I grep this string from a SVG file:
<g transform="translate(0.000000,980.000000) scale(0.100000,-0.100000)"
and I want to get the number 980 within a bash script variable. My problem is that I don't manage to pipe the right expression to get only that number 980 out of the string. I need to add that, of course, the number 980 can be any number from any length (for example, 5967 or 98...).
Could you offer me a solution? I'm stuck there...
Assuming your SVG input file is input.svg. You should try:
cat input.svg | grep translate | sed 's/^.*translate(.*,\(.*\)\..*) scale.*$/\1/'
From my understanding, you can use awk.
grep whatever | awk -F"," '{print $2}' | awk -F"." '{print $1}'
No need for more than one simple command:
awk -F"[,.]" '/your_search_string/{print $3}'
HTH Chris
just bash, I assume you want the 2nd parameter to "translate()"
$ line='<g transform="translate(0.000000,980.000000) scale(0.100000,-0.100000)"'
$ num=${line#*translate*,}; echo $num
980.000000) scale(0.100000,-0.100000)"
$ num=${num%%.*}; echo $num
980
This might work for you:
sed '/^<g transform/!d;s/[^,]*,//;s/[^0-9].*//
The below awk command should work for you.
awk -v FS="[ =(,)]" '{print $5}' "Yourfilename" | awk -v FS="[.]" '{print $1}'
Related
Can I able to give the value(32) in the form of variable in the below awk command instead of hardcoding 32 directly?
df -h | head -1|awk '{printf "%s%32s",$1,$2}'
I tried like awk -v var=32 but its not working.
Can anyone suggest me please.
awk -v var=32 '{printf "%s%*s\n", $1, var, $2}'
awk -v var=32 '{printf "%s%"var"s", $1,$2}'
Note: The solution of Ed Morton is cleaner as it does not use AWK string concatenations but makes direct use of the printf formatting
Simultaneously, if you want to get rid of your head then you can combine everything as:
$ df -h | awk -v var=32 '{printf "%s%"var"s", $1,$2; exit}'
One alternative to the answer given by Ed Morton, could be useful, if you have the number already stored in an environment variable (say: FIELD_WIDTH). In this case,
df -h | head -1|awk '{printf "%s%" ENVIRON["FIELD_WIDTH"] "s",$1,$2}'
would do the job.
UPDATE:
You should also get rid of the head:
df -h | awk 'NR==1 {printf "%s%" ENVIRON["FIELD_WIDTH"] "s",$1,$2}'
I'm trying to extract the column which matches the date pattern like: YYYY-MM-DD, but didn't understand the difference between below commands
Working command
echo 1,2,3,4,2015-12-34 | awk -F, '{if($5~/^[0-9][0-9][0-9][0-9]-[0-9][0-9]-[0-9][0-9]$/) print $1}'
Not working command
echo 1,2,3,4,2015-12-34 | awk -F, '{if($5~/^[0-9]{d}-[0-9]{2}-[0-9]{2}$/)print $1}'
Can someone explain me why it's happening, am i missing a granular thing?
You could try following and let me know if this helps you.
echo 1,2,3,4,2015-12-34 | awk --re-interval -F, '{if($5~/^[0-9]{4}-[0-9]{2}-[0-9]{2}$/)print $1}'
OR
echo 1,2,3,4,2015-12-34 | awk --re-interval -F, 'match($NF,/[0-9]{4}-[0-9]{2}-[0-9]{2}/){print $1}'
NOTE: My awk version is OLD so I am using --re-interval you could remove it in case you have recent awk version.
I have this file (serials.txt) containing serial numbers:
S/N:175-1915011190
S/N:244-1920023447
S/N:335-1920101144
S/N:244-1920101149
Using grep or similar tool I want to select all serials NOT starting with '244'
I'm able to select all the '244' with grep -Eo '244-[0-9]*' serials.txt but I want the opposite.
Something like grep -Eo '(^244)-[0-9]*' serials.txt
The output should be (without S/N:)
175-1915011190
335-1920101144
Following awk may help you in same.
awk '!/S\/N:244/' Input_file
EDIT: Above code will give complete line as output if you need starting from serial number to till end in output then following may help you.
awk -F':' '!/S\/N:244/{print $2}' Input_file
EDIT2: Adding a sed solution too here for same.
sed -n '/:244/d;s/.*://;p' Input_file
The -v option on grep would be helpful here, and then cut to remove the leading cruft:
grep -v ':244-' serials.txt | cut -c5-
Here you go, without S/N:
grep -v ':244' serials.txt | cut -d':' -f2
Antigrep for :244, cuts with delimiter : shows field 2.
awk -F':' '$2!~/^244/{print $2}' file
I'm trying to get the numbers that's in between two colons and other numbers in a file.
Example:
1234:12345678:1234
1234:12345678:1234
1234:12345678:1234
I want the output to show all of the 12345678's and nothing else.
Like this:
12345678
12345678
12345678
I achieved this using:
egrep -o "[0-9]{8}" file
Problem is that I need a different solution than egrep -o (awk or sed?)
I searched and tried a couple of things but without succes.
Any help would be appreciated!
If the "number" is always 2nd column, you could do with awk:
awk -F: '{print $2}' file
For the awk solution,
awk -F: '{print $2}' file
Or simply use cut to do that,
cut -d: -f2 file
would this work?
awk -F':' '{print $2}' test > test results.txt
I'm trying to write a bash shell script, that opens a certain file CATALOG.dat, containing the following lines, made of both characters and numbers:
event_0133_pk.gz
event_0291_pk.gz
event_0298_pk.gz
event_0356_pk.gz
event_0501_pk.gz
What I wanna do is print the numbers (only the numbers) inside a new file NUMBERS.dat, using something like > ./NUMBERS.dat, to get:
0133
0291
0298
0356
0501
My problem is: how do I extract the numbers from the text lines? Is there something to make the script read just the number as a variable, like event_0%d_pk.gz in C/C++?
A grep solution:
grep -oP '[0-9]+' CATALOG.dat >NUMBERS.dat
A sed solution:
sed 's/[^0-9]//g' CATALOG.dat >NUMBERS.dat
And an awk solution:
awk -F"[^0-9]+" '{print $2}' CATALOG.dat >NUMBERS.dat
There are many ways that you can achieve your result. One way would be to use awk:
awk -F_ '{print $2}' CATALOG.dat > NUMBERS.dat
This sets the field separator to an underscore, then prints the second field which contains the numbers.
Awk
awk 'gsub(/[^[:digit:]]/,"")' infile
Bash
while read line; do echo ${line//[!0-9]}; done < infile
tr
tr -cd '[[:digit:]\n]' <infile
You can use grep command to extract the number part.
grep -oP '(?<=_)\d+(?=_)' CATALOG.dat
gives output as
0133
0291
0298
0356
0501
Or
much simply
grep -oP '\d+' CATALOG.dat
You don't need perl mode in grep for this. BREs can do this.
grep -o '[[:digit:]]\+' CATALOG.dat > NUMBERS.dat