We have a huge chunk of data and we want to perform a few operations on them. Removing duplicates is one of the main operations.
Ex.
a,me,123,2631272164
yrw,wq,1237,123712,126128361
yrw,dsfswq,1323237,12xcvcx3712,1sd26128361
These are three entries in a file and we want to remove duplicates on the basis of 1st column. So, 3rd row should be deleted. Each row may have different number of columns but the column we are interested into, will always be present.
In memory operation doesn't look feasible.
Another option is to store the data in database and removing duplicates from there but it's again not a trivial task.
What design should I follow to dump data into database and removing duplicates?
I am assuming that people must have faced such issues and solved it.
How do we usually solve this problem?
PS: Please consider this as a real life problem rather than interview question ;)
If the number of keys is also infeasible to load into memory, you'll have to do a Stable(order preserving) External Merge Sort to sort the data and then a linear scan to do duplicate removal. Or you could modify the external merge sort to provide duplicate elimination when merging sorted runs.
I guess since this isn't an interview question or efficiency/elegance seems to not be an issue(?). Write a hack python script that creates 1 table with the first field as the primary key. Parse this file and just insert the records into the database, wrap the insert into a try except statement. Then preform a select * on the table, parse the data and write it back to a file line by line.
If you go down the database route, you can load the csv into a database and use 'duplicate key update'
using mysql:-
Create a table with rows to match your data (you may be able to get away with just 2 rows - id and data)
dump the data using something along the lines of
LOAD DATA LOCAL infile "rs.txt" REPLACE INTO TABLE data_table FIELDS TERMINATED BY ',';
You should then be able to dump out the data back into csv format without duplicates.
If the number of unique keys aren't extremely high, you could simply just do this;
(Pseudo code since you're not mentioning language)
Set keySet;
while(not end_of_input_file)
read line from input file
if first column is not in keySet
add first column to keySet
write line to output file
end while
If the input is sorted or can be sorted, then one could do this which only needs to store one value in memory:
r = read_row()
if r is None:
os.exit()
last = r[0]
write_row(r)
while True:
r = read_row()
if r is None:
os.exit()
if r[0] != last:
write_row(r)
last = r[0]
Otherwise:
What I'd do is keep a set of the first column values that I have already seen and drop the row if it is in that set.
S = set()
while True:
r = read_row()
if r is None:
os.exit()
if r[0] not in S:
write_row(r)
S.add(r[0])
This will stream over the input using only memory proportional to the size of the set of values from the first column.
If you need to preserve order in your original data, it MAY be sensible to create new data that is a tuple of position and data, then sort on the data you want to de-dup. Once you've sorted by data, de-duplication is (essentially) a linear scan. After that, you can re-create the original order by sorting on the position-part of the tuple, then strip it off.
Say you have the following data: a, c, a, b
With a pos/data tuple, sorted by data, we end up with: 0/a, 2/a, 3/b, 1/c
We can then de-duplicate, trivially being able to choose either the first or last entry to keep (we can also, with a bit more memory consumption, keep another) and get: 0/a, 3/b, 1/c.
We then sort by position and strip that: a, c, b
This would involve three linear scans over the data set and two sorting steps.
Related
We have a giant file which we repartitioned according to one column, for example, say it is STATE. Now it seems like after repartitioning, the data cannot be sorted completely. We are trying to save our final file as a text file but instead of the first state listed being Alabama, now California shows up first. OrderBy doesn't seem to have an effect after running the repartition.
df = df.repartition(100, ['STATE_NAME'])\
.sortWithinPartitions('STATE_NAME', 'CUSTOMER_ID', 'ROW_ID')
I can't find a clear statement in the documentation about this, only this hint for pyspark.sql.DataFrame.repartition:
The resulting DataFrame is hash partitioned.
Obviously, repartition doesn't bring the rows in a specific (namely alphabetic) order (not even if they were ordered previously), it only groups them. That .sortWithinPartitions imposes no global order is no wonder considering the name, which implies that the sorting only occurs within the partitions, not on them. You can try .sort instead.
I have an excel file which is non-system generated report format.
I wish to calculate and generate another new output.
