I am making a simple web application using Struts 2 + Spring Security 3. And I want to use Pre-Post Annotations for Method Level Security.
But the Annotations are not working.
Here is my web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" id="WebApp_ID" version="2.5">
<display-name>MyCustomSpringSecurity</display-name>
<context-param>
<param-name>contextConfiguration</param-name>
<param-value>/WEB-INF/applicationContext.xml</param-value>
</context-param>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<filter>
<filter-name>springSecurityFilterChain</filter-name>
<filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
</filter>
<filter-mapping>
<filter-name>springSecurityFilterChain</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<filter>
<filter-name>struts2</filter-name>
<filter-class>org.apache.struts2.dispatcher.FilterDispatcher</filter-class>
</filter>
<filter-mapping>
<filter-name>struts2</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
</web-app>
This is my struts.xml
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE struts PUBLIC "-//Apache Software Foundation//DTD Struts Configuration 2.1//EN" "http://struts.apache.org/dtds/struts-2.1.dtd">
<struts>
<package name="default" extends="struts-default">
<action name="firstPage" class="code.action.MyAction" method="showPage">
<result name="success">/firstPage.jsp</result>
</action>
</package>
</struts>
This is my applicationContext.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans:beans xmlns="http://www.springframework.org/schema/security" xmlns:beans="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security-3.1.xsd">
<global-method-security pre-post-annotations="enabled" >
</global-method-security>
<beans:bean id="myAction" class="code.action.MyAction">
<intercept-methods>
<protect access="ROLE_ADMIN" method="showPage"/>
</intercept-methods>
</beans:bean>
<http auto-config="true" use-expressions="true">
<intercept-url pattern="/index.jsp" access="permitAll" />
<intercept-url pattern="/firstPage" access="hasRole('ROLE_USER')" />
</http>
<authentication-manager>
<authentication-provider>
<user-service>
<user name="user" password="user" authorities="ROLE_USER" />
</user-service>
</authentication-provider>
</authentication-manager>
</beans:beans>
Finally This is MyAction.java
package code.action;
import org.springframework.security.access.prepost.PreAuthorize;
public class MyAction {
#PreAuthorize("hasRole('ROLE_ADMIN')")
public String showPage(){
System.out.println("in showPage");
return "success";
}
}
You can clearly see that I am assigning role to user is ROLE_USER but I want it to be ROLE_ADMIN when accessing that method, so logically there should be error of 403 Access Denied when running this code. But it is able to access that method and shows next page.
So I think the annotations are not working.
Any body knows whats going on ?
In order for Spring annotations to be meaningful in a Struts 2 action you must use the Struts 2 Spring Plugin. This will use Spring to instantiate Struts 2 objects, allowing annotation processing, injection, etc.
We cannot directly use Spring annotations like this.
There is another plugin Struts 2 - Spring Plugin for the same purpose. You can download the jar file from the link and include it in your project.
Related
I am a Spring security newbie am am having an issue when I am pairing it up with GWT. Namely, my calls to the services in GWT are marked as 403 forbidden.
