Sorry everyone. My english is so bad,but i have some questions to ask.
When i try to use ajax get a freemarker view.It's not render just html code.
The following is my config.
springmvc-servlet.xml
<bean id="freemakerViewResolver" class="org.springframework.web.servlet.view.freemarker.FreeMarkerViewResolver">
<property name="cache" value="true" />
<property name="prefix" value="" />
<property name="suffix" value=".html" />
<property name="contentType" value="text/html;charset=UTF-8"></property>
<property name="requestContextAttribute" value="request" />
<property name="exposeSpringMacroHelpers" value="true" />
<property name="exposeRequestAttributes" value="true" />
<property name="exposeSessionAttributes" value="true" />
</bean>
freeMarkerConfigurer
<bean id="freeMarkerConfigurer"
class="org.springframework.web.servlet.view.freemarker.FreeMarkerConfigurer">
<property name="templateLoaderPath" value="/WEB-INF/views/" />
<property name="freemarkerSettings">
<props>
<prop key="template_update_delay">0</prop>
<prop key="default_encoding">UTF-8</prop>
<prop key="number_format">0.##########</prop>
<prop key="datetime_format">yyyy-MM-dd HH:mm:ss</prop>
<prop key="date_format">yyyy-MM-dd</prop>
<prop key="time_format">HH:mm:ss</prop>
<prop key="classic_compatible">true</prop>
<prop key="template_exception_handler">ignore</prop>
</props>
</property>
</bean>
my view
<ul>
<#list items as item>
<li>item.name</li>
</#list>
</ul >
response data
<ul></ul >
It's my wrong.I submit the wrong parameters,so the list is empty.
I have searched all the answers to 404 error pages about Spring MVC dispatcher, and I cannot find the answer to my issue.
I am also having an issue with Spring framework 4.1.6 as it no longer has the SimpleForm for forms for log in.
I understand that I need Maven to use the lastest Spring Security log in, which I plan to create a new Spring/Maven project and import this application into.
Just really want to know I have flow control going on before I export it to the Spring/Maven project. So any help with why my Welcome screen is not being found ....is much appreciated.
Heres my web.xml
enter code here<servlet>
<servlet-name>springMVCpizza</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/config/springMVCpizza-servletConfig.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>springMVCpizza</servlet-name>
<url-pattern>*.jsp</url-pattern>
</servlet-mapping>
<welcome-file-list>
<welcome-file>Welcome.jsp</welcome-file>
</welcome-file-list>
Here is my dispatcher-servlet:
<mvc:annotation-driven />
<context:component-scan base-package="com.pizza.controllers" />
<bean id="urlMapping" class="org.springframework.web.servlet.SimpleUrlHandlerMapping">
<property name="mappings">
<props>
<prop key="Welcome.jsp">welcomePageController</prop>
</props>
</property>
</bean>
<bean id= "welcomePageController" class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="LogIn" ref="LoginFormController">
</property>
</bean>
<bean id="loginFormController" class="com.pizza.controllers.loginFormController"></bean>
<bean id="localeChangeInterceptor" class="org.springframework.web.servlet.i18n.LocaleChangeInterceptor">
<property name="paramName" value="lang"/></bean>
<bean id="urlMapping" class="org.springframework.web.servlet.handler.SimpleUrlHandlerMapping">
<property name="interceptors">
<list>
<ref bean="localeChangeInterceptor"/>
</list>
</property>
<property name="urlMap">
<map>
<entry key="/LogIn.jsp">
<ref bean="loginFormController"/>
</entry>
</map>
</property>
</bean>
<bean id="loginFormController" class="com.pizza.web.LoginFormController">
`enter code here`<property name="commandName"><value>login</value></property>
`enter code here` <property name="commandClass"><value>com.pizza.web.LogIn</value></property>
</bean>
<bean id="loginValidator" class="com.pizza.web.LoginValidator"/>
<bean id="loginFormController" class="com.pizza.controllers.LoginFormController">
<property name="sessionForm"><value>false</value></property>
<property name="commandName"><value>login</value></property>
<property name="commandClass"><value>com.pizza.web.LogIn</value> </property>
<property name="validator"><ref bean="loginValidator"/></property>
<property name="formView"><value>LogIn.jsp</value></property>
<property name="successView"><value>success</value></property>
<property name="urlMap">
<map>
<entry key="/LogIn.jsp">
<ref bean="loginFormController"/>
</entry>
</map>
</property>
</bean>
<bean id="LocaleChangeInterceptor"
class="org.springframework.web.servlet.i18n.LocaleChangeInterceptor">
<property name="paramName" value="hl"/>
</bean>
<bean id="localeResolver" class="org.springframework.web.servlet.i18n.SessionLocaleResolver"/>
<bean id="ViewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix" value="/WEB-INF/jsp/" />
<property name="suffix" value=".jsp" />
</bean>
<bean id="multipartResolver" class="org.springframework.web.multipart.commons.CommonsMultipartResolver" >
<!-- maximum file size in bytes -->
<property name ="maxUploadSize" value="100000"/>
</bean>
Heres the Welcome jsp:
<%# page language="java" contentType="text/html; charset=ISO-8859-1"
