I am trying to handle a xsd:choice in the B2B transformation engine.
(xsd examples here)
That is I have a
And I am only intrested in getting the "one" part
And I only want extract the "one" element not caring from which underlying type it comes from, i.e. I want to put the result into "one" below regardless if it comes from the thingyone, thingytwo or thingythree.
In XSLT terms I would like to do:
<root xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://xmlns.differentthingies.com/20111119/thingy" xsi:schemaLocation="http://xmlns.differentthingies.com/20111119/thingy differentthinggies.xsd">
<differentthingies>
<thingythree>
<one>thisisthingythree1</one>
<three2>thisisthingythree2</three2>
<three3>thisisthingythree3</three3>
</thingythree>
</differentthingies>
</root>
Transformed by
<xsl:template match="/">
<xsl:variable name="var1_root" select="ns0:root"/>
<root xmlns="http://xmlns.differentthingies.com/20111119/anotherthingy">
<xsl:attribute name="xsi:schemaLocation" namespace="http://www.w3.org/2001/XMLSchema-instance">http://xmlns.differentthingies.com/20111119/anotherthingy thingy.xsd</xsl:attribute>
<thingyone>
<xsl:for-each select="$var1_root/ns0:differentthingies/ns0:thingyone/ns0:one">
<one>
<xsl:value-of select="string(.)"/>
</one>
</xsl:for-each>
<xsl:for-each select="$var1_root/ns0:differentthingies/ns0:thingythree/ns0:one">
<one>
<xsl:value-of select="string(.)"/>
</one>
</xsl:for-each>
<xsl:for-each select="$var1_root/ns0:differentthingies/ns0:thingytwo/ns0:one">
<one>
<xsl:value-of select="string(.)"/>
</one>
</xsl:for-each>
</thingyone>
</root>
</xsl:template>
Would become
<root xmlns="http://xmlns.differentthingies.com/20111119/anotherthingy" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://xmlns.differentthingies.com/20111119/anotherthingy thingy.xsd">
<thingyone>
<one>thisisthingythree1</one>
</thingyone>
</root>
Related
I have one XML file that I need to transform based on a mapping file with XSLT 2.0. I'm using the Saxon HE processor.
My mapping file:
<element root="TEST">
<childName condition="/TEST/MyElement/CHILD[text()='B']>/TEST/MyElement/CHILD</childName>
<childBez condition="/TEST/MyElement/CHILD[text()='B']>/TEST/MyElement/CHILDBEZ</childBez>
</element>
I have to copy the elements CHILD and CHILDBEZ plus the parent and the root elements when the text of CHILD equals B.
So with this Input:
<?xml version="1.0" encoding="UTF-8"?>
<TEST>
<MyElement>
<CHILD>A</CHILD>
<CHILDBEZ>ABEZ</CHILDBEZ>
<NotInteresting></NotInteresting>
</MyElement>
<MyElement>
<CHILD>B</CHILD>
<CHILDBEZ>BBEZ</CHILDBEZ>
<NotInteresting2></NotInteresting2>
</MyElement>
</TEST>
the desired output:
<TEST>
<MyElement>
<childName>B</childName>
<childBez>BBEZ</childBez>
</MyElement>
</TEST>
what I have so far (based on this solution XSLT 2.0 XPATH expression with variable):
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:strip-space elements="*"/>
<xsl:param name="mapping" select="document('mapping.xml')"/>
<xsl:key name="map" match="*" use="."/>
<xsl:template match="/">
<xsl:variable name="first-pass">
<xsl:apply-templates mode="first-pass"/>
</xsl:variable>
<xsl:apply-templates select="$first-pass/*"/>
</xsl:template>
<xsl:template match="*" mode="first-pass">
<xsl:param name="parent-path" tunnel="yes"/>
<xsl:variable name="path" select="concat($parent-path, '/', name())"/>
<xsl:variable name="replacement" select="key('map', $path, $mapping)"/>
<xsl:variable name="condition" select="key('map', $path, $mapping)/#condition"/>
<xsl:choose>
<xsl:when test="$condition!= ''">
<!-- if there is a condition defined in the mapping file, check for it -->
</xsl:when>
<xsl:otherwise>
<xsl:element name="{if ($replacement) then name($replacement) else name()}">
<xsl:attribute name="original" select="not($replacement)"/>
<xsl:apply-templates mode="first-pass">
<xsl:with-param name="parent-path" select="$path" tunnel="yes"/>
</xsl:apply-templates>
</xsl:element>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
<xsl:template match="*">
<xsl:copy>
<xsl:apply-templates/>
</xsl:copy>
</xsl:template>
<xsl:template match="*[#original='true' and not(descendant::*/#original='false')]"/>
</xsl:stylesheet>
but the problem is that it's impossible to evaluate dynamic XPATH expressions with XSLT 2.0. Does anyone knows a workaround for that? Plus I have a problem with the mapping file. When there is only one element in it, it's not working at all.
