I want to convert a URL which is of the format
path/to/my/app/Controller_action/id/2
to
path/to/my/app/Controller_action/id/User_corresponding_to_id_2
I have already seen this tutorial from Yii, but it isnt helping me with anything. Can anyone help me with this?
EDIT: I would also like to know if this thing is even possible in the POST scenario, ie I will only have path/to/my/app/Controller_action in the URL.
Add a getUrl method in your User model
public function getUrl()
{
return Yii::app()->createUrl('controller/action', array(
'id'=>$this->id,
'username'=>$this->username,
));
}
Add the following rule urlManager component in config/main.php
'controller/action/<username:.*?>/<id: \d+>'=>'controller/action'
And use the models url virtual attribute everywhere
dInGd0nG is on the correct track, but if I understand correctly you wish to do actions based on the actual username instead of the ID as well right?
It's not that hard in Yii. I'm assuming here for simplicity the controller is user and the action is view.
Your User controller:
public function actionView($id)
{
if (is_numeric($id))
$oUser = User::model()->findByPk($id);
else
// Luckily Yii does parameter binding, wouldn't be such a good idea otherwise :)
$oUser = User::model()->findByAttributes(array('username' => $id));
...
}
Your urlManager config:
'user/view/<id: \w+>' => 'user/view',
Or more generally:
'user/<action: \w+>/<id: \w+> => 'user/<action>',
To generate a user url in a view:
$this->createUrl('user/view', array('id' => $oUser->username));
Related
I'm wondering how I can render a view, or display a page with my default theme in OctoberCMS, via a route that executes a function in a controller.
If I have the following route:
Route::get('bransje', [
'uses' => 'Ekstremedia\Cityportal\CPController#bransje'
]);
And in my controller CPController ive tried several things, like I used to with Laravel:
public function bransje() {
$stuff = Stuff::with('info');
return View::make('cms::bransje')->with('stuff',$stuff);
}
But I cannot seem to get it to work, and I've tried to search the web, but it's hard to find answers. I have found a workaround, and that is to make a plugin component, then I can include that component and do:
public function onRun()
{
$this->eventen = $this->page['stuff'] = $this->stuff();
}
protected function stuff()
{
return ...
}
Is there any way so I can make pages without using the Cms, and that are wrapped in my default theme? I've tried
return View::make('my-theme-name::page');
and a lot of variants but no luck.
I know I can also do a:
==
public function onRun()
{
}
in the start of my page in the cms, but I'm not sure how to call a function from my plugin controller via there.
You can bypass frontend routing by using routes.php file in your plugin.
Full example in this video turotial.
If this answer can still be useful (Worked for October v434).
I have almost the same scenerio.
What I want to achieve is a type of routing like facebook page and profile.
facebook.com/myprofile is the same url structure as facebook.com/mypage
First I create a page in the CMS for each scenario (say catchpage.htm)
Then a created a catchall route at the buttom of routes.php in my plugin that will also not disturb the internal working of octobercms.
if (!Request::is('combine/*') && !Request::is('backend/*') && !Request::is('backend')) {
// Last fail over for looking up slug from the database
Route::get('{slug}/{slug2?}', function ($slug, $slug2 = null) {
//Pretend this are our routes and we can check them against the database
$routes = ["bola", "sade", "bisi", "ade", "tayo"];
if(in_array($slug, $routes)) {
$cmsController = new Cms\Classes\Controller;
return $cmsController->render("/catchpage", ['slug' => $slug]);
}
// Some fallback to 404
return Response::make(View::make('cms::404'), 404);
});
}
The if Request::is check is a list of all the resource that october uses under the hood, please dont remove the combine as it is the combiner route. Remove it and the style and script will not render. Also the backend is the url to the backend, make sure to supply the backend and the backend/*.
Finally don't forget to return Response::make(View::make('cms::404'), 404); if the resource is useless.
You may put all these in a controller though.
If anyone has a better workaround, please let us know.
