simulating the "add another item" ajax call in drupal 7 using jquery - ajax

I am trying to get jQuery to send a mousedown event to the Drupal 7 "add another item" button for a multi-value field, then wait until the ajax call has completed before filling in that new blank row with data from an element in a jQuery object (that has several elements). I need to use a loop to cycle through the elements (ingredients) in this jQuery object, but no matter what I try my page dies...
Currently, I have something like the following:
i = 0;
ingredients = newHtml.find('.recipe_ingredients > li');
ingredientsLength = ingredients.length;
$('#edit-field-ingredients-und-add-more').mousedown();
while(i < ingredientsLength) {
if ( document.readyState !== 'complete' ) {
// code to fill in the new blank row with data from 'ingredients'
$('#edit-field-ingredients-und-add-more').mousedown();
i++;
}
}
Because I don't yet know how to issue the ajax call myself using jQuery (or using Drupal) I've been trying to just check whether the call has completed by using .readyState and other hack-like methods. I'm just not sure what to try next!
Am I going about this the completely wrong way? Is there a straightforward way to make the "add another item" multi-value field ajax call using jQuery? Any help would be greatly appreciated...

I am not sure if there's a nicer way in Drupal 7, but in Drupal 6 you could use jQuery(document).ajaxComplete with the settings.url property to tell when a specific "Add another item" click had finished.
Start with:
(function($) {
$(document).ajaxComplete(function(e, xhr, settings)
{
alert(settings.url);
});
}(jQuery));
Once you've identified the right settings.url for your field, change that to:
(function($) {
$(document).ajaxComplete(function(e, xhr, settings)
{
if (settings.url == "the path from step 1") {
// Code to populate your fields here
}
});
}(jQuery));
And voila!
You might want to read the page by Jay Matwichuk where I originally learned this technique awhile back. All credit to him (and nclavaud for his comment there), really.

Related

Ajaxinate Endless scolling has stopped product Quick View from working

I am using Shopify "Streamline Theme" with quick product view and I recently added infinite scroll to products on each collection using Ajaxinate.js.
When I open a collection page it loads with some products which is supposed to do, The products already there work fine with quick view and quick add to cart and also.
The Infinite scroll works fine and it loads new product fine but the problem is raised when the new products loaded through AJAX call doesn't have work with the quick view function.
I have tried to create a callback function to activate the quick view with no success, using the theme initialisation code with no success.
function callBack(){
theme.init();
theme.initQuickShop();
};
document.addEventListener("DOMContentLoaded", function() {
var endlessClick = new Ajaxinate({
method: "scroll",
loadingText: 'Loading...',
callback: callBack
});
});
Edit -------
My problem, is that when the page is loaded only the initial loaded products quickview elements are loaded in the DOM. When the scroll more button is clicked, the newly loaded products are loaded without their respective quickview elements. Hence why the quickview does't work for them. The theme.js file comes with this initialisation code:
theme.reinitProductGridItem = function($scope) {
if (AOS) {
AOS.refreshHard();
}
if (theme.settings.currenciesEnabled) {
theme.currencySwitcher.ajaxrefresh();
}
// Reload quick shop buttons
theme.initQuickShop(true);
// Refresh reviews app
if (window.SPR) {
SPR.initDomEls();SPR.loadBadges();
}
// Re-register product templates in quick view modals.
// Will not double-register.
sections.register('product-template', theme.Product, $scope);
// Re-hook up collapsible box triggers
theme.collapsibles.init();
};
I have tried to integrate this into a callback but no success, the quickview modal doesn't seem to load for the newly loaded products:
function callBack(){
ReloadSmartWishlist();
var $container = $('#CollectionSection');
theme.reinitProductGridItem($container);
// I have tried the following init qith no success:
// theme.init();
// theme.initQuickShop(true);
// theme.initQuickShop();
// sections.register('product-template', theme.Product, $container);
// AOS.refreshHard();
};
document.addEventListener("DOMContentLoaded", function() {
var endlessClick = new Ajaxinate({
method: "click",
loadingText: 'Loading...',
offset: 0,
callback: callBack
});
});
I am missing something but what? :/
Note for other things like loading products images with the callback and the wishlist app, it works as intended...
When you load elements via AJAX and if the events are not attached to a parent element that is not removed from the DOM, those elements will not have an attached event to them.
The term used here is event delegation.
Here is an example of non-delegated event:
document.querySelectorAll('a').addEventListener('click', function(){
// Do something
})
Since you are attaching the event to the existing "a" elements if you add new 'a' via AJAX those elements will not have the event since Javascript already attached all the events and it will not reattach them if you don't specifically recall them again.
Here is an example of a delegated event:
document.querySelector('body').addEventListener('click', function(target){
let target = event.target;
if (target.tagName === 'A'){
// Do something here
}
})
Where we attach the event to the body tag ( where it's a better idea to attach it to a closer none-modified parent element of the ajax items ) and once we click we check if our target tag is an "a" and do something then.
So long story short, you will need to delegate the quick cart link so that it works after you load the items via AJAX.
Drip is correct you need to delegate your event, but for people like me it's hard to completely understand how to do that.
I'm not sure how your quickview is structured, but if you open it with a .click function and can use jquery use the [.on() function][1].
For example: I use a quickview that opens on a button click. My button is attached to my product-grid-item.liquid with this bit of code:
<div class="quick-view-button">
<a class="quick-view" data-handle="{{ product.handle }}" href="javascript:void(0);">Quick View</a>
</div>
My quickview function originally looked like this:
function quickView() {
$(".quick-view").click(function () {
//all of the quickview code
What happens is exactly like you described. The event listeners only loaded on the first product load but nothing after an AJAX load.
Using jquery's .on() binds the event listener to the element meaning when it's loaded in later it'll still have the event. Here's an example of what my code looks like after using .on()
function quickView() {
$('body').on('click','.quick-view',function(){
I really hope this helps you or someone else with this problem.
[1]: http://api.jquery.com/on/

