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I have this:
array = ["a","b","c"]
How do I get this:
"a","b","c"
I need to get the items out of the array, each double-quoted, separated by a comma.
array.collect { |a| "\"#{a}\"" }.join(",")
I'm just started to learn ruby, I guess:
return ["a","b","c"].map{|i| '"' + i + '"'}.join(",")
Might you want to get this:
irb(main):009:0> [1, 2, 3].map(&:to_s).join('","')
=> "1\",\"2\",\"3"
"a","b","c" this is not abject (these are 3 objects). But in ruby any code returns object value. So you should know what you want to get: 1 object (I returning string in this example) or various. If you want to get 3 objects you should extract array like this:
a, b, c = [1,2,3].map(&:to_s)
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Im aiming for a regex formula to return chunks of a string based on a character, if this string contains L1 then its going to be only one chunk, if L2 is found it would return 2 chunks, L3 = 3 chunks.
Example
Lets assume we have this string
"L2N1N1"
and we would like to get 2 string
"L2N1" and "L2N1N1"
Another example
"L3N1N1N2"
to return 3 strings
"L3N1" "L3N1N1" "L3N1N1N2"
Im using Ruby
"L3N1N1N2".sub(/L(\d)(?:N\d)+/) do |m|
$1.to_i.times.map { |i| m[0..3+2*i] }.join(' ')
end
#⇒ "L3N1 L3N1N1 L3N1N1N2"
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I need a regular expression that only matches three digit numbers in the following array. I need the result to be a new array.
Input:
my_array = [111,45456,456,74897,787,45466,789,6587,784,234,456,4658,4587,235,456]
Desired output:
new_array = [111,456,787,789,784,234,456,235,456]
Why regular expression on numbers? You can select all numbers less than 1000 and greater than 99.
my_array.select { |n| n<1000 && n>99 }
Just the regexp would look like this: /^\d{3}$/. But if you'd like an expression that would return an array of values that match that expression this would do it: my_array.select{ |num| num.to_s.match(/^\d{3}$/) }.
Take a look at RegExr to learn more about Regular Expressions.
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I am trying to count the arrays themselves not the elements. so say i had the following
arrays = [["1 2"],["3 4"],["5 6"],["6 7"]]
i am then trying to find a way to return only one of these arrays as a set of instructions if asked for?
Your example showed a multi-dimensional array, which is an array of arrays.
To count the number of arrays in this 2 dimensional array, in other words the number of elements, you could use the following methods.
arrays = [["1 2"],["3 4"],["5 6"],["6 7"]]
arrays.length
arrays.size
arrays.count
If you would like to return one of them you simply reference the element
arrays[0]
=> Returns ["1 2"]
If you want to return a random element,
arrays.sample
=> Returns a random array
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I use the excellent faker gem to generate random words for my models. Eg. product.name = Faker::Lorem.word
Sometimes I need to generate a sentence, and I want the length of the sentence to
vary each time.
How to achieve this with ruby?
How about:
result = rand(max_size).times.map { produce_word }
Since you have not provided enough information, this is my approach, [*1..100].sample will return a random number between 1 and 100, so looping that times the string which is returned bya method named get_word will get stored in the array word_array
word_array = []
[*1..100].sample.times do
word_array << get_word
end
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Need to add two arrays before that need to add some value at starting of the first array. Look at the following:
#conunty_format = [ "country", "imps", "revenue","network_revenue"]
final_ca = [2000,55.62,88.69]
I need to add "Canada" to final_ca and generate hash with corresponding county_format.
Hash[#conunty_format.zip(final_ca.unshift('canada'))]
=> {"country"=>"canada", "imps"=>2000, "revenue"=>55.62, "network_revenue"=>88.69}
You can use Array Zip and some properties of Array to achieve it in a single line. see the below code.
resulted_hash = #country_format.zip(final_ca.unshift("Canada")).inject({}) do |r, s| r.merge!({s[0] => s[1]}) end