elisp create unnamed buffer from contents of file - elisp

Question

I was trying some code from Elisp Cookbook, and I initially tought that this code:
(defun process-file (file)
"Read the contents of a file into a temp buffer and then do
something there."
(when (file-readable-p file)
(with-temp-buffer
(insert-file-contents file)
(goto-char (point-min))
(while (not (eobp))
;; do something here with buffer content
(forward-line)))))
Will create a new ( unnamed/unsaved ) buffer on my emacs window, having the contents of that file ( and maybe open it in the foreground ). However, this doesn't happen. Can you guide me towards this?
EDIT: I experimented a little, and got to this:
(defun myTest (file)
(interactive "f")
; check if file is readable
(when (file-readable-p file)
; create a new "untitled" buffer
(let ((myBuf (get-buffer-create "untitled")))
; make it the current displayed buffer
(switch-to-buffer myBuf)
(insert "Hello"))))
Is this the way to do it?
Since this is a buffer named "untitled", I can only have one of these in a session. Is there something I could use to have more than one, without resorting to random numbers?

Answer 1

The elisp way to generate a unique buffer name is to use generate-new-buffer-name. The documentation is:
(generate-new-buffer-name NAME &optional IGNORE)
Return a string that is the name of no existing buffer based on NAME.
If there is no live buffer named NAME, then return NAME. Otherwise
modify name by appending `', incrementing NUMBER (starting at
2) until an unused name is found, and then return that name. Optional
second argument IGNORE specifies a name that is okay to use (if it is
in the sequence to be tried) even if a buffer with that name exists.