I am really new a bash and I was trying to search a csv file column for a value and then add a counter. I found this online but it prints it and I have been trying to count how many times an R shows up and not print the whole thing.
awk -F "\"*,\"*" '{print $2}' $file
The csv file is like:
12345,R,N,N,Y,N,N,N,Bob Builder
I am looking for R in column 2. Can anybody point me in the right direction?
The following should do what you want (where file.csv is your csv file):
Case sensitive version:
cut -f 2 -d , file.csv | grep -c R
Case insensitive version:
cut -f 2 -d , file.csv | grep -ic R
Explanation
cut -f 2 -d , file.csv
This takes each line of file.csv and extracts the specified fields. The -f 2 option means extract field 2 and the -d , means use a ',' as the field delimiter. The output of this is then piped to grep.
grep -c R This looks for lines containing 'R'. Since it is passed the contents of the previous cut command, it is looking for an 'R' in field two. The -c option means count the number of matching lines.
Using awk only:
awk -F "\",\"" '{if ($2 == "R") cnt++} END{print cnt}' file
For a fun - perl only - this count everything.
perl -F, -anle 'map{$cnt{$_}{$F[$_]}++}0..$#F;END{print $cnt{1}{R}}'
Related
I have a text file with a large amount of data which is tab delimited. I want to have a look at the data such that I can see the unique values in a column. For example,
Red Ball 1 Sold
Blue Bat 5 OnSale
...............
So, its like the first column has colors, so I want to know how many different unique values are there in that column and I want to be able to do that for each column.
I need to do this in a Linux command line, so probably using some bash script, sed, awk or something.
What if I wanted a count of these unique values as well?
Update: I guess I didn't put the second part clearly enough. What I wanted to do is to have a count of "each" of these unique values not know how many unique values are there. For instance, in the first column I want to know how many Red, Blue, Green etc coloured objects are there.
You can make use of cut, sort and uniq commands as follows:
cat input_file | cut -f 1 | sort | uniq
gets unique values in field 1, replacing 1 by 2 will give you unique values in field 2.
Avoiding UUOC :)
cut -f 1 input_file | sort | uniq
EDIT:
To count the number of unique occurences you can make use of wc command in the chain as:
cut -f 1 input_file | sort | uniq | wc -l
awk -F '\t' '{ a[$1]++ } END { for (n in a) print n, a[n] } ' test.csv
You can use awk, sort & uniq to do this, for example to list all the unique values in the first column
awk < test.txt '{print $1}' | sort | uniq
As posted elsewhere, if you want to count the number of instances of something you can pipe the unique list into wc -l
Assuming the data file is actually Tab separated, not space aligned:
<test.tsv awk '{print $4}' | sort | uniq
Where $4 will be:
$1 - Red
$2 - Ball
$3 - 1
$4 - Sold
# COLUMN is integer column number
# INPUT_FILE is input file name
cut -f ${COLUMN} < ${INPUT_FILE} | sort -u | wc -l
Here is a bash script that fully answers the (revised) original question. That is, given any .tsv file, it provides the synopsis for each of the columns in turn. Apart from bash itself, it only uses standard *ix/Mac tools: sed tr wc cut sort uniq.
#!/bin/bash
# Syntax: $0 filename
# The input is assumed to be a .tsv file
FILE="$1"
cols=$(sed -n 1p $FILE | tr -cd '\t' | wc -c)
cols=$((cols + 2 ))
i=0
for ((i=1; i < $cols; i++))
do
echo Column $i ::
cut -f $i < "$FILE" | sort | uniq -c
echo
done
This script outputs the number of unique values in each column of a given file. It assumes that first line of given file is header line. There is no need for defining number of fields. Simply save the script in a bash file (.sh) and provide the tab delimited file as a parameter to this script.
Code
#!/bin/bash
awk '
(NR==1){
for(fi=1; fi<=NF; fi++)
fname[fi]=$fi;
}
(NR!=1){
for(fi=1; fi<=NF; fi++)
arr[fname[fi]][$fi]++;
}
END{
for(fi=1; fi<=NF; fi++){
out=fname[fi];
for (item in arr[fname[fi]])
out=out"\t"item"_"arr[fname[fi]][item];
print(out);
}
}
' $1
Execution Example:
bash> ./script.sh <path to tab-delimited file>
Output Example
isRef A_15 C_42 G_24 T_18
isCar YEA_10 NO_40 NA_50
isTv FALSE_33 TRUE_66
I'm trying to get as bash variable list of users which are in my csv file. Problem is that number of users is random and can be from 1-5.