How to know on client side whether a postback occured?

I am developing a Greasemonkey script and this script changes some elements in a table. However, when we click a button in the table an asynchronous postback happens and the table is refreshed.
So, my elements are also refreshed. How do I know a postback has occurred so that I can run my script again to change the new elements in the table? (The page uses Telerik.)
Don't bother trying to check for a postback That's almost always a painful way of doing things. You care about the table content, monitor that.
See:
Run Greasemonkey script on the same page, multiple times?
Fire Greasemonkey script on AJAX request
How can I detect AJAX node insertion without using DOM mutation events?
and several others.
Just as Brock Adams says in his answer, I decided to monitor table and wrote this code:
function repairInputEvents() {
for (var i = 0; i < document.getElementsByTagName("input").length; i++) {
//Add event to buttons that cause postback.
document.getElementsByTagName("input")[i].addEventListener("click", function() {
//Run the following just before postback.
document.getElementsByClassName("table")[0].setAttribute("title", "old");
var checkAjaxInterval = setInterval(function() { checkAjax(); }, 1000);
function checkAjax() {
if (document.getElementsByClassName("table")[0].getAttribute("title") != "old") {
clearInterval(checkAjaxInterval);
repairInputEvents();
repairSelectEvents();
}
}
});
}
}
//First run
repairInputEvents();
repairSelectEvents();

Loading a hidden div into an AJAX jQuery UI tab (future DOM element)

