"Ruby-esque" if else conditional statements - ruby

Question

I'm currently reading The Ruby Programming Language, and I am not sure how to read Ruby-esque if else statements properly. Can you help me write the ruby code below in the second code block in regular if-else statements like this?
if some_condition
return x
else
return y
end
So the ruby codes I am unsure of are these.
minimum = if x < y then x else y end
max = x > y ? x : y
Thank you!

Answer 1

Both of the forms you seem to be having difficulty with make use of an idea Ruby takes from the Functional Programming paradigm: namely, Everything is an expression, and therefore returns a value. This is even true for conditional statements, an idea that languages like Java don't really support (for example:
public boolean test() {
boolean x = if (1 > 2 ) { false; } else { true; };
return x;
}
simply isn't syntactically valid).
You can see this in a Ruby terminal:
will_be_assigned_nil = false if (1 > 2) # => nil
will_be_assigned_nil # => nil
So, to your question.
The first one can be rewritten like this:
if x < y
mininum = x
else
minimum = y
end
The second is like the ternary operator in other languages, and is equivalent to:
if x > y
max = x
else
max = y
end
It's helpful to remember the roots & heritage of languages when trying to understand their constructs. Ruby shares the "More Than One Way To Do It" philosophy with Perl, and idiomatic Ruby code often has a high emphasis on elegance.
The "post-expression"-style conditionals are a good example of this. If I have guard expressions at the start of my methods, it's not uncommon for me to write:
raise "Pre-condition x not met" unless x # (or "if !x" , preference thing)
raise "Pre-condition y not met" unless y # etc., etc.
instead of
if !x
raise "Pre-condition x not met"
end
if !y
raise "Pre-condition y not met"
end