# used inside a self method is doing what exactly? - ruby

I saw this in some code today.
class Foo
def self.bar
#myvar = 'x'
end
end
What exactly is this accessing? As far as I can tell, this isn't accessible form instance methods. What's this called (something google-able) as I cant seem to find examples of this anywhere else.

The #myvar syntax identifies myvar as an instance variable so the real question is this:
What is self inside a class method?
And the answer is "self is the class object". So, #myvar is an instance variable of the Foo class object. If you add another class method:
class Foo
def self.pancakes_house
#myvar
end
end
And then do this:
Foo.bar
puts Foo.pancakes_house
You'll see x on the standard output.

A class is also an object, so you are setting a instance variable in class Foo.
>> Foo.bar
>> Foo.instance_variable_get("#myvar")
=> 'x'
Now, for a typical use, add class << self; attr_accessor :myvar; end to your class and you can write:
>> Foo.bar
>> Foo.myvar
=> 'x'

For googling, this is sometimes called a "class instance variable". That is, an instance variable of an object that just happens to be a class.

Related

Rails and class variables

class MainController < ApplicationController
#my_var = 123
def index
var1 = #my_var
end
def index2
var2 = #my_var
end
end
Why is neither var1 no var2 equal to 123?
Variables with # are instance variables in ruby. If you're looking for class variables, they're prefixed with ##, so you should be using ##my_var = 123 instead.
And the reason you can't use instance variables that way, is because if you define instance variables outside methods, they don't live in the same scope as your methods, but only live while your class is interpreted.
var1 in your example is a local variable, which will only be visible inside the index method.
Examples:
class Foo
##class_variable = "I'm a class variable"
def initialize
#instance_variable = "I'm an instance variable in a Foo class"
local_variable = "I won't be visible outside this method"
end
def instance_method_returning_an_instance_variable
#instance_variable
end
def instance_method_returning_a_class_variable
##class_variable
end
def self.class_method_returning_an_instance_variable
#instance_variable
end
def self.class_method_returning_a_class_variable
##class_variable
end
end
Foo.new
=> #<Foo:0x007fc365f1d8c8 #instance_variable="I'm an instance variable in a Foo class">
Foo.new.instance_method_returning_an_instance_variable
=> "I'm an instance variable in a Foo class"
Foo.new.instance_method_returning_a_class_variable
=> "I'm a class variable"
Foo.class_method_returning_an_instance_variable
=> nil
Foo.class_method_returning_a_class_variable
=> "I'm a class variable"
#my_var, in your sample code, is an instance variable on the class MainController. That is, it's a class-level instance variable, and not an instance-level instance variable. It exists in a totally different scope to the instance variable associated with an instance of the class.
Within the body of your instance methods, index and index2, you are attempting to dereference an instance variable on an object that is an instance of class MainController, but you have not defined that instance variable anywhere, so you get back nil.
If you want to use #my_var as a class-level instance variable, you can get its value from within an instance of the class like this:
var1 = self.class.instance_variable_get(:#my_var)
Class variables are indicated with a ## prefix, and their use is not entirely encouraged. A couple of minutes with Google will tell you why.
Because code executes in different context. You can see here:
class MainController
puts self
def print_self
puts self
end
end
#=> MainController
MainController.new.print_self #=> <MainController:0x00000001761140>
As you can see in first print the self is MainController, in second print the self is the object which derived from MainController class.
In the assignment to #my_vay this variable belongs to MainController, and in the second cases, the #my_var belongs to object (not a class) and these varaibles are different.

Why does this Ruby method need to be a class level method?

