Drop Filepath on DIR - ruby

I am having problems splitting the filepath and just getting the filenames.
Here is my Code:
file=File.new("files.txt", "w")
file_list=Dir["../path/*txt"]
file.puts file_list
I tried a few different ways to split it, but I keep getting an Array Error,
Best Regards,
AZCards

Please try this snippet:
file = File.new("files.txt", "w")
Dir['../path/*.txt'].each { |f| file.puts File.basename(f, '.txt') }
That give you a list of filenames in specified folder without 'txt' extension.

file=File.new("files.txt", "w")
Dir.entries("/path/to/directory").each do |path|
m = /([^\/]+)\.txt$/.match(path)
file.puts m[1] if m
end

Just map the list of full paths, using basename, yielding the bare filename list.
Assuming you can want to drop extensions:
file = File.new("files.txt", "w")
file_list = Dir["../path/*txt"].map {|f| File.basename f, '.txt'}
file.puts file_list

Related

Remove concrete string from CSV in Ruby

I got a ruby script which take XML files and create from them CSV. This CSV use semicolons as delimiter -> but, content of XML contains these tags:
- &
- <
- >
And this of course break the structure of CSV file. I need clean it up. This cleaner must be writen in Ruby. I try next code, but this complete destroy the file.
#Clean up CSV file
#Remove: & \< >
file_names = ['terms.csv']
file_names.each do |file_name|
text = File.read(file_name)
new_contents = text.gsub(/&/, " and ")
# To merely print the contents of the file, use:
puts new_contents
# To write changes to the file, use:
File.open(file_name, "w") {|file| file.puts new_contents }
end
file_names.each do |file_name|
text = File.read(file_name)
new_contents = text.gsub(/</, " < ")
puts new_contents
File.open(file_name, "w") {|file| file.puts new_contents }
end
file_names.each do |file_name|
text = File.read(file_name)
new_contents = text.gsub(/>/, " > ")
puts new_contents
File.open(file_name, "w") {|file| file.puts new_contents }
end
I never use Ruby - this is my first contact. Is there better way how to do this?
I solved it... I change CSV delimiter from ";" to "#" in FOR cycle which create a CSV file. It is not ideal solution, but it works.

How to take the result from another method

I have a directory structure with sub-directories:
../../../../../MY_PROJECT/TEST_A/cats/
../../../../../MY_PROJECT/TEST_B/dogs/
../../../../../MY_PROJECT/TEST_A/tigers/
../../../../../MY_PROJECT/TEST_A/elephants/
each of which has a file that ends with ".sln":
../../../../../MY_PROJECT/TEST_A/cats/cats.sln
../../../../../MY_PROJECT/TEST_B/dogs/dogs.sln
...
These files contain information specific to their directory. I would like to do the following:
Create a file "myfile.txt" within each sub-directory, and write some strings to them:
../../../../../MY_PROJECT/TEST_A/cats/myfile.txt
../../../../../MY_PROJECT/TEST_B/dogs/myfile.txt
../../../../../MY_PROJECT/TEST_A/tigers/myfile.txt
../../../../../MY_PROJECT/TEST_A/elephants/myfile.txt
Copy a specific string in the ".sln" files to the myfile.txt of certain directories using the following method:
def parse_sln_files
sln_files = Dir["../../../../../MY_PROJECT/TEST_*/**/*.sln"]
sln_files.each do |file_name|
File.open(file_name) do |f|
f.each_line { |line|
if line =~ /C Source files ="..\\/ #"
path = line.scan(/".*.c"/)
puts path
end
}
end
end
end
I would like to do something like this:
def create_myfile
Dir['../../../../../MY_PROJECT/TEST_*/*/'].each do |dir|
File.new File.join(dir, 'myfile.txt'), 'w+'
Dir['../../../../../TEST/TEST_*/*/myfile.txt'].each do |path|
File.open(path,'w+') do |f|
f.puts "some text...."
f.puts "some text..."
f.puts # here I would like to return the result of parse_sln_files
end
end
end
end
Any suggestions on how to express this?
It seems like you want to read list of C file names from a Visual C++ Solution file, and store in a separate file in the same directory. You may have to merge the two loops that you have shown in your code, and do something like this:
def parse_sln_and_store_source_files
sln_files = Dir["../../../../../MY_PROJECT/TEST_*/**/*.sln"]
sln_files.each do |file_name|
#### Lets collect source file names in this array
source_file_names = []
File.open(file_name) do |f|
f.each_line { |line|
if line =~ /C Source files ="..\\/ #"
path = line.scan(/".*.c"/)
############ Add path to array ############
source_file_names << path
end
}
end
#### lets create `myfile.txt` in same dir as that of .sln
test_file = File.expand_path(File.dirname(file_name)) + "/myfile.txt"
File.open(test_file,'w+') do |f|
f.puts "some text...."
f.puts "some text..."
##### Iterate over source file names & write to file
source_file_names.each { |n| f.puts n }
end
end
end
This can be done bit more elegantly with few more refactoring. Also note that this is not tested code, hopefully, you get the gist of what I am suggesting.

