I'm just working on my first gem (pretty new to ruby as well), entire code so far is here;
https://github.com/mikeyhogarth/tablecloth
One thing I've tried to do is to create a yaml file which the gem can access as a lookup (under lib/tablecloth/yaml/qty.yaml). This all works great and the unit tests all pass, hwoever when I build and install the gem and try to run under irb (from my home folder) I am getting;
Errno::ENOENT: No such file or directory - lib/tablecloth/yaml/qty.yaml
The code is now looking for the file in ~/lib/tablecloth... rather than in the directory the gem is installed to. So my questions are;
1) How should i change line 27 of recipe.rb such that it is looking in the folder that the gem is installed to?
2) Am I in fact approaching this whole thing incorrectly (is it even appropriate to use static yaml files within gems in this way)?
Well first of all you should refer to the File in the following way:
file_path = File.join(File.dirname(__FILE__),"yaml/qty.yaml")
units_hash = YAML.load_file(filepath)
File.dirname(__FILE__) gives you the directory in which the current file (recipe.rb) lies.
File.join connects filepaths in the right way. So you should use this to reference the yaml-file relative to the recipe.rb folder.
If using a YAML-file in this case is a good idea, is something which is widely discussed. I, myself think, this is an adequate way, especially in the beginning of developing with ruby.
A valid alternative to yaml-files would be a rb-File (Ruby Code), in which you declare constants which contain your data. Later on you can use them directly. This way only the ruby-interpreter has to work and you save computing time for other things. (no parser needed)
However in the normal scenario you should also take care that reading in a YAML file might fail. So you should be able to handle that:
file_path = File.join(File.dirname(__FILE__),"yaml/qty.yaml")
begin
units_hash = YAML.load_file(filepath)
rescue Psych::SyntaxError
$stderr.puts "Invalid yaml-file found, at #{file_path}"
exit 1
rescue Errno::EACCES
$stderr.puts "Couldn't access file due to permissions at #{file_path}"
exit 1
rescue Errno::ENOENT
$stderr.puts "Couldn't access non-existent file #{file_path}"
exit 1
end
Or if you don't care about the details:
file_path = File.join(File.dirname(__FILE__),"yaml/qty.yaml")
units_hash =
begin
YAML.load_file(filepath)
rescue Psych::SyntaxError, Errno::EACCES, Errno::ENOENT
{}
end
Related
I got a method where I use Dir.chdir(File.dirname(__FILE__)) inside. I am using it so that I can run the ruby file from anywhere and not get this error: No such file or directory # rb_sysopen - 'filename' (Errno::ENOENT).
Using the method for the first time works fine but using it for the second time throws an error. See method and exact error below.
def meth(string)
Dir.chdir(File.dirname(__FILE__))
hash = JSON.parse(File.read("file.json"))
# do something with hash and string
# return some value
end
meth("first string") # this returns what is expected
meth("second string") # this second usage of the method throws the error
Error sample pinpointing the line where I used Dir.chdir(File.dirname(__FILE__)):
dir/decoder.rb:44:in `chdir': No such file or directory # dir_s_chdir - lib (Errno::ENOENT)
Not sure if OS plays a role here, I am using an m1 BigSur on version 11.2.3.
Why is this happening?
What needs to be done so that the method` can be used as much as needed without running into the error?
Your problem here seems to be that __FILE__ is a relative path like dir/decoder.rb and that path becomes invalid after the first time Dir.chdir is used, because that command changes the working directory of your entire Ruby process. I think the solution would be to do something like this in your decoder.rb file:
DecoderDir = File.realpath(File.dirname(__FILE__))
def meth
Dir.chdir(DecoderDir)
# ...
end
I'm guessing that the first time the Ruby interpreter processes the file, that is early enough that the relative path in __FILE__ still refers to the right place. So, at that time, we generate an absolute path for future use.
By the way, a well-behaved library should not run Dir.chdir because it will affect all use of relative paths throughout your entire Ruby process. I pretty much only run Dir.chdir once and I run it near the beginning of my top-level script. If you're making a reusable library, you might want to do something like this to calculate the absolute path of the file you want to open:
DecoderJson = File.join(DecoderDir, 'file.json')
The challenge prompt is above, and my latest attempt is below. The directories and files are created as expected, and the read-out after executing chef-apply multipleCopies.rb tells me the files are linked, but when I update any one of the files, the others do not follow suit. Any ideas? Here is my code:
for x in 1..3
directory "multipleCopy#{x}" do
mode '0755'
action :create
end
end
file "multipleCopy1/secret.txt" do
mode '0755'
action :create
end
for x in 2..3
link "multipleCopy#{x}/secret.txt" do
to "multipleCopy1/secret.txt"
link_type :hard
subscribes :reload, "multipleCopy1/secret.txt", :immediately
end
end
Note: For less headache, I am testing the recipe locally before uploading to the ubuntu server referenced in the prompt, which is why my file paths are different and why I have not yet included the ownership properties.
So a file hard link doesn't seem to be what the question is going for (though I would say your solution is maybe better since this is really not what Chef is for, more on that later). Instead they seem to want you to have three actually different files, but sync the contents.
