In my Enyo app, I have a VirtualRepeater which produces Controls containing various text displays and an IntegerPicker.
I have two problems with this repeater:
1) If three rows are produced, clicking on the IntegerPicker in rows 1 and 2 brings up the drop-down picker UI over the top of the IntegerPicker in row 0.
2) I initialise each IntegerPicker with a max value using setMax(). However, if three rows are produced, the IntegerPickers in rows 0 and 1 will have the same max value as that in row 2.
It looks as if only one IntegerPicker is being created and is being used on the first row.
I tried replacing my VirtualRepeater with a Repeater, and changed my repeater row creation function to return a new instance of the item containing the IntegerPicker, instead of returning true. However this produces the error:
warning: enyo.Component.addComponent(): Duplicate component name "itemName" violates unique-name-under-owner rule, replacing existing component in the hash and continuing, but this is an error condition and should be fixed.
It seems that Repeaters need their delegates created inline, which seems quite inelegant.
This code sample illustrates the problem:
enyo.kind({
name:"Test",
kind:enyo.Control,
components: [
{
kind: "VirtualRepeater",
onSetupRow: "setupRow",
components: [{
name: "theIP", kind: "IntegerPicker", min:0
}]
}
],
setupRow: function(inSender, inIndex) {
if (inIndex < 3) {
this.$.theIP.setMax(inIndex);
return true;
}
return false;
}
});
How can I create an arbitrary number of IntegerPickers in my app? Any help appreciated!
What you are doing with theIP in your setupRow function is accessing a specific IntegerPicker itself, which is a child component of the Virtual Repeater. To set the max value of a given IntegerPicker corresponding to the row, give your VirtualRepeater a name attribute, like "PickerList":
kind: "VirtualRepeater",
onSetupRow: "setupRow",
name: "PickerList",
components:[//this should be empty to begin with]
Then you can access each row in the repeater like this:
setupRow: function(inSender, pickerMax) {
var newPicker = new IntegerPicker(pickerMax);
this.$.PickerList.push(newPicker);
To get a specific row in the VirtualRepeater you need to do it like this:
this.$.PickerList[1];
Here is an extended Enyo tutorial which makes use of the VirtualRepeater:
https://developer.palm.com/content/resources/develop/extended_enyo_tutorial.html
Related
We've just moved over from bootstrap to Vuetify, but i'm struggling with something.
We have some updates sent (over signalR) that update a list of jobs, i'd like to be able to target a job that has been changed and change the row color for that particular job for a few seconds so the operator can see its changed.
Has anyone any pointers on how we can do this on a Vuetify v-data-table
Thanks
I ran into the same problem. This solution is a bit crude and a bit too late, but may help someone else.
In this example I change the colour of the row permanently until the page reloads. The problem with a temporary highlight is that if the table is sorted there is no way to put the row in the visible part of the table - v-data-table will put it where it belongs in the sort, even if it's out of the view.
Collect the list of IDs on initial load.
Store the list inside data of the component.
Use a dynamic :class attribute to highlight rows if the ID is not in the list (added or edited rows)
Solution in detail
1. Use TR in the items template to add a conditional class.
<template slot="items" slot-scope="props">
<tr :class="newRecordClass(props.item.email, 'success')">
<td class="text-xs-center" >{{ props.item.email }}</td>
:class="newRecordClass(props.item.email, 'success')" will call custom method newRecordClass with the email as an ID of the row.
2. Add an additional array to store IDs in your data to store
data: {
hydrated: false,
originalEmails: [], <--- ID = email in my case
3. Populate the list of IDs on initial data load
update(data) {
data.hydrated = true; // data loaded flag
let dataCombined = Object.assign(this.data, data); // copy response data into the instance
if (dataCombined.originalEmails.length == 0 ) {
// collect all emails on the first load
dataCombined.originalEmails = dataCombined.listDeviceUsers.items.map( item => item.email)
}
return dataCombined;
}
Now the instance data.originalEmails has the list of IDs loaded initially. Any new additions won't be there.
4. Add a method to check if the ID is in the list
newRecordClass(email, cssClass) {
// Returns a class name for rows that were added after the initial load of the table
if (email == "" || this.data.originalEmails.length==0) return "" // initial loading of the table - no data yet
if (this.data.originalEmails.indexOf(email) < 0 ) return cssClass
}
:class="newRecordClass(..." binds class attribute on TR to newRecordClass method and is being called every time the table is updated. A better way of doing the check would be via a computed property (https://v2.vuejs.org/v2/guide/computed.html#Computed-Properties). Vue would only call it when the underlying data changed - a method is called every time regardless.
Removing the highlight
You can modify newRecordClass method to update the list of IDs with new IDs after a delay to change the colour to normal.
#bakersoft - Did you find a solution? I suspect there is an easier way to skin this cat.
