I have a VARCHAR2 value in the format '14-SEP-11 12.33.48.537150 AM' and I need to convert this to a TIMESTAMP as is. That is like,
SELECT TO_DATE('14-SEP-11 12.33.48.537150 AM', '<format_string>') FROM DUAL;
I want the return from the above query to be '14-SEP-11 12.33.48.537150 AM' in TIMESTAMP data format.
What should be the 'format_string' for this.
Please help since I tried many things but none works.. :(
I am using Oracle 11gR2.
Thanks.
DATE and TIMESTAMP are two different datatypes. So you need to use the correct conversion function for each, which in your case would be TO_TIMESTAMP().
SELECT TO_TIMESTAMP('14-SEP-11 12.33.48.537150 AM', 'DD-MON-RR HH:MI:SS.FF AM')
FROM DUAL;
select from_tz(to_timestamp('14-SEP-11 12.33.48.537150 PM', 'DD-Mon-RR HH.MI.SS.FF AM'), 'EUROPE/LONDON') from dual
Related
I have a column in table A as
select create_time from table_a;
The value is
08-MAR-19 08.23.47.897000000 PM GMT.
This column has been marked as VARCHAR2 for some business purpose. Now I am trying to get this column and convert the value to TIMESTAMP for some purpose, like this as below:
SELECT TO_TIMESTAMP(create_time, 'DD-MON-YYYY HH.MI.SS.FF AM') from table_a;
But I am getting error:
ORA-01830: date format picture ends before converting entire input string
Can someone help me to convert this varchar data to timestamp. The reason I am trying to do is, I need to convert this time from one timezone to another :
eg:
SELECT FROM_TZ(TO_TIMESTAMP(create_time, 'DD-MON-YYYY HH.MI.SS.FF AM'), 'UTC') AT TIME ZONE 'CET' from table_a;
SQL> select replace('08-MAR-19 08.23.47.897000000 PM GMT','GMT','') AS RESULT from dual
;
RESULT
--------------------------------
08-MAR-19 08.23.47.897000000 PM
SQL> select to_timestamp(replace('08-MAR-19 08.23.47.897000000 PM GMT','GMT','')) as RESULT from dual ;
RESULT
---------------------------------------------------------------------------
08-MAR-19 08.23.47.897000000 PM
SQL> select from_tz(to_timestamp(replace('08-MAR-19 08.23.47.897000000 PM GMT','GMT','')),'UTC') AT TIME ZONE 'CET' AS RESULT from dual ;
RESULT
---------------------------------------------------------------------------
08-MAR-19 09.23.47.897000000 PM CET
SQL>
The four characters GMT at the end are not accounted for in your format string
SELECT TO_TIMESTAMP('08-MAR-19 08.23.47.897000000 PM GMT', 'DD-MON-YYYY HH.MI.SS.FF AM') from dual;
The following takes care of that:
SELECT TO_TIMESTAMP(substr(create_time, 1, LENGTH(create_time) -4), 'DD-MON-YYYY HH.MI.SS.FF AM') t from dual;
Try this.
select TO_TIMESTAMP( REPLACE(ts, 'GMT', '')) from test_timestamp;
Remove GMT using REPLACE
WITH A AS (SELECT REPLACE('08-MAR-19 08.23.47.897000000 PM GMT','GMT','') AS D FROM DUAL)
SELECT TO_TIMESTAMP (D, 'DD-MON-YYYY HH.MI.SS.FF AM')
FROM A
Doing something like:
to_timestamp(replace(create_time ,'GMT', null))
relies on your NLS settings, both for the timestamp format - particularly that it has an RR year mask - and the language for the month abbreviation. It would be safer to do:
to_timestamp(replace(create_time, ' GMT', null),
'DD-MON-RR HH.MI.SS.FF AM', 'NLS_DATE_LANGUAGE=ENGLISH')
If the time zone isn't always GMT, but is always a valid and recognised region (not BST, for instance) then you might want to preserve the full date/time including that zone:
to_timestamp_tz(create_time, 'DD-MON-RR HH.MI.SS.FF AM TZR',
'NLS_DATE_LANGUAGE=ENGLISH')
If you want that as a plain timestamp you can cast it, possibly changing to a specific zone first:
cast(to_timestamp_tz(create_time, 'DD-MON-RR HH.MI.SS.FF AM TZR',
'NLS_DATE_LANGUAGE=ENGLISH') as timestamp)
or
cast(to_timestamp_tz(create_time, 'DD-MON-RR HH.MI.SS.FF AM TZR',
'NLS_DATE_LANGUAGE=ENGLISH') at time zone 'Asia/Tokyo' as timestamp)
or normalised to UTC (which won't affect GMT values, of course, as they're essentially the same):
sys_extract_utc(to_timestamp_tz(create_time, 'DD-MON-RR HH.MI.SS.FF AM TZR',
'NLS_DATE_LANGUAGE=ENGLISH'))
db<>fiddle
select to_date('25-MAY-20 12.10.12.320000 PM', 'dd-mon-yy hh:mi:ss pm') from dual;
getting the error
"am or pm required"
Oracle only stores precision up to seconds in a date type. If you want fractional seconds (e.g. milliseconds) you will need to use a timestamp column. But in any case, your current format mask is wrong. Try this instead:
SELECT TO_TIMESTAMP('25-Feb-20 12.10.12.320000 PM', 'dd-mon-yy hh.mi.ss.ff6 pm')
FROM dual
Demo
You can convert your timestamp into char and then convert to date.