So first the easy parts, creating the directories and the empty initial files. It's rare to see those for loops used in Ruby code, though it is syntactically valid:
3.times do |n|
directory "/var/save/multipleCopy#{n+1}" do
owner "ubuntu"
group "root"
mode "755"
end
file "/var/save/multipleCopy#{n+1}/secret.txt" do
owner "root
group "root"
mode "755"
end
end
But that doesn't implement the hard part of sync'ing the files. For that we need to first analyze the mtimes on the files and use the most recent as the file content to set.
latest_file = 3.times.sort_by { |n| ::File.mtime("/var/save/multipleCopy#{n+1}/secret.txt") rescue 0 }
latest_content = ::File.read("/var/save/multipleCopy#{latest_file+1}/secret.txt") rescue nil
and then in the file resource:
file "/var/save/multipleCopy#{n+1}/secret.txt" do
owner "root
group "root"
mode "755"
content latest_content
end
As for this not being a good use of Chef: Chef is about writing code which asserts the desired state of the machine. In the case of files like this, rather than doing this kind of funky stuff to check if a file has been edited, you would just say that Chef owns the file content for all three and if you want to update it, you do it via your cookbook (and then usually use a template or cookbook_file resource).
I am doing a demo command line project in Ruby. The structure is like this:
/ROOT_DIR
init.rb
/SCRIPT_DIR
(other scripts and files)
I want users to only go into the application using init.rb, but as it stands, anyone can go into the sub-folder and call other ruby scripts directly.
Questions:
What ways can above scenario be prevented?
If I was to use directory permissions, would it get reset when running the code from a Windows machine to on Linux machine?
Is there anything that can be included in Ruby files itself to prevent it from being directly called from OS command line?
You can't do this with file permissions, since the user needs to read the files; removing the read permission means you can't include it either. Removing the execute permission is useful to signal that these file aren't intended to be executed, but won't prevent people from typing ruby incl.rb.
The easiest way is probably to set a global variable in the init.rb script:
#!/usr/bin/env ruby
FROM_INIT = true
require './incl.rb'
puts 'This is init!'
And then check if this variable is defined in the included incl.rb file:
unless defined? FROM_INIT
puts 'Must be called from init.rb'
exit 0
end
puts 'This is incl!'
A second method might be checking the value of $PROGRAM_NAME in incl.rb; this stores the current program name (like argv[0] in many other languages):
unless $PROGRAM_NAME.end_with? 'init.rb'
puts 'Must be called from init.rb'
exit 0
end
I don't recommend this though, as it's not very future-proof; what if you want to rename init.rb or make a second script?
I'm working with ruby 2.0 on windows 7 (unfortunately I have to) and have issue with this code:
FileUtils.touch(file)
This code is needed to update file.ctime (which probably will have problems too)
So, when files is processed I 'touch' them and not processing them in next iteration.
How can I deal with it error?
ruby_path/fileutils.rb:1137:in 'utime': Permission denied 'path_to_file' Errno::EACCES
'block in touch'
'each'
'touch'
example:
file = File.new('file_path')
FileUtils.mkdir_p(path)
FileUtils.cp(file.path, path)
FileUtils.touch(file)
I tested with ruby 1.9 and 2.0. FileUtils.touch works without problems.
Can you provide a MWE. Did you check the permissions on the file you want to check.
Especially: Are you sure, you don't touch a directory?
If you don't want to check for directories, you may extend FileUtils by FileUtils.save_touch:
require 'fileutils'
module FileUtils
def self.save_touch(fpath)
FileUtils.touch(fpath) unless File.directory?(fpath)
end
end
FileUtils.save_touch(Dir.pwd)
After update of question:
FileUtils.touch has one parameter: a file name or path to a file.
You have to adapt your example:
file = File.new('file_path')
FileUtils.mkdir_p(path)
FileUtils.cp(file.path, path)
FileUtils.touch(file.path)
I'm trying to write a Sinatra app that reads in a list from a file, and then spits back a random item from that list.
I'm having trouble figuring out the path to the file to read it, though. Sinatra says 'no such file or directory' when I try to load an item in my browser:
Errno::ENOENT at /wod
No such file or directory - http://localhost:4567/listing.txt
Here is the code:
require 'sinatra'
#list
get /item
puts read_list[rand(#list.size)]
end
def read_list
File.open('listing.txt', 'r').readlines
end
I have the file in /public, which the Sinatra README says is the default location for hosting static files. Furthermore, if I put it in /public I can navigate to localhost:4567/listing.txt and read the file in the browser.
A couple things I noticed:
get /item
isn't correct, it should be:
get '/item' do
If you start your code inside the same directory the Ruby code is in, the current working-directory will be ".", which is where Ruby will look when trying to:
File.open('listing.txt', 'r').readlines
Ruby will actually use './listing.txt' as the path. That's OK if you manually launch the code from the root directory of the application, but that doesn't work well if you try to launch it from anywhere else.
It's better to be explicit about the location of the file when you're actually trying to load something for use with a web server. Instead of relying on chance, there are a couple things you can do to help make it more bullet-proof. Consider this:
def read_list
running_dir = File.dirname(__FILE__)
running_dir = Dir.pwd if (running_dir == '.')
File.open(running_dir + '/public/listing.txt', 'r').readlines
end
File.dirname gets the path information from __FILE__, which is the absolute path and name of the current file running. If the application was started from the same directory as the file, that will be ., which isn't what we want. In that case, we want the absolute path of the current working-directory, which Dir.pwd returns. Then we can append that to the path of the file you want, from the root of the application.
You'll need to do File.read('public/listing.txt', 'r') to get what you want here.
File.open isn't part of Sinatra and doesn't know to look in a specific place for static files, so it just looks in the current working directory.