I am not a Solaris expert and I am trying to create a shell script that will change my prompt to PWD and the ksh to bash and I have this:
PS1='$PWD $ ' exec bash --noprofile --rcfile /dev/null
or
PS1='\w $' exec bash --noprofile --rcfile /dev/null
Both of them dont work from a sh. if i add them from the command line then the first time my bash appears on prompt and the second time the PS1='$PWD $' kicks in and my prompt changes.
Firstly, why is PS1='$PWD $' not working from shell script . and why do i have to run the command from command line twice to acheive my results.
Also, in my export/home/syed/ directory there are three files local.login, local.profile, and local.cshrc. is there any way i can use them that when ever i log in i dont need to run my shell script and upon login i get bash shell and my prompt as i want it
(am i asking too much, i dont like the ksh as it does not have any features like up arrow recall last commands and tab auto complete features)
thanks
Syed...
When you exec from within a script, the script is what is replaced, not the parent shell.
Try sourcing the script rather than running it.
Also, in Solaris, you can use passwd -e to change your login shell.
You may be able to symlink ~/.profile to your existing ~/local.profile (or similar). Note that .cshrc is for the C Shell and is not compatible with ksh or Bash.
If you want that your default shell will be bash, change it in /etc/passwd
When you exec bash it sets up its own environment from scratch. Pass it an --rcfile containing the settings you would like for it to inherit.
Related
I am trying to learn the basics of shell. I used vim editro for creating my own list of commands to be executed. Here is the way I created the code
vi mycommands
then inside this file I wrote
cd Documents
I am using macOS Catalina which has zsh by default but switched to bash
So when I write the following command in the terminal:
$ sh +x mycommands
It shows
+cd Documents
The Documents has some files and directories but it is not changing directory.Where am I going wrong?
Any help will be greatly appreciated.
Scripts run like sh myscript execute in a separate sub-shell, not the current shell. Changing directory inside a script will not cause your shell to change directory. If you want to change directory in your shell, you need to run the commands in your shell.
To do that, run:
. ./myscript (sh, bash) or source ./myscript (bash).
See this question.
I am trying to get a bash script to run in git bash while specifying a different .bashrc than the one in my home directory (or none at all) however it is proving an impossible task.
To my understanding this should work:
"C:\Program Files (x86)\Git\bin\sh.exe " --rcfile .bashrc --login -i C:/Scripts/myscript.sh
However no matter what I try either the --rcfile file flag will be completely ignored or the script will get parse errors because it is not parsed by bash.
The following are my findings:
--login flag is needed to get the script to be parsed by bash rather than windows command prompt
--rcfile and also --norc are completely ignored if flags --login is used
I have tried every possible combination I think of, including calling the script within my .bashrc file, swapping the flags around, using the -c flag to run the script command and swapping my .bashrc files around to try using the --norc flag instead.
Is this just a result of shitty bash implementation for windows or am I doing something wrong?
Any help on the matter is appreciated.
You can try sourcing your .bashrc inside the script myscript.sh.
source .bashrc
Or
. .bashrc
As far as I can tell, the -i flag is overridden by the fact that you provide a script for bash to run. Your shell isn't actually interactive, so --rcfile is ignored. The only way I can tell to both run a script and source an additional file is to use a non-interactive login shell; however, in that case, you are restricted to using .bash_profile, .bash_login, or .profile, whichever is found first:
bash --login myscript.sh
There is no --loginfile to override the choice of file sourced prior to myscript.sh.
UPDATE: I forgot about BASH_ENV.
export BASH_ENV=.bashrc
bash myscript.sh
I do not know how you would go about adding BASH_ENV to your environment in Git bash.
I want to run a script called tuxsay that combines fortune and cowsay to have tux say some words of wisdom. I made an alias in by .bash_aliases calling it tuxsay and executing the script
FORTUNE= $(fortune)
cowsay -f tux $FORTUNE
I then have a script that will spawn a new terminal and I want it to output the results of my first script then allow me to work in the terminal, something like
xterm -e "tuxsay&"
So how can I spawn a new terminal use cowsay then allow me to work in it?
Specifics: I have a startup script that will spawn applications that I typically use, and I want it to spawn a terminal that runs my tuxsay script then allows me to work. I am on Ubuntu 12.04 LTS and am running dwm 6.0
Why not just add your command to your .bashrc file? Then it will be run every time a new interactive shell is started. You can test if the $TERM variable contains "xterm", and make your output conditional upon that. e.g. add the following line to the end of .bashrc:
[[ "$TERM" =~ xterm ]] && tuxsay
Update
While I think the above is still probably the most useful general answer, I noticed a few more things:
tuxsay is a bash alias. bash aliases are only understood within bash itself, but when you pass a command to xterm -e, that command is executed directly by the xterm without any bash involvement. The system won't be able to find and execute a file called "tuxsay" and will fail.
If executed from bash, the & character will put tuxsay command (alias) in the background, but this doesn't really help here. What you need is a new shell to start up once tuxsay is done.
Be careful with .bash_aliases. I noticed on my Redhat-based system that aliases placed in this file were not working, because .bash_aliases file is not sourced in. (My Bash aliases don't work) So it looks like .bash_aliases is sourced by default from Ubuntu-based systems, but no guarantees for others.