POST http://127.0.0.1:8888/grapl/adminService 403 (Forbidden)
Here is my spring-security.xml
<?xml version="1.0" encoding="UTF-8"?>
<b:beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:b="http://www.springframework.org/schema/beans"
xmlns:security="http://www.springframework.org/schema/security"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security.xsd">
<!-- This is where we configure Spring-Security -->
<security:http auto-config="true" use-expressions="true">
<security:intercept-url pattern="/login" access="permitAll" />
<security:intercept-url pattern="/**" access="isAuthenticated()" />
<security:intercept-url pattern="/grapl/auth/**" access="isAuthenticated()"/>
<security:intercept-url pattern="/grapl/adminService/**" access="isAuthenticated()"/>
</security:http>
<b:bean id="graplAuthentication" class="com.lilly.rim.security.GraplAuthentication"/>
<security:authentication-manager alias="authenticationManager">
<security:authentication-provider ref="graplAuthentication" />
</security:authentication-manager>
</b:beans>
Web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
version="2.5"
xmlns="http://java.sun.com/xml/ns/javaee">
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring-security.xml, /WEB-INF/applicationContext.xml</param-value>
</context-param>
<filter>
<filter-name>springSecurityFilterChain</filter-name>
<filter-class>org.springframework.web.filter.DelegatingFilterProxy
</filter-class>
</filter>
<filter-mapping>
<filter-name>springSecurityFilterChain</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<!-- Servlets -->
<servlet>
<servlet-name>AdminServiceServlet</servlet-name>
<servlet-class>com.foo.rim.server.AdminServiceImpl</servlet-class>
</servlet>
<servlet>
<servlet-name>LoaderServiceServlet</servlet-name>
<servlet-class>com.foo.rim.server.LoaderServiceImpl</servlet-class>
</servlet>
<servlet>
<servlet-name>authServlet</servlet-name>
<servlet-class>com.foo.rim.server.AuthServiceImpl</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>authServlet</servlet-name>
<url-pattern>/grapl/auth</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>AdminServiceServlet</servlet-name>
<url-pattern>/grapl/adminService</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>LoaderServiceServlet</servlet-name>
<url-pattern>/grapl/loaderService</url-pattern>
</servlet-mapping>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<welcome-file-list>
<welcome-file>grapl.html</welcome-file>
</welcome-file-list>
</web-app>
Login and authentication is fine. I am redirected to my gwt frontend. My backend for the Spring authentication is a custom provider. All the configuration is done in the spring-security.xml.
Do the GWT servlets need a Spring annotation? Any example I have seen seems like it should all work via the configuration.
I needed to disable the csrf check.
<security:http ...
<security:csrf disabled="true" />
</security:http>
I want to use Spring Security but I'm getting 404 error in the web.xml page after adding spring security tag in the web.xml page. If I remove the security tags in the web.xml then the .jsp pages are running the local host. I am unable to figure out the problem in the tags in the web.xml. Please help me in finding the problem. I have given all the XML codes.
Below is my code snippet from my project.
web.xml:
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
id="WebApp_ID" version="3.0">
<display-name>Spring Web Application</display-name>
<!-- changed -->
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>
/WEB-INF/spring-dispatcher-servlet.xml,
/WEB-INF/spring-security.xml
</param-value>
</context-param>
<filter>
<filter-name>springSecurityFilterChain</filter-name>
<filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
</filter>
<filter-mapping>
<filter-name>springSecurityFilterChain</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<servlet>
<servlet-name>spring-dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>spring-dispatcher</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
</web-app>
This is my dispatcher.xml:
<?xml version="1.0" encoding="UTF-8"?>
<beans:beans xmlns="http://www.springframework.org/schema/security"
xmlns:beans="http://www.springframework.org/schema/beans"
xmlns:ctx="http://www.springframework.org/schema/context"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-2.5.xsd
http://www.springframework.org/schema/mvc
http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-2.5.xsd ">
<ctx:annotation-config></ctx:annotation-config>
<ctx:component-scan base-package="com.springMvc"></ctx:component-scan>
<ctx:component-scan base-package="com.springSecurity"></ctx:component-scan>
</beans:beans>
The spring security xml is given:
<?xml version="1.0" encoding="UTF-8"?>
<beans:beans xmlns="http://www.springframework.org/schema/security"
xmlns:beans="http://www.springframework.org/schema/beans"
xmlns:ctx="http://www.springframework.org/schema/context"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-4.2.xsd
http://www.springframework.org/schema/mvc
http://www.springframework.org/schema/mvc/spring-mvc-4.2.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-4.2.xsd
http://www.springframework.org/schema/security
http://www.springframework.org/schema/security/spring-security-4.2.xsd">
<http>
<intercept-url pattern="/helloSecurity*" access="ROLE_USER" />
<http-basic/>
</http>
<authentication-manager>
<authentication-provider>
<user-service>
<user name="sjit" password="123" authorities="ROLE_USER"/>
</user-service>
</authentication-provider>
</authentication-manager>
</beans:beans>
I just equipped a simple Spring test project with basic authentication functionality. When the server is loaded I get the well-known error
org.springframework.beans.factory.NoSuchBeanDefinitionException: No bean named 'springSecurityFilterChain' is defined.
