I run my shell script but return a error "syntax error near unexpected token `done'", I wonder why it is ? The important thing is I can run it in another computer...
See my code below:
input=$1
folder=$2
output=$3
while read line
do
url=`echo $line | awk -F'\t' '{print $2}'`
id=`echo $line | awk -F'\t' '{print $2}' | sed 's/http:\/\/buy.yahoo.com.tw\/gdsale\/gdsale.asp?gdid=//g'`
ans=`echo $line | awk -F'\t' '{print $3}'`
flag=`grep "$ans" $folder/$id".spec"`
if [ -n "$flag" ]; then
echo "yes $line" >> $3
else
echo "no $line" >> $3
fi
done < $input
Thanks!
If it runs on one machine but not another, then there are differences in the script files on the different machines. Perhaps you have different line endings on one machine -- check them both with dos2unix
Related
I've been trying to run this code in a server but always send an 'Eqw' status.
I want to process a file that contains three columns, one with a path, and the others are information about that file.
Can anyone please help me to figure out what's wrong in my code?
#!/bin/bash
source $HOME/.bashrc
source /share/apps/Profiles/share-profile.sh
module load compilers/python-2.7.15
MANIFEST=path with the file with three columns
TRIM=trimming program that does work properly
#Run pyadapter_trim.py to trim adapter sequences
COUNTER=0;
#for each file in the input manifest, run tirimming program
while read LINE
do
READ=`echo "$LINE" | awk -F"\t" '{print $1}'`
SAMPLE=`echo "$LINE" | awk -F"\t" '{print $2}'`
GENOME=`echo "$LINE" | awk -F"\t" '{print $3}'`
WDIR=`(dirname $READ1)`
cd $WDIR
QCDIR=$WDIR"/ats"
mkdir -p $QCDIR
echo -e "Processing sample ${SAMPLE}"
echo -e "${READ1}..."
python $TRIM -a $READ
echo ""
COUNTER=`expr $COUNTER + 1`
done < "$MANIFEST"
echo "$COUNTER Files Processed"
I've been trying to get this function to work. I'm on a 17" MacBook Pro Early 2011. Setting all the variables under "else" work great if you run them separately, they also echo properly. For some reason when I put them in the function… I get a syntax error on line 12 and
battery ()
{
BATTERYISPRESENT=`ioreg -l | grep Cycle`
if [[ $BATTERYISPRESENT != *'Cycle' ]]
then
echo "No Battery Present, Probably a desktop Mac."
else
BATTERYCYCLES=`system_profiler SPPowerDataType | grep "Cycle Count" | awk '{print $3}'`
BATTCURRCAP=`pmset -g batt | sed -n '2 p' | awk '{ print $2 }' | sed 's/;//g'`
BATTERYCHARGESTATUS=`system_profiler SPPowerDataType | grep "Charging" | awk '{ print $2 }'`
BATTERYISCHARGING=`system_profiler SPPowerDataType | grep -A 4 "AC Charger Information" | grep "Connected: " | awk '{ print $2 }'`
CHARGERISCONNECTED=`system_profiler SPPowerDataType | grep -A 4 "AC Charger Information" | grep "Connected: " | awk '{ print $2 }'`
echo $BATTERYCYCLES
echo $BATTCURRCAP
echo $BATTERYISCHARGING
echo $CHARGERISCONNECTED
}
The output reads:
line 12: unexpected EOF while looking for matching ``'
line 18: syntax error: unexpected end of file
Any assistance would be greatly appreciated.
A fi upon you — you're missing the fi at the end of the else.
I am writing a shell script and I would like to have this code
echo $(awk '{print $1}' /proc/uptime) / 3600 | bc
without the newline character at the end.
I wanted to write it using echo -n, but this code
echo -n $(awk '{print $1}' /proc/uptime) / 3600 | bc
results a syntax error:
(standard_in) 1: syntax error
Can you help me with this?
Thank you very much!
echo $(awk '{print $1}' /proc/uptime) / 3600 | bc | tr -d "\n"
Alternatives:
echo -n $(($(cut -d . -f 1 /proc/uptime)/3600))
mapfile A </proc/uptime; echo -n $((${A%%.*}/3600))
A solution using echo -n:
echo -n $(echo $(awk '{print $1}' /proc/uptime) / 3600 | bc)
In general, if foo produces a line of output, you can print the same output without a newline using echo -n $(foo), even if foo is complicated.
