I am new to oracle. In our application, we need to execute a procedure when the run duration of a scheduled job exceeds 10 minutes. We are checking in user_scheduler_jobs table and have to fire a procedure when the last_run_duration column exceeds 10 minutes. We tried to create a trigger for this purpose as shown below :
CREATE TRIGGER TRG1
AFTER UPDATE ON ALL_SCHEDULER_JOBS
BEGIN
MONITOR_JOB_DURATION();
END TRG1;
But when I try to compile the trigger it is showing an error as
Error report:
ORA-25001: cannot create this trigger type on views
25001. 00000 - "cannot create this trigger type on views"
*Cause: Only INSTEAD OF triggers can be created on a view.
*Action: Change the trigger type to INSTEAD OF.
Is user_scheduler_jobs a view?
If I proceed with INSTEAD OF trigger, will it effect the updation which is automatically happening after job execution?
Is user_scheduler_jobs a view? It surely is. What's more, it is in the SYS schema and you really should not be attempting to mess with that schema. It is crucial to the running of your database and it should be kept exactly as Oracle installs it.
Oracle Enterprise Manager has some functionality to monitor jobs. Did you look at that before embarking on rolling your own?
The best way to deal with this is to check in your code how long something has been running and then do something. As APC says on no account start putting triggers or anything else in the SYS schema, you'll cause more trouble that it's worth. Something like the below should work:
declare
l_start_time date default sysdate;
-- other stuff
begin
-- do something
if sysdate - l_start_time > ( 1 / 24 / 6 )
-- run something else
-- maybe using dbms_scheduler
end if;
-- do more stuff
end;
Related
We are initiating the rebuilding of many materialized views by using dbms_job.submit to execute a stored procedure that perform the rebuilding. However, I am having trouble trying to figure out how to determine if a submitted job failed. The issue that I am having is that the job is failing but I cannot identify what the issue is. So, I am trying to start out with a simple example, which is probably failing on a permission issue but I don't know where to look for the error message.
I have the following test procedure that I want to initiate using dbms_job.submit.
CREATE OR REPLACE PROCEDURE MYLANID.JUNKPROC
AS
lv_msg varchar2(3000);
BEGIN
INSERT INTO MYLANID.junk_log ( msg ) VALUES ('Hello World' );
commit;
EXCEPTION
WHEN OTHERS THEN
lv_msg := SUBSTR(sqlerrm, 1, 3000);
INSERT INTO MYLANID.junk_log ( msg ) VALUES (lv_msg);
END;
/
Note that this table is used above:
CREATE TABLE MYLANID.JUNK_LOG (
EVENT_TIME TIMESTAMP(6) DEFAULT systimestamp,
MSG VARCHAR2(3000 BYTE))
To submit the above procedure as a job, I execute the following anonymous block.
declare l_jobid binary_integer;
BEGIN
dbms_job.submit(job => l_jobid, what => 'BEGIN MYLANID.JUNKPROC; END;');
DBMS_OUTPUT.PUT_LINE('l_jobid:' || l_jobid);
commit;
END;
I then execute the following SQL...
select * from all_jobs;
...to see one record that represents my submitted job. When I re-query the all_jobs view, I see that this record quickly disappears from the view within a few seconds, presumably when the job completes. All is happy so far. I would like to use the presence of a record in the all_jobs view to determine whether a submitted job is running or has failed. I expect to be able to tell if it failed by looking at the ALL_JOBS.FAILURES column having a non null value > 0.
The problem, probably a permission issue, begins when I switch to another schema and I switch all of the occurrences of the above SQL and replace "MYSCHEMA" with "ANOTHERSCHEMA" that I also have access to. For example, I create the following
Table: ANOTHERSCHEMA.JUNK_LOG
Procedure: ANOTHERSCHEMA.JUNKPROC
I am even able to execute the stored procedure successfully in a query window while logged in as MYSCHEMA:
EXEC ANOTHERSCHEMA.JUNKPROC
However, if I execute the following code to submit a job that involves running the same ANOTHERSCHEMA procedure but by submitting it as a JOB...
declare l_jobid binary_integer;
BEGIN
dbms_job.submit(job => l_jobid, what => 'BEGIN ANOTHERSCHEMA.JUNKPROC; END;');
DBMS_OUTPUT.PUT_LINE('l_jobid:' || l_jobid);
commit;
END;
...then, when I query the jobs ALL_JOBS view...
select * from all_jobs;
...I see that the job has a positive value for the column FAILURE and I have no record of what the error was. This FAILURE count value continues to gradually increment over time as Oracle presumably retries up to 16? times until the job is marked BROKEN in the ALL_JOBS view.
But this is just a simple example and I don't know where to look for the error message that would tell me why the job using ANOTEHRSCHEMA references failed.