If dynamic XPath evaluation isn't an option in your chosen processor, then generating an XSLT stylesheet is often a good alternative. In fact, it's often a good alternative anyway.
One way of thinking about this is that your mapping file is actually a program written in a very simple transformation language. There are two ways of executing this program: you can write an interpreter (dynamic XPath evaluation), or you can write a compiler (XSLT stylesheet generation). Both work well.
I am having some trouble getting this to work and I could really need some help.
I want to store the smallest variable that has a sibling which is not null.
I have a XML which looks like this:
<Root>
<Item>
<ValueOne>5</ValueOne>
<Item>bababa</Item>
</Item>
<Item>
<ValueOne>3</ValueOne>
<Item>ababa</Item>
</Item>
<Item>
<ValueOne>1</ValueOne>
<Item/>
</Item>
</Root>
I want the smallest ValueOne who's sibling Item has a value.
I was thinking something like:
<xsl:variable name="var">
<xsl:for-each select="Root/Item">
<xsl:if test="not(/Item = '')">
<xsl:sort data-type="text"/>
<xsl:if test="position()=1">
<xsl:value-of select="/Item"/>
</xsl:if>
</xsl:if>
</xsl:for-each>
</xsl:variable>
But this doesn't work and I am not sure why. As you might tell I'm not the best at xslt. I cannot rename anything in the xml or change the structure of it.
Assuming those spaces and returns are non-essential, you could use:
<xsl:variable name="var">
<xsl:for-each select="Root/Item[normalize-space(Item)]">
<xsl:sort select="ValueOne" data-type="number" order="ascending"/>
<xsl:if test="position()=1">
<xsl:value-of select="normalize-space(ValueOne)"/>
</xsl:if>
</xsl:for-each>
</xsl:variable>
With all the redundant white space removed, this can be simplified to:
<xsl:variable name="var">
<xsl:for-each select="Root/Item[Item/text()]">
<xsl:sort select="ValueOne" data-type="number" order="ascending"/>
<xsl:if test="position()=1">
<xsl:value-of select="ValueOne"/>
</xsl:if>
</xsl:for-each>
</xsl:variable>
I'm trying to work out a transformation that will process an input with several Flights with Departure and Arrival into a single output with the complete route for the flights.
Input is as follows:
<FlightTrip>
<flights>
<departureAirport>
<airportCode>LocB</airportCode>
</departureAirport>
<departureTime>2013-03-28T10:00:00.000</departureTime>
<arrivalAirport>
<airportCode>LocC</airportCode>
</arrivalAirport>
</flights>
<flights>
<departureAirport>
<airportCode>LocA</airportCode>
</departureAirport>
<departureTime>2013-03-27T15:00:00.000</departureTime>
<arrivalAirport>
<airportCode>LocB</airportCode>
</arrivalAirport>
</flights>
<flights>
<departureAirport>
<airportCode>LocC</airportCode>
</departureAirport>
<departureTime>2013-03-30T14:00:00.000</departureTime>
<arrivalAirport>
<airportCode>LocD</airportCode>
</arrivalAirport>
</flights>
</FlightTrip>
The desired output would be this:
<FullTrip>LocA LocB LocC LocD</FullTrip>
I've tried to use foreach inside the output variable but I can't get it right. I also need to sort the input based on the departure date as the Flights can be in a different order (as per the sample input).
Any ideas of how to achieve this?
Thanks a lot!