Given the Report format as below:-
1) Inside the query when load this excel file, how can I create a new column to copy and paste on the first found value (1#51) at column at the next record, if the next record is empty. Once, if detected a new value (1#261) then copy and paste to the subsequent null value of few next records till this end?
2) The final aim is to generate a new output to auto match/calculate the money to be assign to different reference. As shown below:-
The reference A ~ E is sharing the 3 bank Ref (28269,28542 & RMP) , was thinking to read the same data source a few times, first time to read the column A ~ O(QueryRef) and 2nd time to read the same source to read from A, Q ~ V(QueryBank).
After this I do not have idea how I can allocate the $$ from Query Bank to QueryRef based on the Sum of Total AR.
Eg,
Total Amt of BankRef 28269, $57,044.67 is sufficient to cover Ref#A $10,947.12
BankRef 28269 still sufficient to cover Ref#B $27,647.60
BankRef 28269 left only $18,449.95 , hence the balance of 28269 be allocate to Ref#C.
Remaining balance of Ref#C will need to use BankRef28542 to cover,i.e. $1,812.29
Ref#D will then be allocated of the remaining balance of BankRef28542, i.e. $4,595.32
Ref#D still left $13,350.03 unallocated, hence this will use BankRef#RMP
Ref#E only need $597.66, and BankRef#RMP is sufficient to cover this.
I am not sure if my above case study can be solved using power query or not, due to me still being a newbie # Power Query? Or this is too complicate to handle hence we need to write a program to auto matching this kinds of scenario?
Attached is the sample source file and output :
https://www.dropbox.com/sh/dyecwcdz2qg549y/AACzezsXBwAf8eHUNxxLD1eWa?dl=0
Any advice/opinion/guidance is very much appreciated.
Answering question one:
You have a feature in Powerquery called FILL, DOWN or UP.
For a selected column you can copy the first non empty value to all rows under until a new non empty row is found and so on.
I have some 'small' text files that contain about 500000 entries/rows. Each row has also a 'key' column. I need to find this keys in a big file (8GB, at least 219 million entries). When found, I need to append the 'Value' from the big file into the small file, at the end of the row as a new column.
The big file that is like this:
KEY VALUE
"WP_000000298.1" "abc"
"WP_000000304.1" "xyz"
"WP_000000307.1" "random"
"WP_000000307.1" "text"
"WP_000000308.1" "stuff"
"WP_000000400.1" "stuffy"
Simply put, I need to look up 'key' in the big file.
Obviously I need to load the whole table in RAM (but this is not a problem I have 32GB available). The big file seems to be already sorted. I have to check this.
The problem is that I cannot do a fast lookup using something like TDictionary because as you can see, the key is not unique.
Note: This is probably a one-time computation. I will use the program once, then throw it away. So, it doesn't have to be the BEST algorithm (difficult to implement). It just need to finish in decent time (like 1-2 days). PS: I prefer doing this without DB.
I was thinking at this possible solution: TList.BinarySearch. But it seems that TList is limited to only 134,217,727 (MaxInt div 16) items. So TList won't work.
Conclusion:
I choose Arnaud Bouchez solution. His TDynArray is impressive! I totally recommend it if you need to process large files.
AlekseyKharlanov's provided another nice solution but TDynArray is already implemented.
Instead of re-inventing the wheel of binary search or B-Tree, try with an existing implementation.
Feed the content into a SQLite3 in-memory DB (with the proper index, and with a transaction every 10,000 INSERT) and you are done. Ensure you target Win64, to have enough space in RAM. You may even use a file-based storage: a bit slower to create, but with indexes, queries by Key will be instant. If you do not have SQlite3 support in your edition of Delphi (via latest FireDAC), you may use our OpenSource unit and its associated documentation.
Using SQlite3 will be definitively faster, and use less resources than a regular client-server SQL database - BTW the "free" edition of MS SQL is not able to handle so much data you need, AFAIR.
Update: I've written some sample code to illustrate how to use SQLite3, with our ORM layer, for your problem - see this source code file in github.
