I'm trying to load content from another page div into another page div.
What i've got:
JQUERY:
$('#news_date-1').load('test.php .news_date-1');
TEST.PHP
<div class="news_date-1">20-11-2009</div>
Destination.html
<div id="news_date-1"></div>
The result i get =
<div id="news_date-1"><div class="news_date-1">20-11-2009</div></div>
The result i want =
<div id="news_date-1">20-11-2009</div>
Can anybody help out?
You can try calling unwrap() on it in the callback.
$('#news_date-1').load('test.php .news_date-1', function () {
$(this) //will refer to #news_date-1
.find('.news_date-1') //find the inserted div inside
.contents() //find all its contents
.unwrap(); //unwrap the contents, thus removing the unneeded div
});
This is not the most beautiful solution, because .load() already inserts it into the DOM, and then you tamper with the DOM again, which should be minimized.
Another way I see is using $.get() instead:
$.get('test.php', function(receivedHtml) {
//getting only the parts we need
var neededHtml = $(receivedHtml).find('.news_date-1').html();
//adding it to DOM
$('#news_date-1').append(neededHtml);
});
Try this:
$.get('test.php', function(data) {
$('#news_date-1').append($(data).find('.news_date-1'));
});
Related
I know it has been given some answers but I will go for it :). As the title says i want to add popover bootstrap but with ajax loaded content. my html, but i want a Loading message to appear first and then the content.
<p class='entry' data-adjaxload = '/calendar/entry/1'>Title1</p>
<p class='entry' data-adjaxload = '/calendar/entry/2'>Title2</p>
<p class='entry' data-adjaxload = '/calendar/entry/3'>Title3</p>
my django view is the following
def entry_details(request, entry_id):
entry = get_object_or_404(Entry, pk=entry_id)
args = dict(entry=entry, user=request.user)
if request.is_ajax():
return render_to_response('mycal/ajax/entry_details.html', args)
else:
entry_form = EntryForm(instance=entry)
args.update(entry_form=entry_form)
return render_to_response('mycal/entry_details.html', args)
Pretty simple. I am using the same view to either load html content via ajax in the popover, or a details page via normal get request
the ajax details page:
<div class="entry">
<p>{{entry.title}}</p>
<p>{{entry.date}}</p>
<p>{{entry.customer}}</p>
</div>
and the script
$(document).ready(function(){
$('p.entry').each(function (){
var i = $(this);
$(i).bind('mouseenter', function(){
i.popover({
html:True,
title:i.html(),
content:'Loading'
}).popover('show');
$.ajax({
url:i.data('ajaxload'),
dataType:'html',
success:function (data){
i.popover({content:data}).popover('show');
}
});
});
$(i).bind('mouseleave', function(){
i.popover('hide');
});
});
});
But whilst it does run tha ajx and fetches the html, it won't load them onto the popover. How can I change that?
Just fiddled what you are looking for with popover content being updated dynamically using echo/json.
Just roll over the p element and wait for the 3 second delay.
If as you say, the data is being loaded properly then the only change needed is:
var popover = i.data('popover');
popover.options.content = data.text;
i.popover('show');
Hi I am printing the ajax html response to div element and giving radio input option to select the file. after selecting the specific file the another div should show the message. but the ajax html response is not working
Jquery script:
$(document).ready(function()
{
$('#upload').ajaxForm({
beforeSubmit: function() {
$('#Analysis').show();
$('#Content_column').hide();
$('#file_list').show();
$('#trait').show();
$('#trait').html('Submitting...');
},
success: function(data) {
var $out = $('#file_list');
$out.html('       File list:');
$out.append('<div id="list">');
$('#list').html(data);
$out.append('</div>');
}
});
});
The output of this script is
<ul class="php-file-tree"><li class="pft-directory">Genotypic<ul><input id="Penotypic" type="radio" name="uploads/Genotypic/" value="uploads/Genotypic/jquery.txt" />jquery.txt<br><input id="Penotypic" type="radio" name="uploads/Genotypic/" value="uploads/Genotypic/marker.csv" />marker.csv<br></ul></li><li class="pft-directory">Other</li><li class="pft-directory">Penotypic<ul><input id="Penotypic" type="radio" name="uploads/Penotypic/" value="uploads/Penotypic/namPheno.csv" />namPheno.csv<br><input id="Penotypic" type="radio" name="uploads/Penotypic/" value="uploads/Penotypic/perl.pl" />perl.pl<br></ul></li></ul>
Jquery script:
$('#Penotypic').click(function() {
var $out1 = $('#trait');
$('#trait').show();
$out1.append('Submitted...');
});
this is not showing anything in the div trait. may be the html response is loading as a tesxt so the #Penotypic is not recognised. please help me to fix this.
