I have a table. it has a column with datatype NUMBER(38,20). it is an id column. out application generates the id. i am trying to insert record with an id value of 105.00010. but it inserts only 105.0001. May i know the reason why it is truncating one value(0). it porperly inserts records from 105.00001 to 105.00009. while inserting 105.00010 it is truncating. Please help me.
column size is **NUMBER(38,20)**
Thanks!
See the following test case:
WITH data_values
AS (SELECT 105.0001 AS test_val FROM dual
UNION ALL
SELECT 105.00010 AS test_val FROM dual)
SELECT test_val,
TO_NUMBER(test_val, '999.99999') AS NUM,
TO_CHAR(test_val, '999.99999') AS STR
FROM data_values;
Results in:
TEST_VAL NUM STR
105.0001 105.0001 105.00010
105.0001 105.0001 105.00010
The value after the final non zero digit is irrelevent to Oracle. Both your numbers are equivalent.
The rightmost zeros after the decimal are insignificant, so the value is not truncated, it is still the same value.
If you need it to stay the same you may need to treat the value as a varchar2.
Related
Does apex_string.split always guarantee that the order of the rows returned is the order of the characters of the string ?
Can I rely on the rownum to always correspond to 1 for the first character of the split string ?
or do I need to add a order by rownum ?
What is the method to get the rows in the same order of the characters of the string ?
My requirement is to insert the rows returned by apex_string.split in the same order as the characters of the string.
I am currently executing the below, will this maintain the character order ?
select t.column_value value, rownum seq
from table(apex_string.split('test','')) t
bulk collect into ins_arr;
for i in ins_arr.first..ins_arr.last
loop
/* execute insert statement */
insert into table (seq, value )
values (ins_arr.seq,ins_arr.value);
end loop
The insert should result in
seq
value
1
t
2
e
3
s
4
t
Thank you in advance,
I don't think it's guaranteed, becuase if it was, it would be in the documentation. But I think you can accomplish what you want by changing your routine. (Note, I have not verified this.)
insert into table (seq, value)
select t.column_value value,
row_number() over (order by t.column_value)
from table(apex_string.split('test','')) t
I think you can do the same with rownum, but I'm never 100% sure what order the rownum and the order by happen in.
Am trying to list top 3 records from atable based on some amount stored in a column FTE_TMUSD which is of varchar datatype
below is the query i tried
SELECT *FROM
(
SELECT * FROM FSE_TM_ENTRY
ORDER BY FTE_TMUSD desc
)
WHERE rownum <= 3
ORDER BY FTE_TMUSD DESC ;
o/p i got
972,9680,963 -->FTE_TMUSD values which are not displayed in desc
I am expecting an o/p which will display the top 3 records of values
That should work; inline view is ordered by FTE_TMUSD in descending order, and you're selecting values from it.
What looks suspicious are values you specified as the result. It appears that FTE_TMUSD's datatype is VARCHAR2 (ah, yes - it is, you said so). It means that values are sorted as strings, not numbers - and it seems that you expect numbers. So, apply TO_NUMBER to that column. Note that it'll fail if column contains anything but numbers (for example, if there's a value 972C).
Also, an alternative to your query might be use of analytic functions, such as row_number:
with temp as
(select f.*,
row_number() over (order by to_number(f.fte_tmusd) desc) rn
from fse_tm_entry f
)
select *
from temp
where rn <= 3;
I need help
i have records 123,456,789 in rows when i am execute like
this one is working
select * from table1 where num1 in('123','456')
but when i am execute
select * from table1 where num1 in(select value from table2)
no resultset found - why?
Check the DataType varchare2 or Number
try
select * from table1 where num1 in(select to_char(value) from table2)
Storing comma separated values could be the cause of problem.
You can try using regexp_substr to split comma.
First and foremost, an important thing to remember: Do not store numbers in character datatypes. Use NUMBER or INTEGER. Secondly, always prefer VARCHAR2 datatype over CHAR if you wish to store characters > 1.
You said in one of your comments that num1 column is of type char(4). The problem with CHAR datatype is that If your string is 3 characters wide, it stores the record by adding extra 1 space character to make it 4 characters. VARCHAR2 only stores as many characters as you pass while inserting/updating and are not blank padded.
To verify that you may run select length(any_char_col) from t;
Coming to your problem, the IN condition is never satisfied because what's actually being compared is
WHERE 'abc ' = 'abc' - Note the extra space in left side operator.