Here are some benchmark info:
with index defined before insertion:
INSERT 1000000 rows in 6.71s
SELECT 1000000 rows per Key index in 1.15s
with index created after insertion:
INSERT 1000000 rows in 2.91s
CREATE INDEX 1000000 in 1.28s
SELECT 1000000 rows per Key index in 1.15s
without the index:
INSERT 1000000 rows in 2.94s
SELECT 1000000 rows per Key index in 129.27s
So for huge data set, an index is worth it, and creating the index after the data insertion reduces the resources used! Even if the insertion is slower, the gain of an index is huge when selecting per key.. You may try to do the same with MS SQL, or using another ORM, and I guess you will cry. ;)
Another answer, since it is with another solution.
Instead of using a SQLite3 database, I used our TDynArray wrapper, and its sorting and binary search methods.
type
TEntry = record
Key: RawUTF8;
Value: RawUTF8;
end;
TEntryDynArray = array of TEntry;
const
// used to create some fake data, with some multiple occurences of Key
COUNT = 1000000; // million rows insertion !
UNIQUE_KEY = 1024; // should be a power of two
procedure Process;
var
entry: TEntryDynArray;
entrycount: integer;
entries: TDynArray;
procedure DoInsert;
var i: integer;
rec: TEntry;
begin
for i := 0 to COUNT-1 do begin
// here we fill with some data
rec.Key := FormatUTF8('KEY%',[i and pred(UNIQUE_KEY)]);
rec.Value := FormatUTF8('VALUE%',[i]);
entries.Add(rec);
end;
end;
procedure DoSelect;
var i,j, first,last, total: integer;
key: RawUTF8;
begin
total := 0;
for i := 0 to pred(UNIQUE_KEY) do begin
key := FormatUTF8('KEY%',[i]);
assert(entries.FindAllSorted(key,first,last));
for j := first to last do
assert(entry[j].Key=key);
inc(total,last-first+1);
end;
assert(total=COUNT);
end;
Here are the timing results:
one million rows benchmark:
INSERT 1000000 rows in 215.49ms
SORT ARRAY 1000000 in 192.64ms
SELECT 1000000 rows per Key index in 26.15ms
ten million rows benchmark:
INSERT 10000000 rows in 2.10s
SORT ARRAY 10000000 in 3.06s
SELECT 10000000 rows per Key index in 357.72ms
It is more than 10 times faster than the SQLite3 in-memory solution. The 10 millions rows stays in memory of the Win32 process with no problem.
And a good sample of how the TDynArray wrapper works in practice, and how its SSE4.2 optimized string comparison functions give good results.
Full source code is available in our github repository.
Edit: with 100,000,000 rows (100 millions rows), under Win64, for more than 10GB of RAM used during the process:
INSERT 100000000 rows in 27.36s
SORT ARRAY 100000000 in 43.14s
SELECT 100000000 rows per Key index in 4.14s
Since this is One-time task. Fastest way is to load whole file into memory, scan memory line by line, parse key and compare it with search key(keys) and print(save) found positions.
UPD: If you have sorted list in source file. And assume you have 411000keys to lookup. You can use this trick: Sort you search keys in same order with source file. Read first key from both lists and compare it. If they differs read next from source until they equal. Save position, if next key in source also equal, save it too..etc. If next key is differ, read next key from search keys list. Continue until EOF.
Use memory-mapped files. Just think your file is already read into the memory in its entirety and do that very binary search in memory that you wanted. Let Windows care about reading the portions of file when you do your in-memory search.
https://en.wikipedia.org/wiki/Memory-mapped_file
https://msdn.microsoft.com/en-us/library/ms810613.aspx
https://stackoverflow.com/a/9609448/976391
https://stackoverflow.com/a/726527/976391
http://msdn.microsoft.com/en-us/library/aa366761%28VS.85.aspx
https://msdn.microsoft.com/en-us/library/windows/desktop/aa366537.aspx
You may take any of those sources for start, just do not forget to update them for Win64
http://torry.net/quicksearchd.php?String=memory+mapped+files&Title=No
A method that needs the file to be sorted, but avoids data structures entirely:
You only care about one line, so why even read the bulk of the file?