Where Do I look for the error log of failed jobs? I'm wondering if this will be somewhere only the DBA can see...
Update:
The above is just a simple test example. In my actual real world situation, my log shows that the job was submitted but I never see anything in USER_JOBS or even DBA_JOBS, which should show everything. I don't understand why the dbms_job.submit procedure would return the job number of the submitted job indicating that it was submitted but no job is visible in the DBA_JOBS view! The job that I did submit should have taken a long time to run, so I don't expect that it completed faster than I could notice.
First off, you probably shouldn't be using dbms_job. That package has been superseded for some time by the dbms_scheduler package which is significantly more powerful and flexible. If you are using Oracle 19c or later, Oracle automatically migrates dbms_job jobs to dbms_scheduler.
If you are using an Oracle version prior to 19c and a dbms_job job fails, the error information is written to the database alert log. That tends to be a bit of a pain to query from SQL particularly if you're not a DBA. You can define an external table that reads the alert log to make it queryable. Assuming you're on 11g, there is a view, x$dbgalertext, that presents the alert log information in a way that you can query it but DBAs generally aren't going to rush to give users permission on x$ tables.
If you use dbms_scheduler instead (or if you are on 19c or later and your dbms_job jobs get converted to dbms_scheduler jobs), errors are written to dba_scheduler_job_run_details. dbms_scheduler in general gives you a lot more logging information than dbms_job does so you can see things like the history of successful runs without needing to add a bunch of instrumentation code to your procedures.
I'm trying to create my trigger but it's asking for binds EVERY time. It works the way I want it to when I click apply on the window that appears... However, it will log an error...
My trigger checks to see if a client is active or not and do NOT allow changes if it is found to be active...
CREATE Trigger Client_Activity
BEFORE Insert or Update or Delete ON Client
FOR EACH ROW
DECLARE
VAR_AC char(2);
BEGIN
IF UPDATING THEN
SELECT Activity INTO VAR_AC
FROM Client_Additionals
WHERE Activity = :Old.Activity;
IF Activity = 'AC'
THEN Raise_Application_Error(-20999, 'active')
END IF;
END;
/
ORACLE VERSION 12 USING SQLDEVELOPER
You have two syntax errors in your trigger:
The IF is missing an END IF
You need to compare the content of the variable var_ac
You are missing a ; after the Raise_Application_Error()
Putting that together, you can create the trigger without problems.
However, you need to use the "Run Script" button in SQL Developer to run a PL/SQL block like that.
SQL*Plus requires no special handling:
I have an 'after create on database' trigger to provide select access on newly created tables within specific schemas to different Oracle roles.
If I execute a create table ... as select statement and then query the new table in the same block of code within TOAD or a different UI I encounter an error, but it works if I run the commands separately:
create table schema1.table1 as select * from schema2.table2 where rownum < 2;
select count(*) from schema1.table1;
If I execute them as one block of code I get:
ORA-01031: insufficient privileges
If I execute them individually, I don't get an error and am able to obtain the correct count.
Sample snippet of AFTER CREATE trigger
CREATE OR REPLACE TRIGGER TGR_DATABASE_AUDIT AFTER
CREATE OR DROP OR ALTER ON Database
DECLARE
vOS_User VARCHAR2(30);
vTerminal VARCHAR2(30);
vMachine VARCHAR2(30);
vSession_User VARCHAR2(30);
vSession_Id INTEGER;
l_jobno NUMBER;
BEGIN
SELECT sys_context('USERENV', 'SESSIONID'),
sys_context('USERENV', 'OS_USER'),
sys_context('USERENV', 'TERMINAL'),
sys_context('USERENV', 'HOST'),
sys_context('USERENV', 'SESSION_USER')
INTO vSession_Id,
vOS_User,
vTerminal,
vMachine,
vSession_User
FROM Dual;
insert into schema3.event_table VALUES (vSession_Id, SYSDATE,
vSession_User, vOS_User, vMachine, vTerminal, ora_sysevent,
ora_dict_obj_type,ora_dict_obj_owner,ora_dict_obj_name);
IF ora_sysevent = 'CREATE' THEN
IF (ora_dict_obj_owner = 'SCHEMA1') THEN
IF DICTIONARY_OBJ_TYPE = 'TABLE' THEN
dbms_job.submit(l_jobno,'sys.execute_app_ddl(''GRANT SELECT
ON '||ora_dict_obj_owner||'.'||ora_dict_obj_name||' TO
Role1,Role2'');');
END IF;
END IF;
END IF;
END;
Jobs are asynchronous. Your code is not.
Ignoring for the moment the fact that if you're dynamically granting privileges that something in the world is creating new tables live in production without going through a change control process (at which point a human reviewer would ensure that appropriate grants were included) which implies that you have a much bigger problem...
