What is the meaning of predicate "simple/1" in Prolog (SWI-Prolog) - prolog

I run into problem while reading a book.
I see a program use predicate "simple" ( I guess simple/1 ). I don't know what is the meaning of this predicate, I can't find it with ?-help(simple) in the console.
But when I tried with some queries in console, it worked something like:
5 ?- simple(p(x)).
false.
6 ?- simple(mia).
true.
7 ?- simple(Mia).
true.
8 ?- simple(f(Mia)).
false.
I guess it is some sort of predicate to determine if the argument was Terms(or Variables) or Complex Terms.

The swi-prolog manual has the following definition:
simple(#Term) is semidet
Term is atomic or a variable.
the definition is in the quintus prolog compatibility library; in the quintus prolog documentation the definition is:
simple(+Term)
Term is currently instantiated to either an atom, a number, a database
or a variable.
in any case, simple/1 is true if the argument is a simple term (not sure what the quintus manuals means by database; possibly a handler for an ODBC connection i guess)

translated to ISO predicates:
simple(T) :- var(T) ; atomic(T).
var/1 it's the most basic metaprogramming device, because it's impossible to predicate (i.e. execute code, binding variables) about any clause without instancing the variables, that are many times the essential part we are interested to.

Related

Prolog singleton variables in rule head causes program to output booleans for all queries

I have this prolog program.
red(rose).
red(anthurium).
white(rose).
white(gardenia).
white(jasmine).
like(Y,X) :-
red(X),!,
fail
;
white(X).
And below is how it responds to different queries.
?- like(rose,gardenia).
true.
?- like(rose,P).
false.
?- like(Val,anthurium).
false.
?- like(rose,X).
false
The problem I now have is this:
When querying with a variable within the query (Eg: ?- like(rose,X).), Prolog usually responds by returning a value, (something like X=some_val). Why I don't get any value for those variables, but either true or false?
All helpful answers are highly appreciated. Thanks in advance.
Think about what Prolog is doing here:
like(rose,P) succeeds if red(P), so it grabs a possible substitution for P, namely rose or anthurium. Then it traverses the cut and then it fails. But "failing" means that the proof search down that path didn't bring any solution, there are no successful bindings to report (the only fail to get information out of a failing branch is to side-effect to a log file and read check it later). In fact, all bindings will be undone on backtracking. The second branch is white(X), but rose is not white, so we fail here, too.
You can also write:
like(_,X) :- \+ red(X).
like(_,X) :- white(X).
which is a bit more readable. One notices that when calling like(_,X), the goal enclosed by the negation-as-failure operator \+ is nonground. This is bad, and causes a floundering query (in other words, don't do that). I have written this little page on "floundering".

current_predicate in SICStus Prolog

SICStus Prolog offers both current_predicate/1 and current_predicate/2.
The manual page states:
current_predicate(?PredSpec)
Unifies PredSpec with a predicate specifications of the form Name/Arity.
current_predicate(?Name, ?Term)
Unifies Name with the name of a user-defined predicate, and Term with the most general term corresponding to that predicate.
They appear to have the same features:
both predicates work for enumerating predicates, both work with modules.
The manual page comments:
current_predicate/1 is part of the ISO Prolog standard; current_predicate/2 is not.
Should I ever use current_predicate/2 in new (= non-legacy) code?
Short answer, no. Don't use it in new code.
The benefit of current_predicate/2 was to allow querying, using a predicate call template, if the predicate is defined, unlike current_predicate/1. E.g.
...,
( current_predicate(_, foo(_, _)) ->
foo(A, B)
; ...
),
...
But you can often use instead the standard predicate_property/2 predicate, which takes a template as first argument.
P.S. The Logtalk linter will scream at you (and suggest a more standard alternative) if it finds you calling current_predicate/2 :-)

My Prolog version doesn't seem to know member

I'm trying out next example in Amzi! Prolog:
member(apple, [apple, broccoli, crackers]).
And the answer is no.
?- member(apple, [apple, broccoli, crackers]).
no
Is there a problem with my version? If I try the same in swipl, then it does work...
?- member(apple, [apple, broccoli, crackers]).
true .
Does Amzi! Prolog use an own implementation of Prolog?
The predicate member/2 is not specified in the official ISO standard, although is often provided by Prolog implementations. But the implementation differs from system to system. Some provide it as a built-in predicate. Others as a library predicate. In the specific case of SWI-Prolog, and assuming the default configuration, the member/2 predicate is defined in the module library(lists), which is auto-loaded when one of its exported predicates is called. Auto-loading is, by default, silent, which often leads users to think that they are calling a built-in predicate. In the case of Amzi! Prolog, it seems that the member/2 predicate is not built-in but you can easily define it yourself. In order to check if a given predicate is a built-in predicate, you can usually use the standard predicate_property/2 predicate. For example, using SWI-Prolog, you get for member/2:
?- predicate_property(member(_,_), Property).
Property = interpreted ;
Property = visible ;
Property = imported_from(lists) ;
Property = file('/Users/pmoura/lib/swipl-6.5.2/library/lists.pl') ;
Property = line_count(106) ;
Property = nodebug ;
Property = number_of_clauses(1) ;
Property = number_of_rules(1) ;
false.
But sadly not all systems provide the standard predicate_property/2 predicate. Prolog standardization is not, unfortunately, one of its shiny points.
Every version of Prolog I ever used was slightly different from the others... Nice to see there's now another one to consider, ISO Prolog :-)
I think this link has good information: http://osprey.unisa.ac.za/phorum/read.php?674,173265,173265

Different predicate in Prolog, don't work (always false)

