Sinatra - How to best move variable/parameter between pages - ruby

I have a register page with the usual email,name,password ..which is validated in the server's submitted route/page. if it fails then I redirect back but I want to fill the values back in the register page..I can put the register form parameters in the session but it will stay there...is there a page memory(a smaller scope than session) just like session which will be just for the next page and then gone/ which is the best way to implement this.
Thanks

Why don't you just render the registration page from the POST route like this:
post '/register' do
#registration_data = params[:stuff] # store all your registration data
if info_validates # everything validates
redirect './user_home'
else # something fails validation
haml :register # or erb or whatever your template engine is
end
end
Then in your view, have it fill in #registration_data if it exists.
Also, you can clear session data with session.clear.

Ajax validation would be much easier. You just register an onclick event to your form submit button that makes a call to a page that returns a json status code with the error information or 200 for OK. If 200, then submit.

Related

How rails form instance works?

I have these two methods, show and create.
def show
#article = Article.find(params[:id])
#comment = Comment.new
#comment.article_id = #article.id
end
def create
#comment = Comment.new(comment_params)
#comment.article_id = params[:article_id]
#comment.save
redirect_to article_path(#comment.article)
end
Show method displays my comment form.
In the show method why do we create a new instance of Comment and also associate the comment
instance to an article id.
Create method actually handles the submission of form.
In the create method, again i am creating a new comment object and again associating the comment's article_id.
My whole questing is why were repeating these things?. Why do I have associate my comment form with article_id when I am displaying it and again I am repeating the steps while submitting the form too.
This repetition could be avoided if you keep those resources nested and build the form as:
<%= form_for(#article, #article.comments.build) do |f| %>
Hope this helps! :)
The reason that you initialize a comment both times is because the user's browser only sees the html form - it doesn't have a concept of a Comment - and because each request to a Rails application is independent - nothing is persisted in the application between requests:
When the user requests the show page for an Article, the request is handled by the application something like this:
The controller creates a new Comment object (in memory).
The form_for helpers in the view build a form from that Comment.
The html for the show page is sent to the user's browser.
At this point the application has done everything it needs to serve this request, so the temporary Comment object is deleted.
When the user submits the form, the values that were entered are sent to the application in the comment_params and the application handles this request like this:
The controller creates a new Comment object (again in memory), but initializes it with the data that the user sent through in comment_params.
The controller saves the Comment - this stores the Comment in the database so it can be loaded later.
The controller redirects back to the show page.
Saving to the database is the main way that the application can persist things between requests - objects in memory only exist while the request is being processed.

Laravel Session data not written/update/availabe in View when using AJAX

When I add things to the Session with Session::put() in my controller action, then that data is not available in my view, with Session::get() when doing AJAX request.
The same problem goes for the Former package, which I use for nice form building. It relies on passing some info via the Session, which is used to mark fields as valid/invalid. This functionality is also not working when using AJAX.
I set a view like always, in my View:
$this->layout->content = View::make('account.login')
For AJAX requests, I do NOT render the normal way with layout, but instead get the specific "content" section of the template and return it:
$this->layout->content->renderSections()['content']
When I do a "normal" request, then Session data works fine.
When I do an AJAX request, then Session data set in the controller DURING the AJAX call is ignored. Any Session data set BEFORE the AJAX call is available.
I'm wondering if Laravel has some issue with Session under AJAX calls, or with the the "renderSection()" method above?
I have checked all the obvious problems:
AJAX request uses the same session ID as non-AJAX request.
GET/POST verbs are used correctly etc.
Replicate:
In CONTROLLER action: Session:put('foo','bar');
In VIEW file (in the content part): Session:put('foo2','bar2');
In VIEW file (in the content part): var_dump(Session::get('foo','bar')); // Returns 'bar' in non-AJAX calls, but returns nothing for AJAX calls (!!!)
In VIEW file (in the content part): var_dump(Session::get('foo2')); // Returns 'bar2' in both AJAX and non-AJAX calls as expected.
It seems like the Session values set in the controller action ARE LOST when it renders the view. Therefore my question if this is 1) an AJAX vs. SESSION issue in Laravel, or 2) an Session vs. renderElement() problem that I am not aware of?
I had the same problem and just found a potential solution:
I found a similar problem relating to laravel 3. For the session to persist in an ajax call you need to return the response correctly.
return json_encode($response);
This is causing the problem. It's not it appears a valid response to enable the session to persist. Change it to:
return Response::json($response);
This enables the session to persist!
For some reason a normal form submit or call to the method allows the first one but ajax does not.
I've seen references elsewhere about echo statements in the method affecting the session - the return I suppose must behaving similar to an echo
This is the post that triggered the solution:
http://forumsarchive.laravel.io/viewtopic.php?id=1304