Open the file and move the "get pointer" (apologies for talking C) halfway through the file. You'll have to figure out if you're at a number or a word, but a number should be close by. Once you know the closest number, you know if it's higher or lower than what you want, and continue with the binary search.
Idea based on Aleksey Kharlanov answer. I accepted his answer.
I only copy his idea here because he did not elaborate it (no pseudo-code or deeper analysis of the algorithm). I want to confirm it works before implementing it.
We sort both files (once).
We load Big file in memory (once).
We read Small file line by line from disk (once).
Code:
In the code below, sKey is the current key in Small file. bKey is the current key in the Big file:
LastPos:= 0
for sKey in SmallFile do
for CurPos:= LastPos to BigFile.Count do
if sKey = bKey
then
begin
SearchNext // search (down) next entries for possible duplicate keys
LastPos:= CurPos
end
else
if sKey < bKey
then break
It works because I know the last position (in Big file) of the last key. The next key can only be somewhere UNDER the last position; ON AVERAGE it should be in the next 440 entries. However, I don't even have to always read 440 entries below LastPos because if my sKey does not exist in the big file, it will be smaller than the bKey so I quickly break the inner loop and move on.
Thoughts?
If I were doing this as a one-time thing, I'd create a set with all the keys I need to look up. Then read the file line-by line, check to see if the key exists in the set, and output the value if so.
Briefly, the algorithm is:
mySet = dictionary of keys to look up
for each line in the file
key = parse key from line
if key in mySet
output key and value
end for
Since Delphi doesn't have a generic set, I'd use TDictionary and ignore the value.
The dictionary lookup is O(1), so should be very fast. Your limiting factor will be file I/O time.
I figure that'd take about 10 minutes to code up, and less than 10 minutes to run.
Suppose I have two key-value data sets--Data Sets A and B, let's call them. I want to update all the data in Set A with data from Set B where the two match on keys.
Because I'm dealing with such large quantities of data, I'm using Hadoop to MapReduce. My concern is that to do this key matching between A and B, I need to load all of Set A (a lot of data) into the memory of every mapper instance. That seems rather inefficient.
Would there be a recommended way to do this that doesn't require repeating the work of loading in A every time?
Some pseudcode to clarify what I'm currently doing:
Load in Data Set A # This seems like the expensive step to always be doing
Foreach key/value in Data Set B:
If key is in Data Set A:
Update Data Seta A
According to the documentation, the MapReduce framework includes the following steps:
Map
Sort/Partition
Combine (optional)
Reduce
You've described one way to perform your join: loading all of Set A into memory in each Mapper. You're correct that this is inefficient.
Instead, observe that a large join can be partitioned into arbitrarily many smaller joins if both sets are sorted and partitioned by key. MapReduce sorts the output of each Mapper by key in step (2) above. Sorted Map output is then partitioned by key, so that one partition is created per Reducer. For each unique key, the Reducer will receive all values from both Set A and Set B.
To finish your join, the Reducer needs only to output the key and either the updated value from Set B, if it exists; otherwise, output the key and the original value from Set A. To distinguish between values from Set A and Set B, try setting a flag on the output value from the Mapper.
All of the answers posted so far are correct - this should be a Reduce-side join... but there's no need to reinvent the wheel! Have you considered Pig, Hive, or Cascading for this? They all have joins built-in, and are fairly well optimized.
This video tutorial by Cloudera gives a great description of how to do a large-scale Join through MapReduce, starting around the 12 minute mark.
Here are the basic steps he lays out for joining records from file B onto records from file A on key K, with pseudocode. If anything here isn't clear, I'd suggest watching the video as he does a much better job explaining it than I can.
In your Mapper:
K from file A:
tag K to identify as Primary Key
emit <K, value of K>
K from file B:
tag K to identify as Foreign Key
emit <K, record>
Write a Sorter and Grouper which will ignore the PK/FK tagging, so that your records are sent to the same Reducer regardless of whether they are a PK record or a FK record and are grouped together.
Write a Comparator which will compare the PK and FK keys and send the PK first.
