I have a code segment as below that uses BufferedReader to read inputs from command shell:
String choice = "";
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
System.out.println("\nEnter choice: ");
choice = br.readLine();
In this case, assuming '3' is my input, the console prints as follows:
Enter choice:
3
I would like to know how can I make the console prints such that it appears as follows:
Enter choice: 3
Appreciate any help!
Change System.out.println("\nEnter choice ");
to
System.out.print("\nEnter choice: ");
(println adds a line terminator at the end of the input string)
Related
In Go, I run the application from the command line as follows:
myapp -message "FOK \nHost:"
In my code:
var args = os.Args
var command = args[1]
var message= args[2]
the message will have the value "FOK \nHost:". Printing the value of message gives me:
fmt.Println("message-> " + message)
output
message-> FOK \nHost:
but if I set the value of the message in the application using the same value, the output is different.
message = "FOK \nHost:"
output
message mod-> FOK
Host:
I'm trying to accomplish the second result, so I'm trying to figure out why are the arguments string different thane when I assign it in the code.
I am running a test suite in Soap UI where I am trying to call one ruby script from groovy script. The step is getting executed successfully but still the script is not able to move on to the next step as it gives this error after running.
Have searched in google about this error, but found no proper resolution. Moreover the error itself is not very explanatory.
Will appreciate any kind of help.
Below is the groovy script which is calling "ap-v4-batch_DEV_QA.rb" ruby script.
This ruby script opens a browser and performs the task successfully and closes the browser. We expect the step to be marked as Passed so that it can move on to the next step, but it gives the error mentioned at the bottom.
Groovy Script:
String script = "webdriver/v4/ap-v4-batch_DEV_QA.rb";
String argv0 = com.eviware.soapui.SoapUI.globalProperties.getPropertyValue("GLOB_DefaultIP");
String argv1 = "com.wupay.batch.process.tasks.PaymentFileParsingTask_RunOnce";
String argv2 = "";
String argv3 = "";
String argv4 = "";
/* Nothing needs to be modified below */
String commandLine = "ruby " + com.eviware.soapui.SoapUI.globalProperties.getPropertyValue("GLOB_ScriptLocation") + "/" + script + " " + argv0 + " " + argv1 + " " + argv2 + " " + argv3 + " " + argv4;
log.info("Running command line: " + commandLine);
java.lang.Runtime runtime = java.lang.Runtime.getRuntime();
java.lang.Process p = runtime.exec(commandLine);
def propertyStep = testRunner.testCase.getTestStepByName("Properties");
java.io.BufferedReader stdInput =
new java.io.BufferedReader(new java.io.InputStreamReader(p.getInputStream()));
java.io.BufferedReader stdError =
new java.io.BufferedReader(new java.io.InputStreamReader(p.getErrorStream()));
String s = null;
String e = null;
StringBuffer eb = new StringBuffer();
while ((e = stdError.readLine()) != null) {
eb.append(e);
log.error("Ruby: " + e);
}
while ((s = stdInput.readLine()) != null) {
log.info("Ruby: " + s);
if(s.startsWith("#prop")) {
String[] propSplit = s.split(":", 3);
testRunner.testCase.setPropertyValue(propSplit[1], propSplit[2]);
}
}
p.waitFor();
log.info("Ruby: exit value " + p.exitValue());
if(eb.length() > 0) {
throw new Exception(eb.toString());
}
Error:
java.lang.Exception: C:/Ruby23/lib/ruby/site_ruby/2.3.0/rubygems/core_ext/kernel_require.rb:133:in require':require "watir-webdriver"is deprecated. Please, userequire "watir". java.lang.Exception: C:/Ruby23/lib/ruby/site_ruby/2.3.0/rubygems/core_ext/kernel_require.rb:133:inrequire': require "watir-webdriver" is deprecated. Please, use require "watir". error at line: 57
I have finally resolved the issue.
The issue was that ruby script was not accepting require "watir-webdriver".
I installed watir and replaced require "watir-webdriver" with require "watir".
now I am not getting the above mentioned error.
Thanks anyways!
Regards,
Faraz
static void Starter(ref int[,] grid)
{
StreamReader reader = new StreamReader(Assembly.GetExecutingAssembly().GetManifestResourceStream(Resources.Sudoku));
string line = reader.ReadLine();
Console.Write(line);
Console.ReadLine();
}
I know this isn't right, but it gets my point across.