Example CSV file:
"record1_data1","record1_data2","record1_data3","user1","user2"
"record2_data1","record2_data2","record2_data3","user1","user2","user3","user4"
"record3_data1","record3_data2","record3_data3","user1"
I would like to get something like
list_of_users="cat file.csv | grep "record2_data2" | <something> "
echo $list_of_users
user1,user2,user3,user4
I'm trying this:
cat file.csv | grep "record2_data2" | awk -F, -v OFS=',' '{print $4,$5,$6,$7,$8 }' | sed 's/"//g'
My result is:
user2,user3,user4,,
Question:
How to remove all "," from the end of my result? Sometimes it is just one but sometimes can be user1,,,,
Can I do it in better way? Users always starts after 3rd column in my file.
This will do what your code seems to be trying to do (print the users for a given string record2_data2 which only exists in the 2nd field):
$ awk -F',' '{gsub(/"/,"")} $2=="record2_data2"{sub(/([^,]*,){3}/,""); print}' file.csv
user1,user2,user3,user4
but I don't see how that's related to your question subject of Getting last X records from CSV file using bash so idk if it's what you really want or not.
Better to use a bash array, and join it into a CSV string when needed:
#!/usr/bin/env bash
readarray -t listofusers < <(cut -d, -f4- file.csv | tr -d '"' | tr ',' $'\n' | sort -u))
IFS=,
printf "%s\n" "${listofusers[*]}"
cut -d, -f4- file.csv | tr -d '"' | tr ',' $'\n' | sort -u is the important bit - it first only prints out the fourth and following fields of the CSV input file, removes quotes, turns commas into newlines, and then sorts the resulting usernames, removing duplicates. That output is then read into an array with the readarray builtin, and you can manipulate it and the individual elements however you need.
GNU sed solution, let file.csv content be
"record1_data1","record1_data2","record1_data3","user1","user2"
"record2_data1","record2_data2","record2_data3","user1","user2","user3","user4"
"record3_data1","record3_data2","record3_data3","user1"
then
sed -n -e 's/"//g' -e '/record2_data/ s/[^,]*,[^,]*,[^,]*,// p' file.csv
gives output
user1,user2,user3,user4
Explanation: -n turns off automatic printing, expressions meaning is as follow: 1st substitute globally " using empty string i.e. delete them, 2nd for line containing record2_data substitute (s) everything up to and including 3rd , with empty string i.e. delete it and print (p) such changed line.
(tested in GNU sed 4.2.2)
awk -F',' '
/record2_data2/{
for(i=4;i<=NF;i++) o=sprintf("%s%s,",o,$i);
gsub(/"|,$/,"",o);
print o
}' file.csv
user1,user2,user3,user4
This might work for you (GNU sed):
sed -E '/record2_data/!d;s/"([^"]*)"(,)?/\1\2/4g;s///g' file
Delete all records except for that containing record2_data.
Remove double quotes from the fourth field onward.
Remove any double quoted fields.
I have this csv file and I am trying to write shell script to calculate sum of column after doing group by on it. Column number is 11th (STATUS)
My script is
awk -F, 'NR>1{arr[$11]++}END{for (a in arr) print a, arr[a]}' $f > $parentdir/outputfile.csv;
File output expected is
COMMITTED 2
but actual output is just 2.
It prints only count and not group by sum. If I delete any other columns and run same query then it works fine but not with below sample data.
FILE NAME;SEQUENCE NR;TRANSACTION ID;RUN NUMBER;START EDITCREATION;END EDITCREATION;END COMMIT;EDIT DURATION;COMMIT DURATION;HAS DEPENDENCY;STATUS;DETAILS
Buldhana_Refinesource_FG_IW_ETS_000001.xml;1;4a032127-b20d-4fa8-9f4d-7f2999c0c08f;1;20180831130210345;20180831130429638;20180831130722406;140;173;false;COMMITTED;
Buldhana_Refinesource_FG_IW_ETS_000001.xml;2;e4043fc0-3b0a-46ec-b409-748f98ce98ad;1;20180831130722724;20180831130947144;20180831131216693;145;150;false;COMMITTED;
change the FS to ; in your script
awk -F';' 'NR>1{arr[$11]++}END{for (a in arr) print a, arr[a]}' file
COMMITTED 2
You're using wrong field separator. Use
awk -F\;
; must be escaped to use it as a literal. Except this, your approach seems OK.
Besides awk, you may also use
tail -n +2 $f | cut -f11 -d\; | sort | uniq -c
or
datamash --header-in -t \; -g 11 count 11 < $f
to do the same thing.
I have a delimited file that is separated by octal \036 or Hexadecimal value 1e.
I need to count the number of delimiters on each line using a bash shell script.