I need to show multiple values (rank and vote) together separated by space as key:value in a webix datatable cell from the following structure :
id2: [{"rank":2, "vote":50}, {"rank":3, "vote":10}]
I want to show only the first element of this above array.
My snippet is here : https://webix.com/snippet/ca50874d
I am not able to figure out how to show these two values together in one cell.
Please help.
Thanks.
To show multiple values in the cell, or if you want to format the value according to you, you just need to use to template for that cell:
While specifying column configuration, you can specify the template for that particular column like below:
template:function(obj) {
}
This template will be called for each row, and obj contains the row object.
For your example you can specify the template like below:
template:function(obj) {
return obj.column1 +':' + obj.column2;
}
I further tried and could figure out the answer on my own. To show the first element of that array object, the 'map' attribute has to be used as below:
{ id:"id2", header:"Rank", width:80, map:"#id2[0].rank# : #id2[0].vote# "}
The working snippet for the same is here : https://webix.com/snippet/928bab77
grid.dataItem(selectedRow)
this is return the selected row which is a kendo.data.ObservableObject.
this object has all the columns for that grid's selected row. Is there a way to iterate thru all the columns and update.
or do i have to do it like this:
dataitem.set("Id", 1);
dataitem.set("name", Eric);
dataitem.set("age", 12);
As far as I understand what you are trying is to copy one JavaScript object into a Grid item, correct?
Let's assume that you have the new value in val:
var val = {
Id : 1,
name: "Eric",
age: 12
};
And you want to copy it in the selected row.
There are several ways of doing it:
What you just did.
Iterate through the different keys of val and copy the value.
Use jQuery extend.
Option 2.
for (var key in val) {
if (val.hasOwnProperty(key)) {
dataitem.set(key, val[key]);
}
}
Option 3.
$.extend(item, val);
item.set("uid", kendo.guid());
The first instruction performs a deep copy of val into item.
The second instruction makes the item dirty by just changing the UID.
NOTE: You don't need to update every single field using set, is enough changing one and all will get updated.
Given a jqGrid populated with local data and created with the option of idPrefix:"custTable" , all the generated rows get the prefix in the html id i.e. custTableRow_1 custTableRow_2 etc. Does this idPrefix'ed version of the id need to be passed in to the jqGrid methods, if so which ones?
for example to delete a row with deleteRowData does it need the prefixed id? how about setRowData or addRowData? when adding after row x it seems to need the prefixed for the srcrowid parameter. How about multiselect rows?
If I delete a row using the prefixed id of the row it disappears from the display but when I reload the grid the delete item shows up again in the grid, like it wasn't removed. This doesn't happen when idPrefix is not used.
thanks for any help.
The option idPrefix was introduced to hold ids on the HTML page unique even you have on the page the ids like the rowids loaded from the server. Typical example is two grids with the data loaded from the server. Let us you have two tables in the database where you use IDENTITY or AUTOINCREMENT in the definition of the PRIMARY KEY. In the case the primary key will be generated automatically in the table and will be unique inside the table, but there are not unique over the tables. So if you would use the primary keys as ids of the grids and place on one page two grids you can have id duplicates.
To solve the problem you can use idPrefix: "a" as additional option in the first grid and use idPrefix: "b" in the second grid. In the case locally jqGrid will uses everywhere ids with the prefix, but the prefix will be cut if the ids will be sent to the server.
So you will see locally in all callbacks (events) and in all methods (like setRowData, addRowData etc) the ids with the prefix, but on the server side the ids the prefixes will be removed immediately before sending to the server.
I recommend you additionally to read another answer about the restrictions in the ids which I posted today.
UPDATED: I looked through the code which you posed on jsfiddle and found some clear bugs in your code. You current code
1) use wrong algorithm to generate id of the new row. For example the following code
// generic way to create an animal
function newAnimal(collection, defaults) {
var next = collection.length + 1;
var newpet = {
id : next,
name: defaults.name + next,
breed: defaults.breed
};
return newpet;
}
use collection.length + 1 for the new id. It's wrong if you allows to delete the items. By adding of two items, deleting one from there and adding new item one more time follows to id duplicates. Instead of that it's more safe to use some variable which will be only incremented. You can use $.jgrid.randId() for example which code is very simple.
2) you call addRowData with adding a prefix manually (see dogsPrefix+newdog.id below). It's wrong because jqGrid adds the prefix one more time to the rows.
// add dog button actions
$('#dogAddAtEnd').click(function() {
var newdog = newAnimal(dogs, dogDefaults);
dogs.push(newdog);
dogAdded();
dogsTable.jqGrid('addRowData', dogsPrefix+newdog.id, newdog);
});
Probably there are more problems, but at least these problems can explain the problems which you described.