To fix this, one good option is to pad the right side expression with as many spaces as required to do the right comparison.The function RPAD( string1, padded_length [, pad_string] ) could be used for this purpose.So, your query should look something like this.
select * from table1 where num1 IN (select rpad(value,4) from table2);
This will likely utilise an index on the column num1 if it exists.
The other one is to use RTRIM on LHS, which is only useful if there's a function based index on RTRIM(num1)
select * from table1 where RTRIM(num1) in(select value from table2);
So, the takeaway from all these examples is always use NUMBER types to store numbers and prefer VARCHAR2 over CHAR for strings.
See Demo to fully understand what's happening.
EDIT : It seems You are storing comma separated numbers.You could do something like this.
SELECT *
FROM table1 t1
WHERE EXISTS (
SELECT 1
FROM table2 t2
WHERE ',' ||t2.value|| ',' LIKE '%,' || rtrim(t1.num1) || ',%'
);
See Demo2
Storing comma separated values are bound to cause problems, better change it.
Let me tell you first,
You have stored values in table2 which is comma seperated.
So, how could you match your data with table1 and table2.
Its not Possible.
That's why you did not get any values in result set.
I found the Solution using string array
SELECT T.* FROM TABLE1 T,
(SELECT TRIM(VALUE)AS VAL FROM TABLE2)TABLE2
WHERE
TRIM(NUM1) IN (SELECT COLUMN_VALUE FROM TABLE(FUNC_GETSTRING_ARRAY(TABLE2.VAL)))
thanks
How can I retrieve a list off nth occurence of data in a clob?
Example of a clob:
<bank>
<bankDetails>
<bankDetailsList>
<pk>1</pk>
<accountName>
<asCurrent>EDGARS LESOTHO</asCurrent>
</accountName>
<bankAccountType>
<asCurrent>CURR</asCurrent>
</bankAccountType>
</bankDetailsList>
<bankDetailsList>
<pk>2</pk>
<accountName>
<asCurrent>EDGARS LESOTHO 2</asCurrent>
</accountName>
<bankAccountType>
<asCurrent>CURR</asCurrent>
</bankAccountType>
</bankDetailsList>
</bankDetails>
</bank>
So I would like to retrieve all values of account names in sql assuming there might be up to nth list of this account names occurring in a clob.
I am using oracle 11g and SqlDeveloper 4.1.3
Your response is highly appreciated.
SELECT EXTRACTVALUE( v.COLUMN_VALUE, '/asCurrent' )
FROM table_name t,
TABLE(
XMLSequence(
EXTRACT(
XMLType( t.clob_column ),
'/bank/bankDetails/bankDetailsList/accountName/asCurrent'
)
)
) v
SELECT level as rnk, regexp_substr(t.clob_column,
'<accountName>[^<]*?<asCurrent>([^<]*?)<', 1, level, null, 1) as acct_name
FROM t
CONNECT BY level <= (select regexp_count(clob_column, '<accountName>') FROM t);
t is the table name and clob_column is the column with clob values (in my test case, the table has one row and one column, the value being the one in the original post).
If you have a column of clob values and need to do this simultaneously for more than one value, this needs to be modified a bit; please clarify the requirement and we can take it from there.
ADDED: To make it work with several rows, you need to modify the CONNECT BY LEVEL clause. You want each row to only reference itself; and to avoid issues with cycles, you need to add one more condition. Like this:
...
CONNECT BY level <= (select regexp_count(clob_column, '<accountName>') FROM t)
and clob_column= prior clob_column
and prior sys_guid() is not null;
I'm doing a query that returns a VARCHAR2 and some other fields. I'm ordering my results by this VARCHAR2 and having some problems related to the linguistic sort, as I discovered on Oracle documentation. For example:
SELECT id, my_varchar2 from my_table ORDER BY MY_VARCHAR2;
Will return:
ID MY_VARCHAR2
------ -----------
3648 A
3649 B
6504 C
7317 D
3647 0
I need it to return the string "0" as the first element on this sequence, as it would be comparing ASCII values. The string can have more than one character so I can't use the ascii function as it ignores any characters except for the first one.
What's the best way to do this?
For that case, you should be able to just order by the BINARY value of your characters;
SELECT id, my_varchar2
FROM my_table
ORDER BY NLSSORT(MY_VARCHAR2, 'NLS_SORT = BINARY')
SQLFiddle here.