Here's a classic fizzbuzz in Ruby:
class PrimeChecker
def print_em
1.upto 100 do |fizzbuzz|
if (fizzbuzz % 2) == 0 && (fizzbuzz % 5) == 0
puts "fizzbuzz: " + fizzbuzz.to_s
elsif (fizzbuzz % 5) == 0
puts "fizz: "+fizzbuzz.to_s
elsif (fizzbuzz % 2) == 0
puts 'buzz: ' + fizzbuzz.to_s
else
puts "-" + fizzbuzz.to_s
end
end
end
end
PrimeChecker.print_em
When I execute this, I get this error:
undefined method 'print_em'.
I change the method to self.print_em and it works. Does this mean it's a class method (I think so)? Was the method "not found" before because I can only call such methods in a class on actual instances of the object? If I wanted it to be a instance method what is the syntax for that? I'm trying to understand Ruby, classes and methods better.
Class methods are just that: called on the class. Whereas instance methods are called on an instance of that class. An example is more useful:
class Foo
def self.bar
"This is a class method!"
end
def bar
"This is an instance method!"
end
end
Foo.bar # => "This is a class method!"
foo = Foo.new # This creates "foo" to be a new instance of Foo
foo.bar # => "This is an instance method!"
Note that "class methods" in Ruby are actually methods on the class object's singleton. This is a rather difficult concept to explain, and you can read more about it if you'd like.
It's not a class method as written; you need to run it with an instance of PrimeChecker:
pc = PrimeChecker.new
pc.print_em
Using self. turns it into a class method, runnable with the syntax you show.
It doesn't need to be a class method, it's just that that's how you're trying to execute it.
Q: When I run ruby.rb I get undefined method 'print_em'. I change the method to self.print_em and it works. Does this mean it's a class method (I think so).
A: Yes. class Bar; ... def self.foo defines a class method foo for class Bar.
Q: Was the method "not found" before because I can only call such methods in a class on actual instances of the object?
A: You were first defining it as an instance method. In that case, it is only available to instances of the class.
Q: If I wanted it to be a instance method what is the syntax for that?
A: The way you had it originally: class Bar; def foo defines instance method foo for class Bar
Yes, you are completely correct. Currently, the way you define it, you can evaluate the method with:
PrimeChecker.new.print_em
The reason def self.my_awesome_method defines it on the class side is because the stuff inside
class MyAwesomeClass
end
is being executed in the context of MyAwesomeClass. It's all Ruby code, as you can see! This enables you to do things like this:
class MyAwesomeClass
puts "Hello from innards of #{self}!" #=> Hello from the innards of MyAwesomeClass!
end
Method definitions will also only work if you call them after the definition location, for example:
class MyAwesomeClass
my_awesome_method # produces a nasty error
def self.my_awesome_method
puts "Hello world"
end
my_awesome_method # executes just fine
end
Hope this clears some things up.

Ruby class inheritance: What is `<<` (double less than)?

class << Awesomeness
What is this << for? I searched, but the results only tell me about string concatenation...
While it's true that class << something is the syntax for a singleton class, as someone else said, it's most often used to define class methods within a class definition. But these two usages are consistent. Here's how.
Ruby lets you add methods to any particular instance by doing this:
class << someinstance
def foo
"Hello."
end
end
This adds a method foo to someinstance, not to its class but to that one particular instance. (Actually, foo is added to the instance's "singleton class," but that's more or less an implementation quirk.) After the above code executes, you can send method foo to someinstance:
someinstance.foo => "Hello."
but you can't send foo to other instances of the same class. That's what << is nominally for. But people more commonly use this feature for syntactic gymnastics like this:
class Thing
def do_something
end
class << self
def foo
puts "I am #{self}"
end
end
end
When this code -- this class definition -- executes, what is self? It's the class Thing. Which means class << self is the same as saying "add the following methods to class Thing." That is, foo is a class method. After the above completes, you can do this:
t = Thing.new
t.do_something => does something
t.class.foo => "I am Thing"
t.foo => NoMethodError: undefined method `foo'
And when you think about what << is doing, it all makes sense. It's a way to append to a particular instance, and in the common case, the instance being appended to is a class, so the methods within the block become class methods.
In short, it's a terse way to create class methods within a class definition block. Another way would be to do this:
class Thing
def self.foo
# ...
end
end
Same thing. Your example is actually a syntax error, but if you understand how << is used with instances and the class keyword, you'll know how to correct it.
<< is the syntax for "Singleton class definition". Here is an example of where/how it is "typically" used.
In a = "abc"; a << "xyz" it is the syntax for "appending data" (to string, array etc.)
If you want inheritance (based on your question title), you want a single <:
class Awesome < ParentAwesomeness
The code you provide isn't valid ruby:
class Awesomeness
end
class Awesome << Awesomeness
end
SyntaxError: (irb):3: syntax error, unexpected tLSHFT, expecting '<' or ';' or '\n'

Why isn't the eigenclass equivalent to self.class, when it looks so similar?

