I am trying to use a simple form with only a text field to get some information that will be used in an action method to redirect to a different action method. Here's the context:
I have a route mapped in my global.asax.cs file which prints "moo" the given amount of times. For example, if you typed "www.cows.com/Moo8", "Moo" would be printed 8 times. The number is arbitrary and will print however many "Moo"s as the number in the URL. I also have a form on the homepage set up as follows:
#using (Html.BeginForm("Moo", "Web"))
{
<text>How many times do you want to moo?</text>
<input type="text" name="mooNumber" />
<input type="submit" value="Moo!" />
}
The number submitted in the form should be sent to the action method "Moo" in the "Web" controller (WebController.cs):
[HttpPost]
public ActionResult Moo(int mooNumber)
{
Console.WriteLine(mooNumber);
return RedirectToAction("ExtendedMoo", new { mooMultiplier = mooNumber });
}
Finally, the "Moo" action method should send me back to the original "www.cows.com/Moo8" page; as you can see above I simply used an already existing action method "ExtendedMoo":
public ViewResult ExtendedMoo(int mooMultiplier)
{
ViewBag.MooMultiplier = RouteData.Values["mooMultiplier"];
return View();
}
How can I access the value submitted in my form and use it in the last call to "ExtendedMoo"?
Refer to this post or this, you might get some idea how routing works. Something is wrong with "www.cows.com/Moo8", try to find it out. Hint "{controller}/{action}/{parameter_or_id}"
Instead of RedirectToAction, use Redirect and create the Url.
This should do the trick:
return Redirect(Url.RouteUrl(new { controller = "Web", action = "ExtendedMoo", mooMultiplier = mooNumber }));
I hope i helps.
Oh wow. Turns out that form was on my Homepage, so instead of using "Moo" as the action method, I needed to override the "Homepage" action method with a [HttpPost] annotation over THAT one. Didn't realize that forms submitted to the page they were rendered from - that was a really useful piece of information in solving this problem!
Thanks all for your attempts at helping out!
If I understood right
You can you use form Collection to get the value from textbox.
Make Sure the input tag has both id and name properties mentioned otherwise it wont be available in form collection.
[HttpPost]
public ActionResult Moo(int mooNumber, **formcollection fc**)
{
**string textBoxVal= fc.getvalue("mooNumber").AttemptedValue;**
Console.WriteLine(mooNumber);
return RedirectToAction("ExtendedMoo", new { mooMultiplier = mooNumber });
}
Related
I have a strongly typed razor view for a model in my MVC 3 project. Basically its for editing the model.
The model contains an Id field for the database key and some other string fields (Its a viewModel and all but thats not the point of the question).
In the view I just have a form and a submit button and nothing else. When the View is posted to the controller the model in the controller has all fields empty EXCEPT for the Id field which seems to have been auto-magically filled up.
How and where does the Id field gets populated in the model without there being a corresponding 'input' element for it in the view.
This is probably a dumb question but I would appreciate even just a link to what I should read up on. Thanks.
I bet it comes from the url as route parameter.
For example you have the following controller:
public class HomeController: Controller
{
public ActionResult Index(int id)
{
vqr model = GetModel(id);
return View(model);
}
[HttpPost]
public ActionResult Index(MyViewModel model)
{
// the model.Id property will be automatically populated here
// because the request was POST /home/index/123
...
}
}
and the following view:
#model MyViewModel
#using (Html.BeginForm())
{
<button type="submit">OK</button>
}
Now you navigate to GET /home/index/123 and you get the following markup:
<form action="/home/index/123" method="post">
<button type="submit">OK</button>
</form>
Notice the action attribute of the form? That's where the id comes from. Basically the Html.BeginForm() helper uses the current url when generating the action attribute, and since the current url is /home/index/123 it is what gets used.
And because if you have left the default routes in your Global.asax, the {id} route token is used at the end of the url, the default model binder successfully binds it to the Id property of your view model.
You are probably hitting a URL similar to the following: /MyObject/Edit/15
This is then returning the page that you have your blank form on.
What happens next is you have an HTML.BeginForm() which is posting BACK to /MyObject/Edit/15
Now because of the post back having the same format your routing rules are picking up the '15' and binding it back to your id.
Have you added the ID field as a hidden field?
e.g.
#Html.HiddenFor(x=> x.ID)
I wanted use MVC and renderpartial to generate a menu but but could not get it to work, and from what I read it seemed maybe RenderAction would be more suitable. Still I have not gotten it to work.