web.xml:
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
<!-- The definition of the Root Spring Container shared by all Servlets and Filters -->
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring/root-context.xml</param-value>
</context-param>
<!-- Creates the Spring Container shared by all Servlets and Filters -->
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<!-- Processes application requests -->
<servlet>
<servlet-name>appServlet</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring/appServlet/servlet-context.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>appServlet</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
<!-- Activate Spring Security -->
<filter>
<filter-name>springSecurityFilterChain</filter-name>
<filter-class>org.springframework.web.filter.DelegatingFilterProxy
</filter-class>
</filter>
<filter-mapping>
<filter-name>springSecurityFilterChain</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
</web-app>
servlet-context.xml contains the security related configuration:
<?xml version="1.0" encoding="UTF-8"?>
<beans:beans xmlns="http://www.springframework.org/schema/mvc" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:beans="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context" xmlns:sec="http://www.springframework.org/schema/security"
xsi:schemaLocation="http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc.xsd
http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd
http://www.springframework.org/schema/security
http://www.springframework.org/schema/security/spring-security.xsd">
<!-- DispatcherServlet Context: defines this servlet's request-processing infrastructure -->
<!-- Enables the Spring MVC #Controller programming model -->
<annotation-driven />
<!-- Handles HTTP GET requests for /resources/** by efficiently serving up static resources in the ${webappRoot}/resources directory -->
<resources mapping="/resources/**" location="/resources/" />
<!-- Resolves views selected for rendering by #Controllers to .jsp resources in the /WEB-INF/views directory -->
<beans:bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<beans:property name="prefix" value="/WEB-INF/views/" />
<beans:property name="suffix" value=".jsp" />
</beans:bean>
<sec:http auto-config='true'>
<sec:intercept-url pattern="/**" access="ROLE_USER" />
</sec:http>
<sec:authentication-manager>
<sec:authentication-provider>
<sec:user-service>
<sec:user name="jimi" password="jimispassword" authorities="ROLE_USER, ROLE_ADMIN" />
<sec:user name="bob" password="bobspassword" authorities="ROLE_USER" />
</sec:user-service>
</sec:authentication-provider>
</sec:authentication-manager>
<context:component-scan base-package="myproject" />
</beans:beans>
What am I missing?
Additionally to M. Deinum's comment I found out that I could just add the path of my servlet-context to the contextConfigLocation:
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring/root-context.xml /WEB-INF/spring/appServlet/servlet-context.xml</param-value>
</context-param>
This solved the problem for me.
I am trying to configure spring security on my simple app, but I keep getting this error.
Caused by: java.lang.IllegalArgumentException: A universal match pattern ('/**') is defined before other patterns in the filter chain, causing them to be ignored. Please check the ordering in your <security:http> namespace or FilterChainProxy bean configuration
I have seen other similar posts, but could not figure out why I am getting this error. I don't seems to have duplicate security:http namespace configured.
Here goes my web.xml
<web-app xmlns="http://java.sun.com/xml/ns/j2ee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd"
version="2.4">
<display-name>sampler</display-name>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>
classpath:**/sampler-context.xml
classpath:**/sampler-security.xml
</param-value>
</context-param>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<servlet>
<servlet-name>sampler</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>sampler</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
<filter>
<filter-name>springSecurityFilterChain</filter-name>
<filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
</filter>
<filter-mapping>
<filter-name>springSecurityFilterChain</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
spring security config:
<beans:beans xmlns="http://www.springframework.org/schema/security"
xmlns:beans="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/security
http://www.springframework.org/schema/security/spring-security-3.1.xsd">
<!-- Add Authentication Manager -->
<authentication-manager>
<authentication-provider>
<user-service>
<user name="admin" authorities="ROLE_USER" password="test"/>
</user-service>
</authentication-provider>
</authentication-manager>
<!-- This would add login screen -->
<http auto-config="true">
<intercept-url pattern="/admin/*" access="ROLE_USER"/>
</http>
Its just a simple login functionality that I wanted to provide as of now. Any help around this issue would be really appreciated.
