^[a-Z0-9]*\./p'`
if test "${cut}X" == 'X'; then
new="$file.$ext"
else
new=`echo $file | sed "s/\(.*\)\..*/\1.$ext/"`
fi
mv $file $new
done
exit

Always use double quotes around variable substitutions, e.g. echo "$FILE" and not echo $FILE. Without double quotes, the shell expands whitespace and glob characters (\[*?) in the value of the variable. (There are cases where you don't need the quotes, and sometimes you do want word splitting, but that's for a future lesson.)
I'm not sure what you're trying to do with sed, but whatever it is, I'm sure it's doable in the shell.
To check if $FILE contains a dot: case "$FILE" in *.*) echo yes;; *) echo no;; esac
To strip the last extension from $FILE: ${FILE%.*}. For example, if $FILE is file1.txt.foo, this produces file1.txt. More generally, ${FILE%SOME_PATTERN} expands to $FILE with a the shortest suffix matching SOME_PATTERN stripped off. If there is no matching suffix, it expands to $FILE unchanged. The variant ${FILE%%SOME_PATTERN} strips the longest suffix. Similarly, ${FILE#SOME_PATTERN} and ${FILE##SOME_PATTERN} strip a suffix.
test "${TEMP}X" == 'X' is weird. This looks like a misremembered trick from the old days. The normal way of writing this is [ "$TEMP" = "" ] or [ -z "$TEMP" ]. Using == instead of = is a bash extension. There used to be buggy shells that might parse the command incorrectly if $TEMP looked like an operator, but these have gone the way of the dinosaur, and even then, the X needs to be at the beginning, because the problematic operators begin with a -: [ "X$TEMP" == "X" ].
If a file name begins with a -, mv will think it's an option. Use -- to say “that's it, no more options, whatever follows is an operand”: mv -- "$FILE" "$NEW_FILE".
This is very minor, but a common (not universal) convention is to use capital letters for environment variables and lowercase letters for internal script variables.
Since you're using only standard shell features, you can start the script with #!/bin/sh (but #!/bin/bash works too, of course).
exit at the end of the script is useless.
Applying all of these, here's the resulting script.
#!/bin/sh
ext="$1"; shift
for file in "$#"; do
base="${file%.*}"
mv -- "$file" "$base.$ext"
done

Not exactly what you are asking about, but have a look at the perl rename utility. Very powerful! man rename is a good start.

Use: for file in *.gif; do mv $file ${file%.gif}.jpg; done
Or see How to rename multiple files

For me this worked
for FILE in `ls`
do
NEW_FILE=${FILE%.*}
NEW_FILE=${NEW_FILE}${EXT}
done
I just want to tell about NEW_FILE=${FILE%.*}.
Here NEW_FILE gets the file name as output. You can use it as you want.
I tested in bash with uname -a = "Linux 2.4.20-8smp #1 SMP Thu Mar 13 17:45:54 EST 2003 i686 i686 i386 GNU/Linux"

