“can't convert Symbol into Integer” weird error - ruby

Question

The is the hash I am working on,
a = {
#...
:fares => {
:itinerary_fare => {
:segment_names=>"C",
:free_seats => "6",
:fare_for_one_passenger => {
:free_seats=>"0",
:#currency => "TL",
:#non_refundable => "false",
:#price => "439.0",
:#service_fee => "25.0",
:#tax => "33.0",
:#type => "Y"
},
:#currency => "TL",
:#non_refundable => "false",
:#price => "439.0",
:#service_fee => "25.0",
:#tax => "33.0",
:#type => "C"
},
:#currency => "TL",
:#tax => "33.0"
},
#..
}
also here another example http://pastebin.com/ukTu8GaG.
The code that gives me headhaches,
a[:fares][:itinerary_fare].each do |f|
puts f[:#price]
end
If I write this into console, it gives me "can't convert Symbol into Integer" error. But if I write, a[:fares][:itinerary_fare][:#price] it works pretty fine.
The weirdest part is, if I write the code to a haml file
%tbody
-#flights.each do |a|
%tr.flight
%td
-a[:fares][:itinerary_fare].each do |f|
-puts f[:#price] #Weird stuff happens here
.prices
%input{:type=>"radio",:name=>"selectedfight",:value=>"#{a[:id]}"}
= f[:#price]
%br
It works, it prints the prices to my console, yet it fails at the SAME LINE.
can't convert Symbol into Integer file: flights.haml location: [] line: 18
This is the most disturbing error I have ever seen, thanks for any help.
Most of the time there are more than 1 :itinerary_fare, I have to iterate.
My data can be shown as http://postimage.org/image/6nnbk9l35/

Answer 1

a[:fares][:itinerary_fare] is a Hash. Hash#each yields key-value-pair arrays to the block.
So, f takes e.g. the array [:#price, "439.0"] in the block.
Hence you are using a symbol (:#price) as an array index. An integer is expected.
In a[:fares][:itinerary_fare][:#price] you are giving it as hash key which works of course.

Answer 2

Why did you delete the previous question, that was already correctly answered? You could only just updated it with more information.
As was answered by other user in your previous post you are iterating over the elements in a[:fares][:itinerary_fare]. You can see this with:
a[:fares][:itinerary_fare].each do |f|
puts f
end
And you dont need a loop, you can use:
a[:fares][:itinerary_fare][:#price]
If you have more than one :itinerary_fare it will only consider the last one, since it's a key of the hash :fares. Maybe you need an array like (left to minimal of elements):
a = {:id=>"1",
:fares=>{
:itinerary_fares=>[{:#price=>"439"}, {:#price=>"1000"}]
}
}
and then:
a[:fares][:itinerary_fares].each do |f|
puts f[:#price]
end