Hey guys im using the method above like:
string = [array componentsJoinedByString:#"\n"];
this prints out each obj in my array, but what it prints out is:
{
Selected = 0;
name = "boots";
number = 69;
}
{
Selected = 0;
name = house;
number = 1001;
}
}
Selected = 0;
name = shirt;
number = 1234;
}
{
Selected = 0;
name = Brewski;
number = 4567;
}
and i just want it to print out:
Brewski
Boots...
etc..
The objects in your array seem to be dictionaries. You should do this instead.
[[array valueForKey:#"name"] componentsJoinedByString:#"\n"]
Related
jslint tell Unexpected 'for'.
so i think that i must convert for with foreach
but how?
if someone can help
thanks
// Grab the original element
var original = document.getElementsByTagName("noscript")[0];
// Create a replacement tag of the desired type
var replacement = document.createElement("span");
var i;
// Grab all of the original's attributes, and pass them to the replacement
for(i = 0, l = original.attributes.length; i < l; ++i){
var nodeName = original.attributes.item(i).nodeName;
var nodeValue = original.attributes.item(i).nodeValue;
replacement.setAttribute(nodeName, nodeValue);
}
// Persist contents
replacement.innerHTML = original.innerHTML;
// Switch!
original.parentNode.replaceChild(replacement, original);
You have a comma after i = 0, <========
it should be semicolon.
Another issue is declaring l = original.attributes.length you don't need the variable l
just use it as for(i = 0; i < original.attributes.length; ++i){
if you still wanna use a forEach you can do it as:
original.attributes.forEach(element => {
var nodeName = element.nodeName;
var nodeValue = element.nodeValue;
replacement.setAttribute(nodeName, nodeValue);
});
thanks for your answer, i got Uncaught TypeError: original.attributes.forEach is not a function
function Switch() {
var original = document.getElementsByTagName("noscript")[0];
var replacement = document.createElement("span");
original.attributes.forEach(element => {
var nodeName = element.nodeName;
var nodeValue = element.nodeValue;
replacement.setAttribute(nodeName, nodeValue);
});
// Persist contents
replacement.innerHTML = original.innerHTML;
// Switch!
original.parentNode.replaceChild(replacement, original);
}
foreach ($pos as $po) {
$po_value[] = 0;
$po_item_total = 0;
foreach ($po->po_items as $po_item) {
$po_item_total = $po_item->qty * $po_item->rate;
$po_value[$po->id] = $po_value[$po->id] + $po_item_total;
}
}
This line
$po_value[$po->id] = $po_value[$po->id] + $po_item_total;
Causes Undefined Offset error.
Could you please help
You are not setting key to your $po_value array to be $po->id and on your first iteration of the second foreach you are looking for it and it is missing.
This should fix it:
$po_value[$po->id] = 0;
Simplified version:
foreach($pos as $po){
$po_total[$po->id] = 0;
foreach($po->po_items as $po_item){
$po_total[$po->id]+= $po_item->qty * $po_item->rate;
}
}
I have an person model with two property like this:
int id;
String name;
and some object with this data:
person0 = {1,"James"};
person1 = {2,"James"};
person2 = {3,"James"};
person3 = {4,"Barbara"};
person4 = {5,"Barbara"};
person5 = {6,"Ramses"};
and array contain objects:
firstArray = [person0, person1, person2, person3, person4, person5];
Therefore how can have this array:
secondArray = [
[person0, person1, person2],
[person3, person4],
[person5]
]
Thank you.
If language does not matter.
map = new Map();
for (persona of personas) {
name = persona.name;
arrayForName = map.get(name);
if (arrayForName == null) {
arrayForName = [];
map.put(name, arrayForName);
}
arrayForName.put(persona)
}
The idea is to have a map (which is a collection key->value).
The value of the map should in turn be an array.
To add elements efficiently, you iterate only once through the data, and add arrays each time a new key is discovered (i.e. the name).
In Java it would be something like:
Map<String, List<Persona>> map = new HashMap<>();
for (Persona persona : personas) {
String name = persona.getName();
List<Persona> listForName = map.get(name);
if (listForName == null) {
listForName = new ArrayList<Persona>();
map.put(name, listForName);
}
listForName.add(persona)
}
Try this code in Java Android:
ArrayList<ArrayList<Person>> secondArr = new ArrayList<>();
ArrayList<Course> tempArr = new ArrayList<>();
for (int i = 0; i < firstArr.size(); i++) {
if ((i + 1) >= firstArr.size()) {
tempArr.add(firstArr.get(i));
secondArr.add(tempArr);
} else {
if (firstArr.get(i).name .equals( firstArr.get(i + 1).name) ) {
tempArr.add(firstArr.get(i));
} else {
tempArr.add(firstArr.get(i));
secondArr.add(tempArr);
tempArr = new ArrayList<>();
}
}
}
Finally secondArr prepared.
And if list not sorted we can use code like this:
for (int i = 0; i <firstArr.size() ; i++) {
boolean isAdd = false;
for (int j = 0; j < secondArr.size() ; j++) {
if (secondArr.get(j).get(0).getName().equals(firstArr.get(i).getName())){
secondArr.get(j).add(firstArr.get(i));
isAdd =true;
break;
}
}
if (!isAdd){
ArrayList<Person> arrayList = new ArrayList<>();
arrayList.add(firstArr.get(i));
secondArr.add(arrayList);
}
}
Let's say, I have following template.
Hello, {I'm|he is} a {notable|famous} person.
Result should be
Hello, I'm a notable person.
Hello, I'm a famous person.
Hello, he is a notable person.
Hello, he is a famous person.
The only possible solution I have in mind - full search, but it is not effective.