Thanku
You have many inputs of id="Penotypic". Make every id unique or use classes as function trigger.
I wouldn't use "/" in the name attribute. See: http://www.w3.org/TR/html401/types.html#type-name
Then try if your ajax script does work. If it doesn't work, try if it works from static page (don't use your first jQuery script, but it's output as a static form). You probably need to bind your event trigger. Use jQuery's on().
I'd like to use bootstrap's carousel to dynamically scroll through content (for example, search results). So, I don't know how many pages of content there will be, and I don't want to fetch a subsequent page unless the user clicks on the next button.
I looked at this question: Carousel with dynamic content, but I don't think the answer applies because it appears to suggest loading all content (images in that case) from a DB server side and returns everything as static content.
My best guess is to intercept the click event on the button press, make the ajax call for the next page of search results, dynamically update the page when the ajax call returns, then generate a slide event for the carousel. But none of this is really discussed or documented on the bootstrap pages. Any ideas welcome.
If you (or anyone else) is still looking for a solution on this, I will share the solution I discovered for loading content via AJAX into the Bootstrap Carousel..
The solution turned out to be a little tricky since there is no way to easily determine the current slide of the carousel. With some data attributes I was able to handle the .slid event (as you suggested) and then load content from another url using jQuery $.load()..
$('#myCarousel').carousel({
interval:false // remove interval for manual sliding
});
// when the carousel slides, load the ajax content
$('#myCarousel').on('slid', function (e) {
// get index of currently active item
var idx = $('#myCarousel .item.active').index();
var url = $('.item.active').data('url');
// ajax load from data-url
$('.item').html("wait...");
$('.item').load(url,function(result){
$('#myCarousel').carousel(idx);
});
});
// load first slide
$('[data-slide-number=0]').load($('[data-slide-number=0]').data('url'),function(result){
$('#myCarousel').carousel(0);
});
Demo on Bootply
I combined #Zim's answer with Bootstrap 4. I hope it will help someone.
First, load just the path of the images:
<div id="carousel" class="carousel slide" data-ride="carousel">
<div class="carousel-inner">
<div class="carousel-item" data-url="/image/1.png"></div>
<div class="carousel-item" data-url="/image/2.png"></div>
<div class="carousel-item" data-url="/image/3.png"></div>
</div>
</div>
Then in JavaScript:
$('document').ready(function () {
const loadCarouselImage = function ($el) {
let url = $el.data('url');
$el.html(function () {
let $img = $('<img />', {
'src': url
});
$img.addClass('d-block w-100');
return $img;
});
);
const init = function () {
let $firstCarousel = $('#carousel .carousel-item:first');
loadCarouselImage($firstCarousel);
$firstCarousel.addClass('active');
$('#productsCarousel').carousel({
interval: 5000
});
};
$('#carousel').on('slid.bs.carousel', function () {
loadCarouselImage($('#carousel .carousel-item.active'));
});
init();
});
I am getting next page on my wordpress blog using jquery, finding the desired div and appending it to the existing one. This part works without a problem. But, what I need to do is, to add slideDown animation to it.