Related

Bash script MV is disappearing files

I've written a script to go through all the files in the directory the script is located in, identify if a file name contains a certain string and then modify the filename. When I run this script, the files that are supposed to be modified are disappearing. It appears my usage of the mv command is incorrect and the files are likely going to an unknown directory.
#!/bin/bash
string_contains="dummy_axial_y_position"
string_dontwant="dummy_axial_y_position_time"
file_extension=".csv"
for FILE in *
do
if [[ "$FILE" == *"$string_contains"* ]];then
if [[ "$FILE" != *"$string_dontwant"* ]];then
filename= echo $FILE | head -c 15
combined_name="$filename$file_extension"
echo $combined_name
mv $FILE $combined_name
echo $FILE
fi
fi
done
I've done my best to go through the possible errors I've made in the MV command but I haven't had any success so far.
There are a couple of problems and several places where your script can be improved.
filename= echo $FILE | head -c 15
This pipeline runs echo $FILE adding the variable filename having the null string as value in its environment. This value of the variable is visible only to the echo command, the variable is not set in the current shell. echo does not care about it anyway.
You probably want to capture the output of echo $FILE | head -c 15 into the variable filename but this is not the way to do it.
You need to use command substitution for this purpose:
filename=$(echo $FILE | head -c 15)
head -c outputs only the first 15 characters of the input file (they can be on multiple lines but this does not happen here). head is not the most appropriate way for this. Use cut -c-15 instead.
But for what you need (extract the first 15 characters of the value stored in the variable $FILE), there is a much simpler way; use a form of parameter expansion called "substring expansion":
filename=${FILE:0:15}
mv $FILE $combined_name
Before running mv, the variables $FILE and $combined_name are expanded (it is called "parameter expansion"). This means that the variable are replaced by their values.
For example, if the value of FILE is abc def and the value of combined_name is mnp opq, the line above becomes:
mv abc def mnp opq
The mv command receives 4 arguments and it attempts to move the files denoted by the first three arguments into the directory denoted by the fourth argument (and it probably fails).
In order to keep the values of the variables as single words (if they contain spaces), always enclose them in double quotes. The correct command is:
mv "$FILE" "$combined_name"
This way, in the example above, the command becomes:
mv "abc def" "mnp opq"
... and mv is invoked with two arguments: abc def and mnp opq.
combined_name="$filename$file_extension"
There isn't any problem in this line. The quotes are simply not needed.
The variables filename and file_extension are expanded (replaced by their values) but on assignments word splitting is not applied. The value resulted after the replacement is the value assigned to variable combined_name, even if it contains spaces or other word separator characters (spaces, tabs, newlines).
The quotes are also not needed here because the values do not contain spaces or other characters that are special in the command line. They must be quoted if they contain such characters.
string_contains="dummy_axial_y_position"
string_dontwant="dummy_axial_y_position_time"
file_extension=".csv"
It is not not incorrect to quote the values though.
for FILE in *
do
if [[ "$FILE" == *"$string_contains"* ]];then
if [[ "$FILE" != *"$string_dontwant"* ]]; then
This is also not wrong but it is inefficient.
You can use the expression from the if condition directly in the for statement (and get rid of the if statement):
for FILE in *"$string_contains"*; do
if [[ "$FILE" != *"$string_dontwant"* ]]; then
...
If you have read and understood the above (and some of the linked documentation) you will be able to figure out yourself where were your files moved :-)

How do I ignore a byte order marker from a while read loop in zsh

I need to verify that all images mentioned in a csv are present inside a folder. I wrote a small shell script for that
#!/bin/zsh
red='\033[0;31m'
color_Off='\033[0m'
csvfile=$1
imgpath=$2
cat $csvfile | while IFS=, read -r filename rurl
do
if [ -f "${imgpath}/${filename}" ]
then
echo -n
else
echo -e "$filename ${red}MISSING${color_Off}"
fi
done
My CSV looks something like
Image1.jpg,detail-1
Image2.jpg,detail-1
Image3.jpg,detail-1
The csv was created by excel.
Now all 3 images are present in imgpath but for some reason my output says
Image1.jpg MISSING
Upon using zsh -x to run the script i found that my CSV file has a BOM at the very beginning making the image name as \ufeffImage1.jpg which is causing the whole issue.
How can I ignore a BOM(byte-order marker) in a while read operation?
zsh provides a parameter expansion (also available in POSIX shells) to remove a prefix: ${var#prefix} will expand to $var with prefix removed from the front of the string.
zsh also, like ksh93 and bash, supports ANSI C-like string syntax: $'\ufeff' refers to the Unicode sequence for a BOM.
Combining these, one can refer to ${filename#$'\ufeff'} to refer to the content of $filename but with the Unicode sequence for a BOM removed if it's present at the front.
The below also makes some changes for better performance, more reliable behavior with odd filenames, and compatibility with non-zsh shells.
#!/bin/zsh
red='\033[0;31m'
color_Off='\033[0m'
csvfile=$1
imgpath=$2
while IFS=, read -r filename rurl; do
filename=${filename#$'\ufeff'}
if ! [ -f "${imgpath}/${filename}" ]; then
printf '%s %bMISSING%b\n' "$filename" "$red" "$color_Off"
fi
done <"$csvfile"
Notes on changes unrelated to the specific fix:
Replacing echo -e with printf lets us pick which specific variables get escape sequences expanded: %s for filenames means backslashes and other escapes in them are unmodified, whereas %b for $red and $color_Off ensures that we do process highlighting for them.
Replacing cat $csvfile | with < "$csvfile" avoids the overhead of starting up a separate cat process, and ensures that your while read loop is run in the same shell as the rest of your script rather than a subshell (which may or may not be an issue for zsh, but is a problem with bash when run without the non-default lastpipe flag).
echo -n isn't reliable as a noop: some shells print -n as output, and the POSIX echo standard, by marking behavior when -n is present as undefined, permits this. If you need a noop, : or true is a better choice; but in this case we can just invert the test and move the else path into the truth path.