I have been trying to manipulate content that is loaded into jQuery UI tabs via AJAX.
As you can imagine, these elements are "future" DOM elements and aren't manipulated by normal $(".someClass")functions.
I've read using .live() for event handling is now deprecated using jQuery 1.7+ and is replaced by the new .on() method.
My issue is that the div I want to hide, when it loads in an AJAX tab, must be manipulated after the initial DOM load and is not bound to a click event at first.
My functions, which are currently wrapped in $() are below.
I think I have the syntax correct for links that use a click handler, but I'm not sure of the correct way to ".hide()" my "hiddenStory" div at load.
I also think that the functions themselves shouldn't be wrapped in an overall $()?
Any help or advice would be greatly appreciated.
$(function(){
// this .hiddenStory div below is what I want to hide on AJAX load
// need syntax and/or new methods for writing this function
$(".hiddenStory").hide();
// this is a function that allows me to toggle a "read more/read less" area
// on the "hiddenStory" div
$(".showMoreOrLess").on('click', (function() {
if (this.className.indexOf('clicked') != -1 ) {
$(this).removeClass('clicked');
$(this).prev().slideUp(500);
$(this).html("Read More" + "<span class='moreUiIcon'></span>");
}
else {
$(this).addClass('clicked');
$(this).prev().slideDown(500);
$(this).html("See Less" + "<span class='lessUiIcon'></span>");
}
}));
});
// prevents default link behavior
// on BBQ history stated tab panes with
// "showMoreOrLess" links
$('.showMoreOrLess').click(function (event)
{
event.preventDefault();
// here you can also do all sort of things
});
// /prevents default behavior on "showMoreOrLess" links
Could you set the display: none via CSS and override it when you wanted to show the element's content? Another option, if you have to do it this way would be to add the `$(".hiddenStory").hide() in the callback from the AJAX load that is populating the element. For example:
$(".hiddenStory").load("http://myurl.com", function(){
$(".hiddenStory").hide();
}
);
If you aren't using the .load method, you should have some sort of call back to tie into (e.g. success if using $.ajax...)

TinyMCE not working in http request xhr ajax generated page

So i I have a page that contains links that call an httpRequest. The request calls a php file that grabs data from mysql and pre populates a form which is then returned to the browser/webpage. My problem is that when the page is returned to the browser via the httpRequest/ajax the text area does not display the tinymce editor, it just displays a normal text area. It looks like my request and ajax is working fine the text area just doesn't have the tinycme editor on it.
When i don't use ajax it works fine but when i put it in a separate file and call it via ajax it doesn't bring in the tinymce editor.
Does anyone know how to fix this problem so that my ajax generated page displays the text area with the tinymce editor. Thank you.
Lets presume that your thinyMCE instance is initialized with code below
// initialize tinyMCE in page
tinyMCE.init({
mode: "textareas",
theme: "advanced"
});
and you have some kind of button somewhere in the page. For purpose of this tip, i will not give it any ID but you may. Now, using jQuery you can easily attach event handler to that button which will call through AJAX your server and take content which you want to put tinyMCE editor. Code which will do such job would look somehow like below.
$(function() {
$("button").bind("click", function() {
var ed = tinyMCE.get('content');
ed.setProgressState(1); // Show progress
$.getJSON('/page/12.json', { /* your data */
}, function(data) {
ed.setProgressState(0); // Hide progress
ed.setContent(data["body"]);
}
});
});
});
You can see that on button.click ajax will call url /page/12.json which will return JSON as response. bare minimum of that response could be:
{
title: "Page title",
body: "<html><head><title>Page title</title>......</html>"
}
I attached anonymous function as callback which will handle response from server. and hide progress indicator which is shown before ajax call.
About JSON
JSON is shorten of JavaScript Object Notation. It is JavaScript code!!! So don't be confused about it. Using JSON you can make javascript object which can have attributes you can use later in your code to access particular peace of data which that object "holds". You can look at it as some kind of data structure if it is easier to you.
Anyway, to show you how this JSON can be created by hand look at examples below
var data = new Object();
data.title = "Page title";
data.body = "<html....";
or
var data = {
title: "page title",
body: "<html...."
};
it is very same thing.
If you want to learn more about JSON point your browser to http://json.org.
===== alternative =====
Alternative to json solution could be just plane ajax call to server and response can be plain HTML (from your question I can assume that you have something like this already). So instad of calling $.getJSON you can use $.get(url, callback); to do same thing. The code at the top of my answer will not dramatically change. Instead of geting JSON in response you will get string which is HTML.
----------- BOTTOM LINE -------
I prefer JSON since it can be easily extended later with other attributes, so there is no painful code changes later ;)
Problem here will be that when you return the full page and render it using the ajax response, your tinymce instance has not been shut down before.
In order to do this you can call this small piece of code before you render the ajax response:
tinymce.execCommand('mceRemoveControl',true,'editor_id');
In this case the editor should initialize correctly. You are not allowed to initialize a tinymce editor with the same id before shutting the first one down.
Strangely i ran into this problem yesterday. Following code should work, but YMMV. Trick is to use the correct steps in ajax events. I used the Regular TinyMCE and made use of the jQuery library already included.
Following goes into your tinyMCE initialization tinyMCE.init() . All of the below block should be outside the document.ready.
myTinyInit = {
//.......All essential keys/values ...........
setup : function(ed) {
ed.onChange.add(function( ed ) {
tinyMCE.triggerSave();
}) }
//.....................
};
// Init the tinyMCE
tinyMCE.init(myTinyInit);
This ensures the content is being saved regularly onto the textarea that holds the value. Next step is setting up the request events.
Normally tinyMCE mceAddControl before the ajax post and mceRemoveControl after the ajax success should do the trick. But I found that often does not work.
I used the form as the jQuery selector in my case.
jQuery( '.myForm' )
.find( 'textarea#myTextArea' )
.ajaxStart(function() {
// If you need to copy over the values, you can do it here.
// If you are using jQuery form plugin you can bind to form-pre-serialize event instead.
// jQuery( this ).val( tinyMCE.get( jQuery( this ).attr( 'id' )).getContent() );
}).ajaxSend( function() {
// ! - step 2
// My case was multiple editors.
myEds = tinyMCE.editors;
for( edd in myEds ) {
myEds[ eds ].remove();
}
// tinyMCE.get( 'myTextarea' ).remove();
// strangely mceRemoveControl didnt work for me.
// tinyMCE.execCommand( 'mceRemoveControl', false, jQuery( this ).attr('id'));
}).ajaxSuccess(function() {
// Now we got the form again, Let's put up tinyMCE again.
txtID = jQuery( this ).attr( 'id' );
// ! - step 3
tinyMCE.execCommand( 'mceAddControl', false, txtID );
// Restore the contents into TinyMCE.
tinyMCE.get( txtID ).setContent( jQuery( this ).val());
});
Problems i came across :
Using mceRemoveControl always gave me r is undefined error persistently.
If you get a blank tinyMCE editor, check the DOM whether the ID of the textarea is replaced with something like mce_02, this means that TinyMCE is being initialized again or something is wrong with the order. If so, the tinyMCE is duplicated with each save.
if you are new to JS, I recommend using jQuery with the form plugin, it might be easier for you. But do use the regular non-jquery tinyMCE, as it is well documented.
I fixed this problem by recalling the function after the ajax call. In this part of my ajax:
if (xmlhttp.readyState==4 && xmlhttp.status==200)
{
document.getElementById("Content").innerHTML=xmlhttp.responseText;
tinymce();
Now it works fine.