Line replacement in directories clears the whole files?

I am trying to recursively replace a whole line from index.html files into a directory with sub-directories.
The code above puts the right lines I'm searching with the var "pattern", but when I run it, it removes everything form my index.html files.
pattern = "Keyword"
replacement = "<td width=\"30\"><img src=\"styles/img/trans.gif\" width=\"30\"></td>"
Dir.glob('/Users/root/Desktop/directory/test/**/index.html') do |item|
next unless File.file?(item)
File.open(item, "w+:ASCII-8BIT") do |f|
f.each_line do |line|
if line.match(pattern)
my_line = line
line.sub(my_line, replacement)
end
end
end
end
What am I doing wrong ?
You need to read the file first, build the expected output, and then write it:
Dir.glob('/Users/root/Desktop/directory/test/**/index.html') do |item|
next unless File.file?(item)
output = IO.readlines(item).map do |line|
if line.match(pattern)
replacement
else
line
end
end
File.open(item, "w+:ASCII-8BIT") do |f|
f.write output.join
end
end
end
You use File.open with open mode w+ which, according to Ruby documentation, is:
"w+" Read-write, truncates existing file to zero length or creates a new file for reading and writing.
To read the file and put some lines use r:
File.open(item, "r:ASCII-8BIT")

Script to append files

I am trying to write a script to do the following:
There are two directories A and B. In directory A, there are files called "today" and "today1". In directory B, there are three files called "today", "today1" and "otherfile".
I want to loop over the files in directory A and append the files that have similar names in directory B to the files in Directory A.
I wrote the method below to handle this but I am not sure if this is on track or if there is a more straightforward way to handle such a case?
Please note I am running the script from directory B.
def append_data_to_daily_files
directory = "B"
Dir.entries('B').each do |file|
fileName = file
next if file == '.' or file == '..'
File.open(File.join(directory, file), 'a') {|file|
Dir.entries('.').each do |item|
next if !(item.match(/fileName/))
File.open(item, "r")
file<<item
item.close
end
#file.puts "hello"
file.close
}
end
end
In my opinion, your append_data_to_daily_files() method is trying to do too many things -- which makes it difficult to reason about. Break down the logic into very small steps, and write a simple method for each step. Here's a start along that path.
require 'set'
def dir_entries(dir)
Dir.chdir(dir) {
return Dir.glob('*').to_set
}
end
def append_file_content(target, source)
File.open(target, 'a') { |fh|
fh.write(IO.read(source))
}
end
def append_common_files(target_dir, source_dir)
ts = dir_entries(target_dir)
ss = dir_entries(source_dir)
common_files = ts.intersection(ss)
common_files.each do |file_name|
t = File.join(target_dir, file_name)
s = File.join(source_dir, file_name)
append_file_content(t, s)
end
end
# Run script like this:
# ruby my_script.rb A B
append_common_files(*ARGV)
By using a Set, you can easily figure out the common files. By using glob you can avoid the hassle of filtering out the dot-directories. By designing the code to take its directory names from the command line (rather than hard-coding the names in the script), you end up with a potentially re-usable tool.
My solution....
def append_old_logs_to_daily_files
directory = "B"
#For each file in the folder "B"
Dir.entries('B').each do |file|
fileName = file
#skip dot directories
next if file == '.' or file == '..'
#Open each file
File.open(File.join(directory, file), 'a') {|file|
#Get each log file from the current directory in turn
Dir.entries('.').each do |item|
next if item == '.' or item == '..'
#that matches the day we are looking for
next if !(item.match(fileName))
#Read the log file
logFilesToBeCopied = File.open(item, "r")
contents = logFilesToBeCopied.read
file<<contents
end
file.close
}
end
end

In Ruby- Parsing Directory and reading first row of the file

Below is the piece of code that is supposed read the directory and for each file entry prints the first row of the file. The issue is x is not visible so file is not being parsed.
Dir.foreach("C:/fileload/src") do |file_name|
x = file_name
puts x
f = File.open("C:/fileload/src/" +x)
f.readlines[1..1].each do |line|
puts line
end
end
Why are you assigning x to file_name? You can use file_name directly. And if you are only reading the first line of the file, why not try this?
#!/usr/bin/ruby
dir = "C:/fileload/src"
Dir.foreach(dir) do |file_name|
full = File.join(dir, file_name)
if File.file?(full)
f = File.open(full)
puts f.first
f.close
end
end
You should use File.join to safely combine paths in Ruby. I also checked that you are opening a file using the File.file? method.
You have no visibility issue with x. You should be using File::join or Pathname#+ to build your file paths. You should exclude non-files from consideration. You're selecting the second line, not the first with [1..1]. Here's a cleaner correct replacement for your sample code.
dir = "C:/fileload/src"
Dir.foreach(dir).
map { |fn| File.join(dir,fn) }.
select { |fn| File.file?(fn) }.
each { |fn| puts File.readlines(fn).first }

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