yii set selected dropdownlist from other dropdownlist - drop-down-menu

i have 4 dropdownlist, 1 dropdownlist as master to control 3 dropdownlist other, this my sample code for master dropdownlist.
<div class="row">
<?php echo $form->labelEx($truck,'Truck'); ?>
<?php echo CHtml::dropDownList('idt',$truck->idt,CHtml::listData(Truck::model()->findAll(),'idt','number'),
array(
'value'=>'1',
'ajax' => array(
'type'=>'POST',
'url'=>CController::createUrl('FindTruck'),
'data'=>array('idt'=>'js:this.value'),
'dataType'=>'html',
))); ?>
</div>
<div class="row">
<?php echo $form->labelEx($employee,'Driver'); ?>
<?php echo CHtml::dropDownList('driver','$variable',CHtml::listData(Employe::model()->findAll(),'ide','name')); ?>
</div>
This My js setDriver
function setDriver(name,value){
document.getElementById(name).value = value
}
and this my controller
public function actionFindTruck() {
echo "<script>setDriver('driver',3);</script>"; // test satatic data
}
the question what code must i write on controller (ActionFindTruck) to change value of $variable above, so if i change Truck, the Driver will be change selected.
Thanks for help.

This is the way I did it, you should be able to change the values to your environment:
public function actionUpdateDropdown()
{
// ajax function to retrieve categories by country:
$lang_id = (!empty($_POST['feature']['language_id'])) ? $_POST['feature']['language_id'] : DEFAULT_LANG_ID;
$data = category::model()->findAll('language_id=:parent_id',
array(':parent_id'=>(int) $lang_id));
$data = CHtml::listData($data,'id','name');
if (!empty($data)) { echo '<option value="">Select Category...</option>'; }
foreach($data as $value=>$name) {
echo CHtml::tag('option',
array('value'=>$value),CHtml::encode($name),true);
}
}

There is a nice discussion of creating dependent drop downs at this URL:
Creating a dependent dropdown

Related

Codeigniter after insert success message show in view

I am new in Codeigniter and I need to show success and error message after insert data's in database.
How can I show the message in the view page?
This is my coding:
Model
function addnewproducts($data)
{
if($data['product_name']!="" && $data['product_qty']!="" && $data['product_price']!="" && $data['date']!="")
{
$res=$this->db->insert('product_list',$data);
return $this->db->insert_id();
}
else
{
return false;
}
}
Controller
function addnewproduct()
{
$this->load->model('products');
$data['product_name'] = trim(strip_tags(addslashes($this->input->post('product_name'))));
$data['product_qty'] = trim(strip_tags(addslashes($this->input->post('product_qty'))));
$data['product_price'] = trim(strip_tags(addslashes($this->input->post('product_price'))));
$data['datetime']=date('d-m-Y');
$res = $this->products->addnewproducts($data);
if($res==true)
{
$data['success'] = 'Successful';
$this->load->view('addproduct',$data);
}
}
View
<p><?php echo $success; ?></p>
There are many ways but below is which i recommend:
Set temp session in controller on success or error:
$res = $this->products->addnewproducts($data);
if($res==true)
{
$this->session->set_flashdata('success', "SUCCESS_MESSAGE_HERE");
}else{
$this->session->set_flashdata('error', "ERROR_MESSAGE_HERE");
}
In View you can display flashdata as below:
echo $this->session->flashdata('success');
or
echo $this->session->flashdata('error');
Source : Codeigniter official website https://codeigniter.com/userguide3/libraries/sessions.html
I appreciate that you got your answer but I think flash data is bit old now, as we can use bootstrap to alert if any error and that looks good to on web page.
In controller
$res = $this->products->addnewproducts($data);
if($res==true)
{
$this->session->set_flashdata('true', 'write_the_message_you_want');
}
else
{
$this->session->set_flashdata('err', "write_the_message_you_want");
}
In View
<?php
if($this->session->flashdata('true')){
?>
<div class="alert alert-success">
<?php echo $this->session->flashdata('true'); ?>
<?php
} else if($this->session->flashdata('err')){
?>
<div class = "alert alert-success">
<?php echo $this->session->flashdata('err'); ?>
</div>
<?php } ?>
Controller:
function addnewproduct()
{
$this->load->model('products');
$data['product_name'] = trim(strip_tags(addslashes($this->input->post('product_name'))));
$data['product_qty'] = trim(strip_tags(addslashes($this->input->post('product_qty'))));
$data['product_price'] = trim(strip_tags(addslashes($this->input->post('product_price'))));
$data['datetime']=date('d-m-Y');
if($this->products->addnewproducts($data));
{
$this->session->set_flashdata('Successfully','Product is Successfully Inserted');
}
else
{
$this->session->set_flashdata('Successfully','Failed To
inserted Product');
}
// redirect page were u want to show this massage.
redirect('Controller/Fucntion_name','refresh');
}// close function
view :
On Redirect Page write This code top of Form
<?php if($responce = $this->session->flashdata('Successfully')): ?>
<div class="box-header">
<div class="col-lg-6">
<div class="alert alert-success"><?php echo $responce;?></div>
</div>
</div>
<?php endif;?>