Cakephp Ajax Button

I have a delete button. which on click it should visit a url like /delete/{id} and once the response from that url is true. i want to delete the comment box like in facebook.
I wont add any extra than Leo's comment, but I will explain with some code. Presume that you are using jQuery...
$(document).ready(function(){
$('tr a.delete').live('click', function(e){
e.preventDefault();
var link = $(this);
$.get($(this).attr('href'), null, function(response){
if(response == 'ok'){ //you should invent how to get 'ok' or other string identifying that the deletion is successful.
link.parents('tr').remove();
} else {
alert('There is a problem while deleting this element');
}
});
})
});
if you put this code on your project it will handle all links which had .delete class and are in a table row.
There are two things which you should do:
You need to pass some string in
order to detect if the operation is
successful or not. In my example I
would print "ok" on success
deletion.
If your table has pagination, it wont
rebuild the table, while it just
will remove the row from the table.
and if you have let's say 5 rows per
page and you delete all of them the
page will remain empty while there
will be other records in the table.
That's why instead of removing the
tr I would reload the whole page.
In that case the code for successful deletion will look like this:
if(response == 'ok'){
$('#content').load(window.location);
}
The script is not optimised, but it will give you the ideas how to achieve your ideas.
HTH
So write an onClick event handler in your view, a php delete method on the appropriate controller called by the event handler and a javascript action to perform when the ajax call returns success.

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