MacOS shell script to move files based on tag

I am trying to write a shell script so that I can move school files from one destination to another based on the input. I download these files from a source like canvas and want to move them from my downloads based on the tag I assign, to the path for my course folder which is nested pretty deep thanks to how I stay organized. Unfortunately, since I store these files in my OneDrive school account, I am unable to eliminate some spacing issues but I believe I have accounted for these. Right now the script is the following:
if [ "$1" = "311" ];
then
course="'/path/to/311/folder/$2'"
elif [ "$1" = "411" ];
then
course="'/path/to/411/folder/$2'"
elif [ "$1" = "516" ];
then
course="'/path/to/516/folder/$2'"
elif [ "$1" = "530" ];
then
course="'/path/to/530/folder/$2'"
elif [ "$1" = "599" ];
then
course="'/path/to/599/folder/$2'"
fi
files=$(mdfind 'kMDItemUserTags='$1'' -onlyin /Users/user/Downloads)
#declare -a files=$(mdfind 'kMDItemUserTags='$1'' -onlyin /Users/user/Downloads)
#mv $files $course
#echo "mv $files $course"
#echo $course
for file in $files
#for file in "${files[#]}"
do
#echo $file
#echo $course
mv $file $course
done
Where $1 is the tag ID and first part of path selection, and $2 is what week number folder I want to move it to. The single quotation marks are there to take care of the spacing in the filepath. I could very easily do this in python but I'm trying to expand my capabilities some. Every time I run this script I get the following message:
usage: mv [-f | -i | -n] [-v] source target
mv [-f | -i | -n] [-v] source ... directory
I initially tried to just move them all at once (per the first mv command that's commented out) and got this error, then tried the for loop, and array but get the same error each time. However, when I uncomment the echo statements in the for loop and manually try to move each one by copying and pasting the paths to the command line, it works perfectly. My best guess is something to do with the formatting of the variable "files", since
echo "mv $files $course"
indicates the presence of a newline character or separator between each file it saves.
I'm sure it's something super simple that I'm missing since I just started trying to pick up shell scripting last week, but nothing I have been able to find online has helped me resolve this. Any help would be greatly appreciated. Thanks
You can replace the files variable assignment and for loop with one command make this the script:
if [ "$1" = "311" ];
then
course="'/path/to/311/folder/$2'"
elif [ "$1" = "411" ];
then
course="'/path/to/411/folder/$2'"
elif [ "$1" = "516" ];
then
course="'/path/to/516/folder/$2'"
elif [ "$1" = "530" ];
then
course="'/path/to/530/folder/$2'"
elif [ "$1" = "599" ];
then
course="'/path/to/599/folder/$2'"
fi
mv -t $course $(mdfind 'kMDItemUserTags='$1'' -onlyin /Users/user/Downloads | sed ':a;N;$!ba;s/\n/ /g)
The sed ':a;N;$!ba;s/\n/ /g command simply replaces the newline characters with spaces, and the -t option for mv simply makes mv take the destination as the first argument.
You're getting rather confused about how quoting works in the shell. First rule: quotes go around data, not in data. For example, you use:
course="'/path/to/311/folder/$2'"
...
mv $file $course
When you set course this way, the double-quotes are treated as shell syntax (i.e. they change how what's between them is parsed), but the single-quotes are stored as part of the variable's value, and will thereafter be treated as data. When you use this variable in the mv command, it's actually looking for a directory literally named single-quote, and under that a directory named "path", etc. Instead, just put the appropriate quotes for how you want it parsed at that point, and then double-quotes around the variable when you use it (to prevent probably-unwanted word splitting and wildcard expansion). Like this:
course="/path/to/311/folder/$2"
...
mv "$file" "$course" # This needs more work -- see below
Also, where you have:
mdfind 'kMDItemUserTags='$1'' -onlyin /Users/user/Downloads
