is there any way to load a view (for header or footer) on every function (in a controller)? I have a couple of if/else statements there and it would be a pain to change it all when I'll need to.
Yes, you can load the view in the __construct function at the top of your controller. Take
a look at the PHP manual on Constructors
function __construct()
{
parent::__construct();
$this->load>-view('your_view');
}
If the header and footer are going to be constant and required components for the visual part of your site, but you may want to load a different content portion between your header and footer, then you can make a function that will take an argument.
private function doViews($argument)
{
$this->load->view('header');
$this->load->view($argument);
$this->load->view('footer');
return NULL;
}
You may want to have an array of available views inside the doViews function in order to do proper validation that the file exists. Then you simply call the function in each method in your controller like this:
$this->doViews('main_content');
You should try using a Template library like this: https://github.com/philsturgeon/codeigniter-template
Then all you need to is put this in the controller (can be in __construct or within a method)
$this->template->set_partial('header', 'layouts/header');
$this->template->set_partial('footer', 'layouts/footer');
$this->template->set_partial('sidebar', 'layouts/sidebar');
Then to send data like you do with a view:
$this->template->build('create', $this->data);
you could create your main_view ... as a master page that already has a structure:
main_view.php
$this->load>-view('header');
<?php //get content here
?>
$this->load>-view('footer');
If you want to change something in the header or footer (through a statement) you can add content:
function __construct()
{
parent::__construct();
$data['footer'] = ($a == 'foo') ? 'footer one' : 'footer two';
$data_to_main = $this->load->view('template/footer', $data, TRUE);
$data_to_main = 'others';
$this->load>-view('main_view', $data_to_main);
}
Related
My boss told me make dry navigation dont use repetitive code, for navigation i am trying to extend CI_Controler and with construct load header nav, body, footer files.
My question is when i create new controller and when i try to load different view files, how to achive that???
my extended controler
class MY_Controller extends CI_Controller
{
public function __construct() {
parent::__construct();
$this->load->view('view_header');
$this->load->view('includes/nav_home');
$this->load->view('view_home');
$this->load->view('view_footer');
}
}
and later when i am creating new controler how to load diffrent view files
class Pages extends MY_Controller
{
public function __construct() {
$this->load->view('includes/nav_new_view');
$
}
}
You can create a template library yourself. For example :
function template($view_name,$view_data){
//below will return html string from view name
$data['content'] = $this->load->view($view_name,$view_data,true)
//load main template view and pass the html string to main template
$this->load->view('main_template',$data);
}
In main template, just echo $content
If I understand your question, you're trying to achieve a template situation. For this, the best way is to actually call your templates view files within a primary page view. What I mean is your controller function (not the constructor, an actual class function representing a page) should call a primary view such as
$this->load->view('page1', $this->data);
and within that file, you call
$this->load->view('nav', $this->data);
then your content and then
$this->load->view('footer', $this->data);
You would then repeat the process for page 2 where in your controller's page2 function, you would call
$this->load->view('page2', $this->data);
and your page2 view file is almost identical to page1 except you use your page 2 content in that area.
You could even use a single template view file and pass it a $content variable (which obviously changes per page) and call
$this->load->view('template', $this->data);
This is the function that I am using in my controller
public function homeList()
{
//Get all the franchises
$franchises = Franchise::all();
//Load the view and pass the franchises
return View::make('frontend.layouts.footer')->with('franchises', $franchises);
}
and I keep getting this error. I don't know how to pass it or what to put on the routes.php file
You should be able to do #include('frontend.layouts.footer')->with('franchises', Franchise::all()).
Update:
To avoid the model in the view, you should use a view composer, as it was stated in a previous answer.
View::composer('frontend.layouts.footer', function($view)
{
$view->with('franchises', Franchise::all());
});
Now you have $franchises available in the view. This code you can place in routes.php or you can create a composers.php and autoload it.
I'm using CodeIgniter. I want to load views inside of other views. How can I do this?
Example:
Let's say I have a "view" called "CommentWall". In CommentWall, I want a bunch of "Comment" views. I use the view for "comment" all over my site!
How can I do this? It seems CodeIgniter only allows me to load views sequentially, which is sort of strange considering I use reusable views INSIDE of other views!
Can I do a $this->load->view('comment'); inside of my view for CommentWall? Or is there some other way to have reusuable views contained inside a view?
You can do it easily, just load the main view, for example CommentWall from the controller
$this->load->view('CommentWall');
To add child views in CommentWall view you can add following line inside your CommentWall view
$this->view('Comment');
For example, if you load CommentWall view from your controller like this
$data['comments'][] = 'Comment one';
$data['comments'][] = 'Comment two';
// load the parrent view
$this->load->view('CommentWall', $data);
Now in the CommentWall (parent view), if you put this
foreach ($comments as $comment) {
$this->view('Comment', array('comment' => $comment));
}
And in your Comment (child view) if you have this
echo $comment . '<br />';
Then you should get output something like this
Comment one
Comment two
Update : Alos, check this answer.