I have defined a route in laravel 4 that looks like so :
Route::get('/books/{id}', 'HomeController#showBook');
in the url It shows /books/1 for example , now i'm asking is there a way to show the name of the book instead but to keep also the id as a parameter in the route for SEO purposes
thanks in advance
You could also do something like this:
Route::get('books/{name}', function($name){
$url = explode("-", $name);
$id = $url[0];
return "Book #$id";
});
So you can get book by id if you pass an url like: http://website.url/books/1-book-name
if your using laravel 8, this may be helpfull.
In your Controller add this
public function show(Blog $blog)
{
return view('dashboard.Blog.show',compact('blog'));
}
In your web.php add this
Route::get('blog/{blog}', [\App\Http\Controllers\BlogController::class,'show'])->name('show');
Then add this to your model (am using Blog as my Model)
public function getRouteKeyName()
{
return 'title'; // db column name you would like to appear in the url.
}
Note: Please let your column name be unique(good practice).
Result: http://127.0.0.1:8000/blog/HelloWorld .....url for a single blog
So no more http://127.0.0.1:8000/blog/1
You are welcome.
You can add as many parameters to the url as you like, like this:
Route::get('/books/{id}/{name}', 'HomeController#showBook');
Now when you want to create an url to this page you can do the following:
URL::action('HomeController#showBook', ['id' => 1, 'name' => 'My awesome book']);
Update:
If you are certain that there will never be two books with the same title, you can just use the name of the book in the url. You just need to do this:
Route::get('/books/{name}', 'HomeControllers#showBook');
In your showBook function you need to get the book from the database using the name instead of the id. I do strongly encourage to use both the id and the name though because otherwise you can get in trouble because I don't think the book name will always be unique.
You can also use model binding check more on laravel docs
For example
Route::get('book/{book:name}',[BookController::class,'getBook'])->name('book');
The name attribute in "book/{book:name}" should be unique.
It is said that shorter the URL, better the seo (atleast my client believes on it).
Now am creating website similar to watchtown.co.uk in laravel. I need to generate in such a way that the uri should not be more than one segment.
Requirement
I have following urls:
1.Need to change From:
localhost/laravelproj/public/brands/brandname/watches
to
localhost/laravelproj/public/brandname-watches.html
2.Need to change From:
localhost/laravelproj/public/brands/brandname/jewellery
to
localhost/laravelproj/public/brandname-jewellery.html
3.Need to change From:
localhost/laravelproj/public/categories/categoryname/watches
to
localhost/laravelproj/public/categoryname-watches.html
4.Need to change From:
localhost/laravelproj/public/categories/categoryname/jewellery
to
localhost/laravelproj/public/categoryname-jewellery.html
5.Need to change From:
localhost/laravelproj/public/products/productname
to
localhost/laravelproj/public/productname-watches.html
I hope you understood the pattern .
I can see watchtown.co.uk has done exactly the same (or is it any other way ?)
I created this function in controller for brands:
public function showProductListingByBrands($brandSlug) {
$brand = Brand::findBySlug($brandSlug)->first();
$products = "";
if($brand){
$products = $brand->products()->paginate(Misc::getSetting('paginate'));
}
$products = Product::findBySlug($brandSlug);
return View::make('store');
}
Now how do i manipulate it as my requirement? Im really new in laravel.
Thanks in advance.
Just to give you a brief idea.
On your route page
Route::get('/{product_name}/', array(
'as' => 'product_page',
'uses' => 'ProductPage#getProduct'
));
As you see when the user goes to the page like
Example: www.website.com/watch
it will go to the controller ProductPage with the method of getProduct, so the variable {product_name} will be passed on the controller.
Controller
public function getProduct($product_name = false) {
$product = Products::where('product_name', '=', $product_name);
// Do check product existing record
if ($product->count() == 0) {
return Redirect::route('some-page-error')
->with('failure', 'The hell are you doing?');
} else {
$product = $product->first();
return View::make('product_page')
->with('product_name', $product);
}
}
So on method getProduct, the parameter $product_name is watch
So, the method will check if the product exists or not, if not the user will be redirected to 404 page.
If not, it will be redirected to the template that you've made then pass all the product data and display it all there.