What I intended to do was create a controller that selects certain articles from a database that will act as categories (this is put into HomeController):
public ActionResult MenuController()
{
var movies = from m in db.Art
where m.ArtikelNr.StartsWith("Webcat")
select m;
return View(movies);
}
And then send that information to a view:
#model IEnumerable<xxxx.Models.Art>
#{
Layout = null;
}
<ul>
#foreach (var item in Model)
{
<li>#Html.DisplayFor(modelItem => item.Benämning_10)</li>
}
This works when I just run it as a normal controller and view, it returns a list of what I want. But if I want to call it from _layout.cshtml (because this menu should appear on every page) like this:
<div id="sidebar">#Html.RenderAction(MenuController)</div>
Then it generates the following error:
CS0103: The name 'MenuController' does not exist in the current context
What is the proper way of calling an action/view/whatever from the _layout.cshtml file?
You should call
#Html.RenderAction("_MenuController")
and be sure that you have a working rule in your Global.asax
As suggested in another answer would be better to use
return PartialView();
I also suggest you to use the ChildActionOnlyAttribute to be sure that this action will never be called as a standard action.
So something like that:
[ChildActionOnly]
public PartialViewResult _MenuController()
{
var movies = from m in db.Art
where m.ArtikelNr.StartsWith("Webcat")
select m;
return PartialView(movies);
}
#{Html.RenderAction("MenuController");}
or
#Html.Action("MenuController")
Simply
#Html.RenderAction("MenuController")
You've forgotten quotes around your string parameter
<div id="sidebar">#Html.RenderAction("_MenuController")</div>
Quotes around your action name :) It might also be good practice to return a partial view:
return PartialView(movies);
UPDATE:
My model going into the save method is PartialViewModel, which in the save method, is pushed into the index's ContactViewModel and sent back. This wasn't clear.
I am playing around with MVC3, and have a contact controller with a SaveDetails action. The index cshtml has a partial with a form whose action is pointing to this controller.
When I submit the form not having completed it fully, thereby firing the validation, the url now contains the SaveDetails action name (http://localhost:7401/Contact/SaveDetails).
The form code is:
#using (Html.BeginForm("SaveDetails", "Contact")) {
...
}
The controller action looks like this:
public ActionResult SaveDetails(Models.PartialsViewModel pvm)
{
return View("Index", new ContactViewModel{ PartialsViewModel = pvm } );
}
What am I doing wrong?
The form has the action attribute set to SaveDetails action, so after submit it redirects the browser to this action.
I don' think you are doing anything wrong but I don't think you are able to do what you are tying to achieve. A request has to go somewhere and in mvc the url is used to identify which action you want to perform. If you are not submitting a post back then the url is going to change.
One way to submit the forms to different actions would be using some ajax.
Submitting the form is a POST. You can use an attribute to identify what request method an action should respond to. This means that you can create another action also called Index but give it the [HttpPost] attribute.
[HttpPost]
public ActionResult Index(Models.ContactViewModel cvm)
{
return View();
}
This way it won't display the action in the url.
I want to pass two values from view to controller . i.e., #Model.idText and value from textbox. here is my code:
#using HTML.BeginForm("SaveData","Profile",FormMethod.Post)
{
#Model.idText
<input type="text" name="textValue"/>
<input type="submit" name="btnSubmit"/>
}
But problem is if i use "Url.ActionLink() i can get #Model.idText . By post action i can get textbox value using FormCollection . But i need to get both of this value either post or ActionLink
using ajax you can achieve this :
don't use form & declare your attributes like this in tags:
#Model.idText
<input type="text" id="textValue"/>
<input type="submit" id="btnSubmit"/>
jquery:
$(function (e) {
// Insert
$("#btnSubmit").click(function () {
$.ajax({
url: "some url path",
type: 'POST',
data: { textField: $('#textValue').val(), idField: '#Model.idText' },
success: function (result) {
//some code if success
},
error: function () {
//some code if failed
}
});
return false;
});
});
Hope this will be helpful.
#using HTML.BeginForm("SaveData","Profile",FormMethod.Post)
{
#Html.Hidden("idText", Model.idText)
#Html.TextBox("textValue")
<input type="submit" value="Submit"/>
}
In your controller
public ActionResult SaveData(String idText, String textValue)
{
return null;
}
I'm not sure which part you are struggling with - submitting multiple values to your controller, or getting model binding to work so that values that you have submitted appear as parameters to your action. If you give more details on what you want to achieve I'll amend my answer accordingly.
You could use a hidden field in your form - e.g.
#Html.Hidden("idText", Model.idText)
Create a rule in global.asax and than compile your your with params using
#Html.ActionLink("My text", Action, Controller, new { id = Model.IdText, text =Model.TextValue})
Be sure to encode the textvalue, because it may contains invalid chars
Essentially, you want to engage the ModelBinder to do this for you. To do that, you need to write your action in your controller with parameters that match the data you want to pass to it. So, to start with, Iridio's suggestion is correct, although not the full story. Your view should look like:
#using HTML.BeginForm("SaveData","Profile",FormMethod.Post)
{
#Html.ActionLink("My text", MyOtherAction, MaybeMyOtherController, new { id = Model.IdText}) // along the lines of dommer's suggestion...