Example with systimestamp:
select to_date(
to_char(systimestamp,'dd-mon-yy hh:mi:ss PM')
, 'dd-mon-yy hh:mi:ss PM')
from dual;
I have a table in which there is a column with datatype TIMESTAMP(0)
When I insert a date into this column using
INSERT INTO TEST_TIMESTAMP VALUES(SYSDATE)
it inserts a date in the following example format
12-SEP-12 10.31.19.000000000 AM
I want to know how the below timestamp formats can be inserted in the table
12-SEP-12 10.31.19 and 12-SEP-12 10.31.19 AM
I tried specifying some formats using TO_CHAR while inserting SYSDATE into the table, but it didn't work.
Please suggest.
when you store a TIMESTAMP it will always store the data at maximum precision (with fractional seconds).
I think what you want to do is supply a format to display the date when you retrieve it from the database.
You can do this like so:
select to_char(timestampColumnName,'DD-MON-YY HH24:MI:SS') "Date" from test_timestamp
or
select to_char(timestampColumnName,'DD-MON-YY HH:MI:SS AM') "Date" from test_timestamp
You can return it very easy like:
SELECT to_char(sysdate,'DD-MON-YY HH24:MI:SS') FROM DUAL;
In your case use:
INSERT INTO TEST_TIMESTAMP(column_name) VALUES(to_char(sysdate,'DD-MON-YY HH24:MI:SS'));
You were missing the extra ().
INSERT INTO TEST_TIMESTAMP
VALUES (TO_TIMESTAMP('12-SEP-12 10.31.19', 'DD-MON-YY HH.MI.SS'));
INSERT INTO TEST_TIMESTAMP
VALUES (TO_TIMESTAMP('12-SEP-12 10.31.19 AM', 'DD-MON-YY HH.MI.SS AM'));
TO_CHAR(SYSDATE, 'DD/MM/YYYY HH24:MI:SS')
This for colum type insert over mode to_char.
I'm trying to convert a time (date + time) from one time zone to another. In the query below, I'm trying to convert a time from EST ("America/New_York") to PST ("America/Los_Angeles"). The query is partially working; the results:
DATABASE_DATE = 2012-02-13 1:00:00 PM
LOCALTIME (what I get): 2012-02-12 10:00:00 AM.
So the time is good but the date is wrong. It should be 2012-02-13 instead of 2012-02-12.
Am I doing something wrong? Here's my query:
select to_date( to_char( ( from_tz( to_timestamp( DATABASE_DATE
, 'YYYY-MM-DD HH:MI:SS')
,'America/New_York')
at time zone 'America/Los_Angeles')
,'YYYY-MM-DD HH:MI:SS')
,'YYYY-MM-DD HH:MI:SS') as localtime
from table
Thanks
to_timestamp() gets a string (VARCHAR2, CHAR ...) if you try to give it a date, then oracle will convert it to a string according to NLS_DATE_FORMAT which might vary in different environments and return unexpected results (as in this case).
What you should do is use to_char first, so your query can look like this:
select to_date(to_char((from_tz(to_timestamp(to_char(DATABASE_DATE, 'YYYY-MM-DD HH:MI:SS PM'), 'YYYY-MM-DD HH:MI:SS PM') ,'America/New_York')
at time zone 'America/Los_Angeles'),'YYYY-MM-DD HH:MI:SS PM'),'YYYY-MM-DD HH:MI:SS PM') as localtime
from table
UPDATE: if I understand you right then you want something like this:
select to_char((from_tz(to_timestamp(to_char(DATABASE_DATE, 'YYYY-MM-DD HH:MI:SS PM'), 'YYYY-MM-DD HH:MI:SS PM') ,'America/New_York')
at time zone 'America/Los_Angeles'),'YYYY-MM-DD HH:MI:SS PM TZD') as localtime
from table
SELECT TO_CHAR(NEW_TIME(systimestamp,'EST','PST'), 'DD-MON-YY HH24:MI:SS') AS converted_timestamp_column FROM DUAL;
Please try this as well .There is a function for this purpose in oracle
https://docs.oracle.com/cd/B28359_01/olap.111/b28126/dml_functions_2036.htm
select NEW_TIME (TO_DATE ('2011/11/11 01:45', 'yyyy/mm/dd HH24:MI'), 'AST', 'MST') from dual;
My date value is stored as varchar2 and the value is 15/August/2009,4:30 PM, how to convert this to a proper date format like DD-MM-YYYY.
You can convert a string to a DATE using the TO_DATE function, then reformat the date as another string using TO_CHAR, i.e.:
SELECT TO_CHAR(
TO_DATE('15/August/2009,4:30 PM'
,'DD/Month/YYYY,HH:MI AM')
,'DD-MM-YYYY')
FROM DUAL;
15-08-2009
For example, if your table name is MYTABLE and the varchar2 column is MYDATESTRING:
SELECT TO_CHAR(
TO_DATE(MYDATESTRING
,'DD/Month/YYYY,HH:MI AM')
,'DD-MM-YYYY')
FROM MYTABLE;
You need to use the TO_DATE function.
SELECT TO_DATE('01/01/2004', 'MM/DD/YYYY') FROM DUAL;