Running and killing servers and watchers from a bash script - bash

For a webapp I am developing, I have a bash script to watch for changes in the source and update the running environment.
function app-serve {
python runserver.py
}
function compile-coffee {
inotifywait -e modity scripts | while read change; do
coffee -o js scripts
done
}
Now, I need these two functions run simultaneously,
app-serve &
compile-coffee &
And wait, too
wait
The problem is, when I want to stop these processes, a simple Ctrl-C isn't doing it. When I do a Ctrl-C, I get the command prompt back, but the processes run in the functions are still alive.
Is there a way to tell bash to just wait until I hit Ctrl-C, and then kill all the subprocesses?
Edit: One clarification, I see the python process I start in app-serve function is killed. Only the inotifywait and a couple of bash processes are dangling.

You can catch the ctrl-c signal in your bash script and have it execute a function that finds the processes and kills them.
See http://hacktux.com/bash/control/c
Probably something like killall app-server and killall compile-coffee.
Don't forget to exit the bash script with a call to exit.

Related

Execute bash script that will continue though Apache restarts

I need to have a bash script triggered and run, but part of the script requires Apache to restart. This obviously kills the script from continuing. I can't move the restarts in the script to the end
I have tried to run the bash scrip though a php script using shell_exec() in a GNU screen session to keep it going but that doesn't work. as soon as Apache goes down the script stops.
There has to be a way to do this but I'm not seeing it.
How I can accomplish this?
Does nohup do the job?
nohup is a POSIX command which means "no hang up". Its purpose is to execute a command such that it ignores the HUP (hangup) signal and therefore does not stop when the user logs out.
Output that would normally go to the terminal goes to a file called nohup.out, if it has not already been redirected.
https://en.wikipedia.org/wiki/Nohup

Trying to close all child processes when I interrupt my bash script

I have written a bash script to carry out some tests on my system. The tests run in the background and in parallel. The tests can take a long time and sometimes I may wish to abort the tests part way through.
If I Control+C then it aborts the parent script, but leaves the various children running. I wish to make it so that I can hit Control+C or otherwise to quit and then kill all child processes running in the background. I have a bit of code that does the job if I'm running running the background jobs directly from the terminal, but it doesn't work in my script.
I have a minimal working example.
I have tried using trap in combination with pgrep -P $$.
#!/bin/bash
trap 'kill -n 2 $(pgrep -P $$)' 2
sleep 10 &
wait
I was hoping that on hitting control+c (SIGINT) would kill everything that the script started but it actually says:
./breakTest.sh: line 1: kill: (3220) - No such process
This number changes, but doesn't seem to apply to any running processes, so I don't know where it is coming from.
I guess if the contents of the trap command get evaluated where the trap command occurs then it might explain the outcome. The 3220 pid might be for pgrep itself.
I'd appreciate some insight here
Thanks
I have found a solution using pkill. This example also deals with many child processes.
#!/bin/bash
trap 'pkill -P $$' SIGINT SIGTERM
for i in {1..10}; do
sleep 10 &
done
wait
This appears to kill all the child processes elegantly. Though I don't properly understand what the issue was with my original code, apart from sending the correct signal.
in bash whenever you you use & after a command it places that command as a background job ( this background jobs are called job_spec ) which is incremented by one until you exit that terminal session. You can use the jobs command to get the list of the background jobs running. To work with this jobs you have to use the % with the job id. The jobs command also accept other options such as jobs -p to see the proces sids of all jobs , jobs -p %JOB_SPEC to see the process of id of that particular job.
#!/usr/bin/env bash
trap 'kill -9 %1' 2
sleep 10 &
wait
or
#!/usr/bin/env bash
trap 'kill -9 $(jobs -p %1)' 2
sleep 10 &
wait
I implemented something like this few years back, you can take a look at it async bash
You can try something like the following:
pkill -TERM -P <your_parent_id_here>

How to make a shell script wait for another with out using sleep

I want to know how to make a shell script wait till other script finishes its execution with out the help of sleep command.
suppose i have scripts run.sh and kill.sh, where run.sh will make all the processes up(means to start running the image on the box) whereas kill.sh contains just the kill commands to kill all the running processes.
Whenever i have run the run.sh, it will make all the processes up and it will end. Then what happens here is all the running processes becoming orphan(handled by init). Whenever we run kill.sh, some of the processes are becoming zombies.
Means, Orphan processes becoming zombies.
To avoid this, i want to make the run.sh wait till the end of kill.sh script.
So, How to make a shell script wait for another script ? Please provide the comments.
Thanks in Advance
You can use wait to let the first script finish without giving an explicit sleep.
#!/bin/bash
./first_script.sh
wait
./second_script.sh

Multiple process from one bash script [duplicate]