Bruno
<?xml version="1.0" encoding="UTF-8" ?>
<xsl:transform xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output indent="yes"/>
<xsl:template match="FlightTrip">
<FullTrip>
<xsl:apply-templates select="flights">
<xsl:sort select="departureTime"/>
</xsl:apply-templates>
</FullTrip>
</xsl:template>
<xsl:template match="flights">
<xsl:value-of select="departureAirport/airportCode"/><xsl:text> </xsl:text>
<xsl:if test="position()=last()">
<xsl:value-of select="arrivalAirport/airportCode"/>
</xsl:if>
</xsl:template>
</xsl:transform>
Will produce:
<FullTrip>LocA LocB LocC LocD</FullTrip>
Working example
Thanks to Joepie for the enlightenment. I had to modify it a bit to get it to work in my environment, ended up using foreach as below:
<xsl:template match="/">
<xsl:variable name="locations">
<xsl:for-each select="/FlightTrip/flights">
<xsl:sort select="departureTime" order="ascending" data-type="text"/>
<xsl:value-of select="concat(departureAirport/airportCode,' - ')"/>
<xsl:if test="position() = last()">
<xsl:value-of select="arrivalAirport/airportCode"/>
</xsl:if>
</xsl:for-each>
</xsl:variable>
<FullTrip>
<xsl:value-of select="$locations"/>
</FullTrip>
</xsl:template>
When applied to the example produces the output below:
<FullTrip>LocA - LocB - LocC - LocD</FullTrip>
Thanks again!
i have some requirement, where i need to replace the references in the same xml file.
limitation is to use xslt 1.0 only.
below is my sample input xml.
<org>
<depts>
<dept>
<deptId>1009</deptId>
<deptName>IT</deptName>
<deptAccessCode>IT-1009</deptAccessCode>
</dept>
<dept>
<deptId>2344</deptId>
<deptName>BPO</deptName>
<deptAccessCode>BP-2344</deptAccessCode>
</dept>
</depts>
<employees>
<employee>
<name>abc</name>
<dept>
<REFERENCE>
<LocationXPath>/org/depts/dept[2]</LocationXPath>
</REFERENCE>
</dept>
<employee>
</employees>
</org>
now i want to replace the node REFERENCE with actual data at the XPath /org/depts/dept[2].
so the output xml should be like below.
<org>
<depts>
<dept>
<deptId>1009</deptId>
<deptName>IT</deptName>
<deptAccessCode>IT-1009</deptAccessCode>
</dept>
<dept>
<deptId>2344</deptId>
<deptName>BPO</deptName>
<deptAccessCode>BP-2344</deptAccessCode>
</dept>
</depts>
<employees>
<employee>
<name>abc</name>
<dept>
<deptId>2344</deptId>
<deptName>BPO</deptName>
<deptAccessCode>BP-2344</deptAccessCode>
</dept>
<employee>
</employees>
</org>
i have several REFERENCE nodes in different elements referencing to different xpaths across the xml tree, which i need to replace them with actual data.
<someWhereInTheXmlTree>
<sometag>
<REFERENCE>
<LocationXPath>some/reference[1]/to/a/node[3]/in/the[4]/same/xml</LocationXPath>
</REFERENCE>
</sometag>
<someWhereInTheXmlTree>
...
<ffff>
<bbbb>
<REFERENCE>
<LocationXPath>abc/xyz[1]/node[4]/element</LocationXPath>
</REFERENCE>
</bbbb>
<ffff>
please help me on this.
Thanks in advance for the help.
So far i have implemented one XSLT to replace the references but now i am facing unwanted empty name spaces.
Here is my XSLT
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:tib="http://www.tibco.com/bw/xslt/custom-functions"
xmlns="http://www.realestate.org/residential/2010/schemas" >
<xsl:output omit-xml-declaration="no" indent="yes" method = "xml" />
<xsl:strip-space elements="*"/>
<xsl:param name="myxml" />
<xsl:template match="node()|#*">
<xsl:param name="isNodeToReplace"><xsl:call-template name="ReferenceCheck" /></xsl:param>
<xsl:choose>
<xsl:when test="$isNodeToReplace='true'">
<xsl:call-template name="replaceWithData">
<xsl:with-param name="ref"><xsl:value-of select="." /></xsl:with-param>
</xsl:call-template>
</xsl:when>
<xsl:otherwise>
<xsl:copy>
<xsl:apply-templates select="node()|#*"/>
</xsl:copy>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
<xsl:template name="ReferenceCheck">
<xsl:choose>
<xsl:when test="name(child::*[1])='REFERENCE' and name(child::*[1]//child::*[1])='LocationXPath'">true</xsl:when>
<xsl:otherwise>false</xsl:otherwise>
</xsl:choose>
</xsl:template>
<xsl:template name="replaceWithData">
<xsl:param name="ref" />
<xsl:copy-of select="tib:evaluate($myxml,$ref)" />
</xsl:template>
</xsl:stylesheet>
in the above XSLT i am passing the entire xml (same xml, which is being processed) as a parameter $myxml
Below is my sample input XML --this is just a snippet of xml,The actual xml file which i am dealing with is too large and contains so complex tree structure.How ever this sample xml is suffice enough to produce my problem.