that doesn't really make any sense. You've got a single-quoted section, 'kMDItemUserTags=' where the quotes have no effect at all (single-quotes suppress all special meanings that characters have, like $ introducing variable substitution, but there aren't any characters there with special meanings, so no reason for the quotes), followed by $ without double-quotes around it, meaning that some special characters (whitespace and wildcards) in its value will get special parsing (which you probably don't want), followed by a zero-length single-quoted string, '', which parses out to exactly nothing. You want the $1 part in double-quotes; some people also include the rest of the string in the double-quoted section, which has no effect at all. In fact, other than the $2 part (and the spaces between parameters), you can quote or not however you want. Thus, any of these would work equivalently:
mdfind kMDItemUserTags="$1" -onlyin /Users/user/Downloads
mdfind "kMDItemUserTags=$1" -onlyin /Users/user/Downloads
mdfind "kMDItemUserTags=$1" '-onlyin' '/Users/user/Downloads'
mdfind 'kMDItemUserTags'="$1" '-'"only"'in' /'Users'/'user'/'Down'loads
...etc
Ok, next problem: parsing the output from mdfind from a series of characters into separate filepaths. This is actually tricky. If you put double-quotes around the resilting string, it'll get treated as one long filepath that happens to contain some newlines in it (which is totally legal, but not what you want). If you don't double-quote it, it'll be split into separate filepaths based on whitespace (not just newlines, but also spaces and tabs -- and spaces are common within macOS filenames), and anything that looks like a wildcard will get expanded to a list of matching filenames. This tends to cause chaos.
The solution: there's one character than cannot occur in a filepath, the ASCII NULL (character code 0), and mdfind -0 will output its list delimited with null characters. You can't put the result in a shell variable (they can't hold nulls either), but you can pass it through a pipe to, say, xargs -0, which will (thanks to the -0 option) parse the nulls as delimiters, and build commands out of the results. There is one slightly tricky thing: you want xargs to put the filepaths it gets in the middle of the argument list to mv, not at the end like it usually does. The -J option lets you tell it where to add arguments. I'll also suggest two safety measures: the -p option to xargs makes it ask before actually executing the command (use this at least until you're sure it's doing the right thing), and the -n option to mv, which tells it not to overwrite existing files if there's a naming conflict. The result is something like this:
mdfind -0 kMDItemUserTags="$1" -onlyin /Users/user/Downloads | xargs -0 -p -J% mv -n % "$course"
It is a good point to consider about filenames with whitespaces.
However the problem is that you are not quoting the filename in the mv command. Please take a look of a simple example below:
filename="with space.txt"
=> assign a variable to a filname with a space
touch "$filename"
=> create a file "with space.txt"
str="'$filename'"
=> wrap with single quotes (as you do)
echo $str
=> yields 'with space.txt' and may look good, which is a pitfall
mv $str "newname.txt"
=> causes an error
The mv command above causes an error because the command is invoked with
three arguments as: mv 'with space.txt' newname.txt. Unfortunately
the pre-quoting with single quotes is meaningless.
Instead, please try something like:
if [ "$1" = "311" ]; then
course="/path/to/311/folder/$2"
elif [ "$1" = "411" ]; then
course="/path/to/411/folder/$2"
elif [ "$1" = "516" ]; then
course="/path/to/516/folder/$2"
elif [ "$1" = "530" ]; then
course="/path/to/530/folder/$2"
elif [ "$1" = "599" ]; then
course="/path/to/599/folder/$2"
else
# illegal value in $1. do some error handling
fi
# the lines above may be simplified if /path/to/*folder/ have some regularity
mdfind "kMDItemUserTags=$1" -onlyin /Users/user/Downloads | while read -r file; do
mv "$file" "$course"
done
# the syntax above works as long as the filenames do not contain newline characters

