select count distinct using pig latin - hadoop

Question

I need help with this pig script. I am just getting a single record. I am selecting 2 columns and doing a count(distinct) on another while also using a where like clause to find a particular description (desc).
Here's my sql with pig I am trying to code.
/*
For example in sql:
select domain, count(distinct(segment)) as segment_cnt
from table
where desc='ABC123'
group by domain
order by segment_count desc;
*/
A = LOAD 'myoutputfile' USING PigStorage('\u0005')
AS (
domain:chararray,
segment:chararray,
desc:chararray
);
B = filter A by (desc=='ABC123');
C = foreach B generate domain, segment;
D = DISTINCT C;
E = group D all;
F = foreach E generate group, COUNT(D) as segment_cnt;
G = order F by segment_cnt DESC;

Answer 1

You could GROUP on each domain and then count the number of distinct elements in each group with a nested FOREACH syntax:
D = group C by domain;
E = foreach D {
unique_segments = DISTINCT C.segment;
generate group, COUNT(unique_segments) as segment_cnt;
};

Answer 2

You can better define this as a macro:
DEFINE DISTINCT_COUNT(A, c) RETURNS dist {
temp = FOREACH $A GENERATE $c;
dist = DISTINCT temp;
groupAll = GROUP dist ALL;
$dist = FOREACH groupAll GENERATE COUNT(dist);
}
Usage:
X = LOAD 'data' AS (x: int);
Y = DISTINCT_COUNT(X, x);
If you need to use it in a FOREACH instead then the easiest way is something like:
...GENERATE COUNT(Distinct(x))...
Tested on Pig 12.

Answer 3

If you don't want to count on any group, you use this:
G = FOREACH (GROUP A ALL){
unique = DISTINCT A.field;
GENERATE COUNT(unique) AS ct;
};
This will just give you a number.