With the above in mind, if you definitely want tuxsay to run on a per-xterm basis – i.e. you want to specify this on the xterm command line – you could do the following one-liner:
xterm -e 'cowsay -f tux $(fortune); bash'
This passes the compound command cowsay -f tux $(fortune); bash to xterm. This compound command consists of two commands: first do the cowsay thing, then start bash.
You could also put these two commands in a shell script and pass the shell-script to xterm.
How can I tell what type my shell is? ie, whether it's traditional sh, bash, ksh, csh, zsh etc.
Note that checking $SHELL or $0 won't work because $SHELL isn't set by all shells, so if you start in one shell and then start a different one you may still have the old $SHELL.
$0 only tells you where the shell binary is, but doesn't tell you whether /bin/sh is a real Bourne shell or bash.
I presume that the answer will be "try some features and see what breaks", so if anyone can point me at a script that does that, that'd be great.
This is what I use in my .profile:
# .profile is sourced at login by sh and ksh. The zsh sources .zshrc and
# bash sources .bashrc. To get the same behaviour from zsh and bash as well
# I suggest "cd; ln -s .profile .zshrc; ln -s .profile .bashrc".
# Determine what (Bourne compatible) shell we are running under. Put the result
# in $PROFILE_SHELL (not $SHELL) so further code can depend on the shell type.
if test -n "$ZSH_VERSION"; then
PROFILE_SHELL=zsh
elif test -n "$BASH_VERSION"; then
PROFILE_SHELL=bash
elif test -n "$KSH_VERSION"; then
PROFILE_SHELL=ksh
elif test -n "$FCEDIT"; then
PROFILE_SHELL=ksh
elif test -n "$PS3"; then
PROFILE_SHELL=unknown
else
PROFILE_SHELL=sh
fi
It does not make fine distinctions between ksh88, ksh95, pdksh or mksh etc., but in more than ten years it has proven to work for me as designed on all the systems I were at home on (BSD, SunOS, Solaris, Linux, Unicos, HP-UX, AIX, IRIX, MicroStation, Cygwin.)
I don't see the need to check for csh in .profile, as csh sources other files at startup.
Any script you write does not need to check for csh vs Bourne-heritage because you explicitly name the interpreter in the shebang line.
Try to locate the shell path using the current shell PID:
ps -p $$
It should work at least with sh, bash and ksh.
If the reason you're asking is to try to write portable shell code, then spotting the shell type, and switching based on it, is an unreliable strategy. There's just too much variation possible.
Depending on what you're doing here, you might want to look at the relevant part of the autoconf documentation. That includes an interesting (and in some respects quite dismal) zoology of different shell aberrations.
For the goal of portable code, this section should be very helpful. If you do need to spot shell variants, then there might be some code buried in autoconf (or at least in one of the ./configure scripts it generates) which will help with the sniffing.
You can use something like this:
shell=`cat /proc/$$/cmdline`
Oh, I had this problem. :D
There is a quick hack, use ps -p $$ command to list the process with PID of the current running process -- which is your SHELL. This returns a string table structure, if you want, you can AWK, or SED the shell out...
The system shell is the thing you see when you open up a fresh terminal window which is not set to something other than bash (assuming this is your default SHELL).
echo $SHELL
Generally, you can find out all the constants defined by running
set
If the output is a lot of stuff then run
set | less
so you can scroll it from the top of the command line or
set > set.txt
To save the output to a file.
Invoking a different interactive shell to bash in your terminal does not mean that your system shell gets changed to something else i.e. your system shell is set to bash although you invoke a csh shell from a bash shell just that one session.
The above means that typing /bin/csh or /bin/python in bash or whatever does not set the system shell to the shell you invoked, at all.
If you really want to see the SHELL constant change then you need to set it to something else. If successful you should see the new shell whenever you open a fresh terminal...
It's old thread but...
In GNU environment You can sh --help and get something like
BusyBox v1.23.2 (2015-04-24 15:46:01 GMT) multi-call binary.
Usage: sh [-/+OPTIONS] [-/+o OPT]... [-c 'SCRIPT' [ARG0 [ARGS]] / FILE [ARGS]]
Unix shell interpreter
So, the first line is shell type =)
I just started using a Solaris 10 (Sparc) box where I telnet in and get confronted with a very unfriendly interface (compared to the standard bash shell I use in cygwin or linux) --- the arrow keys do not work as I expect them to. Being an NIS system, changing the shell is not as easy as using the "chsh" command. And setting the SHELL environment variable in ~/.login and ~/.profile is not working for me. So I'm thinking that I may need to write a script to determine if bash is running the script and starting bash if the answer is no. My first attempt, trying to invoke /bin/bash from ~/.profile seems to work but kind of doesn't feel right. Other suggestions? And how do I tell programmatically which shell is actually executing?
You can tell what shell is running with echo $0. For example:
$ echo $0
-bash
If you're changing shell you probably want to replace the current shell process rather than be a child of it, so use exec.
Also, you want to pass bash the -l flag so it acts as if it has been called as part of the login process.
So you'll want something like:
exec bash -l
You are probably running with ksh(1) on Solaris. You have several options, read the manpage for ksh and configure it or install another shell you're more familiar with like bash. I'd personnaly recommend zsh.