The problem was in the regex of classpath in the context-param.
<param-value>
classpath:**/sampler-context.xml
classpath:**/sampler-security.xml
</param-value>
Changing it to
<param-value>
classpath*:sampler-context.xml
classpath*:sampler-security.xml
</param-value>
solves this problem.
I'm having problems trying to create a custom login page for Spring web application.
The default login form works normally.
But when I add
**<form-login login-page="/login" />**
the app runs without errors but "unable to display page" shows up.
Have you got any ideas?
Thanks
Here is my web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" id="WebApp_ID" version="3.0">
<display-name>testweb</display-name>
<filter>
<filter-name>springSecurityFilterChain</filter-name>
<filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
</filter>
<filter-mapping>
<filter-name>springSecurityFilterChain</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<!--
- Loads the root application context of this web app at startup.
-->
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<!--
- Location of the XML file that defines the root application context
- Applied by ContextLoaderListener.
-->
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>
/WEB-INF/applicationContext-security.xml
</param-value>
</context-param>
<!-- Processes application requests -->
<servlet>
<servlet-name>dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
</web-app>
Here is my spring config file
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:context="http://www.springframework.org/schema/context"
xmlns:tx="http://www.springframework.org/schema/tx"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xsi:schemaLocation="
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.0.xsd
http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-3.0.xsd
http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd
">
<!-- DispatcherServlet Context: defines this servlet's request-processing infrastructure -->
<!-- Scans within the base package of the application for #Components to configure as beans -->
<!-- #Controller, #Service, #Configuration, etc. -->
<context:component-scan base-package="myPACKAGE" />
<!-- Enables the Spring MVC #Controller programming model -->
<mvc:annotation-driven />
<!-- Resolve logical view names to .jsp resources in the /WEB-INF/views directory -->
<bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix" value="/WEB-INF/views/" />
<property name="suffix" value=".jsp" />
</bean>
</beans>
Here is my spring security file
<?xml version="1.0" encoding="UTF-8"?>
<beans:beans xmlns:beans="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:context="http://www.springframework.org/schema/context"
xmlns="http://www.springframework.org/schema/security"
xsi:schemaLocation="
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.0.xsd
http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security-3.1.xsd
">
<http auto-config="true">
<intercept-url pattern="/*" access="ROLE_USER" />
**<form-login login-page="/login" />**
</http>
<authentication-manager>
<authentication-provider>
<user-service>
<user name="myuser" password="mypwd" authorities="ROLE_USER" />
</user-service>
</authentication-provider>
</authentication-manager>
</beans:beans>
The custom login page is login.jsp inside WEB-INF/views/login.jsp
You need to give access for anonymous users to the login page. Add following snippet to your http element
<intercept-url pattern="/login*" access="IS_AUTHENTICATED_ANONYMOUSLY" />
EDIT. Order is matter. It must be inserted before this line:
<intercept-url pattern="/*" access="ROLE_USER" />
your login - what is it? HTML? JSP? you need to write the URI of your login page (e.g. /login.html), and not just /login.
try to put your login page in a sub-dir (e.g. /login) that enables anonymous users to see it:
< http pattern="/login/**" security="none" />
and then
<security:form-login
login-page="/login/login.jsp"
...
You said you are using spring so I will assume you are using spring-mvc, have you added
<!-- selects a static view for rendering without the need for an explicit controller -->
<mvc:view-controller path="/login" view-name="login"/>
to your webmvc configuration.
Also to change the login page mapping you can add
<definition extends="default" name="/login">
<put-attribute name="body" value="/WEB-INF/views/login.jspx"/>
</definition>
This should do I guess.
<intercept-url pattern="/login.htm" access="permitAll()"/>
<form-login login-page="/login.htm"
authentication-failure-url = "/positionViewer/login.htm?login_error=1" />