Basename puts single quotes around variable

I am writing a simple shell script to make automated backups, and I am trying to use basename to create a list of directories and them parse this list to get the first and the last directory from the list.
The problem is: when I use basename in the terminal, all goes fine and it gives me the list exactly as I want it. For example:
basename -a /var/*/
gives me a list of all the directories inside /var without the / in the end of the name, one per line.
BUT, when I use it inside a script and pass a variable to basename, it puts single quotes around the variable:
while read line; do
dir_name=$(echo $line)
basename -a $dir_name/*/ > dir_list.tmp
done < file_with_list.txt
When running with +x:
+ basename -a '/Volumes/OUTROS/backup/test/*/'
and, therefore, the result is not what I need.
Now, I know there must be a thousand ways to go around the basename problem, but then I'd learn nothing, right? ;)
How to get rid of the single quotes?
And if my directory name has spaces in it?
If your directory name could include spaces, you need to quote the value of dir_name (which is a good idea for any variable expansion, whether you expect spaces or not).
while read line; do
dir_name=$line
basename -a "$dir_name"/*/ > dir_list.tmp
done < file_with_list.txt
(As jordanm points out, you don't need to quote the RHS of a variable assignment.)
Assuming your goal is to populate dir_list.tmp with a list of directories found under each directory listed in file_with_list.txt, this might do.
#!/bin/bash
inputfile=file_with_list.txt
outputfile=dir_list.tmp
rm -f "$outputfile" # the -f makes rm fail silently if file does not exist
while read line; do
# basic syntax checking
if [[ ! ${line} =~ ^/[a-z][a-z0-9/-]*$ ]]; then
continue
fi
# collect targets using globbing
for target in "$line"/*; do
if [[ -d "$target" ]]; then
printf "%s\n" "$target" >> $outputfile
fi
done
done < $inputfile
As you develop whatever tool will process your dir_list.tmp file, be careful of special characters (including spaces) in that file.
Note that I'm using printf instead of echo so that targets whose first character is a hyphen won't cause errors.
This might work
while read; do
find "$REPLY" >> dir_list.tmp
done < file_with_list.txt