Try
class Main extends CI_Controller {
function __construct()
{
parent::__construct();
$data->comments =$this->load->view('comment');
$this->load->vars($data);
}
And in every view try
echo $comments;
Just load the "Comment" vies as string in controller and pass it to "CommentWall" view.
You can do it like this:
//Controller:
public function load_comment_wall($param) {
$comments_view = ""; //String that holds comment views
//here load the comments for this wall as follows:
//assuming $comment_ids is array of id's of comment to be put in this wall...
foreach($comment_ids as $comment_id) {
$temp = $this->load->view("comment",array('comment_id'=>$comment_id),TRUE); //Setting last parameter to TRUE will returns the view as String
$comments_view = $comment_views.$temp;
}
$data['comments'] = $comments_view;
//load comment wall
$this->load->view('comment_wall',$data);
}
//In Comment wall View, add the following line
echo $comments;
I have view (frontend) in my own component (view.html.php):
class MevViewMev extends JView{
function display($tpl = null){
parent::display($tpl);
}
}
And template:
<?php defined('_JEXEC') or die('Restricted access'); ?>
<div>
ASFADSFDSF
</div>
How to display it without joomla template (head section, styles, etc). I want to call this part of jquery onclick method in the window.
To display the component only add "tmpl=component" parameter to url.
If need to display something besides component's view it can be customized - create "component.php" file in template's root folder and include in it whatever you need.
More templates can be done in the same way - create "some_template.php" in template's root folder and add "tmpl=some_template" parameter to url.
Start Edit
OK so the below works, but I found a better way. In your controller do ...
if (JRequest::getVar('format') != 'raw') {
$url = JURI::current() . '?' . $_SERVER['QUERY_STRING'] . '&format=raw';
header('Location: ' . $url);
// or, if you want Content-type of text/html just use ...
// redirect($url);
}
End Edit
You can set 'tmpl' to 'component', as suggested by Babur Usenakunov, in which case scripts and css may be loaded, like ...
JRequest::setVar('tmpl','component');
However if you want to create raw output you can add &format=raw or in your component make a view of type 'raw' ...
Unfortunately the only functional way I can find to make a viewType of raw render correctly is to call exit() after the view class calls parent::display() ...
In your controller.php ...
class com_whateverController() extends JController
{
function __construct()
{
// the following is not required if you call exit() in your view class (see below) ...
JRequest::setVar('format','raw');
JFactory::$document = null;
JFactory::getDocument();
// or
//JFactory::$document = JDocument::getInstance('raw');
parent::__construct();
}
function display()
{
$view = $this->getView('whatever', 'raw');
$view->display();
}
}
then in views/whatever/view.raw.php ...
class com_whateverViewWhatever extends JView
{
public function display($tpl = null)
{
parent::display();
exit; // <- if you dont have this then the output is captured in and output buffer and then lost in the rendering
}
}
I know this comes in very late, but for future readers, here's how I did it for my extension, without editing the template, or adding anything in the URL (since I have control over neither of those):
jimport('joomla.application.component.view');
use \Joomla\CMS\Factory;
// Comp stands for the Component's name and NoTmpl stands for the View's name.
class CompViewNoTmpl extends \Joomla\CMS\MVC\View\HtmlView {
// Force this view to be component-only
public function __construct() {
$app = Factory::getApplication();
$app->input->set('tmpl', 'component');
parent::__construct();
}
I'm trying to add a link to one of my blocks to a specific action of one of my controllers. Looking through the class docs and googling didn't resolve something useful. (maybe I just used the wrong search queries).
My Controller has two actions:
indexAction() and exportAction()
Now, in one of my blocks I wand to add link to exportAction(). I've found the method addLink() but this doesn't work.
Maybe anyone knows how to do that ? Or could point me to the right resources on the net ?
Regards, Alex
Block Example:
<?php
class Polyvision_Tempest_Block_Adminhtml_View extends Mage_Adminhtml_Block_Template
{
public function __construct()
{
parent::__construct();
}
protected function _toHtml()
{
$html = "whatever";
return $html;
}
}
?>
Your question isn't clear/complete.
A block renders HTML, either through a phtml template or through PHP code. To add an HTML link, you just render a html anchor tag with an href
//via PHP
protected function _toHtml()
{
$html = 'My Link';
return $html;
}
//via phtml template
#your block
class Polyvision_Tempest_Block_Adminhtml_View extends Mage_Adminhtml_Block_Template
{
protected function _construct()
{
$this->setTemplate('path/to/from/template/folder/as/basetemplate.phtml');
}
}
#your template
My Link';
The addLink method is a special method that only applies to certain types of blocks. When you call it it add links information to the block's data properties. Then, it's _toHtml method or phtml template has been written such that it loops over the stored data to output links. It doesn't apply to general blocks, which is what makes your question confusing.
Hope that helps!