In my form I have following designing
Template dropdown list
name Textbox
from Textbox
subject textbox
content textbox
If i m selecting any template from template then remaining fields like name,from,subject,etc can be changed a per selection of template...
please give the solution for this
<div class="row">
<?php echo $form->labelEx($model,'profile_id'); ?>
<?php echo $form->dropDownList($model,'profile_id', CHtml::listData(Email::model()->findAll(), 'email_id', 'name'), array('empty'=>'---Select Template---')); ?>
<?php echo $form->error($model,'profile_id'); ?>
</div>
Thanks in advance!!!!!
$("#dropdownlist").change(function(
var value = this.val();
switch (value) {
case 'template1':
// change fields
break;
case 'template2':
// change fields
break;
default:
alert("ERROR: this template not exist.");
}
));
Related
I would like a help to solve this problem. I'm using Yii 1.1 and trying to create a dynamic CheckBox list in which its elements change depending on the value selected in a DropDown element.
I created this DropDown element with the arguments in Ajax to perform the function update in the Controller. The function in the Controller is doing the lookup in the table according to the value passed.
Up to this point, the code is working fine, generating an array with the values that should be displayed. The problem is that I'm not able to configure the return of these data and I can't even display them in the View.
Below is the code data:
View - DropDown element:
echo CHtml::activeDropDownList($model, 'standard',
array(CHtml::listData(standard::model()->findAll(), 'name','name')),
array('empty'=>'',
'ajax'=>array(
'type'=>'POST',
'url'=>CController::createUrl('/getTeam',array('form'=>'Team','field'=>'standard')),
'update'=>'#Audit_team'),
)
);?>
Controller:
public function actionGetTeam($form,$field) {
$post = $_POST;
$standard = $post[$form][$field];
$Lists = TblAuditStandard::model()->findAll("standard = $standard");
foreach ($Lists as $List){
$AuditTeam[] = $List->name." - ".$List->login;
asort($AuditTeam);
foreach ($AuditTeam as $id=>$value )
echo CHtml::tag('option',array('value'=>$id),$value,true);
}
}
View - Checkbox element:
<div class="row">
<?php echo $form->labelEx($model,'team'); ?>
<?php echo CHtml::activeCheckBoxList($model,'team',array()); ?>
<?php echo $form->error($model,'team'); ?>
</div>
I hope someone can help me solve this problem. Thanks.
Refer to my code below, when user click on en button, the content will be changed to English, while clicking tw button, the content will be changed to Chinese.
However, the page will be refreshed each time when user click either en or tw button. I want to ask how can I implement AJAX content update in this case?
The result is when user click either en or tw button, the page won't be refreshed to change the content language.
Thanks
I have refer to Yii docs here, but seem that it is not appropriate for my case
C:\wamp\www\website\protected\views\site\index.php
<?php
$lang = isset($_GET["lang"]) ? $_GET["lang"] : "en_uk";
$lang = $lang == "en" ? "en_uk" : "zh_tw";
Yii::app()->setLanguage($lang);
?>
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="get">
<input type="submit" value="en" name="lang" />
<input type="submit" value="tw" name="lang" />
</form>
<div class="main">
<?php echo Yii::t(Yii::app()->controller->id, "Causeway Bay"); ?>
</div>
Best practice is to reload the page in these cases, because usually you have to update so much, that it is just not worth it.
That said, CHtml's ajaxSubmitButton is the cleanest way to implement this, because you can map every event of your call very easily. It looks something like this:
<?php
echo CHtml::ajaxSubmitButton('en', CHtml::normalizeUrl(array('site/changeLanguage')),
array(
'error'=>'js:function(){
alert("error");
}',
//if you add a return false in this, it will not submit.
'beforeSend'=>'js:function(){
alert("beforeSend");
}',
'success'=>'js:function(data){
alert("success, data from server: "+data);
}',
'complete'=>'js:function(){
alert("complete");
}',
//'update'=>'#where_to_put_the_response',
)
);
?>
You don't have to use every parameter of course. The update parameter can update a HTML tag instantly.