Form is not getting submitted when render partial in Yii

I am partially rendering a form in a view in which user can add subaccounts(profiles). The view in which the form is called is another form where all subaccounts are listed as radiolist.
Below is my view.
<div class="inputs">
<?php $form=$this->beginWidget('CActiveForm', array(
'id'=>'selectUser-form',
'enableAjaxValidation' => false,
)); ?>
<?php echo CHtml::activeRadioButtonList($model,'id', $model->getSubAccounts(),array('prompt'=>'Please Select'));?>
<?php echo CHtml::submitButton($model->isNewRecord ? 'Book Now' : 'Save'); ?>
<?php echo CHtml::Button('Cancel',array('submit'=>array('cancel','id'=>$model->a_id)));?>
<?php $this->endWidget(); ?>
<div id="data"></div>
<?php echo CHtml::ajaxButton ("Add Users",
CController::createUrl('/user/user/addSubAccount'),
array('update' => '#data'));
?>
Below is my addSubAccount action.
public function actionAddSubAccount()
{
$profile=new YumProfile;
if (isset($_POST['YumProfile']))
{
$profile->attributes = $_POST['YumProfile'];
$profile->user_id=Yii::app()->user->id;
if($profile->save())
$this->redirect(array('/home/create'));}
if(!Yii::app()->request->isAjaxRequest){
$this->render('subaccount_form', array('profile'=>$profile));}
else{
$this->renderPartial('subaccount_form', array('profile'=>$profile));
}
}
Below is subaccount_form.
<?php $this->title = Yum::t('SubAccounts');?>
<div class="wide form">
<?php $activeform = $this->beginWidget('CActiveForm', array(
'id'=>'subaccount-form',
'enableAjaxValidation'=>true,
'enableClientValidation'=>true,
'clientOptions' => array(
'validateOnChange' => true,
'validateOnSubmit' => true,
),
));
?>
<div class="row"> <?php
echo $activeform->labelEx($profile,'Firstname');
echo $activeform->textField($profile,'firstname');
echo $activeform->error($profile,'firstname');
?> </div>
<div class="row"> <?php
echo $activeform->labelEx($profile,'Lastname');
echo $activeform->textField($profile,'lastname');
echo $activeform->error($profile,'lastname');
?> </div>
<div class="row"> <?php
echo $activeform->labelEx($profile,'Age');
echo $activeform->textField($profile,'age');
echo $activeform->error($profile,'age');
?> </div>
<div class="row submit">
<?php echo CHtml::submitButton(Yum::t('Add')); ?>
</div>
<?php $this->endWidget(); ?>
My form is rendering. But it's not getting submitted.What am i doing wrong?
After submitting,I need the view to be refreshed and to display the newly added user as an option in the radio list.
EDIT:
I tried like adding the following in the CActiveForm Widget array:
'action' => array( '/user/user/addsubAccount' ),
But still no result.Instead it is saving my data two times when i go through my direct way,meaning render method. :-(
It is because
'enableAjaxValidation'=>true,
Ajax validation is set to true in your form. Set its value to false
'enableAjaxValidation'=>FALSE, and then your form will submit :)
and if you want it to be true only then you should uncomment
$this->performAjaxValidation($model);
in your controller's action
Update 1
if(!Yii::app()->request->isAjaxRequest){
$this->render('subaccount_form', array('profile'=>$profile));}
else{
//change this line
$this->renderPartial('subaccount_form', array('profile'=>$profile),FALSE,TRUE);
}
This link might help you
on renderPartial the action attribute of the form is set to the current page instead of being set to the actual update or create url
My Solution
$form=$this->beginWidget('CActiveForm', array(
'id'=>'country-form',
'action' => Yii::app()->createUrl(is_null(Yii::app()->request->getParam('id'))?'/country/create':'/country/update/'.Yii::app()->request->getParam('id')),