Batch renaming files with Bash

How can Bash rename a series of packages to remove their version numbers? I've been toying around with both expr and %%, to no avail.
Examples:
Xft2-2.1.13.pkg becomes Xft2.pkg
jasper-1.900.1.pkg becomes jasper.pkg
xorg-libXrandr-1.2.3.pkg becomes xorg-libXrandr.pkg
You could use bash's parameter expansion feature
for i in ./*.pkg ; do mv "$i" "${i/-[0-9.]*.pkg/.pkg}" ; done
Quotes are needed for filenames with spaces.
If all files are in the same directory the sequence
ls |
sed -n 's/\(.*\)\(-[0-9.]*\.pkg\)/mv "\1\2" "\1.pkg"/p' |
sh
will do your job. The sed command will create a sequence of mv commands, which you can then pipe into the shell. It's best to first run the pipeline without the trailing | sh so as to verify that the command does what you want.
To recurse through multiple directories use something like
find . -type f |
sed -n 's/\(.*\)\(-[0-9.]*\.pkg\)/mv "\1\2" "\1.pkg"/p' |
sh
Note that in sed the regular expression grouping sequence is brackets preceded by a backslash, \( and \), rather than single brackets ( and ).
I'll do something like this:
for file in *.pkg ; do
mv $file $(echo $file | rev | cut -f2- -d- | rev).pkg
done
supposed all your file are in the current directory. If not, try to use find as advised above by Javier.
EDIT: Also, this version don't use any bash-specific features, as others above, which leads you to more portability.
We can assume sed is available on any *nix, but we can't be sure
it'll support sed -n to generate mv commands. (NOTE: Only GNU sed does this.)
Even so, bash builtins and sed, we can quickly whip up a shell function to do this.
sedrename() {
if [ $# -gt 1 ]; then
sed_pattern=$1
shift
for file in $(ls $#); do
mv -v "$file" "$(sed $sed_pattern <<< $file)"
done
else
echo "usage: $0 sed_pattern files..."
fi
}
Usage
sedrename 's|\(.*\)\(-[0-9.]*\.pkg\)|\1\2|' *.pkg
before:
./Xft2-2.1.13.pkg
./jasper-1.900.1.pkg
./xorg-libXrandr-1.2.3.pkg
after:
./Xft2.pkg
./jasper.pkg
./xorg-libXrandr.pkg
Creating target folders:
Since mv doesn't automatically create target folders we can't using
our initial version of sedrename.
It's a fairly small change, so it'd be nice to include that feature:
We'll need a utility function, abspath (or absolute path) since bash
doesn't have this build in.
abspath () { case "$1" in
/*)printf "%s\n" "$1";;
*)printf "%s\n" "$PWD/$1";;
esac; }
Once we have that we can generate the target folder(s) for a
sed/rename pattern which includes new folder structure.
This will ensure we know the names of our target folders. When we
rename we'll need to use it on the target file name.
# generate the rename target
target="$(sed $sed_pattern <<< $file)"
# Use absolute path of the rename target to make target folder structure
mkdir -p "$(dirname $(abspath $target))"
# finally move the file to the target name/folders
mv -v "$file" "$target"
Here's the full folder aware script...
sedrename() {
if [ $# -gt 1 ]; then
sed_pattern=$1
shift
for file in $(ls $#); do
target="$(sed $sed_pattern <<< $file)"
mkdir -p "$(dirname $(abspath $target))"
mv -v "$file" "$target"
done
else
echo "usage: $0 sed_pattern files..."
fi
}
Of course, it still works when we don't have specific target folders
too.
If we wanted to put all the songs into a folder, ./Beethoven/ we can do this:
Usage
sedrename 's|Beethoven - |Beethoven/|g' *.mp3
before:
./Beethoven - Fur Elise.mp3
./Beethoven - Moonlight Sonata.mp3
./Beethoven - Ode to Joy.mp3
./Beethoven - Rage Over the Lost Penny.mp3
after:
./Beethoven/Fur Elise.mp3
./Beethoven/Moonlight Sonata.mp3
./Beethoven/Ode to Joy.mp3
./Beethoven/Rage Over the Lost Penny.mp3
Bonus round...
Using this script to move files from folders into a single folder:
Assuming we wanted to gather up all the files matched, and place them
in the current folder, we can do it:
sedrename 's|.*/||' **/*.mp3
before:
./Beethoven/Fur Elise.mp3
./Beethoven/Moonlight Sonata.mp3
./Beethoven/Ode to Joy.mp3
./Beethoven/Rage Over the Lost Penny.mp3
after:
./Beethoven/ # (now empty)
./Fur Elise.mp3
./Moonlight Sonata.mp3
./Ode to Joy.mp3
./Rage Over the Lost Penny.mp3
Note on sed regex patterns
Regular sed pattern rules apply in this script, these patterns aren't
PCRE (Perl Compatible Regular Expressions). You could have sed
extended regular expression syntax, using either sed -r or sed -E
depending on your platform.
See the POSIX compliant man re_format for a complete description of
sed basic and extended regexp patterns.
Here is a POSIX near-equivalent of the currently accepted answer. This trades the Bash-only ${variable/substring/replacement} parameter expansion for one which is available in any Bourne-compatible shell.
for i in ./*.pkg; do
mv "$i" "${i%-[0-9.]*.pkg}.pkg"
done
The parameter expansion ${variable%pattern} produces the value of variable with any suffix which matches pattern removed. (There is also ${variable#pattern} to remove a prefix.)
I kept the subpattern -[0-9.]* from the accepted answer although it is perhaps misleading. It's not a regular expression, but a glob pattern; so it doesn't mean "a dash followed by zero or more numbers or dots". Instead, it means "a dash, followed by a number or a dot, followed by anything". The "anything" will be the shortest possible match, not the longest. (Bash offers ## and %% for trimming the longest possible prefix or suffix, rather than the shortest.)
I find that rename is a much more straightforward tool to use for this sort of thing. I found it on Homebrew for OSX
For your example I would do:
rename 's/\d*?\.\d*?\.\d*?//' *.pkg
The 's' means substitute. The form is s/searchPattern/replacement/ files_to_apply. You need to use regex for this which takes a little study but it's well worth the effort.
better use sed for this, something like:
find . -type f -name "*.pkg" |
sed -e 's/((.*)-[0-9.]*\.pkg)/\1 \2.pkg/g' |
while read nameA nameB; do
mv $nameA $nameB;
done
figuring up the regular expression is left as an exercise (as is dealing with filenames that include spaces)
This seems to work assuming that
everything ends with $pkg
your version #'s always start with a "-"
strip off the .pkg, then strip off -..
for x in $(ls); do echo $x $(echo $x | sed 's/\.pkg//g' | sed 's/-.*//g').pkg; done
I had multiple *.txt files to be renamed as .sql in same folder.
below worked for me:
for i in \`ls *.txt | awk -F "." '{print $1}'\` ;do mv $i.txt $i.sql; done
Thank you for this answers. I also had some sort of problem. Moving .nzb.queued files to .nzb files. It had spaces and other cruft in the filenames and this solved my problem:
find . -type f -name "*.nzb.queued" |
sed -ne "s/^\(\(.*\).nzb.queued\)$/mv -v \"\1\" \"\2.nzb\"/p" |
sh
It is based on the answer of Diomidis Spinellis.
The regex creates one group for the whole filename, and one group for the part before .nzb.queued and then creates a shell move command. With the strings quoted. This also avoids creating a loop in shell script because this is already done by sed.

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