<input type="text" name="textValue"/>
<input type="submit" name="btnSubmit"/>
#Html.Hidden("idText", Model.idText)
}
Note that I have added the #Html.Hidden helper to add a hidden input field for that value into your field. That way, the model binder will be able to find this datum. Note that the Html.Hidden helper is placed WITHIN your form, so that this data will posted to the server when the submit button is clicked.
Also note that I have added dommer's suggestion for the action link and replaced your code. From your question it is hard to see if this is how you are thinking of passing the data to the controller, or if this is simply another bit of functionality in your code. You could do this either way: have a form, or just have the actionlink. What doesn't make sense is to do it both ways, unless the action link is intended to go somewhere else...??! Always good to help us help you by being explicit in your question and samples. Where I think dommer's answer is wrong is that you haven't stated that TextValue is passed to the view as part of the Model. It would seem that what you want is that TextValue is entered by the user into the view, as opposed to being passed in with the model. Unlike idText that IS passed in with the Model.
Anyway, now, you need to set up the other end, ie, give your action the necessary
[HttpPost]
public ActionResult SaveData(int idText, string textValue) // assuming idText is an int
{
// whatever you have to do, whatever you have to return...
}
#dommer doesn't seem to have read your code. However, his suggestion for using the Html.ActionLink helper to create the link in your code is a good one. You should use that, not the code you have.
Recapping:
As you are using a form, you are going to use that form to POST the user's input to the server. To get the idText value that is passed into the View with the Model, you need to use the Html.Hidden htmlhelper. This must go within the form, so that it is also POSTed to the server.
To wire the form post to your action method, you need to give your action parameters that the ModelBinder can match to the values POSTed by the form. You do this by using the datatype of each parameter and a matching name.
You could also have a complex type, eg, public class MyTextClass, that has two public properties:
public class MyTextClass
{
public int idText{get;set}
public string TextValue{get;set;}
}
And then in your controller action you could have:
public ActionResult SaveData(MyTextClass myText)
{
// do whatever
}
The model binder will now be able to match up the posted values to the public properties of myText and all will be well in Denmark.
HTH.
PS: You also need to read a decent book on MVC. It seems you are flying a bit blind.
Another nit pick would be to question the name of your action, SaveData. That sounds more like a repository method. When naming your actions, think like a user: she has simply filled in a form, she has no concept of saving data. So the action should be Create, or Edit, or InformationRequest, or something more illustrative. Save Data says NOTHING about what data is being saved. it could be credit card details, or the users name and telephone...
I am still new to MVC, so sorry if this is an obvious question:
I have a page where the user can choose one of several items. When they select one, they are taken to another form to fill in their details.
What is the best way to transfer that value to the form page?
I don't want the ID of the item in the second (form) pages URL.
so it's /choose-your-item/ to /redemption/ where the user sees what was selected, and fills the form in. The item selected is displayed, and shown in a hidden form.
I guess one option is to store in a session before the redirect, but was wondering if there was another option.
I am using MVC3
Darin Dimitrov's answer would be best if you don't need to do any additional processing before displaying the /redemption/ page. If you do need to some additional processing, you're going to have to use the TempDataDictionary to pass data between actions. Values stored in the TempDataDictionary lasts for one request which allows for data to be passed between actions, as opposed to the values stored in the ViewDataDictionary which only can be passed from an action to a view. Here's an example below:
public ActionResult ChooseYourItem()
{
return View();
}
[HttpPost]
public ActionResult ChooseYourItem(string chosenItem)
{
TempData["ChosenItem"] = chosenItem;
// Do some other stuff if you need to
return RedirectToAction("Redemption");
}
public ActionResult Redemption()
{
var chosenItem = TempData["ChosenItem"];
return View(chosenItem);
}
If you don't want the selected value in the url you could use form POST. So instead of redirecting to the new page, you could POST to it:
#using (Html.BeginForm("SomeAction", "SomeController"))
{
#Html.DropDownListFor(...)
<input type="submit" value="Go to details form" />
}
To help others, this is how I resolved my issue of needing multiple buttons posting back, and wanting to pass a different Id each time.
I have a single form on the page, that posts back to my controller:
The Form:
#using (Html.BeginForm("ChooseYourItem", "Item", FormMethod.Post))
{
And the code
[AcceptVerbs(HttpVerbs.Post)]
public ActionResult ChooseYourItem(string itemId)
{
TempData["ITEMID"] = itemId
return RedirectToAction("Create", "Redemption");
}
Then, inside the form, I create buttons whose name == "itemId", but has a different value each time.
For example
<strong>Item 1</strong>
<button value="123" name="itemid" id="btn1">Select</button>
<strong>Item 2</strong>
<button value="456" name="itemid" id="btn2">Select</button>