How to use ajax with codeigniter's modules

I have a page written in codeigniter framework.
Now I want to add a button to page (eg 'show more') that will get data with 'ajax.php' from the database and display them on the site, but I do not want it separately connect to the database and then get the results, just want to be able to collect data (in ajax.php) as well as in codeigniter controllers (using models)...
Hope you understand me :)
Here you go just add view more button and call this js and ajax function..This is code i have used please see it and use it as per your requirment
$('.more').live("click",function()
{
var this_tag = $(this);
var ID = $(this).attr("id");
if(ID)
{
$("ol#updates").addClass('tiny-loader');
this_tag.html('Loading.....');
$.post(siteUrl+"ajax/ajax_more",{lastmsg:ID,restid:$(this_tag).data("restid")},function(html){
$("ol#updates").removeClass('tiny-loader');
$("ol#updates").append(html);
$("#more"+ID).remove();// removing old view-more button
});
}
else
{
this_tag.fadeOut('slow');// no results
}
return false;
});
code in ajax file
<?php if ( ! defined('BASEPATH')) exit('No direct script access allowed');
class Ajax_more extends CI_Controller {
public function __construct()
{
parent::__construct();
$this->load->model('general_model');
$this->limit =REVIEW_DETAIL;
}
public function index($offset = 0)
{
$lastmsg=$this->input->post('lastmsg');
$rest_id=$this->input->post('restid');
$value=('reviews.*,usermaster.Name as User');
$joins = array
(
array
(
'table' => 'tk_usermaster',
'condition' => 'usermaster.Id = reviews.UserId',
'jointype' => 'leftouter'
),
);
$this->results = $this->general_model->get_joinlist('reviews',$value,$joins,array('reviews.Status'=>'Enable','reviews.RestaurantId'=>$rest_id,'reviews.Id <'=>$lastmsg),'reviews.Id','desc',$this->limit,$offset);
$data['list_review']= $this->results['results'];
?>
<?php foreach ($data['list_review'] as $row): ?>
<div class="user_reviews_data" >
<div class="width-20 float-left">
<span class="padleft-10"><?php echo $row->User; ?> </span>
<br/>
<span class="padleft-10 "><div class="rateit" data-rateit-value="<?php echo $row->Rating;?>" data-rateit-ispreset="true" data-rateit-readonly="true"></div></span>
<div class="muted padleft-10 float-left"><small><?php echo date('dS M Y' ,strtotime($row->CreatedDate)); ?></small></div>
</div>
<div class="width-80 float-left"><?php echo $row->Feedback;?></div>
<span class="report_span">Report this Feedback <img src="<?php echo base_url();?>themes/images/FLAG_GREY.png"></span>
</div>
<?php
$msg_id = $row->Id;
endforeach; ?>
</div>
<div id="more<?php echo #$msg_id; ?>" class="btn-container center_text morebox">
View More
</div>
<?php
}
}

CodeIgniter Update Not Working

I have a form in a modal that I'm using to do an update on a record. The form seems to submit okay, the URL in the browser points to the right location (domain.net/cities/update_city/1) but no view shows up and the record is never updated. I've searched the internet but most tutorials seem to skim over the update or hardcode the id to update. I've only been using CI for a week.
Model Code
// Edit City
function edit_city($city_id) {
$data = array('city_name' => $this->input->post('city_name'));
$this->db->where('city_id', $city_id);
$this->db->update('cities', $data);
}
View Code (Form is in a modal and gets city_id added by jQuery)
<div class="modal-body">
<?php $this->load->helper('form'); ?>
<?php echo form_open('/cities/update_city/'); ?>
<label class="control-label" for="name">City</label>
<input type="text" name="city_name" id="city_name" value=""/><br />
<input type="submit" name="submit" class="btn-small btn-primary" value="Edit City" />
<button class="btn-small" data-dismiss="modal">Cancel</button>
<?php echo form_close(); ?>
</div>
<script>
// scripts for modal windows
$(document).on("click", ".edit-modal", function () {
var city_name = $(this).data('name');
var city_id = $(this).data('id');
$(".modal-body #city_name").val( city_name );
//set the forms action to include the city_id
$(".modal-body form").attr('action','/cities/update_city/'+city_id);
$('#editCityDialog').modal('show');
});
Controller Code
// Update City
function update_city($city_id) {
$this->load->model('cities_model');
if ($this->input->post('submit')) {
$data = array('city_name' => $this->input->post('city_name'));
$this->cities_model->edit_city('cities', array('city_id' => $city_id),$data);
redirect('/cities');
}
}
Here is an example, you can use it to update easily (i'm bad at english, sorry).
Model:
class Cities_model extends CI_Model{
function edit($table,$where,$data){
foreach ($where as $key => $value){
$this->db->where($key,$value);
}
$this->db->update($table,$data);
}
}
Controller:
function update_city($city_id){
$this->load->model('cities_model');
if($this->input->post('submit'){
$data = array('city_name' => $this->input->post('city_name'));
$this->cities_model->edit('cities',array('city_id' => $city_id),$data); //(table,where,data); see in model.
redirect('');
}
}
* if you go a link as "http://......update_city/2" and a function update_city($city_id), $city_id will receive as "2" and you need not to write uri_segment to get $city_id. Hope that help you
EDIT :
Controller:
function update_city($city_id) {
$this->load->model('cities_model');
if ($this->input->post('submit')) {
$this->cities_model->edit_city($city_id);
redirect('/cities');
}
}