pageEncoding="ISO-8859-1"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>Welcome to the Pizza Store</title>
</head>
<body bgcolor="#EEEEEE">
<center>
<h1>Welcome to the Pizza Store!</h1>
Sign In
<p>Or </p> Create Account
</center>
</body>
</html>
I am facing trouble in JSP spring internationalization. My dispatcherServlet.xml contains:
<bean id="localeResolver"
class="org.springframework.web.servlet.i18n.SessionLocaleResolver">
<property name="defaultLocale" value="en" />
</bean>
<bean id="localeChangeInterceptor"
class="org.springframework.web.servlet.i18n.LocaleChangeInterceptor">
<property name="paramName" value="language" />
</bean>
<bean class="org.springframework.web.servlet.mvc.support.ControllerClassNameHandlerMapping" >
<property name="interceptors">
<list>
<ref bean="localeChangeInterceptor" />
</list>
</property>
</bean>
<!-- Application Message Bundle -->
<bean id="messageSource" class="org.springframework.context.support.ReloadableResourceBundleMessageSource">
<property name="basename" value="/WEB-INF/messages/messages" />
<property name="cacheSeconds" value="0" />
<property name="defaultEncoding" value="UTF-8"/>
</bean>
and my jsp contains
<html>
<head>
<title>Admin</title>
</head>
<body>
<a href=<c:url value="/j_spring_security_logout"/>>Logout</a><br/>
Language : English|
Chinese
<h1>
<spring:message code="only.Admin.allowed.here" text="default text" />
</h1>
Current Locale : ${pageContext.response.locale}
</body>
</html>
The default EN language works fine, but I am not able to change the language into Chinese while clicking on Chinese option. The address bar URL changes to /admin?language=en to /admin? language=zh_CN but displays no result.
Thanks in advance.
I'm struggling to make something veeery simple work. Everything I really need to do is to write a property value in a view, i.e.:
<!DOCTYPE html>
<head>
...
<base href="${properties.config.baseurl}" />
...
</head>
<body>
...
</body>
</html>
My Spring MVC configuration (relevant bit):
<bean id="properties" class="org.springframework.beans.factory.config.PropertiesFactoryBean">
<property name="locations">
<list><value>/WEB-INF/config.properties</value></list>
</property>
</bean>
<bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix" value="/WEB-INF/jsp/" />
<property name="suffix" value=".jsp" />
<property name="exposedContextBeanNames">
<list><value>properties</value></list>
</property>
</bean>
/WEB-INF/config.properties file:
config.baseurl = http://localhost:8080/
The view doesn't display anything at all (i.e. <base href="" />), can anyone explain to me why?
Thank you.
You need to use
${properties['config.baseurl']}
rather than
${properties.config.baseurl}
Otherwise it will try to navigate config.baseurl like a bean path, rather than as a string literal.
I am working on a web app where I have most of my pages making use of apache tiles (2.1.2), but a few of them need to just be plain jsps.
I am having a problem in that both an InternalResourceViewResolver and a UrlBasedViewResolver will try to resolve the view no matter what, so that no matter which ordering I use, it will either fail on the plain JSP pages, or on the tiles pages.
Here is the config:
<bean id="tilesViewResolver" class="org.springframework.web.servlet.view.UrlBasedViewResolver">
<property name="viewClass" value="org.springframework.web.servlet.view.tiles2.TilesView"/>
<property name="order" value="0"/>
</bean>
<bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix" value="/"/>
<property name="suffix" value=".jsp"/>
<property name="order" value="1"/>
</bean>
To make it more clear what I am trying to do, I need to be able to have view states like this:
<view-state id="someState" view="/someDir/foo"><!--render foo.jsp -->
<transition on="foo" to="bar"/>
</view-state>
<view-state id="someState" view="something.core"><!--render tile defintion named 'something.core' -->
<transition on="foo" to="bar"/>
</view-state>
Does anyone know how to configure things so that I can get it to render tiles definitions and plain jsps?
As you say, you cannot chain these together. The javadoc for both states clearly that they must both be at the end of the resolver chain.
I suggest that if you really need to use these togather, then you write a simple custom implementation of ViewResolver which takes the view name, and decides which of your two "real" view resolvers to delegate to. This assumes that you can tell which resolver to call based on the view name.
So you'd define a custom ViewResolver like this:
public class MyViewResolver implements ViewResolver {
private ViewResolver tilesResolver;
private ViewResolver jspResolver;
public void setJspResolver(ViewResolver jspResolver) {
this.jspResolver = jspResolver;
}
public void setTilesResolver(ViewResolver tilesResolver) {
this.tilesResolver = tilesResolver;
}
public View resolveViewName(String viewName, Locale locale) throws Exception {
if (isTilesView(viewName)) {
return tilesResolver.resolveViewName(viewName, locale);
} else {
return jspResolver.resolveViewName(viewName, locale);
}
}
private boolean isTilesView(String viewName) {
.....