django, return to previous page after form POST submit

In my web page I have a form that is being filled with data after some ajax requests. For example when a user chooses an item from the list, a simple ajax request is sent to the database that the item has been selected (but not confirmed, yet). Then the list on the web page reloads using a simpe ajax request (just the list, not the whole page) to fetch the new item list.
I think this is more or less a classic cart implementation.
However, when the user presses submit (classic form POST submit, not ajax POST for some reasons concerning the implementation) to confirm the whole list, I would like to return to the current page. (Current page varies) Is this possible? I am using django.
Thanks.
You can supply a next GET parameter when submitting the form, similar to django.contrib.auth's login() method:
https://docs.djangoproject.com/en/dev/topics/auth/#django.contrib.auth.views.login:
<form action="/url/to/post/form/?next={{ some_variable }}">
where the variable can simply be the current URL (taken from the request) or a generated URL. In the view processing the form, simply check for a next parameter and redirect appropriately:
from django.shortcuts import redirect
if 'next' in request.GET:
return redirect(request.GET['next'])
You may be able to use the Post/Redirect/Get Design pattern (PRG). For more general information about Post/Redirect/Get please see the following: http://en.wikipedia.org/wiki/Post/Redirect/Get There are some nice process flow diagrams there.
A generic example of a view implementing PRG might look like the following:
# urls.py
urlpatterns = patterns('',
url(r'^/$', views.my_view, name='named_url'),
)
# forms.py
class MyForm(forms.Form):
pass # the form
# views.py
def my_view(request, template_name='template.html'):
""" Example PostRedirectGet
This example uses a request context, but isn't
necessary for the PRG
"""
if request.POST:
form = MyForm(request.POST)
if form.is_valid():
try:
form.save()
# on success, the request is redirected as a GET
return HttpResponseRedirect(reverse('named_url'))
except:
pass # handling can go here
else:
form = MyForm()
return render_to_response(template_name, {
'form':form
}, context_instance=RequestContext(request))
If you need to do something more interesting with the GET, reverse can take args and kwargs. Manipulate the view params, url_pattern, and reverse call to display the results you would like to see.
One additional note is that you don't have to redirect to the same view (as this example does). It could be any named view that you would like to redirect the user to.
current page is a very vague term but i am assuming you want the page that referred you to the form page, this is normally (not always) stored in the HTTP_REFERRER header of the request itself. You could try to fetch that from the request and do a redirect.

