Jquery and ajax - ajax

Question

I am quite new to JS and JQ so I am ask this basic question. I have code like this:
$(".delete").click(function() {
var commentContainer = $(this).parent();
var id = $(this).attr("id");
var string = 'id='+ id ;
$.ajax({
url: "<?php echo site_url('messages/delete') ?>",
type: "POST",
data: string,
cache: false,
success: function(){
commentContainer.slideUp('1500', function() {$(this).remove();
$('#messages').fadeOut('1000');
});
}
});
return false;
});
For now it is working like it should. But I want to add something more. Div with id #messages contains all messages, and I wish that upon deleting message it fadeout(it is working) and then load new data and present all messages again without the deleted one.
Also, there is a counter that counts unread messages, and I created separate page for ajax purpose, but I don't know how to go on from fadeOut.
This is the code from the seperate page:
<?php if(isset ($messages)) { ?>
<?php foreach ($messages as $msg){ ?>
<div class="col_3">
<?php
if($msg['read'] == 0){ echo 'Status of message: Unreaded';}
elseif($msg['read'] == 1){echo 'Status of message: Readed';}
echo "<p>Message from: $msg[name]</p>";
echo "<p>Sender email: $msg[email]</p>";
echo "<p>Message: <br />$msg[message]</p>"; ?>
Delete message
</div>
I edited code a bit, but still nothing.
$(".delete").click(function() {
var commentContainer = $(this).parent();
var id = $(this).attr("id");
var string = 'id='+ id ;
$.ajax({
url: "<?php echo site_url('messages/delete') ?>",
type: "POST",
data: string,
cache: false,
success: function(){
commentContainer.slideUp('600', function() {$(this).remove();
$('.messages').fadeOut('2000', function(){$(this).remove();
$('#messages').load("<?php echo site_url('messages/show') ?>").show().fadeIn('1000');
});
});
}
});
return false;
});
When I look page source I can see that the content has been changed, but it is not displayed.

Answer 1

I didn't quite understand what you are trying to do but if this is what you mean by saying but I don't know how to go on from fadeOut you can put a callback function to fadeOut
$('#messages').fadeOut('1000', function () {
// Do something here
);