I am learning Prolog for an university exam using SWI Prolog and I have some question about this simple program that implement the different predicate that say TRUE if two element are different (if they do not match) and say FALSE if they match.
This is the code:
different(X,X) :- !,
fail.
diferent(_,_).
The problem is that if I try to execute the following query in the Prolog shell I always obtain FALSE:
[debug] 10 ?- different(a,b).
false.
[debug] 11 ?- different(a,a).
false.
As you can see the first query have to say TRUE because a don't match with b
Why?
change diferent(_,_) to different(_,_). Ie it is a spelling error.
Your second predicate is not being examined as it does not match your query.
The program should be
different(X,X) :- !,fail.
different(_,_).
This "exercise" is pointless. Use prolog-dif!
IMO the only reasonable definition of different/2 is:
different(A,B) :- dif(A,B).
If you are using emacs for editing your prolog files (If not I strongly recommend you switching to it) I suggest you using hi-lock-mode. I will highlight in a pattern-like fashion all matches in the file whenever the cursor is over a word. It can save you hours of pain when you develop bigger projects.

Defining a rule that the user cannot query

How do I define a rule that the user cannot query?
I only want the program itself to call this rule through another rule.
Ex:
rule1():- rule2().
rule2():- 1<5.
?-rule1().
true
?-rule2().
(I don't know what the answer will be, I just want this query to fail!)
Use a Logtalk object to encapsulate your predicates. Only the predicates that you declare public can be called (from outside the object). Prolog modules don't prevent calling any predicate as using explcit qualification bypasses the list of explicitly exported predicates.
A simple example:
:- object(rules).
:- public(rule1/1).
rule1(X) :-
rule2(X).
rule2(X) :-
X < 5.
:- end_object.
After compiling and loading the object above:
?- rules::rule1(3).
true.
?- rules::rule2(3).
error(existence_error(predicate_declaration,rule2(3)),rules::rule2(3),user)
If you edit the object code and explicitly declare rule2/1 as private you would get instead the error:
?- rules::rule2(3).
error(permission_error(access,private_predicate,rule2(3)),rules::rule2(3),user)
More information and plenty of examples at http://logtalk.org/
First, some notes:
I think you mean "predicate" instead of "rule". A predicate is a name/k thing such as help/0 (and help/1 is another) and can have multiple clauses, among them facts and rules, e.g. length([], 0). (a fact) and length([H|T], L) :- ... . (a rule) are two clauses of one predicate length/2.
Do not use empty parenthesis for predicates with no arguments – in SWI-Prolog at least, this will not work at all. Just use predicate2 instead of predicate2() in all places.
If you try to call an undefined predicate, SWI-Prolog will say ERROR: toplevel: Undefined procedure: predicate2/0 (DWIM could not correct goal) and Sicstus-Prolog will say {EXISTENCE ERROR: predicate2: procedure user:predicate2/0 does not exist}
Now, to the answer. Two ideas come to my mind.
(1) This is a hack, but you could assert the predicate(s) every time you need them and retract them immediately afterwards:
predicate1 :-
assert(predicate2), predicate2, retractall(predicate2).
If you want a body and arguments for predicate2, do assert(predicate2(argument1, argument2) :- (clause1, clause2, clause3)).
(2) Another way to achieve this would be to introduce an extra argument for the predicate which you do not want to be called by the user and use it for an identification that the user cannot possibly provide, but which you can provide from your calling predicate. This might be a large constant number which looks random, or even a sentence. This even enables you to output a custom error message in case the wrong identification was provided.
Example:
predicate1 :-
predicate2("Identification: 2349860293587").
predicate2(Identification) :-
Identification = "Identification: 2349860293587",
1 < 5.
predicate2(Identification) :- Identification \= "Identification: 2349860293587",
write("Error: this procedure cannot be called by the user. Use predicate1/0 instead."),
fail.
I don't use the equivalent predicate2("Identification: 2349860293587") for the first clause of predicate2/0, because I'm not sure where the head of the clause might appear in Prolog messages and you don't want that. I use a fail in the end of the second clause just so that Prolog prints false instead of true after the error message. And finally, I have no idea how to prevent the user from looking up the source code with listing(predicate2) so that will still make it possible to simply look up the correct identification code if s/he really wants to. If it's just to keep the user from doing accidental harm, it should however suffice as a protection.
This reminds me to facility found in Java. There one can query the
curent call stack, and use this to regulate permissions of calling
a method. Translated to Prolog we find in the old DEC-10 Prolog the
following predicate:
ancestors(L)
Unifies L with a list of ancestor goals for the current clause.
The list starts with the parent goal and ends with the most recent
ancestor coming from a call in a compiled clause. The list is printed
using print and each entry is preceded by the invocation number in
parentheses followed by the depth number (as would be given in a
trace message). If the invocation does not have a number (this will
occur if Debug Mode was not switched on until further into the execution)
then this is marked by "-". Not available for compiled code.
Since the top level is usually a compiled predicate prolog/0, this could be
used to write a predicate that inspects its own call stack, and then decides
whether it wants to go into service or not.
rule2 :- ancestors(L), length(L,N), N<2, !, write('Don't call me'), fail.
rule2 :- 1<5.
In modern Prologs we don't find so often the ancestors/1 predicate anymore.
But it can be simulated along the following lines. Just throw an error, and
in case that the error is adorned with a stack trace, you get all you need:
ancestors(L) :- catch(sys_throw_error(ignore),error(ignore,L),true).
But beware stack eliminiation optimization might reduce the stack and thus
the list returned by ancestors/1.
Best Regards
P.S.: Stack elimination optimization is already explained here:
[4] Warren, D.H.D. (1983): An Abstract Prolog Instruction Set, Technical Note 309, SRI International, October, 1983
A discussion for Jekejeke Prolog is found here:
http://www.jekejeke.ch/idatab/doclet/prod/en/docs/10_pro08/13_press/03_bench/05_optimizations/03_stack.html

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