fopen with dynamic filename is not working - bash

Question

I need to make a web site on which people can upload data files that after some treatment will be plotted using the jpgraph. The file is analyzed with a bash script called analfile.sh. The bash script is like this:
#!/bin/bash
file=$1
fecha=`date +%s`
mv $1 $fecha.dat
echo $fecha.dat
So, it gives back another file which name is like: 1321290921.dat. That is the file that I need to plot.
This my current php code:
$target_path = "/home/myhome";
$target_path = $target_path . basename( $_FILES['rdata']['name']);
$target_file = basename( $_FILES['rdata']['name']);
if(move_uploaded_file($_FILES['rdata']['tmp_name'], $target_path)) {
echo "The file ". $target_file. " has been uploaded";
chdir('/home/myhome');
$filetoplot=shell_exec('./analfile.sh'.' '.$target_file);
} else{
echo "There was an error uploading the file, please <a href=\"index.html\">try again!
</a>";
}
//$filetoplot="1321290921.dat"
echo "<br>The file to be opened is ". $filetoplot. "<br>";
if ($file_handle = fopen("$filetoplot", 'r')) {
while ( $line_of_text = fgets($file_handle) ) {
$parts = explode('.', $line_of_text);
echo $line_of_text ;
print $parts[0] . $parts[1]. $parts[2]. "<br>";
}
fclose($file_handle);
}
I have permissions to read and write on the target directory. I find strange that if I uncomment the line $filetoplot="1321290921.dat" then the script works perfectly. I guess I am doing something stupid since this is my first code in php but after some hours googling I was not able to find a solution.
Any help will be appreciated.

Answer 1

First thing I'm seeing is that you don't append trailing slash (/) to your home path, so that the path would be like /home/myhomefoo rather than /home/myhome/foo.
You should also move $target_file earlier, and reuse that within $target_path. There's no reason to do the same thing twice.
If that doesn't help, we'll see what goes next.