Django Forms - Processing GET Requests

We have an existing Django form that accepts GET requests to allow users to bookmark their resulting query parameters. The form contains many fields, most of which are required. The form uses semi-standard boilerplate for handling the request, substituting GET for POST:
if request.method == 'GET':
form = myForm(request.GET)
if form.isValid()
# Gather fields together into query.
else
form = myForm()
The problem is that the first time the form is loaded, there's nothing in the GET request to populate the required fields with, so most of the form lights up with 'missing field' errors.
Setting initial values doesn't work; apparently, the non-existent values in the GET request override them.
How can we avoid this? I'm pretty certain we're simply not processing things correctly, but I can't find an example of a form that handles GET requests. We want errors to show up if the user hits the "Submit" button while fields are blank or otherwise invalid, but don't want these errors showing up when the form is initially displayed.
The positional argument to the forms.Form subclass informs Django that you intend to process a form rather than just display a blank/default form. Your if request.method == 'GET' isn't making the distinction that you want because regular old web requests by typing a URL in a web browser or clicking a link are also GET requests, so request.method is equal to GET either way.
You need some differentiating mechanism such that you can tell the difference between a form display and a form process.
Ideas:
If your processing is done via. AJAX, you could use if request.is_ajax() as your conditional.
Alternatively, you could include a GET token that signifies that the request is processing. Under this example, first you'd need something in your form:
<input type="hidden" name="action" value="process_form" />
And then you can look for that value in your view:
if 'action' in request.GET and request.GET['action'] == 'process_form':
form = myForm(request.GET)
if form.is_valid():
# form processing code
else:
form = myForm()
I'll also give you the standard, boilerplate point that it's generally preferable not to use GET for form processing if you can help it (precisely because you run into difficulties like this since you're using an anomalous pattern), but if you have a use case where you really need it, then you really need it. You know your needs better than I do. :-)
If your clean page load doesn't have any non form GET params, you can differentiate between a clean page load and a form submit in your view. Instead of the usual
form = YourForm()
if request.POST:
you can do
if request.GET.items():
form = YourForm(request.GET)
if form.is_valid():
...
else:
form = YourForm()
If your clean page load could have other params (eg email link tracking params) you'll need to use the QueryDict methods to test if any of your form params are in the request.
request.GET is and empty dictionary when you first load a clean form. Once you have submitted the form, request.GET will be populated with your fields data, even if the fields contain only empty data.
My first question is this, which I posted as comment:
Why not just use request.POST and the standard way of processing form data?
After considering everything here, perhaps what you are looking for is a way of processing data in your query string to populate a form. You can do that without using request.GET as your form.data.
In my own views, I take advantage of a utility function I created to add initial data to the form from request.GET, but I am not going to share that function here. Here's the signature, though. initial_dict is typically request.GET. model_forms is either a single ModelForm or a list of ModelForm.
def process_initial_data(model_forms, initial_dict):
Nevertheless, I am able to process the form through the standard practice of using request.POST when the form is POSTed. And I don't have to pass around all kinds of information in the URL query string or modify it with JavaScript as the user enters information.

Use CodeIgniter form validation in a view

I have footer view that's included on all my pages which contains a form. I would like to be able to make use of CI's form validation library to validate the form. Is that possible?
Currently the form posts back to the current page using the PHP_SELF environment variable. I don't want to get it to post to a controller because when validation fails it loads the controller name in the address bar, which is not the desired behaviour.
Any suggestions gratefully received.
Thanks,
Gaz
One way, whilst far from ideal, would be to create a "contact" function in every controller. This could be in the form of a library/helper.
CI doesn't natively let you call one controller from another, although I believe there are extensions that enable this.
Another option would be an AJAX call instead, which would allow you to post to a generic controller, validate etc whilst remaining on the current page.
In this use case, I would definitely go for an AJAX call to a generic controller. This allows you to show errors even before submitting in the origin page.
Another way (slightly more complex), involves posting your form data to a generic controller method, passing it a hidden input containing the current URL.
The generic controller method handling your form can then redirect to the page on which the user submitted the form, passing it the validation errors or a success message using flash session variables: $this->session->set_flashdata('errors',validation_errors()) might do the trick (untested)
The good thing about this is that you can use the generic form-handling method for both the ajax case (suppressing the redirect) and the non-ajax case
AJAX would be best, just like everyone else says.
I would redirect the form to one function in one controller, you could make a controller just for the form itself. Then have a hidden value with the return URL. As far as errors go you could send them back with flashdata.
Just remember to never copy paste code, it a bad practice and guarantees bugs.
//make sure you load the proper model
if ($this->form_validation->run() == FALSE){
// invalid
$redirect = $this->input->post('url');
$this->session->set_flashdata('errors',validation_errors());
redirect($redirect);
} else {
/*
success, do what you want here
*/
redirect('send them where ever');
}

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