This is how my working code so far looks like:
$.get(next_page, function(data) {
var response = $(data);
var more_div = $(response).find('.FeaturedRow1').html();
$('.FeaturedRow1').append(more_div).slideDown('slow');
$('.navigation').not(':last').hide();
I tried adding hide() to response, more_div as well as append lines. In the first case, I get error stating that it cannot set property display of undefined.
In the second case, in the console it display HTML and says "has no method hide". I also tried adding a line $(more_div).hide() but again, I get the error "Uncaught TypeError: Cannot set property 'display' of undefined".
If I use hide in the 3rd line
$('.FeaturedRow1').hide().append(more_div).slideDown('slow');
it hides the whole FeaturedRow1 div and animates it, that takes me to the top of the div, which is what I don't want.
EDIT: Here's the important HTML structure and jQuery code for the desired section
<div class="FeaturedRow1">
<div class="postspage">
//list of posts here
</div>
<div class="navigation">
<span class="loadless">
//hyperlink to previous page
</span>
<span class="loadmore">
//hyperlink to next page
</span>
</div>
</div>
When you click on the hyperlink inside the loadmore, the following jQuery code gets called
$('.loadmore a').live('click', function(e) {
e.preventDefault();
var next_page = $(this).attr('href');
$.get(next_page, function(data) {
var $response = $(data);
var $more_div = $response.find('.FeaturedRow1').hide();
$more_div.appendTo('.FeaturedRow1').delay(100).slideDown('slow')
$('.navigation').not(':last').hide();
});
});
$('.loadless').live('click', function(e) {
e.preventDefault();
if ($('.postpage').length != 1) {
$('.postpage').last().remove();
}
$('.navigation').last().remove();
$('.navigation').last().show();
});
You get error as you are using html method which returns a string not a jQuery object, try the following.
var $response = $(data);
var $more_div = $response.find('.FeaturedRow1').hide();
$more_div.appendTo('.FeaturedRow1').delay(100).slideDown('slow');
//$('.navigation').not(':last').hide();
Update:
$.get(next_page, function(data) {
var $response = $(data);
var more_div = $response.find('.FeaturedRow1').html();
$('<div/>').hide()
.append(more_div)
.appendTo('.FeaturedRow1')
.delay(100)
.slideDown('slow')
$('.navigation').not(':last').hide();
});
I am using an iFrame with a form that return some content with an AJAX link.
I am then moving the returned content out of the iFrame into the main page.
However, then the ajax link does not work and the error "Element is null" is created once the link is clicked.
How can I move content from the iFrame and still have the AJAX link working?
Here's the code returned by the iFrame:
<span id="top">
<a id="link8" onclick=" event.returnValue = false; return false;" href="/item_pictures/delete/7">
<img src="/img/delete.bmp"/>
</a>
<script type="text/javascript">
parent.Event.observe('link8', 'click', function(event) {
new Ajax.Updater('top','/item_pictures/delete/3', {
asynchronous:true, evalScripts:true,
onCreate:function(request, xhr) {
document.getElementById("top").innerHTML = "<img src=\"/img/spinner_small.gif\">";
},
requestHeaders:['X-Update', 'top']
})
}, false);
</script>
</span>
I see two problems with your code.
First the solution (I think :-))
When your iframe loads, the javascript in it runs. Javascript attaches an observer to parent document's link8.
Inside the observer you define another function (onCreate). This function will run in iframe context, making document object refer to iframe and not to main document. When you remove link8 from iframe to move it to main document, document.getElementById("top") will become null - hence error.
Perhaps change it to:
parent.document.getElementById("top").innerHTML = "<img src=\"/img/spinner_small.gif\">";
Second problem (that is not really a problem in this particular case) is, if you move whole span (including the script) to main document, the javascript will run again in main document's context. In your case, you should see an error or warning after you move the content, stating that parent is null (or similar).
To remove the second problem, return your iframe data in two divs or similar. Then copy only div with html to main document.
What I did was move the AJAX call out to an external js file and called the function once the link was clicked. It works now.