May be there is a good algorithm for such kind of job but I do not know what task about. All permutations in array is very close to this but I have no idea how to use it here.
Here is working solution (it's part of object, so here is only relevant part).
generateText() parses string and converts 'Hello, {1|2}, here {3,4}' into ['Hello', ['1', '2'], 'here', ['3', '4']]]
extractText() takes this multidimensional array and creates all possible strings
STATE_TEXT: 'TEXT',
STATE_INSIDE_BRACKETS: 'INSIDE_BRACKETS',
generateText: function(text) {
var result = [];
var state = this.STATE_TEXT;
var length = text.length;
var simpleText = '';
var options = [];
var singleOption = '';
var i = 0;
while (i < length) {
var symbol = text[i];
switch(symbol) {
case '{':
if (state === this.STATE_TEXT) {
simpleText = simpleText.trim();
if (simpleText.length) {
result.push(simpleText);
simpleText = '';
}
state = this.STATE_INSIDE_BRACKETS;
}
break;
case '}':
if (state === this.STATE_INSIDE_BRACKETS) {
singleOption = singleOption.trim();
if (singleOption.length) {
options.push(singleOption);
singleOption = '';
}
if (options.length) {
result.push(options);
options = [];
}
state = this.STATE_TEXT;
}
break;
case '|':
if (state === this.STATE_INSIDE_BRACKETS) {
singleOption = singleOption.trim();
if (singleOption.length) {
options.push(singleOption);
singleOption = '';
}
}
break;
default:
if (state === this.STATE_TEXT) {
simpleText += symbol;
} else if (state === this.STATE_INSIDE_BRACKETS) {
singleOption += symbol;
}
break;
}
i++;
}
return result;
},
extractStrings(generated) {
var lengths = {};
var currents = {};
var permutations = 0;
var length = generated.length;
for (var i = 0; i < length; i++) {
if ($.isArray(generated[i])) {
lengths[i] = generated[i].length;
currents[i] = lengths[i];
permutations += lengths[i];
}
}
var strings = [];
for (var i = 0; i < permutations; i++) {
var string = [];
for (var k = 0; k < length; k++) {
if (typeof lengths[k] === 'undefined') {
string.push(generated[k]);
continue;
}
currents[k] -= 1;
if (currents[k] < 0) {
currents[k] = lengths[k] - 1;
}
string.push(generated[k][currents[k]]);
}
strings.push(string.join(' '));
}
return strings;
},
The only possible solution I have in mind - full search, but it is not effective.
If you must provide full results, you must run full search. There is simply no way around it. You don't need all permutations, though: the number of results is equal to the product of the number of alternatives in each template.
Although there are multiple ways to implement this, recursion is among the most popular approaches. Here is some pseudo-code to get you started:
string[][] templates = {{"I'm", "he is"}, {"notable", "famous", "boring"}}
int[] pos = new int[templates.Length]
string[] fills = new string[templates.Length]
recurse(templates, fills, 0)
...
void recurse(string[][] templates, string[] fills, int pos) {
if (pos == fills.Length) {
formatResult(fills);
} else {
foreach option in templates[pos] {
fills[pos] = option
recurse(templates, fills, pos+1);
}
}
}
It seems like the best solution here is going to be n*m where n=the first array and m= the second array . There are nm required lines of output, which means that as long as you are only doing nm you aren't doing any extra work
The generic running time for this is where there is more than 2 arrays with options, it would be
n1*n2...*nm where each of those is equal to the size of the respective list
A nested loop where you just print out the value for the current index of the outer loop along with the current value for the index of the inner loop should do this properly
I want to set i to 0 of the first item from a json criteria, eg. if the criteria is green in this case the i will start from 3... if criteria = blue it will start on 2... i need to set it to start from 0 or 1 whether it is.. also how to count total of a criteria, eg. green total is 2,, blue=1, red=2... thanks in advance!
var myBox_html ="";
var i = 0;
function createDiv(1x,2x,3x) {
A = '<something>'+1x;
B = '<something>'+2x;
C = '<something>'+3x;
myBox_html += '<something-more>'+A+B+C;
}
criteria // is a parameter from url, in this case means green
get_it = function(doc) {
var jsonData = eval('(' + doc + ')');
for (var i=0; i<jsonvar.name.length; i++) {
var 1x = jsonvar.name[i].1;
var 2x = jsonvar.name[i].2;
var 3x = jsonvar.name[i].3;
if (1x == criteria){
var Div = createDiv(1x,2x,3x);
} else {null}
}
document.getElementById("myBox").innerHTML = myBox_html;
}
get_it();
json should look like this:
var jsonvar = {"name":[{"1":"red","2":"round","3":"fruit"},{"1":"red","2":"squared","3":"box"},{"1":"blue","2":"squared","3":"box"},{"1":"green","2":"squared","3":"box"},{"1":"green","2":"pear","3":"fruit"}]};
Consider several solutions:
1: Generate criteria-grouped JSON response on the server-side. E.g.
var jsonvar = '{"name":{
"red": [{"1":"red","2":"round","3":"fruit"}, {"1":"red","2":"squared","3":"box"}],
"blue": [{"1":"blue","2":"squared","3":"box"}],
"green":[{"1":"green","2":"squared","3":"box"}, {"1":"green","2":"pear","3":"fruit"}]}}';
2: Convert you JSON array to criteria-grouped format as defined above. Here is sample routine for such a grouping:
function group_elements (arr) {
var result = {};
for (var i=0; i < arr.length; i++) {
if (!result[arr[i][1]]) {
result[arr[i][1]] = [];
}
result[arr[i][1]].push(arr[i]);
}
return result;
}
Both solutions allows you to iterate only filtered records and count length of group.