But it would be nice if you put the Route into /product/{product_name}, also it would be also good if it's product id instead of product name since product name can get redundant.
So yea.
edits
I don't know what you're trying to do and why it must be .html, but mmm.. Just wanna give you an idea. Well I don't know if my answer is a good way, someone might give better answer than me.
I'm building a website using Codeigniter and I really like how in the MVC pattern URLs are used to reference controller methods. It seems very logical and intuitive however, I seem to be running in an array of issues with this very pattern!
So I am building an events website and currently I'm passing everything through one main Site controller, passing a number of parameters:
public function index($page = NULL, $city = NULL, $type_venue = NULL, $slug = NULL)
{
// if the page argument is empty show the homepage
if( ! ($page))
{
$page = 'home';
}
// create an array for passing to the views
$data = array(
'title_city' => $city,
'title_type_venue' => str_replace('-', ' ', $type_venue),
'locations' => $this->locations_model->load(),
'events' => $this->events_model->load($city, $type_venue, $slug),
'venues' => $this->venues_model->load($city, $slug)
);
// construct the page layout with the following views
$this->load->view('partials/head', $data);
$this->load->view('partials/header', $data);
$this->load->view('content/'.$page, $data);
$this->load->view('partials/footer');
}
This works fine, in that it loads content for the following URLs:
site.com/events/bristol/open-mic/city-varieties/another-incredible-event
site.com/events/bristol/open-mic/city-varieties/
site.com/events/bristol/open-mic/
site.com/events/bristol/
However if I want to pass anything else through this controller that isn't an event, i.e. register/user, I have to write a specific route for this!
Worth noting my routing is:
$route['(:any)'] = 'site/index/$1';
I could write separate controllers for each entity, i.e. events, venues, cities but each one would look largely like the above (correct?) in that each would need the parameters to get the data.
My question is - what is the best practice approach for developing long query strings like this? Is a single controller correct? It doesn't feel like it, but then multiple controllers would violate DRY, just because they all need so much similar data. Any help appreciated!
Avoid putting everything into a single controller; even further, in each controller, avoid putting everything into a single index function.
There is no need to write specific controllers for each function in Codeigniter - suggest you read that part again in the manual. Most of your routing will be done automatically for you if you follow the normal guidelines.
The more you try to use a single controller or function, the more you will have to add untestable, unmanageable, unscalable conditional code later.
I am trying to do some very simple validation in my CakePHP contact form, but validation does not work eventhough I think I did everything necessary. Here's what I did:
I made a model like this:
class Office extends AppModel
{
var $name = 'Office';
var $useTable = false;
public $validate = array('onderwerp' => 'notEmpty');
}
(I also tried many other values for $validate from the CakePHP online manual)
In Config/bootstrap.php I made this rule for not letting CakePHP expect plural "Offices":
Inflector::rules('plural', array('rules' => array(),
'irregular' => array(),
'uninflected' => array('office')));
In OfficeController, I do this in my method contact():
$this->Office->set($this->request->data);
if($this->Office->validates()){
echo "code validates";
} else {
print_r($this->Office->validationErrors);
}
And in my Office/contact.ctp view, I have (amongst other code like starting and ending the form) this code:
$this->Form->input('onderwerp', array('label'=>false, 'size' => 60));
Now, even when I fill in the form, leaving empty the field 'onderwerp', it executes the code that should be executed when the code is executed.
When I print_r($this->request->data) or print_r($this->Office) I see that my onderwerp field is there and that it is empty (or filled when I do fill in something).
Now, when I add a public function validates() in my model and echo something there, it IS being displayed. So I'd say CakePHP knows where to find my model, and does execute my controller code. I also tried adding return parent::validates(); in my validates() function, but this also yielded no validation error, or any other error for that matter. My debug level is set to 2.
I guess I'm missing a needle in this haystack. Thanks for helping me finding it!
so drop all the inflector stuff.
and use the right model in your Form->create()
either
$this->Form->create(null)
or
$this->Form->create('Office');
and if you follow my advice to use a table less model with schema you will also have more power over input creation and validation.