I got help regarding the following question:
batch rename files with ids intact
It's a great example of how to rename specific files in a group, but I am wondering if there is a similar script I could use to do the following:
I have a group of nested folders and files within a root directory that contain [myprefix_foldername] and [myprefix_filename.ext]
I would like to rename all of the folders and files to [foldername] and [filename.ext]
Can I use a similar methodology to what is found in the post above?
Thanks!
jml
Yes, quite easily, with find.
find rootDir -name "myprefix_*"
This will give you a list of all files and folders in rootDir that start with myprefix_. From there, it's a short jump to a batch rename:
find rootDir -name "myprefix_*" | while read f
do
echo "Moving $f to ${f/myprefix_/}"
mv "$f" "${f/myprefix_/}"
done
EDIT: IFS added per http://www.cyberciti.biz/tips/handling-filenames-with-spaces-in-bash.html
EDIT 2: IFS removed in favor of while read.
EDIT 3: As bos points out, you may need to change while read f to while read -d $'\n' f if your version of Bash still doesn't like it.
Related
I have been trying to use the command line to delete all files in all subdirectories with the name s_1_1102_c.jpg.
This question is similar to what I need How to remove folders with a certain name but it is removing directories and I only want to delete the files with the name s_1_1102_c.jpg.
I will need to remove this file from 260 subdirectories under the L001 directory. My directory structure is like this:
L001
C5.1
s_1_1101_a.jpg
s_1_1101_c.jpg
s_1_1101_g.jpg
s_1_1101_t.jpg
s_1_1102_a.jpg
s_1_1102_c.jpg
s_1_1102_g.jpg
s_1_1102_t.jpg
s_1_1103_a.jpg
s_1_1103_c.jpg
s_1_1103_g.jpg
s_1_1103_t.jpg
C6.1
s_1_1101_a.jpg
s_1_1101_c.jpg
s_1_1101_g.jpg
s_1_1101_t.jpg
s_1_1102_a.jpg
s_1_1102_c.jpg
s_1_1102_g.jpg
s_1_1102_t.jpg
s_1_1103_a.jpg
s_1_1103_c.jpg
s_1_1103_g.jpg
s_1_1103_t.jpg
Ultimately I need to remove several files from all subdirectories (s_1_1101_g.jpg, s_1_1101_t.jpg, s_1_1102_a.jpg, s_1_1102_c.jpg, s_1_1102_g.jpg, s_1_1102_t.jpg). So maybe there is a way to provide a list of the file names I need to delete.
How can I delete these files?
find . -name "s_1_1102_c.jpg" -exec rm -f {} \;
Note: This will find and delete the file in any subdirectory of the current one. So you could execute it in L001 or wherever else you want to do this.
for i in s_1_1101_g.jpg s_1_1101_t.jpg s_1_1102_a.jpg s_1_1102_c.jpg s_1_1102_g.jpg s_1_1102_t.jpg; do
echo rm L001/*/"$i";
done
If output looks fine, remove echo.
The final method I used to delete my files was given by #Peter - Reinstate Monica
for f in s_1_1101_t.jpg s_1_1102_a.jpg s_1_1102_c.jpg s_1_1102_g.jpg s_1_1102_t.jpg s_1_1103_a.jpg s_1_1103_c.jpg s_1_1103_g.jpg s_1_1103_t.jpg s_1_1104_a.jpg s_1_1104_c.jpg s_1_1104_g.jpg s_1_1104_t.jpg s_1_2101_g.jpg s_1_2101_t.jpg s_1_2102_a.jpg s_1_2102_c.jpg s_1_2102_g.jpg s_1_2102_t.jpg s_1_2103_a.jpg s_1_2103_c.jpg s_1_2103_g.jpg s_1_2103_t.jpg s_1_2104_g.jpg s_1_2104_t.jpg; do find /hpc/home/L001 -name $f -delete; done
I was concerned that my file list would be too long but it worked in this situation.
So I have a bunch of directories that are kind of like this (but with more files):
1-0
file1
file2
folder
file 3
1-1
file1
file2
folder
file 3
etc.