can't use multiple ajaxLink for loading CJuiDialog widget

I have a problem when using multiple ajaxLink for loading CJuiDialog widget in yii. I'm using multiple dropdowns, each dropdown's value determine next dropdown.
Here is my code for viewing first dropdown and a link to create new item using Cdialog widget.
<?php $cs = Yii::app()->getClientScript();
$cs->registerCoreScript("jquery");
?>
<div class="form">
<?php $form=$this->beginWidget('CActiveForm', array(
'enableAjaxValidation'=>false,
)); ?>
<div class="row">
<?php
echo $form->labelEx($model,'uname'); ?>
<?php echo $form->dropDownList($model,'uname',$model- >getUniversityList(),array('onchange'=>'getSchemes(this.value)','empty'=>'Select university')); ?>
<?php echo $form->error($model,'uname'); ?>
<?php //create university dialoge box
if(!Yii::app()->user->isGuest)
{
echo CHtml::ajaxLink('create new university',array('university/dialoge'),array(
'success'=>'js:function(data){
$("#createUniversity").dialog("open");
document.getElementById("create_university").innerHTML=data;
}'));
$this->beginWidget('zii.widgets.jui.CJuiDialog',array(
'id'=>'createUniversity',
'options'=>array(
'title'=>'Create University',
'autoOpen'=>false,
'modal'=>'true',
'width'=>'auto',
'height'=>'auto',
),
));
echo "<div id='create_university'></div>";
$this->endWidget('zii.widgets.jui.CJuiDialog');
}
?>
<div id="scheme">
</div>
</div>
<?php $this->endWidget(); ?>
</div>
<input type="hidden" id="url" value="<?php echo $this->createUrl('scheme/test'); ?>">
this works pretty good.
here is the javascript code for loading next dropdown in the same view file
<script type="text/javascript">
function getSchemes(uid)
{
if(uid==""){
document.getElementById("scheme").innerHTML='';
return;
}
jQuery(function($){
var url=document.getElementById("url").value;
$.post(url, { uid:uid },
function(data){
document.getElementById("scheme").innerHTML=data;
document.getElementById("scheme_link").style.display="block";
});
});
}
The scheme drop down is loaded as the scheme view code is
<?php $cs = Yii::app()->getClientScript();
$cs->registerCoreScript("jquery");
?>
<?php
echo "<div class=".'label'."><label for=".'sch'.">Scheme</label></div>";
echo "<select id=".'sch'." onchange='getDepartments(this.value);'>";
echo "<option value=".''.">"."Select Scheme</option>";
foreach($schemes as $s)
{
echo "<option value='".$s->schemeid."' >".$s->scheme_name."</option>";
}
echo "</select>";
?>
<?php
if(!Yii::app()->user->isGuest)
{
echo CHtml::ajaxLink('create new Scheme',array('scheme/dialoge','id'=>5),array(
'success'=>'js:function(data1){
$("#createScheme").dialog("open");
document.getElementById("create_scheme").innerHTML=data;
}'));?>
<?php
$this->beginWidget('zii.widgets.jui.CJuiDialog',array(
'id'=>'createScheme',
'options'=>array(
'title'=>'Create Scheme',
'autoOpen'=>false,
'modal'=>'true',
'width'=>'auto',
'height'=>'auto',
),
));
echo "<div id='create_scheme'></div>";
$this->endWidget('zii.widgets.jui.CJuiDialog');
}
?>
<div id="department">
</div>
<input type="hidden" id="urldepart" value="<?php echo $this->createUrl('department/test'); ?> ">
the second ajaxLink is shown as create new scheme but on clicking the link it shows the old create university dialog box instead of create scheme.
The simplest solution for this is to create the ID of the element that is causing problems as random.
Try adding:
'id' => 'some-element'.uniqid() // avoid mutliple ajax request because of using live
in the $htmlOptions array of ajaxLink

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