A more straightforward solution using pure awk (since awk does arithmetic and output formatting, there's not much point in using both awk and bc):
awk '{printf("%d", $1 / 3600)}' /proc/uptime
I run my safe shell script to make sure a binary is running
to check a binary is running I do following command
pidof prog.bin | awk '{print NF}'
is some system it gives me 0 when binary not running
and
in some systems it gives me NULL(nothing)
I can check the NULL using -z option but why awk command acting this way ??
Instead of pidof you can use:
pgrep -qf prog.bin
And check its exit status.
As per man pgrep:
-f Match against full argument lists. The default is to match against process names.
-q Do not write anything to standard output.
You can use this,
if [ `pidof 'NetworkManager'` ]; then
echo "Running"
else
echo "Not Running"
fi
One way to handle this sort of thing (undefined variables) in awk is like this:
echo hi | awk '{print a}'
compared with:
echo hi | awk '{print a || 0}'
0
One Liner for If else
[[ $(pidof 'NetworkManager') ]] && echo "Running" || echo "Not Running"
Try this:
pidof prog.bin | awk '{ if (NF!=0) print NF }'
Here's some tests with awk and NF:
$ # regular line of input
$ echo foo | awk '{print NF}'
1
$ # empty line
$ echo | awk '{print NF}'
0
$ # a word on input with no newline
$ printf "%s" nonewline | awk '{print NF}'
1
$ # no input, not even a newline
$ printf %s | awk '{print NF}'
# no output from awk
I suspect the pidof case is the last: not even a newline. To force a newline:
echo $(pidof prog) | ...
printf "%s\n" "$(pidof prog)" | ...
I am getting the below error ith my code.What is missing in it? My goal is to print 13.0.5.8 in $version
#!/bin/ksh
file="abc_def_APP_13.0.5.8"
if echo "$file" | grep -E "abc_def_APP"; then
echo "Version found: $file"
version1=(echo $file | awk -F_ '{print $NF}' | cut -d. -f1-3)
version2=(echo $file | awk -F_ '{print $NF}' | cut -d. -f4-)
echo $version1
echo $version2
version=$version$version2
echo $version
else
echo "Version not found"
fi
Please find below the error:
./version.sh: line 7: syntax error near unexpected token `|'
./version.sh: line 7: ` version1=(echo $file | awk -F_ '{print $NF}' | cut -d. -f1-3)'
./version.sh: line 9: syntax error near unexpected token `|'
./version.sh: line 9: ` version2=(echo $file | awk -F_ '{print $NF}' | cut -d. -f4-)'
./version.sh: line 18: syntax error near unexpected token `else'
There's no need for awk at all. Just trim every character before the last underscore, like so:
file="abc_def_APP_13.0.5.8"
version="${file##*_}"
echo "$version"
See http://mywiki.wooledge.org/BashFAQ/073 for documentation on this technique, or see "parameter expansion" in bash's own docs.
To treat the last segment separately is also straightforward:
file="abc_def_APP_13.0.5.8"
version="${file##*_}" # result: 13.0.5.8
version_end="${version##*.}" # result: 8
version_start="${version%.*}" # result: 13.0.5
echo "${version_start}/${version_end}" # result: 13.0.5/8
Because this happens internally to bash, without executing any external commands (such as awk), it should be considerably faster to execute than other approaches given.
The problem is your backticks are missing $ you need to fix the following two lines like so:
version1=$(echo $file | awk -F_ '{print $NF}' | cut -d. -f1-3)
version2=$(echo $file | awk -F_ '{print $NF}' | cut -d. -f4-)
This will fix the syntactical errors. The following line doesn't make much sense as $version hasn't been initialize yet:
version=$version$version2
Did you mean:
version="${version1}.${version2}"
A side note you are using the -E option with grep but you aren't using any extended regexp features, in fact you are doing a fixed string string search so -F is more appropriate. You probably also want to use the -q option to suppress the output from grep.
Personally I would do:
file="abc_def_APP_13.0.5.8"
echo "$file" | awk '/abc_def_APP/{print "Version found: "$0;
print $4,$5,$6;
print $7;
print $4,$5,$6,$7;
next}
{print "Version not found"}' FS='[_.]' OFS=.
If you just want the version number in the variable version then why not simply:
version=$(echo "$file" | grep -o '[0-9].*')
It can all be done in a single awk command and without additional cut command. Consider following command:
read version1 version2 < <(echo $file|awk -F "[_.]" '{
printf("%s.%s.%s ", $4, $5, $6); printf("%s", $7);
for (i=8; i<=NF; i++) printf(".%s", $i); print ""}')
echo "$version1 :: $version2"
OUTPUT
13.0.5 :: 8