CakePHP 2.1.1 foreach - cakephp-2.1

Question

In my view I want a HTML table something like this:
COUNTRY TOWN
france paris
This is my query:
$foo=$this->country->find('all', array(
'contain' => array(
'Town' => array(
'conditions' => array("Town.country_id = country.id"),
'fields' => array('id','name')
)
)
)
);
I want to display to my view like this:
line6 <?php foreach ($diponibilite as $f): ?>
line7
line8 <tr>
line9 <td><?php echo $f['country']['name'];?></td>
line10 <td><?php echo $f['town']['name'];?></td>
line11
line12 </tr>
line13 <?php endforeach; ?>
The models 'country' and 'town' are associated:
country hasmany town and town belongsto country
unfortunately, an error:
Notice (8): Undefined index: name [APP\View\index\index.ctp, line 10]
Why?

Answer 1

The problem is that since you have a Country hasmany Town relationship there could be multiple towns in one country (as the output of debug( $f ) shows).
To print all of the towns you need another loop:
<?php foreach( $diponibilite as $f ): ?>
<tr>
<td><?php echo $f[ 'country' ][ 'name' ]; ?></td>
<td><?php
foreach( $f[ 'town' ] as $town ) {
echo $town[ 'name' ].' ';
}
?></td>
</tr>
<?php endforeach; ?>
Or, if you just want the first one, use $f[ 'town' ][ 0 ][ 'name' ].
Side note: if you have the associations set up properly, you don't need the condition in the find. You can just do
$foo = $this->country->find( 'all', array(
'contain' => array(
'Town.id',
'Town.name'
)
)
);