EDIT:
This can be done easily if you use the controller's renderPartial method, for instance in your site controller if you have the action responsible for the index.
public function actionIndex(){
//get variables, etc
if(Yii::app()->request->isAjaxRequest) {
$lang = $_POST['nameOfSubmit'];
}else {
//...
}
//if the 3rd parameter is true, the method returns the generated HTML to a variable
$page = $this->renderPartial('_page', array(/*parameters*/ ), true);
echo $page;
}
And then, in your view file you can simply have
<?php echo CHtml::ajaxSubmitButton('en', CHtml::normalizeUrl(array('site/index')),
array('update'=>'#content_div',));?>
and
<?php echo CHtml::ajaxSubmitButton('tw', CHtml::normalizeUrl(array('site/index')),
array('update'=>'#content_div',));?>
I need to theme views in Drupal 7. There is a content type 'Book' and I need to list 5 books and theme them in special manner(preview image, title and author).
When I override views-view-field.tpl.php and print raw SQL result, I see that all fields are displayed. This code
echo "<pre>";
print_r($row);
echo "</pre>";
gives
[entity] => stdClass Object
(
[title] => ...
....
[nid] => 34
...
[body] => Array
...
But I don't want pass [body] from database to php side, because it can be huge and cause a performance issue. I haven't selected [body] in view settings.
Is there a way to pass only certain fields to views-view-field.tpl.php?
Thanks in advance.
The variables available are written in the documentation inside the sites/all/modules/views/theme folder's files.
Usually, the variable you need to look at and modify on a views-view-fields.tpl.php template is $fields
I use the devel module (http://drupal.org/project/devel) to view the variables available:
<?php
//after enabling the devel module...
dpm($fields);
// This will print a Kuomo display on the page with the array's vars
?>
Generally, on a view of nodes,
<?php print $fields['title']->content; ?>
will print the node title. For fields, try
<?php print $fields['field_FIELDNAME']->content; ?>
If you have the memory, you can capture ALL vars available on the template in the Kuomo with
<?php dpm(get_defined_vars()); ?>
Make sure you clear your cache before you try to view the vars.
If what you want to do is theme a certain field you can create a template for that specific field like this one: views-view-field--field-nameofmyfield.tpl.php place it in your theme folder and rescan the templates in the Theme:information part of the View configuration.
For that to work you have to have the field added to Fields in the View.
To sort through your information in a theme use this:
<?php dpm ($rows); ?> // View all the information in the view
<?php foreach ($rows as $row_count => $row): ?>
<?php print $row['title'];
<?php print $row['nid'];
<?php endforeach; ?>
If you want to change of theme of view then Change views-view-fields.tpl.php like this:
<div class="pagecontent">
<div class="colleft">
<?php if($fields['field_file']->content){ ?><div class="views-field-file"><?php print $fields['field_file']->content; ?></div><?php } ?>
</div>
<div class="colright">
<div class="views-field-title"><?php print $fields['title']->content; ?></div>
<div class="views-field-body"><?php print $fields['body']->content; ?></div>
<div class="views-field-view-node"><?php print $fields['view_node']->content; ?></div>
</div>
</div>
Hi everybody: i had define a new content type that have:
a title, a link field, and a image field.
So, i want to make that image comes to be the background of the content type when i show it. How can i do that?
Thanks in advance
A very quick way to do this would be to add a custom node.tpl.php to your theme and do this:
<?php
$url = file_create_url($node->field_image[$node->language][0]['uri']);
?>
<div style="background:url(<?php echo $url; ?>) left top no-repeat;" id="node-<?php print $node->nid; ?>" class="<?php print $classes; ?> clearfix"<?php print $attributes; ?>>
// Rest of node.tpl.php here
I wanted to comment on Clive's answer, but do not have the "rep" :(. Wouldn't it be best with a check for node-type?
<?php
if ($type == 'MACHINE_NAME_FOR_YOUR_TYPE') {
$url = file_create_url($node->field_image[$node->language][0]['uri']);
?>
<div style="background:url(<?php echo $url; ?>) left top no-repeat;" id="node-<?php print $node->nid; ?>" class="<?php print $classes; ?> clearfix"<?php print $attributes; ?>>
<?php } ?>
// Rest of node.tpl.php here
If you use Field Group module, check Field Group Background Image.