I've missed the memo somewhere, and I hope you'll explain this to me.
Why is the eigenclass of an object different from self.class?
class Foo
def initialize(symbol)
eigenclass = class << self
self
end
eigenclass.class_eval do
attr_accessor symbol
end
end
end
My train of logic that equates the eigenclass with class.self is rather simple:
class << self is a way of declaring class methods, rather than instance methods. It's a shortcut to def Foo.bar.
So within the reference to the class object, returning self should be identical to self.class. This is because class << self would set self to Foo.class for definition of class methods/attributes.
Am I just confused? Or, is this a sneaky trick of Ruby meta-programming?
class << self is more than just a way of declaring class methods (though it can be used that way). Probably you've seen some usage like:
class Foo
class << self
def a
print "I could also have been defined as def Foo.a."
end
end
end
This works, and is equivalent to def Foo.a, but the way it works is a little subtle. The secret is that self, in that context, refers to the object Foo, whose class is a unique, anonymous subclass of Class. This subclass is called Foo's eigenclass. So def a creates a new method called a in Foo's eigenclass, accessible by the normal method call syntax: Foo.a.
Now let's look at a different example:
str = "abc"
other_str = "def"
class << str
def frob
return self + "d"
end
end
print str.frob # => "abcd"
print other_str.frob # => raises an exception, 'frob' is not defined on other_str
This example is the same as the last one, though it may be hard to tell at first. frob is defined, not on the String class, but on the eigenclass of str, a unique anonymous subclass of String. So str has a frob method, but instances of String in general do not. We could also have overridden methods of String (very useful in certain tricky testing scenarios).
Now we're equipped to understand your original example. Inside Foo's initialize method, self refers not to the class Foo, but to some particular instance of Foo. Its eigenclass is a subclass of Foo, but it is not Foo; it couldn't be, or else the trick we saw in the second example couldn't work. So to continue your example:
f1 = Foo.new(:weasels)
f2 = Foo.new(:monkeys)
f1.weasels = 4 # Fine
f2.monkeys = 5 # Also ok
print(f1.monkeys) # Doesn't work, f1 doesn't have a 'monkeys' method.
The simplest answer: the eigenclass can't be instantiated.
class F
def eigen
class << self
self
end
end
end
F.new.eigen.new #=> TypeError: can't create instance of virtual class
Yehuda Katz does a pretty good job of explaining the subtleties in "Metaprogramming in Ruby: It's All About the Self"

In Ruby are there any related applications of the syntax: class << self ... end

class << self
attr_accessor :n, :totalX, :totalY
end
The syntax above is used for defining class instance variables. But when I think about what syntax implies, it doesn't make any sense to me, so I'm wondering if this type of syntax is used for any other types of definitions. My point of confusion here is this:
class << self
The append operator normally means "add what's on the right to the object on the left". But in the context of this block, how does that add up to "put the contents of this block into the definition of the class instance rather than the instance"?
For the same reason I'm confused as to why in one context class << self can define class instance variables while in another it seems to create class variables such as here:
class Point
# Instance methods go here
class << self
# Class methods go here
end
end
in Ruby you can reopen existing classes and add methods. That is, you can say:
class Foo
def bob
return "hello from bob"
end
end
these methods get stored somewhere in an internal dictionary (maybe an instance variable) of the Foo-class (which is just an instance of the Class-class and therefore has instance variables)
But the suprising thing is, that you can also add methods to instances of existing objects
foo = Foo.new
foo2 = Foo.new
def foo.fred
return "I am fred"
end
foo.fred #=> "I am fred"
foo2.fred #=> NoMethodError
but Where is this method actually stored?
Turns out Ruby creates a new class behind the scenes (sometimes called singleton class, metaclass or eigenclass) which gets inserted in the inheritance heirarchy between the Foo-class and its instance.
So the inheritance relationship looks like that:
foo < (eigenclass of foo) < Foo < Class
(if you say foo.superclass you will not see the singleton class)
the class << X-syntax is a way to get to this special class, so that you can manipulate it directly. The following code blocks are exactly equivalent:
def foo.bar
return "xy"
end
# is exactly the same as
class << foo
def bar
return "xy"
end
end
So the similarity between class Foo < Bar and class << Foo is not accidental, there is inheritance going on in both.
Think of class << X as "open up the metaclass of X"
The thing to remember in Ruby is that classes themselves are just objects. (Instances of the class Class) so if you say:
class Foo
class << self
def k
return "x"
end
end
end
(self is bound to Foo in this code block) so k is an instance method of the eigenclass of Foo, which makes it a class method for Foo
all this is explained more clearly in the chapter about classes of the Pickaxe (the web version does not contain the diagrams, unfortunately) and _whys Seeing Metaclasses Clearly
Think of the class as containing a dictionary of members including all the accessors and instance variables. When you tell the class to "append" to "itself", you're saying "add these to the dictionary of class members."
I'll grant the notation is a little hinky, though.
it's actually confusing to think of it in terms of an "append" operator. a better way to look at it is that just as class Foo opens up class Foo, that is, it sets 'self' to the class object Foo, creating it if necessary, so class << self opens up the eigenclass of the current 'self' object. note that it is not limited to self - for any object bar, you can say class << bar to open up the eigenclass of that object.
class A
def hello
print "hello world"
end
end
a = A.new
b = A.new
class << a
def goodbye
print "goodbye cruel world"
end
end
a.hello
b.hello
a.goodbye
b.goodbye

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