Input file
<?xml version="1.0" encoding="UTF-8"?>
<org xmlns="http://www.realestate.org/residential/2010/schemas">
<depts>
<dept>
<deptId>1</deptId>
<deptName>health</deptName>
<deptAccessCode>HL007845</deptAccessCode>
</dept>
</depts>
<employees>
<employee>
<name>TOM</name>
<dept>
<REFERENCE>
<LocationXPath>/org/depts/dept[1]</LocationXPath>
</REFERENCE>
</dept>
</employee>
</employees>
</org>
my output file
<?xml version="1.0" encoding="UTF-8"?>
<org xmlns="http://www.realestate.org/residential/2010/schemas">
<depts>
<dept>
<deptId>1</deptId>
<deptName>health</deptName>
<deptAccessCode>HL007845</deptAccessCode>
</dept>
</depts>
<employees>
<employee>
<name>TOM</name>
<dept xmlns="">
<deptId>1</deptId>
<deptName>health</deptName>
<deptAccessCode>HL007845</deptAccessCode>
</dept>
</employee>
</employees>
</org>
Where as Expected output
<?xml version="1.0" encoding="UTF-8"?>
<org xmlns="http://www.realestate.org/residential/2010/schemas">
<depts>
<dept>
<deptId>1</deptId>
<deptName>health</deptName>
<deptAccessCode>HL007845</deptAccessCode>
</dept>
</depts>
<employees>
<employee>
<name>TOM</name>
<dept>
<deptId>1</deptId>
<deptName>health</deptName>
<deptAccessCode>HL007845</deptAccessCode>
</dept>
</employee>
</employees>
</org>
so i am getting unwanted empty name space in << dept xmlns="">> in the replaced root element.
Hope this could clearly explain my problem
Thanks in Advance
ultimately i have found the solution at the link below to remove the unwanted empty name spaces.
http://social.msdn.microsoft.com/forums/en-US/xmlandnetfx/thread/0de59291-ef3a-4a4c-9ca5-17923b16a504
Here is the new XSLT
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:tib="http://www.tibco.com/bw/xslt/custom-functions"
xmlns="http://www.realestate.org/residential/2010/schemas" >
<xsl:output omit-xml-declaration="no" indent="yes" method = "xml" />
<xsl:strip-space elements="*"/>
<xsl:param name="myxml" />
<xsl:template match="node()|#*">
<xsl:param name="isNodeToReplace"><xsl:call-template name="ReferenceCheck" /></xsl:param>
<xsl:choose>
<xsl:when test="$isNodeToReplace='true'">
<xsl:call-template name="replaceWithData">
<xsl:with-param name="ref"><xsl:value-of select="." /></xsl:with-param>
</xsl:call-template>
</xsl:when>
<xsl:otherwise>
<xsl:copy>
<xsl:apply-templates select="node()|#*"/>
</xsl:copy>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
<xsl:template name="ReferenceCheck">
<xsl:choose>
<xsl:when test="name(child::*[1])='REFERENCE' and name(child::*[1]//child::*[1])='LocationXPath'">true</xsl:when>
<xsl:otherwise>false</xsl:otherwise>
</xsl:choose>
</xsl:template>
<xsl:template name="replaceWithData">
<xsl:param name="ref" />
<xsl:apply-templates select="tib:evaluate($myxml,$ref)" mode="move-to-namespace">
<xsl:with-param name="namespace" select="'http://www.realestate.org/residential/2010/schemas'" />
</xsl:apply-templates>
</xsl:template>
<xsl:template match="*" mode="move-to-namespace">
<xsl:param name="namespace" />
<xsl:element name="{local-name()}" namespace="{$namespace}">
<xsl:copy-of select="#*" />
<xsl:apply-templates select="node()" mode="move-to-namespace">
<xsl:with-param name="namespace" select="$namespace"/>
</xsl:apply-templates>
</xsl:element>
</xsl:template>
<xsl:template match="text() | comment() | processing-instruction()" mode="move-to-namespace">
<xsl:copy/>
</xsl:template>
</xsl:stylesheet>
if any xslt expert refines it further to avoid any unnecessary instruction with proper explanation its very glad.