The result of this step will be that all records with the same key will be sent to the same Reducer and be in the same set of values to be reduced. The record tagged with PK will be first, followed by all records from B which need to be joined. Now, the Reducer:
value_of_PK = values[0] // First value is the value of your primary key
for value in values[1:]:
value.replace(FK,value_of_PK) // Replace the foreign key with the key's value
emit <key, value>
The result of this will be file B, with all occurrences of K replaced by the value of K in file A. You can also extend this to effect a full inner join, or to write out both files in their entirety for direct database storage, but those are pretty trivial modifications once you get this working.
I'm using Windows Azure Table Storage to store millions of entities, however I'm trying to figure out the best solution that easily allows for two things:
1) a search on an entity, will retrieve that entity and at least (pageSize) number of entities either side of that entity
2) if there are more entities beyond (pageSize) number of entities either side of that entity, then page next or page previous links are shown, this will continue until either the start or end is reached.
3) the order is reverse chronological order
I've decided that the PartitionKey will be the Title provided by the user as each container is unique in the system. The RowKey is Steve Marx's lexiographical algorithm:
http://blog.smarx.com/posts/using-numbers-as-keys-in-windows-azure
which when converted to javascript instead of c# looks like this:
pad(new Date(100000000 * 86400000).getTime() - new Date().getTime(), 19) + "_" + uuid()
uuid() is a javascript function that returns a guid and pad adds zeros up to 19 chars in length. So records in the system look something like this:
PK RK
TEST 0008638662595845431_ecf134e4-b10d-47e8-91f2-4de9c4d64388
TEST 0008638662595845432_ae7bb505-8594-43bc-80b7-6bd34bb9541b
TEST 0008638662595845433_d527d215-03a5-4e46-8a54-10027b8e23f8
TEST 0008638662595845434_a2ebc3f4-67fe-43e2-becd-eaa41a4132e2
This pattern allows for every new entity inserted to be at the top of the list which satisfies point number 3 above.
With a nice way of adding new records in the system I thought then I would create a mechanism that looks at the first half of the RowKey i.e. 0008638662595845431_ part and does a greater than or less than comparison depending on which direction of the already found item. In other words to get the row immediately before 0008638662595845431 I would do a query like so:
var tableService = azure.createTableService();
var minPossibleDateTimeNumber = pad(new Date(-100000000*86400000).getTime() - new Date().getTime(), 19);
tableService.getTable('testTable', function (error) {
if (error === null) {
var query = azure.TableQuery
.select()
.from('testTable')
.where('PartitionKey eq ?', 'TEST')
.and('RowKey gt ?', minPossibleDateTimeNumber + '_')
.and('RowKey lt ?', '0008638662595845431_')
.and('Deleted eq ?', 'false');
If the results returned are greater than 1000 and azure gives me a continuation token, then I thought I would remember the last items RowKey i.e. the number part 0008638662595845431. So now the next query will have the remembered value as the starting value etc.
I am using Windows Azure Node.Js SDK and language is javascript.
Can anybody see gotcha's or problems with this approach?
I do not see how this can work effectively and efficiently, especially to get the rows for a previous page.
To be efficient, the prefix of your “key” needs to be a serially incrementing or decrementing value, instead of being based on a timestamp. A timestamp generated value would have duplicates as well as holes, making mapping page size to row count at best inefficient and at worst difficult to determine.
Also, this potential algorithm is dependent on a single partition key, destroying table scalability.
The challenge here would be to have a method of generating a serially incremented key. One solution is to use a SQL database and performing an atomic update on a single row, such that an incrementing or decrementing value is produced in sequence. Something like UPDATE … SET X = X + 1 and return X. Maybe using a stored procedure.
So the key could be a zero left padded serially generated number. Split such that say the first N digits of the number is the partition key and remaining M digits are the row key.
For example
PKey RKey
00001 10321
00001 10322
….
00954 98912
Now, since the rows are in sequence it is possible to write a query with the exact key range for the page size.
Caveat. There is a small risk of a failure occurring between generating a serial key and writing to table storage. In which case, there may be holes in the table. However, your paging algorithm should be able to detect and work around such instances quite easily by specify a page size slightly larger than necessary or by retrying with an adjusted range.