}
}
You'd need to implement the isTilesView method to decide which resolver to delegate to.
In the XML config, define this new view resolver, and make sure it appears before the other ones.
<bean class="MyViewResolver">
<property name="tilesResolver" ref="tilesViewResolver"/>
<property name="jspResolver" ref="viewResolver"/>
</bean>
I've just solved the same problem by splitting the *-servlet.xml config file in two; in my case the main application uses Tiles, but I want QUnit tests to be simple JSPs.
app-servlet.xml contains only the Tiles view resolver, tests-servlet.xml only contains the JSP view resolver and web.xml mappings are dispatching requests to the correct servlet basing on the URL.
<servlet-mapping>
<servlet-name>app</servlet-name> <!-- will reach app-servlet.xml -->
<url-pattern>/foo</url-pattern> <!-- will use "foo" Tile -->
<url-pattern>/bar</url-pattern> <!-- will use "bar" Tile -->
</servlet-mapping>
<servlet-mapping>
<servlet-name>tests</servlet-name> <!-- will reach tests-servlet.xml -->
<url-pattern>/foo-test</url-pattern> <!-- will use foo-test.jsp -->
<url-pattern>/bar-test</url-pattern> <!-- will use bar-test.jsp -->
</servlet-mapping>
It looks like you're on the right track, but the thing to bear in mind is that some view resolvers behave as if they have always resolved the view. You need to make sure to put such resolvers last in your ordering. I believe the Tiles view is one such.
Edit: whoops... yes, the other poster is correct, both of these resolvers will do 'always match' so you can't use them both in a chain. Another alterative would be to try to extend the TilesView to do a simple JSP render if it cant find a configured tile view.
Yes you can use any number of view resolver in your your project.
So you can use both 'tiles View resolver' and 'Internal view resolver' in same project. .
you have to configure a ContentNegotiatingViewResolver . .
and give order value in your view resolvers.
<property name="order" value="int Value here" />
like I have given tiles view resolver 2 and internalviewresolver 3. .It will first check in tiles definitions if a view is not found in tiles it will be checked in InternaiViewResolver
here is some configurations that works for me.
<bean
class="org.springframework.web.servlet.view.ContentNegotiatingViewResolver">
<property name="order" value="1" />
<property name="mediaTypes">
<map>
<entry key="json" value="application/json" />
<entry key="html" value="text/html" />
</map>
</property>
<property name="parameterName" value="accept"></property>
<property name="favorParameter" value="true"></property>
<property name="defaultContentType" value="text/html"></property>
<property name="viewResolvers">
<list>
<ref bean="tilesViewResolver" />
<ref bean="internalViewResolver" />
</list>
</property>
<property name="defaultViews">
<list>
<bean
class="org.springframework.web.servlet.view.json.MappingJacksonJsonView" />
</list>
</property>
<property name="ignoreAcceptHeader" value="true" />
</bean>
<!-- Configures the Tiles layout system -->
<bean class="org.springframework.web.servlet.view.tiles2.TilesConfigurer"
id="tilesConfigurer">
<property name="definitions">
<list>
<value>/WEB-INF/layouts/layouts.xml</value>
<!-- Scan views directory for Tiles configurations -->
<value>/WEB-INF/views/**/views.xml</value>
</list>
</property>
</bean>
<bean id="tilesViewResolver"
class="org.springframework.web.servlet.view.UrlBasedViewResolver"
p:viewClass="org.springframework.web.servlet.view.tiles2.TilesView">
<property name="order" value="3" />
</bean>
<bean id="internalViewResolver"
class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="order" value="2" />
<property name="prefix">
<value>/WEB-INF/views/</value>
</property>
<property name="suffix">
<value>.jsp</value>
</property>
</bean>
I resolved this issue by simply adding tiles definition for plain jsp's layout, like this:
<definition name="plain-jsp.layout" template="/WEB-INF/layouts/plainJsp.jspx" >
<put-attribute name="content" value=""/>
</definition>
Then you just can use this layout as template for including your simple jsp files.
<definition name="catalog/details" extends="plain-jsp.layout">
<put-attribute name="content" value="/WEB-INF/views/catalog/details.jspx"/>
</definition>
And layout template file:
<html xmlns:tiles="http://tiles.apache.org/tags-tiles"
xmlns:jsp="http://java.sun.com/JSP/Page" version="2.0">
<jsp:output doctype-root-element="HTML"/>
<jsp:directive.page contentType="text/html;charset=UTF-8" />
<jsp:directive.page pageEncoding="UTF-8" />
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
<meta http-equiv="X-UA-Compatible" content="IE=8" />
</head>
<body>
<div id="content">
<tiles:insertAttribute name="content"/>
</div>
</body>
</html>