I'm trying to use a shell script to start a command. I don't care if/when/how/why it finishes. I want the process to start and run, but I want to be able to get back to my shell immediately...
You can just run the script in the background:
$ myscript &
Note that this is different from putting the & inside your script, which probably won't do what you want.
Everyone just forgot disown. So here is a summary:
& puts the job in the background.
Makes it block on attempting to read input, and
Makes the shell not wait for its completion.
disown removes the process from the shell's job control, but it still leaves it connected to the terminal.
One of the results is that the shell won't send it a SIGHUP(If the shell receives a SIGHUP, it also sends a SIGHUP to the process, which normally causes the process to terminate).
And obviously, it can only be applied to background jobs(because you cannot enter it when a foreground job is running).
nohup disconnects the process from the terminal, redirects its output to nohup.out and shields it from SIGHUP.
The process won't receive any sent SIGHUP.
Its completely independent from job control and could in principle be used also for foreground jobs(although that's not very useful).
Usually used with &(as a background job).
nohup cmd
doesn't hangup when you close the terminal. output by default goes to nohup.out
You can combine this with backgrounding,
nohup cmd &
and get rid of the output,
nohup cmd > /dev/null 2>&1 &
you can also disown a command. type cmd, Ctrl-Z, bg, disown
Alternatively, after you got the program running, you can hit Ctrl-Z which stops your program and then type
bg
which puts your last stopped program in the background. (Useful if your started something without '&' and still want it in the backgroung without restarting it)
screen -m -d $command$ starts the command in a detached session. You can use screen -r to attach to the started session. It is a wonderful tool, extremely useful also for remote sessions. Read more at man screen.

bash restart sub-process using trap SIGCHLD?

I've seen monitoring programs either in scripts that check process status using 'ps' or 'service status(on Linux)' periodically, or in C/C++ that forks and wait on the process...
I wonder if it is possible to use bash with trap and restart the sub-process when SIGCLD received?
I have tested a basic suite on RedHat Linux with following idea (and certainly it didn't work...)
#!/bin/bash
set -o monitor # can someone explain this? discussion on Internet say this is needed
trap startProcess SIGCHLD
startProcess() {
/path/to/another/bash/script.sh & # the one to restart
while [ 1 ]
do
sleep 60
done
}
startProcess
what the bash script being started just sleep for a few seconds and exit for now.
several issues observed:
when the shell starts in foreground, SIGCHLD will be handled only once. does trap reset signal handling like signal()?
the script and its child seem to be immune to SIGINT, which means they cannot be stopped by ^C
since cannot be closed, I closed the terminal. The script seems to be HUP and many zombie children left.
when run in background, the script caused terminal to die
... anyway, this does not work at all. I have to say I know too little about this topic.
Can someone suggest or give some working examples?
Are there scripts for such use?
how about use wait in bash, then?
Thanks
I can try to answer some of your questions but not all based on what I
know.
The line set -o monitor (or equivalently, set -m) turns on job
control, which is only on by default for interactive shells. This seems
to be required for SIGCHLD to be sent. However, job control is more of
an interactive feature and not really meant to be used in shell scripts
(see also this question).
Also keep in mind this is probably not what you intended to do
because once you enable job control, SIGCHLD will be sent for every
external command that exists (e.g. every time you run ls or grep or
anything, a SIGCHLD will fire when that command completes and your trap
will run).
I suspect the reason the SIGCHLD trap only appears to run once is
because your trap handler contains a foreground infinite loop, so your
script gets stuck in the trap handler. There doesn't seem to be a point
to that loop anyways, so you could simply remove it.
The script's "immunity" to SIGINT seems to be an effect of enabling
job control (the monitor part). My hunch is with job control turned on,
the sub-instance of bash that runs your script no longer terminates
itself in response to a SIGINT but instead passes the SIGINT through to
its foreground child process. In your script, the ^C i.e. SIGINT
simply acts like a continue statement in other programming languages
case, since SIGINT will just kill the currently running sleep 60,
whereupon the while loop will immediately run a new sleep 60.
When I tried running your script and then killing it (from another
terminal), all I ended up with were two stray sleep processes.
Backgrounding that script also kills my shell for me, although
the behavior is not terribly consistent (sometimes it happens
immediately, other times not at all). It seems typing any keys other
than enter causes an EOF to get sent somehow. Even after the terminal
exits the script continues to run in the background. I have no idea
what is going on here.
Being more specific about what you want to accomplish would help. If
you just want a command to run continuously for the lifetime of your
script, you could run an infinite loop in the background, like
while true; do
some-command
echo some-command finished
echo restarting some-command ...
done &
Note the & after the done.
For other tasks, wait is probably a better idea than using job control
in a shell script. Again, it would depend on what exactly you are trying
to do.

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