Thanks in advance
In general:
Not posiible in pure XSLT 1.0.
Not possible in pure XSLT 2.0
May be possible in pure XSLT 3.0 -- read about the
<xsl:evaluate> instruction.
In XSLT 1.0 you may be lucky if your XSLT processor implements the EXSLT dyn:evaluate() extension function (a few do).
Otherwize, you will have to write an extension function to select the
nodes and return them back.
If there are restrictions on the syntax of the XPath expressions, then it may be possible to implement a pure XSLT 1.0 solution.
This is not possible in pure XSLT 1.0. You have to use extension function, e.g. Xalan evaluate expression
I would like to select a node and modify its attributes and child-nodes using an
xsl:script function. In addition, templates matching child-nodes of that node should
STILL perform their job (after script is done processing the node).
Can it be done using XSLT?
Can you please provide an example / skeleton for such a transformation?
Yes, it can be done. I don't seem to see what the problem is because the XML (or whatever output) of an XSL script is buffered independently from its input.
This is illustrated in the following example whereby a simple XSL script copies an input XML document mostly as-is, changing a few things:
the root element name and attribute
flattening by removing the element from the hierarchy
dropping the results/date element
rename the item's 'source' attribute 'origin'
change the item's 'level' attribute value
rename the FirstName and LastName elements of the item elements
Sample input
<?xml version="1.0" encoding="ISO-8859-1"?>
<MyRoot version="1.2">
<results>
<info>Alpha Bravo</info>
<author>Employee No 321</author>
<date/>
<item source="www" level="6" cost="33">
<FirstName>Jack</FirstName>
<LastName>Frost</LastName>
<Date>1998-10-30</Date>
<Organization>Lemon growers association</Organization>
</item>
<item source="db-11" level="1" cost="65" qry="routine 21">
<FirstName>Mike</FirstName>
<LastName>Black</LastName>
<Date>2006-10-30</Date>
<Organization>Ford Motor Company</Organization>
</item>
</results>
</MyRoot>
Output produced
<?xml version="1.0" encoding="utf-16"?>
<MyNewRoot version="0.1">
<author>Employee No 321</author>
<info>Alpha Bravo</info>
<item cost="33" origin="www" level="77">
<GivenName>Jack</GivenName>
<FamilyName>Frost</FamilyName>
<Date>1998-10-30</Date>
<Organization>Lemon growers association</Organization>
</item>
<item cost="65" qry="routine 21" origin="db-11" level="77">
<GivenName>Mike</GivenName>
<FamilyName>Black</FamilyName>
<Date>2006-10-30</Date>
<Organization>Ford Motor Company</Organization>
</item>
</MyNewRoot>
XSL script
<?xml version='1.0'?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
exclude-result-prefixes="#default">
<xsl:template match="MyRoot">
<xsl:call-template name="MainTemplate">
</xsl:call-template>
</xsl:template>
<xsl:template name="MainTemplate">
<MyNewRoot version="0.1">
<xsl:copy-of select="results/author" />
<xsl:copy-of select="results/info" />
<xsl:for-each select="results/item">
<xsl:call-template name="FixItemElement"/>
</xsl:for-each>
</MyNewRoot>
</xsl:template>
<xsl:template name="FixItemElement">
<xsl:copy>
<xsl:copy-of select="#*[not(name()='source' or name()='level')]" />
<xsl:attribute name="origin">
<xsl:value-of select="#source"/>
</xsl:attribute>
<xsl:attribute name="level">
<xsl:value-of select="77"/>
</xsl:attribute>
<xsl:for-each select="descendant::*">
<xsl:choose>
<xsl:when test="local-name(.) = 'FirstName'">
<GivenName>
<xsl:value-of select="."/>
</GivenName>
</xsl:when>
<xsl:when test="local-name(.) = 'LastName'">
<FamilyName>
<xsl:value-of select="."/>
</FamilyName>
</xsl:when>
<xsl:otherwise>
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:otherwise>
</xsl:choose>
</xsl:for-each>
</xsl:copy>
</xsl:template>