I was trying to use awk, not sure if this is the best way.
Sample Input (| is a representation of \036)
Example|Running|123|
Expected output:
3
awk -F'|' '{print NF-1}' file
Change | to whatever separator you like. If your file can have empty lines then you need to tweak it to:
awk -F'|' '{print (NF ? NF-1 : 0)}' file
You can try
awk '{print gsub(/\|/,"")}'
Simply try
awk -F"|" '{print substr($3,length($3))}' OFS="|" Input_file
Explanation: Making field separator -F as | and then printing the 3rd column by doing $3 only as per your need. Then setting OFS(output field separator) to |. Finally mentioning Input_file name here.
This will work as far as I know
echo "Example|Running|123|" | tr -cd '|' | wc -c
Output
3
This should work for you:
awk -F '\036' '{print NF-1}' file
3
-F '\036' sets input field delimiter as octal value 036
Awk may not be the best tool for this. Gnu grep has a cool -o option that prints each matching pattern on a separate line. You can then count how many matching lines are generated for each input line, and that's the count of your delimiters. E.g. (where ^^ in the file is actually hex 1e)
$ cat -v i
a^^b^^c
d^^e^^f^^g
$ grep -n -o $'\x1e' i | uniq -c
2 1:
3 2:
if you remove the uniq -c you can see how it's working. You'll get "1" printed twice because there are two matching patterns on the first line. Or try it with some regular ascii characters and it becomes clearer what the -o and -n options are doing.
If you want to print the line number followed by the field count for that line, I'd do something like:
$grep -n -o $'\x1e' i | tr -d ':' | uniq -c | awk '{print $2 " " $1}'
1 2
2 3
This assumes that every line in the file contains at least one delimiter. If that's not the case, here's another approach that's probably faster too:
$ tr -d -c $'\x1e\n' < i | awk '{print length}'
2
3
0
0
0
This uses tr to delete (-d) all characters that are not (-c) 1e or \n. It then pipes that stream of data to awk which just counts how many characters are left on each line. If you want the line number, add " | cat -n" to the end.
I have 2 csv files, these are their contents.
file1(23 fields)
data11,data12,ID1,data14...
data21,data22,ID2,data24...
data31,data32,ID3,data34...
file2 (22 fields)
ID1,value12,value13,...
ID1,value22,value23,...
ID1,value32,value33,...
ID2,value42,value43,...
ID3,value52,value53,...
The output should be...
OUTPUT:
data11,data12,ID1,data14,...,value12,value13
data11,data12,ID1,data14,...,value22,value23
data11,data12,ID1,data14,...,value32,value33
data21,data22,ID2,data24,...,value42,value43
data31,data32,ID3,data34,...,value52,value53
Can anyone help me to get this output using awk or any bash built-ins?
Thanks!
You can use join ..Specify the column order required for output after -o eg: 1.1 refers 1st column of 1st (file1) file. It is also required to pre-sort the input files
join -t "," -1 3 -2 1 -o 1.1,1.2,1.3,1.4,2.2,2.3
<( sort -t "," -k3 /tmp/file1 ) <( sort -t "," -k1 /tmp/file2 )
Sorry, my fault to misunderstand ur problem, try the following cmd, it should be what u want:
for line1 in `cat file1`;do id=`echo $line1|awk -F ',' '{print $3}'`;\
awk -v id=$id -v line1=$line1 -F ',' '($1==id){print line1","$0}' file2;done
the output of this cmd is
data11,data12,ID1,data14...,ID1,value12,value13,...
data11,data12,ID1,data14...,ID1,value22,value23,...
data11,data12,ID1,data14...,ID1,value32,value33,...
data21,data22,ID2,data24...,ID2,value42,value43,...
data31,data32,ID3,data34...,ID3,value52,value53,...
and if u don't want the repeated column of ID*, u can do this like
for line1 in `cat file1`;do id=`echo $line1|awk -F ',' '{print $3}'`;\
awk -v id=$id -v line1=$line1 -F ',' '($1==id){printf "%s",line1;\
for(i=2;i<NF;i++) printf ",%s",$i;print ","$NF}' file2;done
it won't print ID* in file2
data11,data12,ID1,data14...,value12,value13,...
data11,data12,ID1,data14...,value22,value23,...
data11,data12,ID1,data14...,value32,value33,...
data21,data22,ID2,data24...,value42,value43,...
data31,data32,ID3,data34...,value52,value53,...
----------wrong answer prior to updated---------
https://www.computerhope.com/unix/upaste.htm
HI,
u can use paste cmd to join related lines of different files
please use man paste cmd for detailed usage