Applescript- For every item that grep finds - applescript

Question

This code obviously won't work but I'm looking for a syntax change to make it work.
for every item that grep finds
set myCommand to do shell script "grep -w word test.log"
set mySecondCommand to do shell script "grep -w end test.log"
end
The following output should be correct (What I want):
word
end
word
end
instead I get because I do not have this theoretical "for every item that grep finds" statement (I don't want this output):
word
word
end
end

Answer 1

Your initial grep results will be in string format eg. one long string. In order to iterate them you will need to turn the string into a list, thus I use the "paragraphs" command. Once you have the initial grep results in list format, then you can use a repeat loop to process the items in the list. When you process the items you will need to store those results in a new list so that at the end of the script you can view the results in total. Something like this...
set firstWord to "word"
set secondWord to "end"
-- use the ls command and grep to find all the txt documents in your documents folder
set aFolder to (path to documents folder) as text
set grepResults to do shell script "ls " & quoted form of POSIX path of aFolder & " | grep \"txt\""
set grepResultsList to paragraphs of grepResults
-- search the found txt documents for the words
set totalResults to {}
repeat with aResult in grepResultsList
set thisPath to aFolder & aResult
try
set myCommand to paragraphs of (do shell script "grep -w " & firstWord & space & quoted form of POSIX path of thisPath)
set myCommandCount to count of myCommand
set end of totalResults to {thisPath, firstWord, myCommandCount, myCommand}
end try
try
set mySecondCommand to paragraphs of (do shell script "grep -w " & secondWord & space & quoted form of POSIX path of thisPath)
set mySecondCommandCount to count of mySecondCommand
set end of totalResults to {thisPath, secondWord, mySecondCommandCount, mySecondCommand}
end try
end repeat
return totalResults