Steps:
Go to the Manage Display page of your content type
Create a div (background image) field group as a wrapper of the node
Select the image field you want to use. Optionally, you can specify an image style
Do not output your image field
I created a confirmation page for deleting an item. This works perfectly.
Now I want to appear the confirmation page in fancybox, still passing all the variables and delete the data or close the dialog.
It's important that the process still works as it does now (delete->confirmationpage->redirect/deletion) so that users with javascript disabled can perform these actions without a problem.
Now have I been reading about zend framework,ajax, json and more, but the more I read, the less I understand.
So in a nutshell, my question:
I want to pass a variable to the fancybox and if 'yes' perform the delete action or on 'no' close the dialog. This within the zend framework and jquery.
Any advice or tips are greatly appreciated!
You need to use content switching in your ajax which will then render your action appropriately, for example:
function confirmDeleteAction() {
if($this->_request->isXmlHttpRequest()) {
//This is ajax so we want to disable the layout
$this->_helper->layout->disableLayout();
//Think about whether you want to use a different view here using: viewRenderer('yourview')
}
//The normal code can go here
}
function deleteAction() {
//You probably don't want to show anything here, just do the delete logic and redirect therefore you don't need to worry where it's coming from
}
And in your fancybox, have a view that has a form and two buttons, the form should point to your delete action with the id of whatever your deleting as a get param. Set some javascript up that says something like (and this is mootools code, but you can convert it easily):
$('confirmButton').addEvent('click', function(e) {
e.preventDefault();
this.getParent('form').submit();
}
$('cancelButton').addEvent('click', function(e) {
e.preventDefault();
$('fancyBox').destroy(); //I'm not sure it has an id of fancyBox, never used it
}
Came across the question today and figured I could give it a fresh look. For Zend Framework the solution is really simple:
This is how the action looks:
public function deleteAction()
{
$this->_helper->layout()->disableLayout();
$this->view->news = $this->newsService->GetNews($this->_getParam('id'));
if($this->getRequest()->isPost())
{
if($this->getRequest()->getPost('delete') == 'Yes')
{
$this->newsService->DeleteNews($this->_getParam('id'), $this->view->user->username, $this->view->translate('deleted: ').'<strong>'.$this->view->pages[0]['title'].'</strong>');
$this->_helper->flashMessenger(array('message' => $this->view->translate('The page is deleted'), 'status' => 'success'));
$this->_helper->redirectToIndex();
}
elseif($this->getRequest()->getPost('delete') == 'No')
{
$this->_helper->flashMessenger(array('message' => $this->view->translate('The page is <u>not</u> deleted'), 'status' => 'notice'));
$this->_helper->redirectToIndex();
}
}
}
The delete.phtml
<div>
<h2><?php echo $this->translate('Delete news'); ?></h2>
<?php
foreach($this->news as $news)
{
?>
<p>
<?php echo $this->translate('You are now deleting <strong>\'').$news['title'].$this->translate('\'</strong>. Are you sure about this?'); ?>
</p>
<p>
<?php echo $this->translate('<strong>Note! </strong>This action is inreversable, even for us!'); ?>
</p>
<form action="<?php echo $this->baseUrl(false).'/news/index/delete/'.$news['id']; ?>" method="post">
<?php
}
?>
<input class="submit deleteYes" type="submit" name="delete" value="<?php echo $this->translate('Yes'); ?>" />
<input class="submit deleteNo" type="submit" name="delete" value="<?php echo $this->translate('No'); ?>" />
</form>
And this is how the link to delete a file looks (within a foreach loop with my database results)
<a class="deleteConfirmation" href="<?php echo $this->baseUrl(false).'/news/index/delete/'.$news->id; ?>">delete</a>
This works like you would expect; when you click on delete the user goes to the delete confirmation page and redirects the user back to the index after the form is submitted. But I wanted the confirmation in a dialog (in my case I use fancybox). To achieve this, add the following jquery to your index:
$('.deleteConfirmation').fancybox({
// Normal fancybox parameters
ajax : {
type : "POST"
}
});