When you run the CREATE TABLE statement, the trigger fires and a job is scheduled to run. That job runs in a separate session and can't start until your CREATE TABLE statement issues its final implicit commit and returns control to the first session. Best case, that job runs a second or two after the CREATE TABLE statement completes. But it could be longer depending on how many background jobs are allowed to run simultaneously, what other jobs are running, how busy Oracle is, etc.
The simplest approach would be to add a dbms_lock.sleep call between the CREATE TABLE and the SELECT that waits a reasonable amount of time to give the background job time to run. That's trivial to code (and useful to validate that this is, in fact, the only problem you have) but it's not foolproof. Even if you put in a delay that's "long enough" for testing, you might encounter a longer delay in the future. The more complicated approach would be to query dba_jobs, look to see if there is a job there related to the table you just created, and sleep if there is in a loop.
I have an error: 'ORA-04092: cannot COMMIT in a trigger' when trying to execute ddl command in one simple oracle after update trigger. Trigger needs to create public database link after one field in column is updated. Here is the source:
create or replace
TRIGGER CreateLinkTrigger
after UPDATE of Year ON tableInit
for each row
DECLARE
add_link VARCHAR2(200);
BEGIN
IF :new.year = '2014'
then
add_link := q'{create public database link p2014 connect to test14 identified by temp using 'ora'}';
execute immediate add_link;
END IF;
END;
So, as You can see i need to create new public database link after new year has been activated.
So when i try to update table 'tableInit' with year value of '2014' i get ORA-04092 error.
Is there any way to avoid this error, or another solution for this?
Thanks...
Creating a database link on the fly seems like an unusual thing to do; your schema should generally be static and stable. However, if you must, it would be simpler to wrap the update and the link in a procedure, or just issue two statements - presumably whatever performs the update is fairly controlled anyway, otherwise you'd have to deal with multiple people triggering this multiple times, which would be even more of a mess.
You can probably make this work by adding PRAGMA autonomous_transaction; to your trigger, as demonstrated for a similar issue (creating a view rather than a link) in this answer, but I'm not in a position to test that at the moment.
create or replace
TRIGGER CreateLinkTrigger
after UPDATE of Year ON tableInit
for each row
DECLARE
add_link VARCHAR2(200);
PRAGMA autonomous_transaction;
BEGIN
...
You could also make the trigger submit an asynchronous job to perform the DDL, as described in this answer, and there's more of an example in this answer, where you'd change the job's anonymous block to do your execute immediate.
It would probably be better to just create the links for the next few years in advance during a maintenance window, or on a schedule, or from a procedure; rather than trying to associate a schema change to a data change.
Okay, I'm new to Oracle PL/SQL and I've stumbled across a problem that I cannot figure out.
I have a procedure that leads to transferring data from one table to another and a trigger that activates on the insertion in the second table. I scheduled that procedure to run every minute (for testing - would be daily once I've figured it out), using the DBMS_JOB.SUBMIT - the scheduled part works perfectly, however after the completion of the procedure the trigger is not fired. I tried with before and after insert clauses, but it is still not working. If I call the procedure directly it works and it does fire the trigger just fine. So... I'm already wondering whether the scheduled procedure can fire the trigger at all?!
This is the schedule's code:
DECLARE
VJOBN BINARY_INTEGER;
BEGIN
DBMS_JOB.SUBMIT(
JOB => VJOBN,
INTERVAL => 'SYSDATE + 1/2880',
WHAT => 'BEGIN my_procedure(); END;'
);
END;
create or replace TRIGGER TO_PRJ
AFTER INSERT ON PROJECTS
FOR EACH ROW
BEGIN
IF INSERTING
THEN DBMS_OUTPUT.PUT_LINE('INSERTED PROJECT WITH ID: '||:NEW.PROJECT_ID||')
END IF;
END;
Table PROJECTS has ID number, name varchar2, and some other that are not important.
The procedure transfers the ID and the name from orders to projects.
P.S. I'm using http://apex.oracle.com and when I get the timestamp from it the time is actually 6 hours behind me - not sure if it can be of any significance...
DBMS_OUTPUT and DBMS_JOB do not work the way you are trying to use them. The scheduled job is probably running, the trigger is firing - but since DBMS_OUTPUTneeds to be activated in the session that executes the DBMS_OUTPUT commands (i.e. the internal session used by DBMS_JOB) you will never see any output.
DBMS_OUTPUT's output is not visible across session, so the session that issues the DBMS_JOB.submit command will NOT receive the output, even if DBMS_OUTPUT is activated for that session.
Try using scheduler, it's much better then jobs. And bring there code of trigger and tables, it may help