UPDATED 2: I examined new demo which you posted. It has still the lines
grid.jqGrid('addRowData', newanimal.id, newanimal,
"after", prefix+ followingId);
and
dogsTable.jqGrid('addRowData', dogsPrefix+newdog.id, newdog);
which must be fixed to
grid.jqGrid('addRowData', newanimal.id, newanimal,
"after", followingId);
and
dogsTable.jqGrid('addRowData', newdog.id, newdog);
Nevertheless I tested the demo after the changes and found bugs in code of addRowData, delRowData and setRowData. The problem are in the line of the delRowData and the same line of setRowData
var pos = $t.p._index[rowid];
can be fixed to the following
var id = $.jgrid.stripPref($t.p.idPrefix, rowid), pos = $t.p._index[id];
Inside of addRowData I suggest to include the line
var id = rowid; // pure id without prefix
before the line
rowid = t.p.idPrefix + rowid;
of addRowData. Another tow lines of addRowData
lcdata[t.p.localReader.id] = rowid;
t.p._index[rowid] = t.p.data.length;
should be changed to
lcdata[t.p.localReader.id] = id;
t.p._index[id] = t.p.data.length;
where unprefixed id will be used.
The modified code of you demo which uses the fixed version of jquery.jqGrid.src.js you can test here.
I will post my bug report to trirand later to inform the developer of the jqGrid. I hope that soon the bug fix will be included in the main code of jqGrid.
Additionally I recommend you to use $.jgrid.stripPref method to strip prefixes from the rowids. For example the function
//general delete selected
function deleteSelectedAnimal(list, grid, prefix)
{
var sel = grid.jqGrid('getGridParam', 'selrow');
if (sel.length)
{
var gridrow = sel;
//get the unprefixed model id
var modelid = gridrow;
if (prefix.length !== 0)
{
modelid = modelid.split(prefix)[1];
}
// make it a numeric
modelid = Number(modelid);
//delete the row in the collection
list = RemoveAnimal(list, modelid);
//delete the row in the grid
grid.jqGrid('delRowData', gridrow);
}
}
from your demo can be rewritten to the following
//general delete selected
function deleteSelectedAnimal(list, grid)
{
var sel = grid.jqGrid('getGridParam', 'selrow'),
gridPrefix = grid.jqGrid('getGridParam', 'idPrefix');
if (sel !== null)
{
//delete the row in the collection
// ??? the gogs list will be not modified in the way !!!
list = RemoveAnimal(list, $.jgrid.stripPref(gridPrefix, sel));
//delete the row in the grid
grid.jqGrid('delRowData', sel);
}
}
I am not sure that the line list = RemoveAnimal(list, $.jgrid.stripPref(gridPrefix, sel)); or the function RemoveAnimal do what you want, but it's not a problem which connected with jqGrid.
One more small remark about your code. You use already in the objects which you add to the grid the id property. It's the same name as defined in the localReader.id. In the case the data from the id property will be used as id attribute of the grid rows (<tr>). The local data parameter will save the id additionally to other properties which are build from the name property of the items of colModel. So I see no sense to define hidden column
{ key: true, name: 'id', align: 'left', hidden: true }
How you can see on the demo all stay works exactly as before if you remove id column from the grids which you use.
UPDATED 3: As promised before I posted the corresponding bug report here.
On my grid, after a user enters text on the bottom row, I am adding another row so they can fill out another row if needed. The grid will grow as needed by the user. This is working fine, however after a page reload and populating from db, the addrowdata() function does not honor existing row ids and creates duplicates, starting from 1 again, e.g. jqg1. It should look at existing row ids and create new unique ids. So if I have 5 rows already, it might start at jqg6. Here is the relevant code inside onCellSelect:
var records = jQuery("#table-1").jqGrid('getGridParam', 'records');
var lastRowId = jQuery("#table-1").jqGrid('getDataIDs')[records - 1];
if (lastRowId == id)
{
jQuery('#table-1').addRowData(undefined, {}, 'last');
}
I have also tried $.jgrid.randId() instead of undefined, same results as expected.
Thanks
Ryan
I think that the error is in the part where you fill grid with the data from the database. The data saved in the database has unique ids. The ids are not in the form jqg1, jqg2, ... So if should be no conflicts. You should just fill the id fields of the JSON with the ids from the database.
One more possibility is that you just specify the rowid parameter (the first parameter) of addRowData yourself. In the case you will have full control on the new ids of the rows added in the grid.
The code of $.jgrid.randId function is very easy. There are $.jgrid.uidPref initialized as 'jqg' and $.jgrid.guid initialized to 1. The $.jgrid.randId function do the following
$.jgrid.randId = function (prefix) {
return (prefix? prefix: $.jgrid.uidPref) + ($.jgrid.guid++);
}
If it is really required you can increase (but not decrease) the $.jgrid.guid value without any negative side effects.