g++, static initialization and -nostdlib - gcc

Question

Compiling / linking with -nostdlib seems to prevent static initialization, even if I add my own crti.s and crtn.s with .init/.fini sections.
Are there workarounds to make g++ generate static initialization code that is inserted in .init or that I can call manually?
This is what I tried:
g++ -o test.o -c -fno-use-cxa-atexit test.cc # has _start (entry point)
# that calls _init and _main
as -o crti.o crti.s # has _init in section .init
as -o crtn.o crtn.s
g++ -o test ./crti.o test.o -nodefaultlibs -nostartfiles ./crtn.o
-nodefaultlibs alone includes static initialization code and call, but forces use of libc-_start/_init.
-nodefaultlibs -nostartfiles allows me to use my own _start / _init, but does not include code or call to static initialization.

Answer 1

From gcc linker docs,
-nostdlib
Do not use the standard system startup files or libraries when
linking. No startup files and only the libraries you specify will be
passed to the linker, and options specifying linkage of the system
libraries, such as -static-libgcc or -shared-libgcc, are ignored.
Hence use,
-nodefaultlibs
Do not use the standard system libraries when linking. Only the libraries you specify will be passed to the linker, options specifying linkage of the system libraries, such as -static-libgcc or -shared-libgcc, will be ignored. The standard startup files are used normally, unless -nostartfiles is used. The compiler may generate calls to memcmp, memset, memcpy and memmove. These entries are usually resolved by entries in libc. These entry points should be supplied through some other mechanism when this option is specified.
Also try,
g++ -Wl, -static
-Wl passes the next command on to the linker
-static On systems that support dynamic linking, this prevents linking with
the shared libraries. On other systems, this option has no effect.