I would like to be able to read in the resource file one line at a time.
Like so:
System.IO.StreamReader StringFromTxt
= new System.IO.StreamReader(path);
string line = StringFromTxt.ReadLine();
I do not necessarily have to read in from the resource, but I am not sure of any other way to call a text file without knowing the directory every time, or hard coding it. I can't have the user pick files.
StreamReader sr = new StreamReader("D:\\CountryCodew.txt");
while (!sr.EndOfStream)
{
string line = sr.ReadLine();
}
MSDN lists the following as the way to read in one line at a time:
https://msdn.microsoft.com/en-us/library/aa287535(v=vs.71).aspx
int counter = 0; //keep track of #lines read
string line;
// Read the file and display it line by line.
System.IO.StreamReader file =
new System.IO.StreamReader("c:\\test.txt");
while((line = file.ReadLine()) != null)
{
Console.WriteLine (line);
counter++;
}
file.Close();
// Suspend the screen.
Console.ReadLine();
Additional examples for getline:
https://msdn.microsoft.com/en-us/library/2whx1zkx.aspx
I would like to get a working code to simply remove from a text line a specific part that always begins with "(" and finish with ")".
Sample text : Hello, how are you (it is a question)
I want to remove this part: "(it is a question)" to only keep this message "Hello, how are you"
Lost...
Thanks
One way using Regular Expressions;
input = "Hello, how are you (it is a question)"
dim re: set re = new regexp
with re
.pattern = "\(.*\)\s?" '//anything between () and if present 1 following whitespace
.global = true
input = re.Replace(input, "")
end with
msgbox input
If the part to be removed is always at the end of the string, string operations would work as well:
msg = "Hello, how are you (it is a question)"
pos = InStr(msg, "(")
If pos > 0 Then WScript.Echo Trim(Left(msg, pos-1))
If the sentence always ends with the ( ) section, use the split function:
line = "Hello, how are you (it is a question)"
splitter = split(line,"(") 'splitting the line into 2 sections, using ( as the divider
endStr = splitter(0) 'first section is index 0
MsgBox endStr 'Hello, how are you
If it is in the middle of the sentence, use the split function twice:
line = "Hello, how are you (it is a question) and further on"
splitter = split(line,"(")
strFirst = splitter(0) 'Hello, how are you
splitter1 = split(line,")")
strSecond = splitter1(UBound(Splitter1)) 'and further on
MsgBox strFirst & strSecond 'Hello, how are you and further on
If there is only one instance of "( )" then you could use a '1' in place of the UBound.
Multiple instances I would split the sentence and then break down each section containing the "( )" and concatenate the final sentence.
I wrote a simple program to gather some statistics about bigrams in some data.
I print statistics to a custom file.
Path file = new Path(context.getConfiguration().get("mapred.output.dir") + "/bigram.txt");
FSDataOutputStream out = file.getFileSystem(context.getConfiguration()).create(file);
My code has following lines:
Text.writeString(out, "total number of unique bigrams: " + uniqBigramCount + "\n");
Text.writeString(out, "total number of bigrams: " + totalBigramCount + "\n");
Text.writeString(out, "number of bigrams that appear only once: " + onceBigramCount + "\n");
I get following output in vim/gedit:
'total number of unique bigrams: 424462
!total number of bigrams: 1578220
0number of bigrams that appear only once: 296139
Apart from unwanted characters at the beginning of the lines, there are some non-printing characters too. What could be the reason behind this?
As #ThomasJungblut says, the writeString method writes out two values for each call to writeString - the length of the string (as a vint) and the String bytes:
/** Write a UTF8 encoded string to out
*/
public static int writeString(DataOutput out, String s) throws IOException {
ByteBuffer bytes = encode(s);
int length = bytes.limit();
WritableUtils.writeVInt(out, length);
out.write(bytes.array(), 0, length);
return length;
}
If you just want to be able to print textual output to this file (i.e. all human readable), then i suggest you wrap the out variable with a PrintStream, and use the println or printf methods:
PrintStream ps = new PrintStream(out);
ps.printf("total number of unique bigrams: %d\n", uniqBigramCount);
ps.printf("total number of bigrams: %d\n", totalBigramCount);
ps.printf("number of bigrams that appear only once: %d\n", onceBigramCount);
ps.close();