And as the question asks I want to prefix the 1-0, 1-1 to all the "files" in the directories and subdirectories of the root folder being the 1-0 etc. Like follows:
1-0
1-0file1
1-0file2
folder
1-0file 3
1-1
1-1file1
1-1file2
folder
1-1file 3
etc.
I've tried a few cmd/batch solutions from other questions and ReNamer but I couldn't find anything that quite did what I wanted. Pretty inexperienced with this kind of stuff so I could have missed something for sure.
ReNamer I can do it but I have to do each directory individually and I have a fair few that I am trying to rename so it's a bit impractical.
I would find this in general a quite terrible idea to do... I cannot imagine a situation where on the long term this may really has been a good idea. One of the reasons is that it just duplicates structural information of the location in the filename itself. Why ?...
On a linux shell there are certainly various ways to accomplish this. Here is a one liner:
find . -type f -name "*" | xargs -n 1 -I {} sh -c 'file_full={}; file_bare=${file_full#./}; file=${file_bare##*/} prefix=${file_bare%%/*}; dir=${file_bare%/*}; echo mv ${file_full} ./${dir}/${prefix}${file}'
Note, there is an echo in the final output. Remove the echo only if you are really happy with the solution and want this to be executed.
I have a bunch of base-parent-folders with different names.
In each of these base-parent-folders i have a folder with same same name(result).
In each of the result folders, i have a result file (data.txt), also named the same in each base-parent-folder.
I need to move all the data.txt files to a new folder (newfolder), and rename them to the base-parent-folder name.
for name in ./*/*/data.txt; do
mv "$name" "../newfolder/$(basename -- "$(dirname -- "$name")").txt";
done
This will move the file but rename the data.txt files to result.txt, and not the unique base-parent-folder name.
Help is much appreciated :D
What i have:
data\data1\result\data.txt
data\data2\result\data.txt
data\data3\result\data.txt
data\data4\result\data.txt
data\data5\result\data.txt
What i want:
data\newfolder\data1.txt
data\newfolder\data2.txt
data\newfolder\data3.txt
data\newfolder\data4.txt
data\newfolder\data5.txt
for f in */*/data.txt;
do mv "$f" "./newfolder/${f%/*/*}.txt";
done
Worked for me. The ./ part did not work. It wanted to add a additional folder called . when moving the file.
Thanks for the help
I have 312 directories labeled,
Ion_0001- Ion_0312.
In each directory I have a file light.out. I'd like to change the file names in each directory to, for example:
Ion_0001.out
I believe I also need to substitute the / so that my output DOESNT look this this:
Ion_0001/.out
Can any one help me out with a simple script??
This is what I've tried:
#!/bin/bash
for dir in */
do
cd $dir
for filename in *.out; do
mv $filename ${filename//$dir.out}
done
cd ..
done
Thanks!
Not a free coding service, but it's simple enough to not make it worth arguing about...
Assuming this file structure:
Ion_0001/
Ion_0001/light.out
Ion_0002/
Ion_0002/light.out
...
Run this code in a script or just at the command line:
for i in Ion_0*
do
mv "${i}/light.out" "${i}/${i}.out"
done
Resulting in this structure:
Ion_0001/
Ion_0001/Ion_0001.out
Ion_0002/
Ion_0002/Ion_0002.out
...
Is that what you were looking for?
for dir in Ion*/; do
mv "${dir}light.out" "${dir}${dir%/}.out"
done
The trailing slash in the Ion*/ pattern limits the results to directories only, but the slash will be present in the variable's value.
I am trying to figure out a way to search a directory for a file older than 365 days. If it finds a match, I'd like it to both delete the file and locate any other files in the directory that have the same basename, and delete those as well.
File name examples: 12345.pdf (Search for) then delete, 12345_a.pdf, 12345_xyz.pdf (delete if exist).
Thanks! I am very new to BASH scripting, so patience is appreciated ;-))
I doubt this can be done cleanly in a single pass.
Your best bet is to use -mtime or a variant to collect names and then use another find command to delete files matching those names.
UPDATE
With respect to your comment, I mean something like:
# find basenames of old files
find .... -printf '%f\n' | sort -u > oldfiles
for file in ($<oldfiles); do find . -name $file -exec rm; done